Pretty-print Nested Hash-map in ClojureScript - clojure

Is there a convenient way in ClojureScript to pretty print a nested hash-map in the way that the whole tree-structure becomes immediately visible.
For instance a map like this
(def my-map {:a {:b 1 :c 9} :b {:d 8 :e {:f 2 :g 3 :h 4}} :c 10})
should be printed like this:
{:a {:b 1
:c 9}
:b {:d 8
:e {:f 2
:g 3
:h 4}}
:c 10}
EDIT: There might also be vectors in the map. The usecase is just to inspect larger data structures during development.

There is no built-in way to do it. You might come close to what you want by using cljs.pprint and setting cljs.pprint/*print-right-margin* to a low value.
I would recommend to take a look at a small library shodan which provides a very useful inspect function:
(require '[shodan.inspection :refer [inspect]])
(inspect {:aaaaaa 1
:bbbbbb {:ccc 2
:dddddd [1 2 3 4 5]}})
It won't print anything in your CLJS REPL but will provide a handy view in your browser's console:
You can collapse and expand nested datastructures - it basically does what you asked for.

As a personal challenge I wrote the following code:
(enable-console-print!)
(def atomic? (complement coll?))
(def padding #(apply str (repeat % " ")))
(def tabulate #(apply str (repeat % "\t")))
(def strcat #(->> (apply concat %&) (apply str)))
(defn my-max-key [x] (if (empty? x) [""] (apply (partial max-key count) x)))
(defn longest-key [m] (->> m keys (filter atomic?) (map str) my-max-key))
(def length (comp count str))
(def not-map? (complement map?))
(def nested? #(some coll? %))
(def join #(apply str (interpose % %2)))
(def join-lines (partial join "\n"))
(defn has-atomic? [coll] (some atomic? coll))
(defn diff-key-lengths [key1 key2] (- (length key1) (length key2)))
(defn convert
([thing] (convert -1 thing))
([depth thing]
(defn convert-items []
(defn convert-seq []
(conj []
(map (partial convert (inc depth)) thing)
""))
(defn string-horizontally [[key value]]
(str (tabulate (inc depth))
key
(padding (diff-key-lengths (longest-key thing) key))
" → "
value))
(defn string-vertically [[key value]]
(str (convert (inc depth) key) "\n"
(convert (+ 2 depth) "↓") "\n"
(convert (inc depth) value) "\n"))
(defn convert-kv [[key value]]
(if (nested? [key value])
(string-vertically [key value])
(string-horizontally [key value])))
(cond (atomic? thing)
[(str (tabulate depth) thing)]
(not-map? thing)
(convert-seq)
(map? thing)
(map convert-kv thing)))
(->> (convert-items) flatten join-lines)))
(def sample-input [["the first thing in this nested vector"]
{{"this is a key in a nested map"
"that points to me!!!"}
{"and that entire map points to this map!!!"
"cool!!!"
"but it gets cooler cause..."
"the value's line up!!!"}}])
(->> sample-input convert println)
The terminal output is (psst... the values in a map do line up but I don't think that chrome uses a monospaced font!):

Related

Using clojure, Is there a better way to to remove a item from a sequence, which is the value in a map?

There is a map containing sequences. The sequences contain items.
I want to remove a given item from any sequence that contains it.
The solution I found does what it should, but I wonder if there is a better
or more elegant way to achieve the same.
my current solution:
(defn remove-item-from-map-value [my-map item]
(apply merge (for [[k v] my-map] {k (remove #(= item %) v)})))
The test describe the expected behaviour:
(require '[clojure.test :as t])
(def my-map {:keyOne ["itemOne"]
:keyTwo ["itemTwo" "itemThree"]
:keyThree ["itemFour" "itemFive" "itemSix"]})
(defn remove-item-from-map-value [my-map item]
(apply merge (for [[k v] my-map] {k (remove #(= item %) v)})))
(t/is (= (remove-item-from-map-value my-map "unknown-item") my-map))
(t/is (= (remove-item-from-map-value my-map "itemFive") {:keyOne ["itemOne"]
:keyTwo ["itemTwo" "itemThree"]
:keyThree ["itemFour" "itemSix"]}))
(t/is (= (remove-item-from-map-value my-map "itemThree") {:keyOne ["itemOne"]
:keyTwo ["itemTwo"]
:keyThree ["itemFour" "itemFive" "itemSix"]}))
(t/is (= (remove-item-from-map-value my-map "itemOne") {:keyOne []
:keyTwo ["itemTwo" "itemThree"]
:keyThree ["itemFour" "itemFive" "itemSix"]}))
I'm fairly new to clojure and am interested in different solutions.
So any input is welcome.
I throw in the specter
version for good measure. It keeps the vectors inside the map
and it's really compact.
(setval [MAP-VALS ALL #{"itemFive"}] NONE my-map)
Example
user=> (use 'com.rpl.specter)
nil
user=> (def my-map {:keyOne ["itemOne"]
#_=> :keyTwo ["itemTwo" "itemThree"]
#_=> :keyThree ["itemFour" "itemFive" "itemSix"]})
#_=>
#'user/my-map
user=> (setval [MAP-VALS ALL #{"itemFive"}] NONE my-map)
{:keyOne ["itemOne"],
:keyThree ["itemFour" "itemSix"],
:keyTwo ["itemTwo" "itemThree"]}
user=> (setval [MAP-VALS ALL #{"unknown"}] NONE my-map)
{:keyOne ["itemOne"],
:keyThree ["itemFour" "itemFive" "itemSix"],
:keyTwo ["itemTwo" "itemThree"]}
i would go with something like this:
user> (defn remove-item [my-map item]
(into {}
(map (fn [[k v]] [k (remove #{item} v)]))
my-map))
#'user/remove-item
user> (remove-item my-map "itemFour")
;;=> {:keyOne ("itemOne"),
;; :keyTwo ("itemTwo" "itemThree"),
;; :keyThree ("itemFive" "itemSix")}
you could also make up a handy function map-val performing mapping on map values:
(defn map-val [f data]
(reduce-kv
(fn [acc k v] (assoc acc k (f v)))
{} data))
or shortly like this:
(defn map-val [f data]
(reduce #(update % %2 f) data (keys data)))
user> (map-val inc {:a 1 :b 2})
;;=> {:a 2, :b 3}
(defn remove-item [my-map item]
(map-val (partial remove #{item}) my-map))
user> (remove-item my-map "itemFour")
;;=> {:keyOne ("itemOne"),
;; :keyTwo ("itemTwo" "itemThree"),
;; :keyThree ("itemFive" "itemSix")}
I think your solution is mostly okay, but I would try to avoid the apply merge part, as you can easily recreate a map from a sequence with into. Also, you could also use map instead of for which I think is a little bit more idiomatic in this case as you don't use any of the list comprehension features of for.
(defn remove-item-from-map-value [m item]
(->> m
(map (fn [[k vs]]
{k (remove #(= item %) vs)}))
(into {})))
Another solution much like #leetwinski:
(defn remove-item [m i]
(zipmap (keys m)
(map (fn [v] (remove #(= % i) v))
(vals m))))
Here's a one-liner which does this in an elegant way. The perfect function for me to use in this scenario is clojure.walk/prewalk. What this fn does is it traverse all of the sub-forms of the form that you pass to it and it transforms them with the provided fn:
(defn remove-item-from-map-value [data item]
(clojure.walk/prewalk #(if (map-entry? %) [(first %) (remove #{item} (second %))] %) data))
What the remove-item-from-map-value fn will do is it will check if current form is a map entry and if so, it will remove specified key from its value (second element of the map entry, which is a vector containing a key and a value, respectively).
The best this about this approach is that is is completely extendable: you could decide to do different things for different types of forms, you can also handle nested forms, etc.
It took me some time to master this fn but once I got it I found it extremely useful!

Clojure loop with count

I am fairly new to Clojure and would help help with some code. I have a function which takes a vector and i would like to loop through the vector and get the value at an index 'i' and the value of 'i' itself. 'i' is the value which is incremented in the loop.
I have checked 'for' at the clojure docs at for and wrote the following code.
(for [i some-vector]
(print (get-intersec i (.length some-vector) loop-count)))
The loop-count variable is supposed to be the loop count.
I have also checked loop but it does not seem like a feasible solution. Can someone help me with a clojure function i can use or help me write a macro or function that can do that.
Thank you.
Ps: To solve my problem, i use my own counter but would like a better solution.
First, keep in mind that for is for list comprehension, that is, creating new sequences. For looping through a sequence for some side effect, like printing, you probably want to use doseq.
To include a numeric count with each element as you loop through, you can use map-indexed:
(def xs [:a :b :c :d])
(doseq [[n elem] (map-indexed #(vector %1 %2) xs)]
(println n "->" elem))
Output:
0 -> :a
1 -> :b
2 -> :c
3 -> :d
If you find yourself doing this a lot, like I did, you can create a macro:
(defmacro doseq-indexed [[[item idx] coll] & forms]
`(doseq [[~idx ~item] (map-indexed #(vector %1 %2) ~coll)]
~#forms))
And use it like this:
> (doseq-indexed [[n elem] xs] (println n "->" elem))
0 -> :a
1 -> :b
2 -> :c
3 -> :d
Don't forget dotimes for simple stuff like this:
(let [data [:a :b :c :d]]
(dotimes [i (count data)]
(println i " -> " (data i))
; or (nth data i)
; or (get data i)
))
with result
0 -> :a
1 -> :b
2 -> :c
3 -> :d
Using loop/recur would look like this:
(let [data [:a :b :c :d]]
(loop [i 0
items data]
(let [curr (first items)]
(when curr
(println i "->" curr)
(recur (inc i) (rest items))))))
Update:
If you need this a lot, I already wrote a function that will add the index value to the beginning of each entry in a sequence:
(ns tst.demo.core
(:use tupelo.test)
(:require [tupelo.core :as t]) )
(dotest
(let [data [:a :b :c :d]]
(t/spy-pretty :indexed-data
(t/indexed data))))
with result
:indexed-data =>
([0 :a]
[1 :b]
[2 :c]
[3 :d])
The general signature is:
(indexed & colls)
Given one or more collections, returns a sequence of indexed tuples
from the collections like:
(indexed xs ys zs) -> [ [0 x0 y0 z0]
[1 x1 y1 z1]
[2 x2 y2 z2]
... ]
If your not set on using for, you could use map-indexed e.g.
(map-indexed (fn [i v]
(get-intersect v (.length some-vector) i))
some-vector))
I don't know what get-intersect is and assume .length is java interop? Anyway, map-indexed expects a function of 2 arguments, the 1st is the index and the second is the value.

Find Value of Specific Key in Nested Map

In Clojure, how can I find the value of a key that may be deep in a nested map structure? For example:
(def m {:a {:b "b"
:c "c"
:d {:e "e"
:f "f"}}})
(find-nested m :f)
=> "f"
Clojure offers tree-seq to do a depth-first traversal of any value. This will simplify the logic needed to find your nested key:
(defn find-nested
[m k]
(->> (tree-seq map? vals m)
(filter map?)
(some k)))
(find-nested {:a {:b {:c 1}, :d 2}} :c)
;; => 1
Also, finding all matches becomes a matter of replacing some with keep:
(defn find-all-nested
[m k]
(->> (tree-seq map? vals m)
(filter map?)
(keep k)))
(find-all-nested {:a {:b {:c 1}, :c 2}} :c)
;; => [2 1]
Note that maps with nil values might require some special treatment.
Update: If you look at the code above, you can see that k can actually be a function which offers a lot more possibilities:
to find a string key:
(find-nested m #(get % "k"))
to find multiple keys:
(find-nested m #(some % [:a :b]))
to find only positive values in maps of integers:
(find-nested m #(when (some-> % :k pos?) (:k %)))
If you know the nested path then use get-in.
=> (get-in m [:a :d :f])
=> "f"
See here for details: https://clojuredocs.org/clojure.core/get-in
If you don't know the path in your nested structure you could write a function that recurses through the nested map looking for the particular key in question and either returns its value when it finds the first one or returns all the values for :f in a seq.
If you know the "path", consider using get-in:
(get-in m [:a :d :f]) ; => "f"
If the "path" is unknown you can use something like next function:
(defn find-in [m k]
(if (map? m)
(let [v (m k)]
(->> m
vals
(map #(find-in % k)) ; Search in "child" maps
(cons v) ; Add result from current level
(filter (complement nil?))
first))))
(find-in m :f) ; "f"
(find-in m :d) ; {:e "e", :f "f"}
Note: given function will find only the first occurrence.
Here is a version that will find the key without knowing the path to it. If there are multiple matching keys, only one will be returned:
(defn find-key [m k]
(loop [m' m]
(when (seq m')
(if-let [v (get m' k)]
v
(recur (reduce merge
(map (fn [[_ v]]
(when (map? v) v))
m')))))))
If you require all values you can use:
(defn merge-map-vals [m]
(reduce (partial merge-with vector)
(map (fn [[_ v]]
(when (map? v) v))
m)))
(defn find-key [m k]
(flatten
(nfirst
(drop-while first
(iterate (fn [[m' acc]]
(if (seq m')
(if-let [v (get m' k)]
[(merge-map-vals m') (conj acc v)]
[(merge-map-vals m') acc])
[nil acc]))
[m []])))))

how can you interleave two vectors of differing lengths in clojure

What is the simplest way to interleave two vectors with n+1 and n members?
(def a [:a :c :e])
(def b [:b :d])
(interleave a b ); truncates to shortest list
[:a :b :c :d]
;what I would like.
(interleave-until-nil a b)
[:a :b :c :d :e]
Cons the first, interleave the rest with arguments reversed.
(cons (first a) (interleave b (rest a)))
;=> (:a :b :c :d :e)
Conj nil to the second, interleave colls get all butlast
(butlast (interleave a (conj b nil)))
;=> (:a :b :c :d :e)
(defn interleave+ [& x]
(take (* (count x) (apply max (map count x)))
(apply interleave (map cycle x))))
(butlast (interleave+ [:a :c :e] [:b :d]))
=> (:a :b :c :d :e)
Tried this as an exercise in lazy seqs. I suspect that there are more elegant ways though.
(defn interleave-all
"interleaves including remainder of longer seqs."
[& seqs]
(if (not-empty (first seqs))
(cons (first (first seqs)) (lazy-seq (apply interleave-all (filter not-empty (concat (rest seqs) [(rest (first seqs))])))))))
If you would like to have nil appended to always have same dimension results, this could be a way to do that:
(defn interleave-all [& seqs]
(reduce
(fn [a i]
(into a (map #(get % i) seqs)))
[]
(range (apply max (map count seqs)))))
For example:
(interleave-all [:a] [:b :c])
outputs:
[:a :b nil :c]
This can be used to transpose a matrix:
(defn matrix-transpose [input]
(partition
(count input)
(apply interleave-all input)))
Example:
(matrix-transpose [[:a] [:b :c]])
Outputs:
[[:a :b] [nil :c]]
Which can be used to i.e. tabular output of lists of differing lengths (but where you need the fixed dimensions to insert nothing where lists have no value for certain indices).

make sequence side-effectfull in Clojure

What I want to do is like following.
(def mystream (stream (range 100)))
(take 3 mystream)
;=> (0 1 2)
(take 3 mystream)
;=> (3 4 5)
(first (drop 1 mystream))
;=> 7
The stream function make sequence side-effectfull like io stream.
I think this is almost impossible.
Here is my attempt.
(defprotocol Stream (first! [this]))
(defn stream [lst]
(let [alst (atom lst)]
(reify Stream
(first! [this]
(let [[fs] #alst]
(swap! alst rest)
fs)))))
(let [mystream (stream (iterate inc 1))]
(map #(if (string? %) (first! mystream) %)
[:a "e" "b" :c "i" :f]))
;=> (:a 1 2 :c 3 :f)
Unfotunately this approach need to implement all function I will use.
Judging by your followup comment to Maurits, you don't need mutation, but rather simply need to emit a new sequence with the elements in the right place.
For example:
(defn replace-when [pred coll replacements]
(lazy-seq
(when (seq coll)
(if (seq replacements)
(if (pred (first coll))
(cons (first replacements)
(replace-when pred (rest coll) (rest replacements)))
(cons (first coll)
(replace-when pred (rest coll) replacements)))
coll))))
user=> (def seq1 [:a :b :c])
#'user/seq1
user=> (def seq2 [:x "i" "u" :y :z "e"])
#'user/seq2
user=> (replace-when string? seq2 seq1)
(:x :a :b :y :z :c)
This won't work with the standard take and drop, but you could quite easily write your own to work on a mutable atom, e.g. you could do something like this:
(def mystream (atom (range 100)))
(defn my-take [n stream]
(let [data #stream
result (take n data)]
(reset! stream (drop n data))
result))
(my-take 3 mystream)
=> (0 1 2)
(my-take 3 mystream)
=> (3 4 5)