Regex password validator - regex

Question

I have the following rules for password validation:
at least 6 characters
at least 1 capital letter
How can I validate this with a RegEx?
Here is my pattern: ^(?=.*[0-9]+.*)(?=.*[a-zA-Z]+.*)[0-9a-zA-Z]{6,}$
The pattern above enforces also numbers ... which I don't need. However user can enter any other characters he/she wishes except that must contain one capital and be longer or equal to 6 characters.

Answer 1

You can try this:
^(?=.*?[A-Z]).{6,}$
DEMO
If you want to allow special characters as well then change it like
^(?=.*?[A-Z])(?=.*?[#?!#$%^&*-]).{6,}$

Answer 2

^(?=.*[A-Z])[\w-[_\]]{6,}$
This force to contains a capital letter with (?=.*[A-Z]) and allow alphanumeric : [\w-[_\]] (\w is [a-zA-Z0-9_] in which we remove the _

Answer 3

You can use this :
(?=.*[A-Z]).{8}
or If you want to full rule, can try this :
(?=[a-z]*[A-Z])(?=\D*\d)(?=.*[#?!#$%^&*-]).{8}

Answer 4

It might be better to evaluate the rules separately to provide feedback to user as to which rule failed to validate.
I suggest doing something like this instead: https://jsfiddle.net/hejecr9d/
// will store list of rules
var rules = []
// at least one capital letter rule
rules.one_capital_letter = {
fail_message: 'password needs at least one capital letter',
validate: function(password){
return /[A-Z]/.test(password)
}
}
// at least six letters rule
rules.at_least_six_letters = {
fail_message: 'password needs to have at least 6 characters',
validate: function(password){
return password.length >= 6
}
}
function validate_password(password) {
// goes through all the rules
for(rule in rules) {
if(!rules[rule].validate(password)) {
return {success: false, message: rules[rule].fail_message}
}
}
// return success after all rules are checked
return {success: true, message: 'password validated successfully'}
}
// Test if it works
var test_strings = ['abcd', 'Abcd', 'Abcdef']
for(i in test_strings) {
$('body').append(test_strings[i] + ': ' + validate_password(test_strings[i]).message + '<br>')
}