Replace characters in old array - c++

Question

I'm solving a problem and stuck on last part now what i am doing. Taking 5 characters from user and save it on character array and than saying enter 3 characters to check does array has your enter characters in it.
For example: User enter 5 characters dagpl.Than second array subArray which search characters from main array now user enter 3 charactersdgl.Result saying 3 characters found. Are you want to replace these 3 characters with new characters? So enter 3 new replace characters now user enter xyz.
Final array would be replace like this xaypz.
My Code doesn't working fine for replacing characters i don't know what i'm doing wrong.
#include<iostream>
#include<cstdlib>
using namespace std;
int main(int argc, char**argv) {
bool check = false;
char arr[6] = { '\0' };
char subarr[4] = { '\0' };
int count = 0;
cout << "Enter Characters : ";
for (int i = 0; i < 5; i++) {
cin >> arr[i];
}
cout << "Enter 3 Characters and see how many times does array has your Search Characters : ";
for (int i = 0; i < 3; i++) {
cin >> subarr[i];
}
//Sub Array
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 5; j++) {
if (subarr[i] == arr[j]) {
if (!check) {
cout << "Found characters are: ";
}
count++;
cout << subarr[i] << ",";
check = true;
}
}
}
if (check) {
cout << '\b';
cout << " ";
cout << endl;
}
if (!check) {
cout << "Sorry Nothing Found" << endl;
}
cout << "total Found : " << count << endl;
//SECTION 3
if (check) {
int n = count + 1;
char* replace = new char[n]();
cout << "You can only replace " << count << " new characters because of find operation! so enter it will be replace old array with it: ";
for (int i = 0; i < n - 1; i++) {
cin >> replace[i];
}
//Replace characters
for (int i = 0; i < n - 1; i++) {
for (int j = 0; j < 5; j++) {
if (subarr[i] == arr[j]) {
arr[j] = replace[j];
}
}
}
delete[]replace;
replace = NULL;
cout << "New Array would be: ";
for (int i = 0; i < 5; i++) {
cout << arr[i];
}
cout << endl;
}
system("pause");
return EXIT_SUCCESS;
}

Answer 1

You're not marking the matched characters from arr
Replace the matched characters from arr[j] with a distinct character so that you can determine where to replace later. you can use null terminator
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 5; j++) {
if (subarr[i] == arr[j]) {
if (!check) {
cout << "Found characters are: ";
}
count++;
cout << subarr[i] << ",";
check = true;
arr[j]='\0'; //replacing the matched character with null terminator
}
}
}
Now traverse through your arr and replace null terminators with characters from replace array
int i=0;
for (int j = 0; j < 5; j++) {
if (arr[j]=='\0') { //replace when it equals to null terminator
arr[j] = replace[i++];
}
}

Answer 2

You want to ask the user to replace a specific number of chars, counting how many chars appear in subarr.
arr is input, subarr is from:
int replacecount[3] = { 0 };
for (int x=0; x<6; x++)
for (int i=0; i<3; i++)
if (input[x] == from[i]) {
++replacecount[i];
break;
}
int count = 0;
for (int i=0; i<3; i++)
if (replacecount[i] > 0)
++count;
std::cout << " you can replace " << count << " characters..." << std::endl;
char to[3];
for (int i=0; i<3; i++)
if (replacecount[i] > 0) {
std::cout << "enter replace character for '" << from[i] << "'" << std::endl;
std::cin >> to[i];
}
for (int x=0; x<6; x++)
for (int i=0; i<3; i++)
if (input[x] == from[i]) {
input[x] = to[i];
break;
}
std::cout << "replaced string is: " << input << std::endl;