Doxygen's call/caller graph references missing for Fortran functions - fortran

I try to generate a call/caller graph for a fixed-form Fortran code using Doxygen 1.8.11 using Dot (GraphViz 2.38).
The call/caller graph works fine for subroutines, but fails (i.e. no references is drawn) for functions with a declared return value.
i.e. for the following code, the call to MYFUNC is not shown in the call graph of MYSUB:
integer function MYFUNC()
implicit none
MYFUNC = 1
end function
subroutine MYSUB ()
implicit NONE
integer MYFUNC
integer RESULT
RESULT = MYFUNC()
return
end
Interestingly, if I remove the line integer MYFUNC from MYSUB, the call graph is drawn correctly, but the code is not valid anymore (i.e., it does not compile).
Is there an option to include function calls in the call/caller graph?

From what I can tell, this is because Doxygen doesn't understand that MYFUNC in MYSUB is the same thing as the function MYFUNC.
You can generate the caller graph for MYFUNC by writing an interface block for it in MYSUB, but this doesn't generate the call graph for MYSUB.
In order to get Doxygen to correctly generate the call/caller graph, you should put the two procedures in a module (alternatively, you can put them in their own separate modules). This also removes the need to define MYFUNC in MYSUB:
module foo
implicit none
contains
integer function myfunc()
myfunc = 1
end function myfunc
subroutine mysub (res)
integer res
res = myfunc()
end subroutine mysub
end module foo
Additionally, Doxygen doesn't seem to generate the call/caller graphs for procedures with uppercase names, at least in version 1.8.8. I have CASE_SENSE_NAMES = YES in my Doxyfile, so I suspect that is a bug.

Related

Are interface blocks ever required to compile Fortran?

I'm trying to teach myself Fortran, and have been messing around with linking multiple files together. Following examples, I have been writing programs in one file, functions in another, and using interface blocks in my main program to refer to the external function.
I was testing how much information was needed in the interface block and realised that I can remove it entirely.
My program:
program test
implicit none
real :: x, y, func
x = 3
y = func(x)
print *, y
end program test
And the function file:
function func(x)
implicit none
real :: x, func
func = x**3
end function func
I then compile it using gfortran -o test test.f90 func.f90 and the code works as expected. My question is, why do I not need to include an interface block in my program file? Is it simply a matter of good practice, or does defining func as a real variable serve as shorthand? I am on Windows, having installed gfortran through minGW.
As an aside/related question, if I instead use a subroutine:
subroutine func(x,y)
implicit none
real :: x,y
y = x**3
end subroutine func
And change the line y = func(x) to call func(x,y) then the code will work fine without any interface block or declaration. Why is this?
The declaration real :: func in the main program here declares func to be a function with (default) real result. This function has an interface in the main program as a result, so it is legitimate to reference that function with y = func(x).
The interface in this case is implicit. In this way, the main program knows exactly three things about func:
it is a function (with that name);
it has the external attribute;
it has real result.
The reference to the function is compatible with that knowledge. Further, how you reference the function matches precisely the properties of the function itself.
Equally, in the case of the subroutine, a call func(x,y) tells the main program exactly three things, again with the implicit interface:
it is a subroutine (with that name);
it has the external attribute;
it takes two real arguments.
Those three things again match the subroutine's definition, so things are fine.
Loosely, then, you don't need an interface block in these cases because the implicit interfaces are good enough.
There are times when an explicit interface is required and in most (nearly all) cases an explicit interface is better. As you can see in other questions and answers, there are usually better ways to provide an explicit interface than using an interface block.
Why do I not need to include an interface block in my program file?
Since Fortran 90, the recommended way to define reusable functions and subroutines is to use modules.
module func_m
contains
function func(x)
implicit none
real :: x, func
func = x**3
end function func
end module func_m
Then write use func_m in the main program, before implicit none: gfortran -c func_m.f90, gfortran -c test.f90 and gfortran -o test test.o func_m.o.
When you use modules, the compiler will check the type of the arguments of the functions. You also do not need to declare real :: func as the declarations are taken from the module.
When you compile as a "simple" object file, the compiler will simply call whatever function is named func without verification, as long as such a function is given in an object file.
The interface block is a kind of "in between". In your case, you could add one in the program file. This would force you to follow that declaration in the program. But it will not prevent linking to wrong functions at link time: there is no guarantee that the interface is right. It is mostly useful if you need to call C or FORTRAN 77 code from someone else, for which you couldn't use modules.
And change the line y = func(x) to call func(x,y) then the code will
work fine without any interface block or declaration. Why is this?
The interface issue is orthogonal to the function vs subroutine issue.
There are some cases where interface blocks are needed. For example if the called subroutine uses a pointer, allocatable or assumed shape arrays (this list is not complete, see the standard for more):
integer, pointer :: x(:,:) ! pointer attribute
integer, allocatable :: x(:,:) ! pointer attribute
integer :: a(:,:) ! assumed shape array
The pointer/allocatable have the advantage that the called subroutine can allocate it for the calling function. Assumed shape arrays automatically transfer the dimensions to the called subroutine.
If you use any of this your program will crash without explicit interface. Easiest solution is like said in the other answer: use modules to have the interface automtically correct. We use a perl script automatically extracting interfaces to have interface check without rewriting the code to modules (and avoid long compile times until all compilers reliably support Fortran 2008 submodules...)

Nested contains statement

I have a program like this
program
call one()
contains one()
some vars
contains two()
use the vars of one
define its own vars
contains three()
use the vars of both one and two
This doesn't compile because Fortran allows only the first contains statement.
I used this design to avoid passing and retyping all the variables of one() into two() and three().
How can I rewrite the program so that the variable sharing is achieved?
I cannot define all the variable before the statement call one().
The code will be to hard to manage, I need the feature :
parent subroutine cannot access internal subroutine variables.
Maybe a solution is to use pointer
call one(pointer_to_two)
then define the routine two() in its own module.
But I find this design complicate with my limited Fortran skills.
And I'm worried it will impact performance.
Should I use a common block?
I use the latest dialect of Fortran with the Intel compiler.
Below is 'compilable' example.
program nested_routines
call one()
contains
subroutine one()
integer :: var_from_one = 10
print *, 1
call b()
contains
subroutine two()
integer :: var_from_two = 20
print *, 2, var_from_one
call c()
contains
subroutine three()
print *, 3, var_from_one, var_from_two
end subroutine
end subroutine
end subroutine
end module
I recommend placing your procedures (subroutines and functions) into a module after a single "contains" and using that module from your main program. The local variables of each procedure will be hidden their callers. The way that this differs from your goals is that you have to redeclare variables. I dislike the inheritance of all variables in a subroutine contained in another because it is possible to mistakenly reuse a variable. If you have a few variables that are shared across many procedures, perhaps the appropriate design choice is to make them global. With Fortran >=90, a module variable is better method for a global variable than common blocks. If you have variables that are communicated between a limited number of procedures, it is generally better to use arguments because that makes the information flow clearer.
this might be possible if there is a separate module for each of the functions specific variables and a separate module for each function implementation
watch out for the order of the module compilation, according to the usage hierarchy necessity
also, i have no idea on the performance effect of doing this
module m1_var
implicit none
contains
end module m1_var
!========================================================================================================================
module m2_var
implicit none
contains
end module m2_var
!========================================================================================================================
module m3_var
implicit none
contains
end module m3_var
!========================================================================================================================
module m3_sub
implicit none
contains
subroutine s3()
use m2_var !to see varibles
!arguments
!local
!allocation
!implementation
end subroutine s3
end module m3_sub
!========================================================================================================================
module m2_sub
implicit none
contains
subroutine s2()
use m3_sub
use m1_var
!arguments
!local
!allocation
!implementation
call s3
end subroutine s2
end module m2_sub
!========================================================================================================================
module m1_sub
use m1_var
implicit none
contains
subroutine s1()
use m2_sub
!arguments
!local
!allocation
!implementation
! call s2
end subroutine s1
end module m1_sub
!========================================================================================================================
program nestmoduse
use m1_sub
implicit none
call s1
end program nestmoduse

How do you call a bind-C function within fortran?

I'm just beginning with Fortran, and I've got a program and a function
PROGRAM multiplication
implicit none
real :: A1
!A1 = mult(2, 3)
!write(*,1) A1
1 format(f8.8)
END PROGRAM multiplication
REAL FUNCTION mult(a, b) BIND(C, name='foomult')
real,value :: a,b
mult = a * b
END FUNCTION
I've got the function working in java through JNA, but when I try to call mult from within the fortran main program, I get a ton of compiling errors (I can provide them if you want). I have a feeling it must be something obvious but I can't find a solution anywhere. Are bound functions not intended to be called from within non-external code? Or do I just have a poor understanding of function syntax?
For the main program, the compiler doesn't "know" the properties of the function, i.e., the types of the function and its arguments. Your function uses an "advanced" argument property, value, so it is necessary to declare the properties in some way to the caller. The easiest way to make those properties known to the caller is to put the function into a module and use that module from a program or procedure that uses it:
module MyModule
contains
FUNCTION mult(a, b) BIND(C, name='foomult')
use iso_c_binding
real (c_float) ,value :: a,b
real (c_float) :: mult
mult = a * b
END FUNCTION
end module MyModule
PROGRAM multiplication
use MyModule
implicit none
real :: A1
A1 = mult(2.0, 3.0)
write(*,*) A1
END PROGRAM multiplication
I've also declared the variables in the function to be compatible with C. It happens, at least with gfortran on my computer, that those are the same as plain real, so they are compatible with the call in the main program. Compatibility could be guaranteed by writing the call as mult (2.0_c_float, 3.0_c_float).

Creating a simple subroutine in fortran

I am new to Fortran and I had made a program where everything did fit into one single file, which worked.
However when i tried to take out parts and put them into modules and subroutines I quickly ran into problems.
Even after removing everything and having only the bare minimum left, it still gives an error regarding the subroutine.
Currently the heavily reduced main program looks like this. It only uses the module and calls the subroutine.
program test
use mod1
call sub1(var)
end program test
and the module looks like:
Module mod1
implicit none
type A
real :: type1
end type A
contains
subroutine sub1(var)
type(A) :: var
var%type1 = 1+1
end subroutine sub1
However I seem to do something wrong here and unfortunately I can not figure out what. I get the error
||Error: Type mismatch in argument 'var' ; passed REAL(4) to TYPE(a)|
end module mod1
Can someone please explain which fundamental mistake I am making in order to prevent the most basic subroutine from working?
In your program you do not explicitly declare var. In days of yore Fortran supported implicit typing and, by default, variables whose name begin with a v will be of type real. Fortran retains this capability, though its use is now frowned upon.
I think you are thinking (as if I had a clue what you are thinking) that var in the program scope will somehow be automatically associated with, or the same as, var in the subroutine in the module. It won't be.
Do these things:
Insert implicit none on the line after use mod1 in your program.
Explicitly declare var within the program, eg type(a) :: var

Use function inside subroutine in FORTRAN77

I am updating legacy code and I need to use a simple mathematical function inside a subroutine. I cannot figure out how to do this. I have a function that works when called from a test program. What do I need to do differently for a subroutine?
example:
subroutine foo(i,j,k)
i = bar(j,k)
stuff = otherstuff
return
end
other info:
bar is an erf approximation.
I am using the PGF90 compiler.
I am new to FORTRAN from C.
thanks!
Basically, calling from a program or a subroutine shouldn't differ. Does the code really look like this, without any declarations? This means all variables will have implicit types: variables with names starting with the letters i-n will be integer, all others real; this also holds for function return values. The code you show, tries to assign a real (bar()) to an integer (i).
If you're writing new code, always start programs and procedures with IMPLICIT NONE. This forces you to explicitly include type declarations for all variables and function return values, greatly reducing errors.