Why template instantiations go on forever here? - c++

In the following code, I want to replace
template <typename T, typename... Args>
auto check (rank<1,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T, Args...>(), decltype(check(rank<2, Ts...>{}, args...))> {
return check(rank<2, Ts...>{}, args...); // Since rank<1,T> derives immediately from rank<2, Ts...>.
}
template <typename T, typename... Args>
auto check (rank<2,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T, Args...>(), decltype(check(rank<3, Ts...>{}, args...))> {
return check(rank<3, Ts...>{}, args...); // Since rank<2,T> derives immediately from rank<3, Ts...>.
}
// etc... until rank<9>.
with the simple
template <std::size_t N, typename T, typename... Args>
auto check (rank<N,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T, Args...>(), decltype(check(rank<N+1, Ts...>{}, args...))> {
return check(rank<N+1, Ts...>{}, args...); // Since rank<N,T> derives immediately from rank<N+1, Ts...>.
}
template <typename T, typename... Args>
auto check (rank<10, T>, Args... args) const { std::cout << "Nothing found.\n"; }
But when I do, the template instantiations go on forever despite the terminating check(rank<10, T>, Args... args) function. Here is the full code using the long version above. Sorry for not minimizing the problem because I don't think I can minimize it and show what the problem is. Jumping to main() will show you the simple task I'm after, but I want to solve it using sequence ranking and overload resolution.
#include <iostream>
#include <type_traits>
#include <tuple>
template <typename T, typename... Args>
constexpr auto has_argument_type_impl(int)
-> decltype(std::is_same<typename T::argument_type, std::tuple<Args...>>{}); // Checking both that T::argument_type exists and that it is the same as std::tuple<Args...>.
template <typename T, typename... Args>
constexpr auto has_argument_type_impl(long) -> std::false_type;
template <typename T, typename... Args>
constexpr bool has_argument_type() { return decltype(has_argument_type_impl<T, Args...>(0))::value; }
template <typename T, std::size_t N, typename... Args>
constexpr auto has_argument_type_n_impl(int)
-> decltype(std::is_same<typename T::template argument_type<N>, std::tuple<Args...>>{}); // Checking both that T::argument_type<N> exists and that it is the same as std::tuple<Args...>.
template <typename T, std::size_t N, typename... Args>
constexpr auto has_argument_type_n_impl(long) -> std::false_type;
template <typename T, std::size_t N, typename... Args>
constexpr bool has_argument_type_n() { return decltype(has_argument_type_n_impl<T, N, Args...>(0))::value; }
template <typename... Ts>
class Factory {
template <std::size_t, typename...> struct rank;
template <std::size_t N, typename First, typename... Rest>
struct rank<N, First, Rest...> : rank<N, Rest...> {};
template <std::size_t N, typename T> struct rank<N,T> : rank<N+1, Ts...> {};
template <typename T> struct rank<10, T> {}; // Need to end the instantiations somewhere.
public:
template <typename... Args>
decltype(auto) create (Args... args) const {
return check(rank<0, Ts...>{}, args...);
}
private:
template <typename T, typename... Rest, typename... Args>
auto check (rank<0, T, Rest...>, Args... args) const
-> std::enable_if_t<has_argument_type<T, Args...>(), decltype(T(args...))> {
return T(args...);
}
template <typename T, typename... Rest, typename... Args>
auto check (rank<0, T, Rest...>, Args... args) const
-> std::enable_if_t<!has_argument_type<T, Args...>(), decltype(check(rank<0, Rest...>{}, args...))> {
return check(rank<0, Rest...>{}, args...);
}
template <typename T, typename... Args>
auto check (rank<0,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T, Args...>(), decltype(check(rank<1, Ts...>{}, args...))> {
return check(rank<1, Ts...>{}, args...); // Since rank<0,T> derives immediately from rank<1, Ts...>.
}
template <std::size_t N, typename T, typename... Rest, typename... Args>
auto check (rank<N, T, Rest...>, Args... args) const
-> std::enable_if_t<has_argument_type_n<T, N-1, Args...>(), decltype(T(args...))> {
return T(args...);
}
template <std::size_t N, typename T, typename... Rest, typename... Args>
auto check (rank<N, T, Rest...>, Args... args) const
-> std::enable_if_t<!has_argument_type_n<T, N-1, Args...>(), decltype(check(rank<N, Rest...>{}, args...))> {
return check(rank<N, Rest...>{}, args...);
}
// I want to use the following instead of what's below it.
// template <std::size_t N, typename T, typename... Args>
// auto check (rank<N,T>, Args... args) const
// -> std::enable_if_t<!has_argument_type_n<T, N-1, Args...>(), decltype(check(rank<N+1, Ts...>{}, args...))> {
// return check(rank<N+1, Ts...>{}, args...); // Since rank<N,T> derives immediately from rank<N+1, Ts...>.
// }
//
// template <typename T, typename... Args>
// auto check (rank<10, T>, Args... args) const { std::cout << "Nothing found.\n"; }
template <typename T, typename... Args>
auto check (rank<1,T>, Args... args) const
-> std::enable_if_t<!has_argument_type_n<T, 0, Args...>(), decltype(check(rank<2, Ts...>{}, args...))> {
return check(rank<2, Ts...>{}, args...); // Since rank<1,T> derives immediately from rank<2, Ts...>.
}
template <typename T, typename... Args>
auto check (rank<2,T>, Args... args) const
-> std::enable_if_t<!has_argument_type_n<T, 1, Args...>(), decltype(check(rank<3, Ts...>{}, args...))> {
return check(rank<3, Ts...>{}, args...); // Since rank<2,T> derives immediately from rank<3, Ts...>.
}
// etc... until rank<9>.
};
// Testing
struct Object {
template <std::size_t, typename = void> struct ArgumentType;
template <typename T> struct ArgumentType<0,T> { using type = std::tuple<int, bool, char, double>; };
template <typename T> struct ArgumentType<1,T> { using type = std::tuple<bool, char, double>; };
template <std::size_t N> using argument_type = typename ArgumentType<N>::type;
Object (int, bool, char, double) { print(); }
Object (bool, char, double) { print(); }
void print() const { std::cout << "Object\n"; }
};
struct Thing {
template <std::size_t, typename = void> struct ArgumentType;
template <typename T> struct ArgumentType<0,T> { using type = std::tuple<int, int, char>; };
template <typename T> struct ArgumentType<1,T> { using type = std::tuple<int, char>; };
template <typename T> struct ArgumentType<2,T> { using type = std::tuple<char>; };
template <std::size_t N> using argument_type = typename ArgumentType<N>::type;
Thing (int, int, char) { print(); }
Thing (int, char) { print(); }
Thing (char) { print(); }
void print() const { std::cout << "Thing\n"; }
};
struct Blob {
using argument_type = std::tuple<int, double>;
Blob (int, double) { print(); }
void print() const { std::cout << "Blob\n"; }
};
struct Widget {
using argument_type = std::tuple<int>;
Widget (double, double, int, double) { print(); }
Widget (int) { print(); }
void print() const { std::cout << "Widget\n"; }
};
int main() {
Factory<Blob, Object, Thing, Widget>().create(4,3.5); // Blob
Factory<Object, Blob, Widget, Thing>().create(2); // Widget
Factory<Object, Thing, Blob, Widget>().create(5); // Widget
Factory<Blob, Object, Thing, Widget>().create(4,true,'a',7.5); // Object
Factory<Blob, Thing, Object, Widget>().create(true,'a',7.5); // Object
Factory<Blob, Object, Thing, Widget>().create('a'); // Thing
}
I know that there are other ways of accomplishing this, but I'm trying to understand sequence ranking better, and would like to know why I cannot use the commented-out section. How to avoid the repetitive code that I need to put (to rank<9>, or even higher rank) that is currently making this code work? Thanks for your patience.
Note: I actually must NOT enter the repetitive part of the code manually as I currently have. Because the highest N value for rank<N, Ts...> used in the check overloads will be determined during compile-time as the highest N value such that a argument_type<N> member type exists among all the Ts.... Thus I HAVE to use the generic part that I commented out, and the rank<10,T> I'm using will have to have the 10 replaced by that specific N value. Thus, this is not just a matter of convenience. I have to solve this problem to continue developing the program.
Edit: Here is a more minimal example, showing the same problem:
#include <iostream>
#include <type_traits>
#include <tuple>
template <typename T>
constexpr auto has_argument_type_impl(int)
-> decltype(typename T::argument_type{}, std::true_type{});
template <typename T>
constexpr auto has_argument_type_impl(long) -> std::false_type;
template <typename T>
constexpr bool has_argument_type() { return decltype(has_argument_type_impl<T>(0))::value; }
template <typename... Ts>
class Factory {
template <std::size_t, typename...> struct rank;
template <std::size_t N, typename First, typename... Rest>
struct rank<N, First, Rest...> : rank<N, Rest...> {};
template <std::size_t N, typename T> struct rank<N,T> : rank<N+1, Ts...> {};
template <typename T> struct rank<10, T> {}; // Need to end the instantiations somewhere.
public:
template <typename... Args>
decltype(auto) create (Args... args) const {
return check(rank<0, Ts...>{}, args...);
}
private:
template <std::size_t N, typename T, typename... Rest, typename... Args>
auto check (rank<N, T, Rest...>, Args... args) const
-> std::enable_if_t<has_argument_type<T>(), decltype(T(args...))> {
return T(args...);
}
template <std::size_t N, typename T, typename... Rest, typename... Args>
auto check (rank<N, T, Rest...>, Args... args) const
-> std::enable_if_t<!has_argument_type<T>(), decltype(check(rank<N, Rest...>{}, args...))> {
return check(rank<N, Rest...>{}, args...);
}
template <typename T, typename... Args>
auto check (rank<0,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T>(), decltype(check(rank<1, Ts...>{}, args...))> {
return check(rank<1, Ts...>{}, args...); // Since rank<0,T> derives immediately from rank<1, Ts...>.
}
// I want to use the following instead of what's below it.
// template <std::size_t N, typename T, typename... Args>
// auto check (rank<N,T>, Args... args) const
// -> std::enable_if_t<!has_argument_type<T>(), decltype(check(rank<N+1, Ts...>{}, args...))> {
// return check(rank<N+1, Ts...>{}, args...); // Since rank<N,T> derives immediately from rank<N+1, Ts...>.
// }
//
// template <typename T, typename... Args>
// auto check (rank<10, T>, Args... args) const { std::cout << "Nothing found.\n"; }
template <typename T, typename... Args>
auto check (rank<1,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T>(), decltype(check(rank<2, Ts...>{}, args...))> {
return check(rank<2, Ts...>{}, args...); // Since rank<1,T> derives immediately from rank<2, Ts...>.
}
template <typename T, typename... Args>
auto check (rank<2,T>, Args... args) const
-> std::enable_if_t<!has_argument_type<T>(), decltype(check(rank<3, Ts...>{}, args...))> {
return check(rank<3, Ts...>{}, args...); // Since rank<2,T> derives immediately from rank<3, Ts...>.
}
// etc... until rank<9>.
};
// Testing
struct Object {};
struct Thing {};
struct Blob {
using argument_type = std::tuple<int, double>;
Blob (int, double) { std::cout << "Blob\n"; }
};
int main() {
Factory<Object, Thing, Blob>().create(4,3.5); // Blob
}

Partial ordering does not kick in until very late in the overload resolution process.
Ignoring all the ping-ponging amongst your various check overloads, eventually you end up with
template <std::size_t N, typename T, typename... Args>
auto check (rank<N,T>, Args... args) const
-> std::enable_if_t<!has_argument_type_n<T, N, Args...>(),
decltype(check(rank<N+1, Ts...>{}, args...))>;
template <typename T, typename... Args>
auto check (rank<10, T>, Args... args) const;
with a rank<10, something I frankly don't care about>. Deduction and substitution will be performed for both overloads; and as part of substitution into the return type of the first signature, you'll instantiate rank<11, Ts...>, which in turn bypasses the terminating specialization of rank, resulting in an infinite chain of template instantiations. You don't even get to the point where the partial ordering tiebreaker chooses the second overload.
Just constrain the first overload to N < 10. It will need to lexically precede the return type (so that when N >= 10 the compiler doesn't attempt to substitute into it), so put it in a default template argument.

Related

Combing two factory methods returning unique_ptr and shared_ptr into one in C++?

Lets assume I have two factory functions, one returning std::unique_ptr and the other returning std::shared_ptr:
template<class T, class... Args>
std::shared_ptr<T> createObjectS (Args... args)
{
// running some code
return std::make_shared<T>(args...);
}
template<class T, class... Args>
std::unique_ptr<T> createObjectU (Args... args)
{
// running some code
return std::make_unique<T>(args...);
}
Is it possible to combine these two functions into one using template meta programming?
You could use SFINAE, but then I don't really see the point to have this inside a function anymore. It's pretty redundant.
#include <memory>
#include <type_traits>
template <class T, class... Args>
typename std::enable_if<
std::is_same<T, std::shared_ptr<typename T::element_type>>::value, T>::type
createObject(Args&&... args) {
// running some code
return std::make_shared<typename T::element_type>(std::forward<Args>(args)...);
}
template <class T, class... Args>
typename std::enable_if<
std::is_same<T, std::unique_ptr<typename T::element_type>>::value, T>::type
createObject(Args&&... args) {
// running some code
return std::make_unique<typename T::element_type>(std::forward<Args>(args)...);
}
int main() {
auto s = createObject<std::shared_ptr<int>>(1);
auto u = createObject<std::unique_ptr<int>>(1);
}
A little bit more compact but essentially the same idea with a scoped enum
#include <memory>
enum class ptr_t { shared, unique };
template <ptr_t P, class T, class... Args>
typename std::enable_if<P == ptr_t::shared, std::shared_ptr<T>>::type
createObject(Args&&... args) {
// running some code
return std::make_shared<T>(std::forward<Args>(args)...);
}
template <ptr_t P, class T, class... Args>
typename std::enable_if<P == ptr_t::unique, std::unique_ptr<T>>::type
createObject(Args&&... args) {
// running some code
return std::make_unique<T>(std::forward<Args>(args)...);
}
int main() {
auto s = createObject<ptr_t::shared, int>(1);
auto u = createObject<ptr_t::unique, int>(1);
}
In C++17 you of course use if constexpr in both cases rather than SFINAE.
#include <memory>
enum class ptr_t { shared, unique };
template <ptr_t P, class T, class... Args>
decltype(auto) createObject(Args &&... args) {
// running some code
if constexpr (P == ptr_t::shared) {
return std::make_shared<T>(std::forward<Args>(args)...);
} else if (P == ptr_t::unique) {
return std::make_unique<T>(std::forward<Args>(args)...);
}
}
With specialization, you may do:
template <typename T> struct FactoryImpl;
template <typename T> struct FactoryImpl<std::unique_ptr<T>>
{
template <typename ... Ts>
auto operator ()(Ts&&... args) const
{
return std::make_unique<T>(std::forward<Ts>(args)...);
}
};
template <typename T> struct FactoryImpl<std::shared_ptr<T>>
{
template <typename ... Ts>
auto operator ()(Ts&&... args) const
{
return std::make_shared<T>(std::forward<Ts>(args)...);
}
};
template<class T, class... Ts>
auto createObjectS (Ts&&... args)
{
return FactoryImpl<T>{}(std::forward<Ts>(args)...);
}
with usage:
auto s = createObject<std::shared_ptr<MyObject>>(42);
auto u = createObject<std::unique_ptr<MyObject>>(42);

Compiler cannot handle std::invoke

What is the problem with this?
struct foo {
void process(int, char, bool) {}
};
foo myfoo;
template <typename Method> struct thing {
void doit() {
Method m = Method{};
(myfoo.*m)(5, 'a', true);
}
};
int main() {
thing<decltype(&foo::process)> t;
t.doit();
}
I think this isolates the problem. What is the workaround if I have to use the type Method, as in the case of my original post below?
Original post:
In the following attempted test:
struct Foo { int play (char, bool) {return 3;} };
struct Bar { double jump (int, short, float) {return 5.8;} };
struct Baz { char run (double) {return 'b';} };
int main() {
Foo foo; Bar bar; Baz baz;
Functor<decltype(&Foo::play), decltype(&Bar::jump), decltype(&Baz::run)> func;
func(foo, bar, baz, 'c', true, 5, 2, 4.5, 6.8);
}
As you can predict, func is supposed to carry out
foo.play('c', true); bar.jump(5, 2, 4.5); baz.run(6.8);
My implementation of the Functor class so far (ignoring perfect forwarding and such for now) is
template <typename... Members>
struct Functor {
using m = many_members<Members...>;
template <typename... Args>
typename m::return_types operator()(Args... args) const { // perfect forwarding to do later
auto t = std::make_tuple(args...);
auto objects = utilities::tuple_head<sizeof...(Members)>(t);
auto arguments = utilities::extract_subtuple<sizeof...(Members), sizeof...(Args) - sizeof...(Members)>(t);
call(objects, arguments); // Won't compile on GCC 7.2 or clang 6.0.
}
private:
template <typename Tuple1, typename Tuple2>
auto call (Tuple1& objects, const Tuple2& args) const {
std::invoke(typename utilities::nth_element<0, Members...>::type{}, std::get<0>(objects), 'c', true);
}
};
where my last line using std::invoke is just to test the concept before I continue. It however will not compile on either GCC 7.2 or clang 6.0, so I cannot continue with the generalization. Any workaround here, or a completely different implementation altogether?
Here is everything I have so far:
namespace utilities {
template <std::size_t N, typename... Ts>
struct nth_element : std::tuple_element<N, std::tuple<Ts...>> { };
template <std::size_t Skip, std::size_t Take, typename Tuple>
auto extract_subtuple (const Tuple&, std::enable_if_t<(Take == 0)>* = nullptr) {
return std::tuple<>();
}
template <std::size_t Skip, std::size_t Take, typename Tuple>
auto extract_subtuple (const Tuple& tuple, std::enable_if_t<(Take > 0)>* = nullptr) {
return std::tuple_cat (std::make_tuple(std::get<Skip>(tuple)), extract_subtuple<Skip + 1, Take - 1>(tuple));
}
template <std::size_t N, typename Tuple>
auto tuple_head (const Tuple& tuple) {
return extract_subtuple<0, N>(tuple);
}
}
template <typename Rs, typename Ts, typename ArgsPacks, typename AllArgs, typename... Members> struct many_members_h;
template <typename Rs, typename Ts, typename ArgsPacks, typename AllArgs>
struct many_members_h<Rs, Ts, ArgsPacks, AllArgs> {
using return_types = Rs;
using classes = Ts;
using args_packs = ArgsPacks;
using all_args = AllArgs;
};
template <typename... Rs, typename... Ts, typename... ArgsPacks, typename... AllArgs, typename R, typename T, typename... Args, typename... Rest>
struct many_members_h<std::tuple<Rs...>, std::tuple<Ts...>, std::tuple<ArgsPacks...>, std::tuple<AllArgs...>, R(T::*)(Args...), Rest...> :
many_members_h<std::tuple<Rs..., R>, std::tuple<Ts..., T>, std::tuple<ArgsPacks..., std::tuple<Args...>>, std::tuple<AllArgs..., Args...>, Rest...> { };
template <typename... Members>
struct many_members : many_members_h<std::tuple<>, std::tuple<>, std::tuple<>, std::tuple<>, Members...> { };
template <typename... Members>
struct Functor {
using m = many_members<Members...>;
template <typename... Args>
typename m::return_types operator()(Args... args) const { // perfect forwarding to do later
auto t = std::make_tuple(args...);
auto objects = utilities::tuple_head<sizeof...(Members)>(t);
auto arguments = utilities::extract_subtuple<sizeof...(Members), sizeof...(Args) - sizeof...(Members)>(t);
call(objects, arguments); // Won't compile on GCC 7.2 or clang 6.0.
}
private:
template <typename Tuple1, typename Tuple2>
auto call (Tuple1& objects, const Tuple2& args) const {
std::invoke(typename utilities::nth_element<0, Members...>::type{}, std::get<0>(objects), 'c', true);
}
};
// Testing
#include <iostream>
struct Foo { int play (char, bool) {return 3;} };
struct Bar { double jump (int, short, float) {return 5.8;} };
struct Baz { char run (double) {return 'b';} };
int main() {
Foo foo; Bar bar; Baz baz;
Functor<decltype(&Foo::play), decltype(&Bar::jump), decltype(&Baz::run)> func;
func(foo, bar, baz, 'c', true, 5, 2, 4.5, 6.8);
}
Taking your smaller first example, note that decltype(&foo::process) is the type called void (foo::*)(int, char, bool).
This type does not contain or imply any association with the original function foo::process itself. Just like the type int doesn't let you get the value of some particular int elsewhere in your program, or the type SomeClass doesn't let you refer to a SomeClass object elsewhere in your program, the type alone doesn't carry a value or identity.
The expression Method{} value-initializes this pointer to member type. Which means the resulting value is a null pointer value. Which means calling it is undefined behavior (and on many systems is likely to result in a segfault).
If you're using C++17 mode, you could use a template <auto Method> non-type parameter and simply pass &foo::process (without using decltype) as the template argument. Some SFINAE techniques could enforce that the argument is actually a pointer to member function, and some helper traits could be used to get the class type and parameter list tuple.
Or if you're using a standard earlier than C++17, you'll have to either make the function pointer a function argument, or make it a template parameter which follows the type, as in template <typename MethodType, MethodType Method>, then call as thing<decltype(&foo::process), &foo::process>.
Thanks to aschepler's answer and advice to use auto... instead of typename... for the member function pointers, I was able to carry the original goal:
#include <tuple>
#include <functional> // std::invoke
#include <type_traits>
#include <utility>
namespace utilities {
template <std::size_t N, auto I, auto... Is>
struct nth_element : nth_element<N - 1, Is...> { };
template <auto I, auto... Is>
struct nth_element<0, I, Is...> {
static constexpr decltype(I) value = I;
};
template <std::size_t N, typename Pack> struct nth_index;
template <std::size_t N, std::size_t... Is>
struct nth_index<N, std::index_sequence<Is...>> : nth_element<N, Is...> { };
template <std::size_t Skip, std::size_t Take, typename Tuple>
auto extract_subtuple (const Tuple&, std::enable_if_t<(Take == 0)>* = nullptr) {
return std::tuple<>();
}
template <std::size_t Skip, std::size_t Take, typename Tuple>
auto extract_subtuple (const Tuple& tuple, std::enable_if_t<(Take > 0)>* = nullptr) {
return std::tuple_cat (std::make_tuple(std::get<Skip>(tuple)), extract_subtuple<Skip + 1, Take - 1>(tuple));
}
template <std::size_t N, typename Tuple>
auto tuple_head (const Tuple& tuple) {
return extract_subtuple<0, N>(tuple);
}
template <typename F, typename T, typename Tuple, std::size_t... Is>
decltype(auto) invoke_with_tuple_h (F&& f, T&& t, Tuple&& tuple, std::index_sequence<Is...>&&) {
return std::invoke(std::forward<F>(f), std::forward<T>(t), std::get<Is>(std::forward<Tuple>(tuple))...);
}
template <typename F, typename T, typename Tuple>
decltype(auto) invoke_with_tuple (F&& f, T&& t, Tuple&& tuple) {
return invoke_with_tuple_h (std::forward<F>(f), std::forward<T>(t), std::forward<Tuple>(tuple), std::make_index_sequence<std::tuple_size_v<std::decay_t<Tuple>>>{});
}
template <typename PartialSums, std::size_t Sum, std::size_t... Is> struct all_partial_sums_h;
template <std::size_t... PartialSums, std::size_t Sum>
struct all_partial_sums_h<std::index_sequence<PartialSums...>, Sum> {
using type = std::index_sequence<PartialSums..., Sum>;
using type_without_last_sum = std::index_sequence<PartialSums...>; // We define this because this is what we need actually.
};
template <std::size_t... PartialSums, std::size_t Sum, std::size_t First, std::size_t... Rest>
struct all_partial_sums_h<std::index_sequence<PartialSums...>, Sum, First, Rest...> :
all_partial_sums_h<std::index_sequence<PartialSums..., Sum>, Sum + First, Rest...> { };
template <typename Pack> struct all_partial_sums;
template <std::size_t... Is>
struct all_partial_sums<std::index_sequence<Is...>> : all_partial_sums_h<std::index_sequence<>, 0, Is...> { };
template <typename Pack> struct pack_size;
template <template <typename...> class P, typename... Ts>
struct pack_size<P<Ts...>> : std::integral_constant<std::size_t, sizeof...(Ts)> { };
template <typename PackOfPacks> struct get_pack_sizes;
template <template <typename...> class P, typename... Packs>
struct get_pack_sizes<P<Packs...>> {
using type = std::index_sequence<pack_size<Packs>::value...>;
};
}
template <typename Method> struct method_traits;
template <typename R, typename C, typename... Args>
struct method_traits<R(C::*)(Args...)> {
using return_type = R;
using class_type = C;
using args_type = std::tuple<Args...>;
};
template <typename Rs, typename Cs, typename ArgsPacks, auto... Members> struct many_members_h;
template <typename Rs, typename Cs, typename ArgsPacks>
struct many_members_h<Rs, Cs, ArgsPacks> {
using return_types = Rs;
using classes = Cs;
using args_packs = ArgsPacks;
};
template <typename... Rs, typename... Cs, typename... ArgsPacks, auto F, auto... Rest>
struct many_members_h<std::tuple<Rs...>, std::tuple<Cs...>, std::tuple<ArgsPacks...>, F, Rest...> :
many_members_h<std::tuple<Rs..., typename method_traits<decltype(F)>::return_type>, std::tuple<Cs..., typename method_traits<decltype(F)>::class_type>, std::tuple<ArgsPacks..., typename method_traits<decltype(F)>::args_type>, Rest...> { };
template <auto... Members>
struct many_members : many_members_h<std::tuple<>, std::tuple<>, std::tuple<>, Members...> { };
template <auto... Members>
struct Functor {
using m = many_members<Members...>;
using starting_points = typename utilities::all_partial_sums<typename utilities::get_pack_sizes<typename m::args_packs>::type>::type;
template <typename... Args>
typename m::return_types operator()(Args&&... args) const {
constexpr std::size_t M = sizeof...(Members);
auto t = std::make_tuple(std::forward<Args>(args)...);
auto objects = utilities::tuple_head<M>(t);
auto arguments = utilities::extract_subtuple<M, sizeof...(Args) - M>(t);
return call(objects, arguments, std::make_index_sequence<M>{});
}
private:
template <typename Tuple1, typename Tuple2, std::size_t... Is>
auto call (Tuple1& objects, const Tuple2& args, std::index_sequence<Is...>&&) const { // perfect forwarding to do later
return std::make_tuple(call_helper<Is>(objects, args)...);
}
template <std::size_t N, typename Tuple1, typename Tuple2>
auto call_helper (Tuple1& objects, const Tuple2& args) const { // perfect forwarding to do later
constexpr std::size_t s = std::tuple_size_v<std::tuple_element_t<N, typename m::args_packs>>;;
constexpr std::size_t a = utilities::nth_index<N, starting_points>::value;
const auto args_tuple = utilities::extract_subtuple<a, s>(args);
return utilities::invoke_with_tuple (utilities::nth_element<N, Members...>::value, std::get<N>(objects), args_tuple);
}
};
// Testing
#include <iostream>
struct Foo { int play (char c, bool b) { std::cout << std::boolalpha << "Foo::play(" << c << ", " << b << ") called.\n"; return 3; } };
struct Bar { double jump (int a, short b, float c) { std::cout << "Bar::jump(" << a << ", " << b << ", " << c << ") called.\n"; return 5.8; } };
struct Baz { char run (double d) { std::cout << "Baz::run(" << d << ") called.\n"; return 'b'; } };
int main() {
Foo foo; Bar bar; Baz baz;
Functor<&Foo::play, &Bar::jump, &Baz::run> func;
const auto tuple = func(foo, bar, baz, 'c', true, 5, 2, 4.5, 6.8);
std::cin.get();
}
Output:
Baz::run(6.8) called.
Bar::jump(5, 2, 4.5) called.
Foo::play(c, true) called.

Can we use variadic template function to filter parameters of specific type, then pass the rest to another function?

for example
// we have a variadic function
void print(...);
// I need such a function to filter parameters of specific type
template<typename... Args>
void print_filter(const Args&... args)
{
// filter non-integral type
print(integral args);
}
// my goal, all non-integral type can be ignored:
print_filter(1.0, 2, "abc", 3) == print(2, 3)
I have used up my knowledge to do that... can you help? or just to prove it's impossible, which also be very helpful. Thanks
A neat trick is to convert the arguments you want into a 1-element forwarding tuple, the arguments you don't want into an empty tuple, tuple_cat the results, then apply (C++17) the resulting tuple to the function you want to invoke:
template<typename... Args>
void print_filter(Args&&... args) {
std::apply(
[](auto&&... args) { return print(std::forward<decltype(args)>(args)...); },
std::tuple_cat(
std::get<std::is_integral<typename std::decay<Args>::type>::value ? 0 : 1>(
std::make_tuple(
[](Args&& arg) { return std::tuple<Args&&>{std::forward<Args>(arg)}; },
[](Args&&) { return std::tuple<>{}; }))(
std::forward<Args>(args))...));
}
Note that this employs another trick, which is to use get to conditionally apply one of two functions to an argument.
Example.
#include <cstddef>
#include <type_traits>
#include <utility>
#include <tuple>
template <typename S, typename M, typename O = std::index_sequence<>>
struct filter : O {};
template <std::size_t I, std::size_t... Is, std::size_t... Js, std::size_t... Ks>
struct filter<std::index_sequence<I, Is...>, std::index_sequence<0, Js...>, std::index_sequence<Ks...>>
: filter<std::index_sequence<Is...>, std::index_sequence<Js...>, std::index_sequence<Ks...>> {};
template <std::size_t I, std::size_t... Is, std::size_t... Js, std::size_t... Ks>
struct filter<std::index_sequence<I, Is...>, std::index_sequence<1, Js...>, std::index_sequence<Ks...>>
: filter<std::index_sequence<Is...>, std::index_sequence<Js...>, std::index_sequence<Ks..., I>> {};
template <template <typename T> class F, typename... Args>
using Filter = filter<std::make_index_sequence<sizeof...(Args)>, std::index_sequence<F<Args>{}...>>;
template <typename... Args, std::size_t... Is>
void print_filter_impl(std::tuple<Args...>&& tuple, std::index_sequence<Is...>)
{
print(std::get<Is>(std::move(tuple))...);
}
template <typename... Args>
void print_filter(Args&&... args)
{
print_filter_impl(std::forward_as_tuple(std::forward<Args>(args)...), Filter<std::is_integral, std::decay_t<Args>...>{});
}
DEMO
Here's one way to do it. Start by creating a dummy separator class:
class SEP { };
Then, a helper function that discards all non-integral arguments by pushing the other arguments to the end of the argument list:
template <class T, class... R>
void print_filter_(T x, R... a) {
if (std::is_integral<T>::value) {
print_filter_(a..., x);
} else {
print_filter_(a...);
}
}
After going through all the initial arguments, it is left with only the integral ones:
template <class... T>
void print_filter_(SEP, T... a) {
print(a...);
}
Finally, call the helper function:
template <class... T>
void print_filter(T... a) {
print_filter_(a..., SEP());
}
#include <iostream>
#include <type_traits>
#include <utility>
#include <tuple>
template <template <typename> class Predicate, std::size_t N, typename Output, typename... Args> struct find_indices_h;
template <template <typename> class Predicate, std::size_t N, std::size_t... Is, typename First, typename... Rest>
struct find_indices_h<Predicate, N, std::index_sequence<Is...>, First, Rest...> : std::conditional_t<
Predicate<First>::value,
find_indices_h<Predicate, N+1, std::index_sequence<Is..., N>, Rest...>,
find_indices_h<Predicate, N+1, std::index_sequence<Is...>, Rest...>
> {};
template <template <typename> class Predicate, std::size_t N, typename Sequence>
struct find_indices_h<Predicate, N, Sequence> {
using type = Sequence;
};
template <template <typename> class Predicate, typename... Args>
using find_indices = typename find_indices_h<Predicate, 0, std::index_sequence<>, Args...>::type;
template <typename... Args>
void print (Args&&... args) {
const int a[] = {(std::cout << args << ' ', 0)...};
static_cast<void>(a);
std::cout << '\n';
}
template <typename F, typename Tuple, std::size_t... Is>
void partial_apply (F f, Tuple&& tuple, std::index_sequence<Is...>) {
f(std::get<Is>(std::forward<Tuple>(tuple))...);
}
template<typename... Args>
void print_filter (const Args&... args) {
const auto partial_print = [](auto&&... ps) { return print(std::forward<decltype(ps)>(ps)...); };
partial_apply(partial_print, std::forward_as_tuple(args...), find_indices<std::is_integral, Args...>{});
}
int main() {
std::cout << std::boolalpha;
print_filter(1, "hello", 'a', true, 1.3, 1000); // 1 a true 1000
}

Passing many functions and storing all their results in a tuple

Consider this output:
int foo (int, char) {std::cout << "foo\n"; return 0;}
double bar (bool, double, long ) {std::cout << "bar\n"; return 3.5;}
bool baz (char, short, float) {std::cout << "baz\n"; return true;}
int main() {
const auto tuple = std::make_tuple(5, 'a', true, 3.5, 1000, 't', 2, 5.8);
multiFunction<2,3,3> (tuple, foo, bar, baz); // foo bar baz
}
So multiFunction<2,3,3> takes the first 2 elements of tuple and passes them to foo, the next 3 elements of tuple and passes them to bar, etc... I got this working (except when the functions have overloads, which is a separate problem). But the return values of each function called are lost. I want those return values stored somewhere, something like
std::tuple<int, double, bool> result = multiFunction<2,3,3> (tuple, foo, bar, baz);
But I don't know how to implement that. For those who want to help get this done, here is my (updated) working code so far, which stores the outputs into a stringstream only. Not easy to get all the values back, especially if the objects saved in the stream are complex classes.
#include <iostream>
#include <tuple>
#include <utility>
#include <sstream>
template <std::size_t N, typename Tuple>
struct TupleHead {
static auto get (const Tuple& tuple) { // The subtuple from the first N components of tuple.
return std::tuple_cat (TupleHead<N-1, Tuple>::get(tuple), std::make_tuple(std::get<N-1>(tuple)));
}
};
template <typename Tuple>
struct TupleHead<0, Tuple> {
static auto get (const Tuple&) { return std::tuple<>{}; }
};
template <std::size_t N, typename Tuple>
struct TupleTail {
static auto get (const Tuple& tuple) { // The subtuple from the last N components of tuple.
return std::tuple_cat (std::make_tuple(std::get<std::tuple_size<Tuple>::value - N>(tuple)), TupleTail<N-1, Tuple>::get(tuple));
}
};
template <typename Tuple>
struct TupleTail<0, Tuple> {
static auto get (const Tuple&) { return std::tuple<>{}; }
};
template <typename Tuple, typename F, std::size_t... Is>
auto functionOnTupleHelper (const Tuple& tuple, F f, const std::index_sequence<Is...>&) {
return f(std::get<Is>(tuple)...);
}
template <typename Tuple, typename F>
auto functionOnTuple (const Tuple& tuple, F f) {
return functionOnTupleHelper (tuple, f, std::make_index_sequence<std::tuple_size<Tuple>::value>{});
}
template <typename Tuple, typename... Functions> struct MultiFunction;
template <typename Tuple, typename F, typename... Fs>
struct MultiFunction<Tuple, F, Fs...> {
template <std::size_t I, std::size_t... Is>
static inline auto execute (const Tuple& tuple, std::ostringstream& oss, const std::index_sequence<I, Is...>&, F f, Fs... fs) {
const auto headTuple = TupleHead<I, Tuple>::get(tuple);
const auto tailTuple = TupleTail<std::tuple_size<Tuple>::value - I, Tuple>::get(tuple);
// functionOnTuple (headTuple, f); // Always works, though return type is lost.
oss << std::boolalpha << functionOnTuple (headTuple, f) << '\n'; // What about return types that are void???
return MultiFunction<std::remove_const_t<decltype(tailTuple)>, Fs...>::execute (tailTuple, oss, std::index_sequence<Is...>{}, fs...);
}
};
template <>
struct MultiFunction<std::tuple<>> {
static auto execute (const std::tuple<>&, std::ostringstream& oss, std::index_sequence<>) { // End of recursion.
std::cout << std::boolalpha << oss.str();
// Convert 'oss' into the desired tuple? But how?
return std::tuple<int, double, bool>(); // This line is just to make the test compile.
}
};
template <std::size_t... Is, typename Tuple, typename... Fs>
auto multiFunction (const Tuple& tuple, Fs... fs) {
std::ostringstream oss;
return MultiFunction<Tuple, Fs...>::execute (tuple, oss, std::index_sequence<Is...>{}, fs...);
}
// Testing
template <typename T> int foo (int, char) {std::cout << "foo<T>\n"; return 0;}
double bar (bool, double, long ) {std::cout << "bar\n"; return 3.5;}
template <int...> bool baz (char, short, float) {std::cout << "baz<int...>\n"; return true;}
int main() {
const auto tuple = std::make_tuple(5, 'a', true, 3.5, 1000, 't', 2, 5.8);
std::tuple<int, double, bool> result = multiFunction<2,3,3> (tuple, foo<bool>, bar, baz<2,5,1>); // foo<T> bar baz<int...>
}
Here's an approach where the number of arguments is deduced greedily:
#include <tuple>
namespace detail {
using namespace std;
template <size_t, size_t... Is, typename Arg>
constexpr auto call(index_sequence<Is...>, Arg&&) {return tuple<>{};}
template <size_t offset, size_t... Is, typename ArgT, typename... Fs>
constexpr auto call(index_sequence<Is...>, ArgT&&, Fs&&...);
template <size_t offset, size_t... Is,
typename ArgT, typename F, typename... Fs,
typename=decltype(declval<F>()(get<offset+Is>(declval<ArgT>())...))>
constexpr auto call(index_sequence<Is...>, ArgT&& argt, F&& f, Fs&&... fs) {
return tuple_cat(make_tuple(f(get<offset+I>(forward<ArgT>(argt))...)),
call<offset+sizeof...(Is)>(index_sequence<>{},
forward<ArgT>(argt),
forward<Fs>(fs)...));}
template <size_t offset, size_t... Is, typename ArgT, typename... Fs>
constexpr auto call(index_sequence<Is...>, ArgT&& argt, Fs&&... fs) {
return call<offset>(index_sequence<Is..., sizeof...(Is)>{},
forward<ArgT>(argt), forward<Fs>(fs)...);}
}
template <typename ArgT, typename... Fs>
constexpr auto multifunction(ArgT&& argt, Fs&&... fs) {
return detail::call<0>(std::index_sequence<>{},
std::forward<ArgT>(argt), std::forward<Fs>(fs)...);}
Demo. However, the above has quadratic time complexity in the number of return values, because tuple_cat is called recursively. Instead, we can use a slightly modified version of call to obtain the indices for each call - the actual tuple is then obtained directly:
#include <tuple>
namespace detail {
using namespace std;
template <size_t, size_t... Is, typename Arg>
constexpr auto indices(index_sequence<Is...>, Arg&&) {return tuple<>{};}
template <size_t offset, size_t... Is, typename ArgT, typename... Fs>
constexpr auto indices(index_sequence<Is...>, ArgT&&, Fs&&...);
template <size_t offset, size_t... Is, typename ArgT, typename F, class... Fs,
typename=decltype(declval<F>()(get<offset+Is>(declval<ArgT>())...))>
constexpr auto indices(index_sequence<Is...>, ArgT&& argt, F&& f, Fs&&... fs){
return tuple_cat(make_tuple(index_sequence<offset+Is...>{}),
indices<offset+sizeof...(Is)>(index_sequence<>{},
forward<ArgT>(argt),
forward<Fs>(fs)...));}
template <size_t offset, size_t... Is, typename ArgT, typename... Fs>
constexpr auto indices(index_sequence<Is...>, ArgT&& argt, Fs&&... fs) {
return indices<offset>(index_sequence<Is..., sizeof...(Is)>{},
forward<ArgT>(argt), forward<Fs>(fs)...);}
template <typename Arg, typename F, size_t... Is>
constexpr auto apply(Arg&& a, F&& f, index_sequence<Is...>) {
return f(get<Is>(a)...);}
template <typename ITuple, typename Args, size_t... Is, typename... Fs>
constexpr auto apply_all(Args&& args, index_sequence<Is...>, Fs&&... fs) {
return make_tuple(apply(forward<Args>(args), forward<Fs>(fs),
tuple_element_t<Is, ITuple>{})...);
}
}
template <typename ArgT, typename... Fs>
constexpr auto multifunction(ArgT&& argt, Fs&&... fs) {
return detail::apply_all<decltype(detail::indices<0>(std::index_sequence<>{},
std::forward<ArgT>(argt),
std::forward<Fs>(fs)...))>
(std::forward<ArgT>(argt), std::index_sequence_for<Fs...>{},
std::forward<Fs>(fs)...);}
Demo 2.
Building from the ground up and ignoring perfect forwarding so that I have to type less. We need a couple helpers. First, we need a partial version of apply that takes which indices from the tuple we want to apply to the function:
<class Tuple, class F, size_t... Is>
auto partial_apply(Tuple tuple, F f, std::index_sequence<Is...>) {
return f(get<Is>(tuple)...);
}
Then, we need to call that function for each subset of the tuple. Let's say we have all of our functions and indexes wrapped in a tuple already:
template <class Tuple, class FsTuple, class IsTuple, size_t... Is>
auto multi_apply(Tuple tuple, FsTuple fs, IsTuple indexes, std::index_sequence<Is...>) {
return std::make_tuple(
partial_apply(tuple,
std::get<Is>(fs),
std::get<Is>(indexes)
)...
);
}
So in this case, we'd want to end up calling multi_apply(tuple, <foo,bar,baz>, <<0,1>,<2,3,4>,<5,6,7>>, <0, 1, 2>).
All we need know is to build the indexes part. We're starting with <2,3,3>. We need to get the partial sums (<0,2,5>) and add that to the index sequences <<0,1>,<0,1,2>,<0,1,2>>. So we can write a partial sum function:
template <size_t I>
using size_t_ = std::integral_constant<size_t, I>;
template <class R, size_t N>
R partial_sum_(std::index_sequence<>, R, size_t_<N> ) {
return R{};
}
template <size_t I, size_t... Is, size_t... Js, size_t S>
auto partial_sum_(std::index_sequence<I, Is...>,
std::index_sequence<Js...>, size_t_<S> )
{
return partial_sum_(std::index_sequence<Is...>{},
std::index_sequence<Js..., S>{}, size_t_<S+I>{} );
}
template <size_t... Is>
auto partial_sum_(std::index_sequence<Is...> is)
{
return partial_sum_(is, std::index_sequence<>{}, size_t_<0>{} );
};
Which we can use to generate all of our indexes as a tuple:
template <size_t... Is, size_t N>
auto increment(std::index_sequence<Is...>, size_t_<N> )
{
return std::index_sequence<Is+N...>{};
}
template <class... Seqs, size_t... Ns>
auto make_all_indexes(std::index_sequence<Ns...>, Seqs... seqs)
{
return std::make_tuple(increment(seqs, size_t_<Ns>{})...);
}
Like so:
template <size_t... Is, class Tuple, class... Fs>
auto multiFunction(Tuple tuple, Fs... fs)
{
static_assert(sizeof...(Is) == sizeof...(Fs));
return multi_apply(tuple,
std::make_tuple(fs...),
make_all_indexes(
partial_sum_(std::index_sequence<Is...>{}),
std::make_index_sequence<Is>{}...
),
std::make_index_sequence<sizeof...(Is)>{}
);
}
If you want to handle void returns, then just make partial_apply return a tuple of a single element (or an empty tuple) and change the make_tuple() usage in multi_apply to tuple_cat().
Here's yet another impl:
template<std::size_t N>
constexpr Array<std::size_t, N> scan(std::size_t const (&a)[N])
{
Array<std::size_t, N> b{};
for (int i = 0; i != N - 1; ++i)
b[i + 1] = a[i] + b[i];
return b;
}
template<std::size_t O, std::size_t... N, class F, class Tuple>
inline decltype(auto) eval_from(std::index_sequence<N...>, F f, Tuple&& t)
{
return f(std::get<N + O>(std::forward<Tuple>(t))...);
}
template<std::size_t... O, std::size_t... N, class Tuple, class... F>
inline auto multi_function_impl1(std::index_sequence<O...>, std::index_sequence<N...>, Tuple&& t, F... f)
{
return pack(eval_from<O>(std::make_index_sequence<N>(), f, std::forward<Tuple>(t))...);
}
template<std::size_t... I, std::size_t... N, class Tuple, class... F>
inline auto multi_function_impl0(std::index_sequence<I...>, std::index_sequence<N...>, Tuple&& t, F... f)
{
constexpr std::size_t ns[] = {N...};
constexpr auto offsets = scan(ns);
return multi_function_impl1(std::index_sequence<offsets[I]...>(), std::index_sequence<N...>(), std::forward<Tuple>(t), f...);
}
template<std::size_t... N, class Tuple, class... F>
auto multi_function(Tuple&& t, F... f)
{
return multi_function_impl0(std::make_index_sequence<sizeof...(N)>(), std::index_sequence<N...>(), std::forward<Tuple>(t), f...);
}
where pack and Array are similar to std::make_tuple and std::array respectively, but to overcome some problems:
std::make_tuple decays it args, so references are lost
std::array cannot have its elems written in constexpr in c++14
DEMO
Here's my solution after following T.C.'s advice, adding to my previous (albeit inefficient) solution:
#include <iostream>
#include <tuple>
#include <utility>
struct NoReturnValue {
friend std::ostream& operator<< (std::ostream& os, const NoReturnValue&) {
return os << "[no value returned]";
}
};
template <std::size_t N, typename Tuple>
struct TupleHead {
static auto get (const Tuple& tuple) { // The subtuple from the first N components of tuple.
return std::tuple_cat (TupleHead<N-1, Tuple>::get(tuple), std::make_tuple(std::get<N-1>(tuple)));
}
};
template <typename Tuple>
struct TupleHead<0, Tuple> {
static auto get (const Tuple&) { return std::tuple<>{}; }
};
template <std::size_t N, typename Tuple>
struct TupleTail {
static auto get (const Tuple& tuple) { // The subtuple from the last N components of tuple.
return std::tuple_cat (std::make_tuple(std::get<std::tuple_size<Tuple>::value - N>(tuple)), TupleTail<N-1, Tuple>::get(tuple));
}
};
template <typename Tuple>
struct TupleTail<0, Tuple> {
static auto get (const Tuple&) { return std::tuple<>{}; }
};
template <typename Tuple, typename F, std::size_t... Is>
auto functionOnTupleHelper (const Tuple& tuple, F f, const std::index_sequence<Is...>&,
std::enable_if_t< !std::is_void<std::result_of_t<F(std::tuple_element_t<Is, Tuple>...)>>::value >* = nullptr) { // This overload is called only if f's return type is not void.
return std::make_tuple(f(std::get<Is>(tuple)...)); // Thanks to T.C.'s advice on returning a single tuple and then calling std::tuple_cat on all the single tuples.
}
template <typename Tuple, typename F, std::size_t... Is>
auto functionOnTupleHelper (const Tuple& tuple, F f, const std::index_sequence<Is...>&,
std::enable_if_t< std::is_void<std::result_of_t<F(std::tuple_element_t<Is, Tuple>...)>>::value >* = nullptr) { // This overload is called only if f's return type is void.
f(std::get<Is>(tuple)...);
return std::tuple<NoReturnValue>(); // Thanks to T.C.'s advice on returning std::tuple<NoReturnValue>() if the return type of 'f' is void.
}
template <typename Tuple, typename F>
auto functionOnTuple (const Tuple& tuple, F f) {
return functionOnTupleHelper (tuple, f, std::make_index_sequence<std::tuple_size<Tuple>::value>{});
}
template <typename Tuple, typename... Functions> struct MultiFunction;
template <typename Tuple, typename F, typename... Fs>
struct MultiFunction<Tuple, F, Fs...> {
template <std::size_t I, std::size_t... Is>
static inline auto execute (const Tuple& tuple, const std::index_sequence<I, Is...>&, F f, Fs... fs) {
const auto headTuple = TupleHead<I, Tuple>::get(tuple);
const auto tailTuple = TupleTail<std::tuple_size<Tuple>::value - I, Tuple>::get(tuple);
const auto r = functionOnTuple(headTuple, f); // Which overload of 'functionOnTupleHelper' is called dedends on whether f's return type is void or not.
return std::tuple_cat (r, MultiFunction<std::remove_const_t<decltype(tailTuple)>, Fs...>::execute (tailTuple, std::index_sequence<Is...>{}, fs...)); // T.C.'s idea of tuple_cat with all the single return tuples.
}
};
template <>
struct MultiFunction<std::tuple<>> {
static auto execute (const std::tuple<>&, std::index_sequence<>) { return std::tuple<>(); }
};
template <std::size_t... Is, typename Tuple, typename... Fs>
auto multiFunction (const Tuple& tuple, Fs... fs) {
return MultiFunction<Tuple, Fs...>::execute (tuple, std::index_sequence<Is...>{}, fs...);
}
// Testing
template <typename T> int foo (int, char) {std::cout << "foo<T>\n"; return 0;}
double bar (bool, double, long) {std::cout << "bar\n"; return 3.5;}
double bar (bool, int) {return 1.4;}
void voidFunction() {std::cout << "voidFunction\n";}
template <int...> bool baz (char, short, float) {std::cout << "baz<int...>\n"; return true;}
int main() {
const auto tuple = std::make_tuple(5, 'a', true, 3.5, 1000, 't', 2, 5.8);
const auto firstBar = [](bool b, double d, long l) {return bar(b, d, l);};
const auto t = multiFunction<2,3,0,3> (tuple, foo<bool>, firstBar, voidFunction, baz<2,5,1>); // Note that since 'bar' has an overload, we have to define 'firstBar' to indicate which 'bar' function we want to use.
std::cout << std::boolalpha << std::get<0>(t) << ' ' << std::get<1>(t) << ' ' << std::get<2>(t) << ' ' << std::get<3>(t) << '\n';
// 0 3.5 [no value returned] true
}
This solution should have linear time complexity. It uses std::tie instead of std::make_tuple, so neither the functions nor the arguments are copied unnecessarily. I think it should be fairly easy to follow compared to some other answers here.
First, we need a utility to invoke a function using a std::tuple of arguments.
template <typename F, typename Args, std::size_t... Is>
auto invoke_impl(F const& f, Args const& args, std::index_sequence<Is...>)
{
return f(std::get<Is>(args)...);
}
template <typename F, typename Args>
auto invoke(F const& f, Args const& args)
{
return invoke_impl(f, args, std::make_index_sequence<std::tuple_size<Args>::value>());
}
Secondly, we need a utility to std::tie a sub-range of tuple elements.
template <std::size_t Offset, typename Tuple, std::size_t... Is>
auto sub_tie_impl(Tuple const& tuple, std::index_sequence<Is...>)
{
return std::tie(std::get<Offset + Is>(tuple)...);
}
template <std::size_t Offset, std::size_t Count, typename Tuple>
auto sub_tie(Tuple const& tuple)
{
return sub_tie_impl<Offset>(tuple, std::make_index_sequence<Count>());
}
Now we can create our utility to consume a std::tuple of arguments using a sequence of functions.
First we std::tie the functions into a tuple, then we split the argument list into a parameter pack of sub-argument lists, and finally we invoke a function for each sub-argument list, packing the results into a tuple which we then return.
template <typename Fs, std::size_t... Is, typename... SubArgs>
auto consume_impl(Fs const& fs, std::index_sequence<Is...>, SubArgs const&... sub_args)
{
return std::make_tuple(invoke(std::get<Is>(fs), sub_args)...);
}
template <std::size_t, typename Args, typename Fs, typename... SubArgs>
auto consume_impl(Args const&, Fs const& fs, SubArgs const&... sub_args)
{
return consume_impl(fs, std::make_index_sequence<sizeof...(SubArgs)>(), sub_args...);
}
template <std::size_t Offset, std::size_t Count, std::size_t... Counts,
typename Args, typename Fs, typename... SubArgs>
auto consume_impl(Args const& args, Fs const& fs, SubArgs const&... sub_args)
{
return consume_impl<Offset + Count, Counts...>(args, fs, sub_args...,
sub_tie<Offset, Count>(args));
}
template <std::size_t... Counts, typename Args, typename... Fs>
auto consume(Args const& args, Fs const&... fs)
{
return consume_impl<0, Counts...>(args, std::tie(fs...));
}
Here's another solution borrowing Barry's partial_apply idea but avoiding the use of his partial_sum function altogether. It is shorter as a result. I think this is linear in time complexity.
#include <iostream>
#include <tuple>
#include <utility>
template <std::size_t Offset, typename F, typename Tuple, std::size_t... Is>
auto partial_apply_impl (F f, const Tuple& tuple, const std::index_sequence<Is...>&) {
return f(std::get<Offset + Is>(tuple)...);
}
template <typename Off, typename F, typename Tuple> // Off must be of type OffsetIndexSequence<A,B> only.
auto partial_apply (F f, const Tuple& tuple) {
return partial_apply_impl<Off::value>(f, tuple, typename Off::sequence{});
}
template <std::size_t Offset, std::size_t Size>
struct OffsetIndexSequence : std::integral_constant<std::size_t, Offset> {
using sequence = std::make_index_sequence<Size>;
};
template <typename Output, std::size_t... Is> struct OffsetIndexSequenceBuilder;
template <template <typename...> class P, typename... Out, std::size_t Offset, std::size_t First, std::size_t... Rest>
struct OffsetIndexSequenceBuilder<P<Out...>, Offset, First, Rest...> :
OffsetIndexSequenceBuilder<P<Out..., OffsetIndexSequence<Offset, First>>, Offset + First, Rest...> {};
template <template <typename...> class P, typename... Out, std::size_t Offset>
struct OffsetIndexSequenceBuilder<P<Out...>, Offset> {
using type = P<Out...>;
};
template <std::size_t... Is>
using offset_index_sequences = typename OffsetIndexSequenceBuilder<std::tuple<>, 0, Is...>::type;
template <typename> struct MultiFunction;
template <template <typename...> class P, typename... Offs>
struct MultiFunction<P<Offs...>> {
template <typename ArgsTuple, typename... Fs>
static auto execute (const ArgsTuple& argsTuple, Fs... fs) {
using ResultTuple = std::tuple<decltype(partial_apply<Offs>(fs, argsTuple))...>;
return ResultTuple{partial_apply<Offs>(fs, argsTuple)...};
}
};
template <std::size_t... Is, typename ArgsTuple, typename... Fs>
auto multiFunction (const ArgsTuple& argsTuple, Fs... fs) {
return MultiFunction<offset_index_sequences<Is...>>::execute(argsTuple, fs...);
}
// Testing
int foo (int, char) {std::cout << "foo\n"; return 0;}
double bar (bool, double, long) {std::cout << "bar\n"; return 3.5;}
bool baz (char, short, float) {std::cout << "baz\n"; return true;}
int main() {
const auto tuple = std::make_tuple(5, 'a', true, 3.5, 1000, 't', 2, 5.8);
const std::tuple<int, double, bool> t = multiFunction<2,3,3> (tuple, foo, bar, baz); // foo bar baz
std::cout << std::boolalpha << std::get<0>(t) << ' ' << std::get<1>(t) << ' ' << std::get<2>(t) << '\n'; // 0 3.5 true
}

How do I expand a tuple into variadic template function's arguments?

Consider the case of a templated function with variadic template arguments:
template<typename Tret, typename... T> Tret func(const T&... t);
Now, I have a tuple t of values. How do I call func() using the tuple values as arguments?
I've read about the bind() function object, with call() function, and also the apply() function in different some now-obsolete documents. The GNU GCC 4.4 implementation seems to have a call() function in the bind() class, but there is very little documentation on the subject.
Some people suggest hand-written recursive hacks, but the true value of variadic template arguments is to be able to use them in cases like above.
Does anyone have a solution to is, or hint on where to read about it?
In C++17 you can do this:
std::apply(the_function, the_tuple);
This already works in Clang++ 3.9, using std::experimental::apply.
Responding to the comment saying that this won't work if the_function is templated, the following is a work-around:
#include <tuple>
template <typename T, typename U> void my_func(T &&t, U &&u) {}
int main(int argc, char *argv[argc]) {
std::tuple<int, float> my_tuple;
std::apply([](auto &&... args) { my_func(args...); }, my_tuple);
return 0;
}
This work around is a simplified solution to the general problem of passing overload sets and function template where a function would be expected. The general solution (one that is taking care of perfect-forwarding, constexpr-ness, and noexcept-ness) is presented here: https://blog.tartanllama.xyz/passing-overload-sets/.
Here's my code if anyone is interested
Basically at compile time the compiler will recursively unroll all arguments in various inclusive function calls <N> -> calls <N-1> -> calls ... -> calls <0> which is the last one and the compiler will optimize away the various intermediate function calls to only keep the last one which is the equivalent of func(arg1, arg2, arg3, ...)
Provided are 2 versions, one for a function called on an object and the other for a static function.
#include <tr1/tuple>
/**
* Object Function Tuple Argument Unpacking
*
* This recursive template unpacks the tuple parameters into
* variadic template arguments until we reach the count of 0 where the function
* is called with the correct parameters
*
* #tparam N Number of tuple arguments to unroll
*
* #ingroup g_util_tuple
*/
template < uint N >
struct apply_obj_func
{
template < typename T, typename... ArgsF, typename... ArgsT, typename... Args >
static void applyTuple( T* pObj,
void (T::*f)( ArgsF... ),
const std::tr1::tuple<ArgsT...>& t,
Args... args )
{
apply_obj_func<N-1>::applyTuple( pObj, f, t, std::tr1::get<N-1>( t ), args... );
}
};
//-----------------------------------------------------------------------------
/**
* Object Function Tuple Argument Unpacking End Point
*
* This recursive template unpacks the tuple parameters into
* variadic template arguments until we reach the count of 0 where the function
* is called with the correct parameters
*
* #ingroup g_util_tuple
*/
template <>
struct apply_obj_func<0>
{
template < typename T, typename... ArgsF, typename... ArgsT, typename... Args >
static void applyTuple( T* pObj,
void (T::*f)( ArgsF... ),
const std::tr1::tuple<ArgsT...>& /* t */,
Args... args )
{
(pObj->*f)( args... );
}
};
//-----------------------------------------------------------------------------
/**
* Object Function Call Forwarding Using Tuple Pack Parameters
*/
// Actual apply function
template < typename T, typename... ArgsF, typename... ArgsT >
void applyTuple( T* pObj,
void (T::*f)( ArgsF... ),
std::tr1::tuple<ArgsT...> const& t )
{
apply_obj_func<sizeof...(ArgsT)>::applyTuple( pObj, f, t );
}
//-----------------------------------------------------------------------------
/**
* Static Function Tuple Argument Unpacking
*
* This recursive template unpacks the tuple parameters into
* variadic template arguments until we reach the count of 0 where the function
* is called with the correct parameters
*
* #tparam N Number of tuple arguments to unroll
*
* #ingroup g_util_tuple
*/
template < uint N >
struct apply_func
{
template < typename... ArgsF, typename... ArgsT, typename... Args >
static void applyTuple( void (*f)( ArgsF... ),
const std::tr1::tuple<ArgsT...>& t,
Args... args )
{
apply_func<N-1>::applyTuple( f, t, std::tr1::get<N-1>( t ), args... );
}
};
//-----------------------------------------------------------------------------
/**
* Static Function Tuple Argument Unpacking End Point
*
* This recursive template unpacks the tuple parameters into
* variadic template arguments until we reach the count of 0 where the function
* is called with the correct parameters
*
* #ingroup g_util_tuple
*/
template <>
struct apply_func<0>
{
template < typename... ArgsF, typename... ArgsT, typename... Args >
static void applyTuple( void (*f)( ArgsF... ),
const std::tr1::tuple<ArgsT...>& /* t */,
Args... args )
{
f( args... );
}
};
//-----------------------------------------------------------------------------
/**
* Static Function Call Forwarding Using Tuple Pack Parameters
*/
// Actual apply function
template < typename... ArgsF, typename... ArgsT >
void applyTuple( void (*f)(ArgsF...),
std::tr1::tuple<ArgsT...> const& t )
{
apply_func<sizeof...(ArgsT)>::applyTuple( f, t );
}
// ***************************************
// Usage
// ***************************************
template < typename T, typename... Args >
class Message : public IMessage
{
typedef void (T::*F)( Args... args );
public:
Message( const std::string& name,
T& obj,
F pFunc,
Args... args );
private:
virtual void doDispatch( );
T* pObj_;
F pFunc_;
std::tr1::tuple<Args...> args_;
};
//-----------------------------------------------------------------------------
template < typename T, typename... Args >
Message<T, Args...>::Message( const std::string& name,
T& obj,
F pFunc,
Args... args )
: IMessage( name ),
pObj_( &obj ),
pFunc_( pFunc ),
args_( std::forward<Args>(args)... )
{
}
//-----------------------------------------------------------------------------
template < typename T, typename... Args >
void Message<T, Args...>::doDispatch( )
{
try
{
applyTuple( pObj_, pFunc_, args_ );
}
catch ( std::exception& e )
{
}
}
In C++ there is many ways of expanding/unpacking tuple and apply those tuple elements to a variadic template function. Here is a small helper class which creates index array. It is used a lot in template metaprogramming:
// ------------- UTILITY---------------
template<int...> struct index_tuple{};
template<int I, typename IndexTuple, typename... Types>
struct make_indexes_impl;
template<int I, int... Indexes, typename T, typename ... Types>
struct make_indexes_impl<I, index_tuple<Indexes...>, T, Types...>
{
typedef typename make_indexes_impl<I + 1, index_tuple<Indexes..., I>, Types...>::type type;
};
template<int I, int... Indexes>
struct make_indexes_impl<I, index_tuple<Indexes...> >
{
typedef index_tuple<Indexes...> type;
};
template<typename ... Types>
struct make_indexes : make_indexes_impl<0, index_tuple<>, Types...>
{};
Now the code which does the job is not that big:
// ----------UNPACK TUPLE AND APPLY TO FUNCTION ---------
#include <tuple>
#include <iostream>
using namespace std;
template<class Ret, class... Args, int... Indexes >
Ret apply_helper( Ret (*pf)(Args...), index_tuple< Indexes... >, tuple<Args...>&& tup)
{
return pf( forward<Args>( get<Indexes>(tup))... );
}
template<class Ret, class ... Args>
Ret apply(Ret (*pf)(Args...), const tuple<Args...>& tup)
{
return apply_helper(pf, typename make_indexes<Args...>::type(), tuple<Args...>(tup));
}
template<class Ret, class ... Args>
Ret apply(Ret (*pf)(Args...), tuple<Args...>&& tup)
{
return apply_helper(pf, typename make_indexes<Args...>::type(), forward<tuple<Args...>>(tup));
}
Test is shown bellow:
// --------------------- TEST ------------------
void one(int i, double d)
{
std::cout << "function one(" << i << ", " << d << ");\n";
}
int two(int i)
{
std::cout << "function two(" << i << ");\n";
return i;
}
int main()
{
std::tuple<int, double> tup(23, 4.5);
apply(one, tup);
int d = apply(two, std::make_tuple(2));
return 0;
}
I'm not big expert in other languages, but I guess that if these languages do not have such functionality in their menu, there is no way to do that. At least with C++ you can, and I think it is not so much complicated...
I find this to be the most elegant solution (and it is optimally forwarded):
#include <cstddef>
#include <tuple>
#include <type_traits>
#include <utility>
template<size_t N>
struct Apply {
template<typename F, typename T, typename... A>
static inline auto apply(F && f, T && t, A &&... a)
-> decltype(Apply<N-1>::apply(
::std::forward<F>(f), ::std::forward<T>(t),
::std::get<N-1>(::std::forward<T>(t)), ::std::forward<A>(a)...
))
{
return Apply<N-1>::apply(::std::forward<F>(f), ::std::forward<T>(t),
::std::get<N-1>(::std::forward<T>(t)), ::std::forward<A>(a)...
);
}
};
template<>
struct Apply<0> {
template<typename F, typename T, typename... A>
static inline auto apply(F && f, T &&, A &&... a)
-> decltype(::std::forward<F>(f)(::std::forward<A>(a)...))
{
return ::std::forward<F>(f)(::std::forward<A>(a)...);
}
};
template<typename F, typename T>
inline auto apply(F && f, T && t)
-> decltype(Apply< ::std::tuple_size<
typename ::std::decay<T>::type
>::value>::apply(::std::forward<F>(f), ::std::forward<T>(t)))
{
return Apply< ::std::tuple_size<
typename ::std::decay<T>::type
>::value>::apply(::std::forward<F>(f), ::std::forward<T>(t));
}
Example usage:
void foo(int i, bool b);
std::tuple<int, bool> t = make_tuple(20, false);
void m()
{
apply(&foo, t);
}
Unfortunately GCC (4.6 at least) fails to compile this with "sorry, unimplemented: mangling overload" (which simply means that the compiler doesn't yet fully implement the C++11 spec), and since it uses variadic templates, it wont work in MSVC, so it is more or less useless. However, once there is a compiler that supports the spec, it will be the best approach IMHO. (Note: it isn't that hard to modify this so that you can work around the deficiencies in GCC, or to implement it with Boost Preprocessor, but it ruins the elegance, so this is the version I am posting.)
GCC 4.7 now supports this code just fine.
Edit: Added forward around actual function call to support rvalue reference form *this in case you are using clang (or if anybody else actually gets around to adding it).
Edit: Added missing forward around the function object in the non-member apply function's body. Thanks to pheedbaq for pointing out that it was missing.
Edit: And here is the C++14 version just since it is so much nicer (doesn't actually compile yet):
#include <cstddef>
#include <tuple>
#include <type_traits>
#include <utility>
template<size_t N>
struct Apply {
template<typename F, typename T, typename... A>
static inline auto apply(F && f, T && t, A &&... a) {
return Apply<N-1>::apply(::std::forward<F>(f), ::std::forward<T>(t),
::std::get<N-1>(::std::forward<T>(t)), ::std::forward<A>(a)...
);
}
};
template<>
struct Apply<0> {
template<typename F, typename T, typename... A>
static inline auto apply(F && f, T &&, A &&... a) {
return ::std::forward<F>(f)(::std::forward<A>(a)...);
}
};
template<typename F, typename T>
inline auto apply(F && f, T && t) {
return Apply< ::std::tuple_size< ::std::decay_t<T>
>::value>::apply(::std::forward<F>(f), ::std::forward<T>(t));
}
Here is a version for member functions (not tested very much!):
using std::forward; // You can change this if you like unreadable code or care hugely about namespace pollution.
template<size_t N>
struct ApplyMember
{
template<typename C, typename F, typename T, typename... A>
static inline auto apply(C&& c, F&& f, T&& t, A&&... a) ->
decltype(ApplyMember<N-1>::apply(forward<C>(c), forward<F>(f), forward<T>(t), std::get<N-1>(forward<T>(t)), forward<A>(a)...))
{
return ApplyMember<N-1>::apply(forward<C>(c), forward<F>(f), forward<T>(t), std::get<N-1>(forward<T>(t)), forward<A>(a)...);
}
};
template<>
struct ApplyMember<0>
{
template<typename C, typename F, typename T, typename... A>
static inline auto apply(C&& c, F&& f, T&&, A&&... a) ->
decltype((forward<C>(c)->*forward<F>(f))(forward<A>(a)...))
{
return (forward<C>(c)->*forward<F>(f))(forward<A>(a)...);
}
};
// C is the class, F is the member function, T is the tuple.
template<typename C, typename F, typename T>
inline auto apply(C&& c, F&& f, T&& t) ->
decltype(ApplyMember<std::tuple_size<typename std::decay<T>::type>::value>::apply(forward<C>(c), forward<F>(f), forward<T>(t)))
{
return ApplyMember<std::tuple_size<typename std::decay<T>::type>::value>::apply(forward<C>(c), forward<F>(f), forward<T>(t));
}
// Example:
class MyClass
{
public:
void foo(int i, bool b);
};
MyClass mc;
std::tuple<int, bool> t = make_tuple(20, false);
void m()
{
apply(&mc, &MyClass::foo, t);
}
template<typename F, typename Tuple, std::size_t ... I>
auto apply_impl(F&& f, Tuple&& t, std::index_sequence<I...>) {
return std::forward<F>(f)(std::get<I>(std::forward<Tuple>(t))...);
}
template<typename F, typename Tuple>
auto apply(F&& f, Tuple&& t) {
using Indices = std::make_index_sequence<std::tuple_size<std::decay_t<Tuple>>::value>;
return apply_impl(std::forward<F>(f), std::forward<Tuple>(t), Indices());
}
This is adapted from the C++14 draft using index_sequence. I might propose to have apply in a future standard (TS).
All this implementations are good. But due to use of pointer to member function compiler often cannot inline the target function call (at least gcc 4.8 can't, no matter what Why gcc can't inline function pointers that can be determined?)
But things changes if send pointer to member function as template arguments, not as function params:
/// from https://stackoverflow.com/a/9288547/1559666
template<int ...> struct seq {};
template<int N, int ...S> struct gens : gens<N-1, N-1, S...> {};
template<int ...S> struct gens<0, S...>{ typedef seq<S...> type; };
template<typename TT>
using makeSeq = typename gens< std::tuple_size< typename std::decay<TT>::type >::value >::type;
// deduce function return type
template<class ...Args>
struct fn_type;
template<class ...Args>
struct fn_type< std::tuple<Args...> >{
// will not be called
template<class Self, class Fn>
static auto type_helper(Self &self, Fn f) -> decltype((self.*f)(declval<Args>()...)){
//return (self.*f)(Args()...);
return NULL;
}
};
template<class Self, class ...Args>
struct APPLY_TUPLE{};
template<class Self, class ...Args>
struct APPLY_TUPLE<Self, std::tuple<Args...>>{
Self &self;
APPLY_TUPLE(Self &self): self(self){}
template<class T, T (Self::* f)(Args...), class Tuple>
void delayed_call(Tuple &&list){
caller<T, f, Tuple >(forward<Tuple>(list), makeSeq<Tuple>() );
}
template<class T, T (Self::* f)(Args...), class Tuple, int ...S>
void caller(Tuple &&list, const seq<S...>){
(self.*f)( std::get<S>(forward<Tuple>(list))... );
}
};
#define type_of(val) typename decay<decltype(val)>::type
#define apply_tuple(obj, fname, tuple) \
APPLY_TUPLE<typename decay<decltype(obj)>::type, typename decay<decltype(tuple)>::type >(obj).delayed_call< \
decltype( fn_type< type_of(tuple) >::type_helper(obj, &decay<decltype(obj)>::type::fname) ), \
&decay<decltype(obj)>::type::fname \
> \
(tuple);
And ussage:
struct DelayedCall
{
void call_me(int a, int b, int c){
std::cout << a+b+c;
}
void fire(){
tuple<int,int,int> list = make_tuple(1,2,3);
apply_tuple(*this, call_me, list); // even simpler than previous implementations
}
};
Proof of inlinable http://goo.gl/5UqVnC
With small changes, we can "overload" apply_tuple:
#define VA_NARGS_IMPL(_1, _2, _3, _4, _5, _6, _7, _8, N, ...) N
#define VA_NARGS(...) VA_NARGS_IMPL(X,##__VA_ARGS__, 7, 6, 5, 4, 3, 2, 1, 0)
#define VARARG_IMPL_(base, count, ...) base##count(__VA_ARGS__)
#define VARARG_IMPL(base, count, ...) VARARG_IMPL_(base, count, __VA_ARGS__)
#define VARARG(base, ...) VARARG_IMPL(base, VA_NARGS(__VA_ARGS__), __VA_ARGS__)
#define apply_tuple2(fname, tuple) apply_tuple3(*this, fname, tuple)
#define apply_tuple3(obj, fname, tuple) \
APPLY_TUPLE<typename decay<decltype(obj)>::type, typename decay<decltype(tuple)>::type >(obj).delayed_call< \
decltype( fn_type< type_of(tuple) >::type_helper(obj, &decay<decltype(obj)>::type::fname) ), \
&decay<decltype(obj)>::type::fname \
/* ,decltype(tuple) */> \
(tuple);
#define apply_tuple(...) VARARG(apply_tuple, __VA_ARGS__)
...
apply_tuple(obj, call_me, list);
apply_tuple(call_me, list); // call this->call_me(list....)
Plus this is the only one solution which works with templated functions.
1) if you have a readymade parameter_pack structure as function argument, you can just use std::tie like this:
template <class... Args>
void tie_func(std::tuple<Args...> t, Args&... args)
{
std::tie<Args...>(args...) = t;
}
int main()
{
std::tuple<int, double, std::string> t(2, 3.3, "abc");
int i;
double d;
std::string s;
tie_func(t, i, d, s);
std::cout << i << " " << d << " " << s << std::endl;
}
2) if you don't have a readymade parampack arg, you'll have to unwind the tuple like this
#include <tuple>
#include <functional>
#include <iostream>
template<int N>
struct apply_wrap {
template<typename R, typename... TupleArgs, typename... UnpackedArgs>
static R applyTuple( std::function<R(TupleArgs...)>& f, const std::tuple<TupleArgs...>& t, UnpackedArgs... args )
{
return apply_wrap<N-1>::applyTuple( f, t, std::get<N-1>( t ), args... );
}
};
template<>
struct apply_wrap<0>
{
template<typename R, typename... TupleArgs, typename... UnpackedArgs>
static R applyTuple( std::function<R(TupleArgs...)>& f, const std::tuple<TupleArgs...>&, UnpackedArgs... args )
{
return f( args... );
}
};
template<typename R, typename... TupleArgs>
R applyTuple( std::function<R(TupleArgs...)>& f, std::tuple<TupleArgs...> const& t )
{
return apply_wrap<sizeof...(TupleArgs)>::applyTuple( f, t );
}
int fac(int n)
{
int r=1;
for(int i=2; i<=n; ++i)
r *= i;
return r;
}
int main()
{
auto t = std::make_tuple(5);
auto f = std::function<decltype(fac)>(&fac);
cout << applyTuple(f, t);
}
The news does not look good.
Having read over the just-released draft standard, I'm not seeing a built-in solution to this, which does seem odd.
The best place to ask about such things (if you haven't already) is comp.lang.c++.moderated, because some folks involved in drafting the standard post there regularly.
If you check out this thread, someone has the same question (maybe it's you, in which case you're going to find this whole answer a little frustrating!), and a few butt-ugly implementations are suggested.
I just wondered if it would be simpler to make the function accept a tuple, as the conversion that way is easier. But this implies that all functions should accept tuples as arguments, for maximum flexibility, and so that just demonstrates the strangeness of not providing a built-in expansion of tuple to function argument pack.
Update: the link above doesn't work - try pasting this:
http://groups.google.com/group/comp.lang.c++.moderated/browse_thread/thread/750fa3815cdaac45/d8dc09e34bbb9661?lnk=gst&q=tuple+variadic#d8dc09e34bbb9661
How about this:
// Warning: NOT tested!
#include <cstddef>
#include <tuple>
#include <type_traits>
#include <utility>
using std::declval;
using std::forward;
using std::get;
using std::integral_constant;
using std::size_t;
using std::tuple;
namespace detail
{
template < typename Func, typename ...T, typename ...Args >
auto explode_tuple( integral_constant<size_t, 0u>, tuple<T...> const &t,
Func &&f, Args &&...a )
-> decltype( forward<Func>(f)(declval<T const>()...) )
{ return forward<Func>( f )( forward<Args>(a)... ); }
template < size_t Index, typename Func, typename ...T, typename ...Args >
auto explode_tuple( integral_constant<size_t, Index>, tuple<T...> const&t,
Func &&f, Args &&...a )
-> decltype( forward<Func>(f)(declval<T const>()...) )
{
return explode_tuple( integral_constant<size_t, Index - 1u>{}, t,
forward<Func>(f), get<Index - 1u>(t), forward<Args>(a)... );
}
}
template < typename Func, typename ...T >
auto run_tuple( Func &&f, tuple<T...> const &t )
-> decltype( forward<Func>(f)(declval<T const>()...) )
{
return detail::explode_tuple( integral_constant<size_t, sizeof...(T)>{}, t,
forward<Func>(f) );
}
template < typename Tret, typename ...T >
Tret func_T( tuple<T...> const &t )
{ return run_tuple( &func<Tret, T...>, t ); }
The run_tuple function template takes the given tuple and pass its elements individually to the given function. It carries out its work by recursively calling its helper function templates explode_tuple. It's important that run_tuple passes the tuple's size to explode_tuple; that number acts as a counter for how many elements to extract.
If the tuple is empty, then run_tuple calls the first version of explode_tuple with the remote function as the only other argument. The remote function is called with no arguments and we're done. If the tuple is not empty, a higher number is passed to the second version of explode_tuple, along with the remote function. A recursive call to explode_tuple is made, with the same arguments, except the counter number is decreased by one and (a reference to) the last tuple element is tacked on as an argument after the remote function. In a recursive call, either the counter isn't zero, and another call is made with the counter decreased again and the next-unreferenced element is inserted in the argument list after the remote function but before the other inserted arguments, or the counter reaches zero and the remote function is called with all the arguments accumulated after it.
I'm not sure I have the syntax of forcing a particular version of a function template right. I think you can use a pointer-to-function as a function object; the compiler will automatically fix it.
I am evaluating MSVS 2013RC, and it failed to compile some of the previous solutions proposed here in some cases. For example, MSVS will fail to compile "auto" returns if there are too many function parameters, because of a namespace imbrication limit (I sent that info to Microsoft to have it corrected). In other cases, we need access to the function's return, although that can also be done with a lamda: the following two examples give the same result..
apply_tuple([&ret1](double a){ret1 = cos(a); }, std::make_tuple<double>(.2));
ret2 = apply_tuple((double(*)(double))cos, std::make_tuple<double>(.2));
And thanks again to those who posted answers here before me, I wouldn't have gotten to this without it... so here it is:
template<size_t N>
struct apply_impl {
template<typename F, typename T, typename... A>
static inline auto apply_tuple(F&& f, T&& t, A&&... a)
-> decltype(apply_impl<N-1>::apply_tuple(std::forward<F>(f), std::forward<T>(t),
std::get<N-1>(std::forward<T>(t)), std::forward<A>(a)...)) {
return apply_impl<N-1>::apply_tuple(std::forward<F>(f), std::forward<T>(t),
std::get<N-1>(std::forward<T>(t)), std::forward<A>(a)...);
}
template<typename C, typename F, typename T, typename... A>
static inline auto apply_tuple(C*const o, F&& f, T&& t, A&&... a)
-> decltype(apply_impl<N-1>::apply_tuple(o, std::forward<F>(f), std::forward<T>(t),
std::get<N-1>(std::forward<T>(t)), std::forward<A>(a)...)) {
return apply_impl<N-1>::apply_tuple(o, std::forward<F>(f), std::forward<T>(t),
std::get<N-1>(std::forward<T>(t)), std::forward<A>(a)...);
}
};
// This is a work-around for MSVS 2013RC that is required in some cases
#if _MSC_VER <= 1800 /* update this when bug is corrected */
template<>
struct apply_impl<6> {
template<typename F, typename T, typename... A>
static inline auto apply_tuple(F&& f, T&& t, A&&... a)
-> decltype(std::forward<F>(f)(std::get<0>(std::forward<T>(t)), std::get<1>(std::forward<T>(t)), std::get<2>(std::forward<T>(t)),
std::get<3>(std::forward<T>(t)), std::get<4>(std::forward<T>(t)), std::get<5>(std::forward<T>(t)), std::forward<A>(a)...)) {
return std::forward<F>(f)(std::get<0>(std::forward<T>(t)), std::get<1>(std::forward<T>(t)), std::get<2>(std::forward<T>(t)),
std::get<3>(std::forward<T>(t)), std::get<4>(std::forward<T>(t)), std::get<5>(std::forward<T>(t)), std::forward<A>(a)...);
}
template<typename C, typename F, typename T, typename... A>
static inline auto apply_tuple(C*const o, F&& f, T&& t, A&&... a)
-> decltype((o->*std::forward<F>(f))(std::get<0>(std::forward<T>(t)), std::get<1>(std::forward<T>(t)), std::get<2>(std::forward<T>(t)),
std::get<3>(std::forward<T>(t)), std::get<4>(std::forward<T>(t)), std::get<5>(std::forward<T>(t)), std::forward<A>(a)...)) {
return (o->*std::forward<F>(f))(std::get<0>(std::forward<T>(t)), std::get<1>(std::forward<T>(t)), std::get<2>(std::forward<T>(t)),
std::get<3>(std::forward<T>(t)), std::get<4>(std::forward<T>(t)), std::get<5>(std::forward<T>(t)), std::forward<A>(a)...);
}
};
#endif
template<>
struct apply_impl<0> {
template<typename F, typename T, typename... A>
static inline auto apply_tuple(F&& f, T&&, A&&... a)
-> decltype(std::forward<F>(f)(std::forward<A>(a)...)) {
return std::forward<F>(f)(std::forward<A>(a)...);
}
template<typename C, typename F, typename T, typename... A>
static inline auto apply_tuple(C*const o, F&& f, T&&, A&&... a)
-> decltype((o->*std::forward<F>(f))(std::forward<A>(a)...)) {
return (o->*std::forward<F>(f))(std::forward<A>(a)...);
}
};
// Apply tuple parameters on a non-member or static-member function by perfect forwarding
template<typename F, typename T>
inline auto apply_tuple(F&& f, T&& t)
-> decltype(apply_impl<std::tuple_size<typename std::decay<T>::type>::value>::apply_tuple(std::forward<F>(f), std::forward<T>(t))) {
return apply_impl<std::tuple_size<typename std::decay<T>::type>::value>::apply_tuple(std::forward<F>(f), std::forward<T>(t));
}
// Apply tuple parameters on a member function
template<typename C, typename F, typename T>
inline auto apply_tuple(C*const o, F&& f, T&& t)
-> decltype(apply_impl<std::tuple_size<typename std::decay<T>::type>::value>::apply_tuple(o, std::forward<F>(f), std::forward<T>(t))) {
return apply_impl<std::tuple_size<typename std::decay<T>::type>::value>::apply_tuple(o, std::forward<F>(f), std::forward<T>(t));
}
Extending on #David's solution, you can write a recursive template that
Doesn't use the (overly-verbose, imo) integer_sequence semantics
Doesn't use an extra temporary template parameter int N to count recursive iterations
(Optional for static/global functors) uses the functor as a template parameter for compile-time optimizaion
E.g.:
template <class F, F func>
struct static_functor {
template <class... T, class... Args_tmp>
static inline auto apply(const std::tuple<T...>& t, Args_tmp... args)
-> decltype(func(std::declval<T>()...)) {
return static_functor<F,func>::apply(t, args...,
std::get<sizeof...(Args_tmp)>(t));
}
template <class... T>
static inline auto apply(const std::tuple<T...>& t, T... args)
-> decltype(func(args...)) {
return func(args...);
}
};
static_functor<decltype(&myFunc), &myFunc>::apply(my_tuple);
Alternatively if your functor is not defined at compile-time (e.g., a non-constexpr functor instance, or a lambda expression), you can use it as a function parameter instead of a class template parameter, and in fact remove the containing class entirely:
template <class F, class... T, class... Args_tmp>
inline auto apply_functor(F&& func, const std::tuple<T...>& t,
Args_tmp... args) -> decltype(func(std::declval<T>()...)) {
return apply_functor(func, t, args..., std::get<sizeof...(Args_tmp)>(t));
}
template <class F, class... T>
inline auto apply_functor(F&& func, const std::tuple<T...>& t,
T... args) -> decltype(func(args...)) {
return func(args...);
}
apply_functor(&myFunc, my_tuple);
For pointer-to-member-function callables, you can adjust either of the above code pieces similarly as in #David's answer.
Explanation
In reference to the second piece of code, there are two template functions: the first one takes the functor func, the tuple t with types T..., and a parameter pack args of types Args_tmp.... When called, it recursively adds the objects from t to the parameter pack one at a time, from beginning (0) to end, and calls the function again with the new incremented parameter pack.
The second function's signature is almost identical to the first, except that it uses type T... for the parameter pack args. Thus, once args in the first function is completely filled with the values from t, it's type will be T... (in psuedo-code, typeid(T...) == typeid(Args_tmp...)), and thus the compiler will instead call the second overloaded function, which in turn calls func(args...).
The code in the static functor example works identically, with the functor instead used as a class template argument.
Why not just wrap your variadic arguments into a tuple class and then use compile time recursion (see link) to retrieve the index you are interested in. I find that unpacking variadic templates into a container or collection may not be type safe w.r.t. heterogeneous types
template<typename... Args>
auto get_args_as_tuple(Args... args) -> std::tuple<Args...>
{
return std::make_tuple(args);
}
This simple solution works for me:
template<typename... T>
void unwrap_tuple(std::tuple<T...>* tp)
{
std::cout << "And here I have the tuple types, all " << sizeof...(T) << " of them" << std::endl;
}
int main()
{
using TupleType = std::tuple<int, float, std::string, void*>;
unwrap_tuple((TupleType*)nullptr); // trick compiler into using template param deduction
}