I'm learning how to make myself a simple XOR encryption. However, to make things more difficult for a person to decipher the message I want to try to swap characters and then swap them back (after the user enters the key for the decryption).
This is my output:
yet ih ssia t se!t !
ey this is a test!!
Does anyone know why it is cutting off the h in the second printout? I'm still fairly new to programming and spent a good hour trying to figure it out.
Here is my code:
#include <cstring>
#include <string>
#include <iostream>
using namespace std;
void doSwap (char &string1, char &string2) {
char temp;
temp = string1;
string1 = string2;
string2 = temp;
}
int main() {
string content = "hey this is a test!!";
string after, after2;
int i;
for (i = 0; i < content.size(); i+=2) {
doSwap(content[i], content[i+2]);
}
after = content;
cout << after << "\n";
for (i = after.size(); i > 0; i -=2) {
doSwap(after[i], after[i-2]);
}
after2 = after;
cout << after2 << "\n";
}
Your loop indexing is not correct. As #tadman pointed out, you will walk off the string.
The first loop would have to terminate 2 indices shorter than the size, so that when you add 2, it would be 1 less than content.size(). Remember C/C++ is 0 indexed, therefore if size is 10, element 9 is the last index of the string.
for (i = 0; i < content.size()-2; i+=2) {
doSwap(content[i], content[i+2]);
}
Similarly the second loop should start 1 short of the size and terminate at 2, so when you index into i-2, you are indexing no less than 0.
for (i = after.size()-1; i >= 2; i -=2) {
doSwap(after[i], after[i-2]);
}
Related
The purpose of this code is to insert an x in between repeating letters. For example, if I were to input "CoolBoolFallmoose", the output would be "CoxolBoxolFalxlmoxose".
The code is also supposed to make an even number of pairs of letters, so if there is an odd amount of characters, an x is added to the end of the string. An example for this would be if we had "ball", it would become "balxlx" to make even pairs: "ba" "lx" "lx".
This is the code I have so far:
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main(){
string cipher, plain, paired = "";
cout << "input plaintext(no spaces, lowercase):\n";
cin >> plain;
for (int i=0;i<plain.length();i++){
if (plain[i]==plain[i+1]){
plain.insert(i,'x');
}
paired[i]=paired[i];
cout<<paired[i];
}
if (paired.length() % 2!= 0){
paired=+'x';
}
cout<<paired<<endl;
return 0;
}
The output I get is just the same as my input, no "x" added in any place.
The issue I am having is, every time I try to use the append() or insert() function for strings, I get an error from my compiler, which is xCode. Is there another way to solve this code?
EDIT: The error says:
No matching member function to call for insert
It also comes up for append().
I don't really know what you wanted to do with this part:
paired[i]=paired[i];
cout<<paired[i];
but otherwise the logic is good. Here is my take on it, x is a counter:
#include <iostream>
#include <string>
using namespace std;
int main(){
string m,n;
int x = 0;
cout << "Input: " << endl;
getline(cin, m);
for(int i = 0;i < m.length();i++){
x++;
n = n + m[i];
if(m[i] == m[i+1]){
n = n + 'x';
x++;
}
}
if((x % 2) != 0){
n = n + 'x';
}
cout << n;
return 0;
}
If you look at the available overloads of std::string::insert(), you will see that your statement plain.insert(i,'x'); does not match any of them, hence the compiler error. The overloads that takes a single char require either:
an index and a count (you are omitting the count)
an iterator and an optional count
There is, however, a couple of overloads that take just an index and a value, but they require a const char* or a std::string, not a single char.
Also, paired[i]=paired[i]; is a no-op. Except in your case, since paired has a size() of 0 since you never append anything to paired, so actually any access to paired[...] is undefined behavior.
Try this instead:
#include <iostream>
#include <string>
using namespace std;
int main(){
string plain, paired;
cout << "input plaintext(no spaces, lowercase):\n";
cin >> plain;
paired = plain;
for (string::size_type i = 1; i < paired.size(); ++i){
if (paired[i] == paired[i-1]){
paired.insert(i, 1, 'x');
// or: paired.insert(paired.begin()+i, 'x');
// or: paired.insert(i, "x");
// or: paired.insert(i, string{'x'});
// or: paired.insert(paired.begin()+i, {'x'});
++i; // skip the x just inserted
}
}
if (paired.size() % 2 != 0){
paired += 'x';
}
cout << paired << endl;
return 0;
}
Demo
A couple of points
First, Although the string.insert function says it takes an int as its first argument it really wants an iterator in this case.
Second, you are inserting elements into your "plain" string which increases its length and you have plain.length within your loop so you create an infinite loop.
Third, insert inserts BEFORE the index so you need to add 1 to I.
The code below will work for your loop:
Int len = plain.length();
Int count = 0;
for (int i = 0; i < len + count; i++)
{
If (plain[i] == plain[i + 1])
{
plain.insert(plain.begin() + (i +1), 'X');
++count;
}
}
cout << plain;
And as, mentioned below, if you want to handle spaces you can use getline(cin, plain) instead of cin.
i am new to this concept in c++
i am trying to reverse string using stack static array implementation in c++.
Input: qwerty
expected output: ytrewq
output which i am getting is: trewq
Can some one explain me why is this happening and any possible solution.
Here's my code
#include <iostream>
#include <string>
using namespace std;
#define SIZE 10
string arr[SIZE];
unsigned a = -1;
void push(char ch) {
a = a + 1;
arr[a] = ch;
}
void pop() {
a = a - 1;
}
void display() {
for (int j = a; j >= 0; j--)
cout << arr[j];
}
int main() {
string str;
getline(cin, str);
for (int i = 0; i < (str.length() - 1); i++)
push(str[i]);
display();
}
Remove the "-1" in :
for(int i=0;i<(str.length())-1;i++)
Else your array doesn't contains the last character.
I made the test without the -1, it works well.
The condition "< str.length()" is enough to loop on all string caracter.
In similar case, use the debugger to see what contains your variable. In these case the variable "arr" don't contains the last input caracter.
You push everything on the stack, so the last element can be popped first. Then do popping to fill a reversed strng. The stack should be a char array.
As this is typically a task, the rest is your puzzle.
Pop typically gives you the top element as:
char pop() {
char ch = arr[a];
--a;
return ch;
}
The correct way to reverse a string would be to do:
std::reverse(str.begin(), str.end());
But I think this might be homework/study so look at your output. You are just missing the last letter. That suggests the upper limit of your loop is wrong doesn't it?
My logic is as follows :
#include<bits/stdc++.h>
using namespace std;
int main(){
char a[50] = {'h','i',' ','m','e',' ','t','e'};
// k = 4 because i have 2 spaces and for each
// space i have to insert 2 spaces . so total 4
//spaces
int k=4;
for(int i=strlen(a)-1 ; i>0 && k >0 ; i--){
if(a[i] != ' ')
{
a[i+k] = a[i];
a[i] = ' ';
}
else
{
k = k - 2;
}
}
printf("%s" , a);
return 0;
}
I have to character array to solve it. I am able to
do it using string stl
The output i get is
hi---me.
But the answer is
hi---me---te.
Your code is tagged C++. But there is nothing C++ in your code. It is pure C.
And, your are including #include<bits/stdc++.h> and using the std namespace using namespace std;. From now on: Please never ever in your whole life do such things again. Or, stop working with C++.
Additionally never ever use plain C-style array like your char a[50] in C++.
In your code you have some bugs. Most critical is the missing terminating 0 and then calling strlen. Before you use a function, always check somewhere, how this function works. Use meaningful variable names. Write comments. Always check boundaries.
I updated your C-Code:
#include <stdio.h>
int main()
{
// Character String to work on
char charString[50] = "hi me te";
// Check all possible positions in string
for (int index = 0; (index < 49) && (0 != charString[index]); ++index)
{
// If there is a space in the string
if (' ' == charString[index])
{
// Shift all characters one position to the right
for (int shiftPosition = 48; shiftPosition >= index; --shiftPosition)
{
charString[shiftPosition + 1] = charString[shiftPosition];
}
++index;
}
}
// Show result
printf("%s\n", charString);
return 0;
}
And here the C++ solution
#include <iostream>
#include <string>
#include <regex>
int main()
{
// Text to work on
std::string text("hi me te");
// Replace every space with 2 spaces. Print result
std::cout << std::regex_replace(text, std::regex(" "), " ");
return 0;
}
Currently I am getting an runtime "assertation error"
Here is the error:
I'm reading words from a text file into dynamically allocated arrays.
this block of code is where I am filling the new arrays.
I know the problem is being caused by this block of code and something about my logic is off just can't see what it is.
//fill new arrays
for( int y = 0; y < new_numwords; y++)
{
for( int i = 0; i < NUM_WORDS; i++)
{
if (!strcmp(SentenceArry[i], EMPTY[0]) == 0)
{
New_SentenceArry[y] = SentenceArry[i];
New_WordCount[y] = WordCount[i];
y++;
}
}
}
Also how would I pass this dynamically allocated 2D array to a function? (the code really needs to be cleaned up as a whole)
char** SentenceArry = new char*[NUM_WORDS]; //declare pointer for the sentence
for( int i = 0; i < NUM_WORDS; i++)
{
SentenceArry[i] = new char[WORD_LENGTH];
}
Here is the full extent of the code.. help would be much appreciated!
Here is what is being read in:
and the current output (the output is how it's suppose to be ):
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <fstream>
#include <cstring>
#include <cctype>
#include <iomanip>
using std::setw;
using std::left;
using std::cout;
using std::cin;
using std::endl;
using std::ifstream;
int main()
{
const int NUM_WORDS = 17;//constant for the elements of arrays
const int WORD_LENGTH = 50;//constant for the length of the cstrings (NEED TO GIVE THE VALUE ZERO STILL!)
short word_entry = 0; //declare counter
short new_numwords= 0; //declare new word count
char EMPTY[1][4]; //NULL ARRAY
EMPTY[0][0] = '\0';//define it as null
char** SentenceArry = new char*[NUM_WORDS]; //declare pointer for the sentence
for( int i = 0; i < NUM_WORDS; i++)
{
SentenceArry[i] = new char[WORD_LENGTH];
}
int WordCount[NUM_WORDS];//declare integer array for the word counter
for(int i = 0; i < NUM_WORDS; i++)//fill int array
{
WordCount[i] = 1;
}
int New_WordCount[NUM_WORDS] = {0};
ifstream read_text("DataFile.txt"); //read in our text file
if (read_text.is_open()) //check if the the file was opened
{
read_text >> SentenceArry[word_entry];
//REMOVE PUNCTUATION BEFORE BEING READ INTO THE ARRAY
while (!read_text.eof())
{
word_entry++; //increment counter
read_text >> SentenceArry[word_entry]; //read in single words of the text file into the array SentenceArry
char* ptr_ch;//declare our pointer that will find chars
ptr_ch = strstr( SentenceArry[word_entry], ",");//look for "," within the array
if (ptr_ch != NULL)//if true replace it with a null character
{
strncpy( ptr_ch, "\0" , 1);
}//end if
else
{
ptr_ch = strstr( SentenceArry[word_entry], ".");//look for "." within the array
if (ptr_ch != NULL)//if true replace it with a null character
{
strncpy( ptr_ch, "\0" , 1);
}//end if
}//end else
} //end while
}//end if
else
{
cout << "The file could not be opened!" << endl;//display error message if file doesn't open
}//end else
read_text.close(); //close the text file after eof
//WORD COUNT NESTED FOR LOOP
for(int y = 0; y < NUM_WORDS; y++)
{
for(int i = y+1; i < NUM_WORDS; i++)
{
if (strcmp(SentenceArry[y], EMPTY[0]) == 0)//check if the arrays match
{
y++;
}
else
{
if (strcmp(SentenceArry[y], SentenceArry[i]) == 0)//check if the arrays match
{
WordCount[y]++;
strncpy(SentenceArry[i], "\0" , 3);
}//end if
}//end if
}//end for
}//end for
//find how many arrays still contain chars
for(int i = 0; i < NUM_WORDS; i++)
{
if (!strcmp(SentenceArry[i], EMPTY[0]) == 0)
{
new_numwords++;
}
}
//new dynamic array
char** New_SentenceArry = new char*[new_numwords]; //declare pointer for the sentence
for( int i = 0; i < new_numwords; i++)
{
New_SentenceArry[i] = new char[new_numwords];
}
//fill new arrays
for( int y = 0; y < new_numwords; y++)
{
for( int i = 0; i < NUM_WORDS; i++)
{
if (!strcmp(SentenceArry[i], EMPTY[0]) == 0)
{
New_SentenceArry[y] = SentenceArry[i];
New_WordCount[y] = WordCount[i];
y++;
}
}
}
//DISPLAY REPORT
cout << left << setw(15) << "Words" << left << setw(9) << "Frequency" << endl;
for(int i = 0; i < new_numwords; i++) //compare i to the array constant NUM_WORDS
{
cout << left << setw(15) << New_SentenceArry[i] << left << setw(9) << New_WordCount[i] << endl; //display the contents of the array SentenceArry
}
//DEALLOCATION
for( int i = 0; i < NUM_WORDS; i++)//deallocate the words inside the arrays
{
delete [] SentenceArry[i];
}
for(int i = 0; i < new_numwords; i++)
{
delete [] New_SentenceArry[i];
}
delete [] SentenceArry; //deallocate the memory allocation made for the array SentenceArry
delete [] New_SentenceArry;//deallocate the memory allocation made for the array New_SentenceArry
}//end main
There are several issues with the code, not withstanding that this could be written using C++, not C with a sprinkling of C++ I/O..
Issue 1:
Since you're using c-style strings, any copying of string data will require function calls such as strcpy(), strncpy(), etc. You failed in following this advice in this code:
for( int y = 0; y < new_numwords; y++)
{
for( int i = 0; i < NUM_WORDS; i++)
{
if (!strcmp(SentenceArry[i], EMPTY[0]) == 0)
{
New_SentenceArry[y] = SentenceArry[i]; // This is wrong
New_WordCount[y] = WordCount[i];
y++;
}
}
}
You should be using strcpy(), not = to copy strings.
strcpy(New_SentenceArry[y], SentenceArry[i]);
Issue 2:
You should allocate WORD_LENGTH for both the original and new arrays. The length of the strings is independent of the number of strings.
char** New_SentenceArry = new char*[new_numwords]; //declare pointer for the sentence
for( int i = 0; i < new_numwords; i++)
{
New_SentenceArry[i] = new char[new_numwords];
}
This should be:
char** New_SentenceArry = new char*[new_numwords]; //declare pointer for the sentence
for( int i = 0; i < new_numwords; i++)
{
New_SentenceArry[i] = new char[WORD_LENGTH];
}
Issue 3:
Your loops do not check to see if the index is going out of bounds of your arrays.
It seems that you coded your program in accordance to the data that you're currently using, instead of writing code regardless of what the data will be. If you have limited yourself to 17 words, where is the check to see if the index goes above 16? Nowhere.
For example:
while (!read_text.eof() )
Should be:
while (!read_text.eof() && word_entry < NUM_WORDS)
Issue 4:
You don't process the first string found correctly:
read_text >> SentenceArry[word_entry]; // Here you read in the first word
while (!read_text.eof() )
{
word_entry++; //increment counter
read_text >> SentenceArry[word_entry]; // What about the first word you read in?
Summary:
Even with these changes, I can't guarantee that the program won't crash. Even it it doesn't crash with these changes, I can't guarantee it will work 100% of the time -- a guarantee would require further analysis.
The proper C++ solution, given what this assignment was about, is to use a std::map<std::string, int> to keep the word frequency. The map would automatically store similar words in one entry (given that you remove the junk from the word), and would bump up the count to 1 automatically, when the entry is inserted into the map.
Something like this:
#include <string>
#include <map>
#include <algorithm>
typedef std::map<std::string, int> StringMap;
using namespace std;
bool isCharacterGarbage(char ch)
{ return ch == ',' || ch == '.'; }
int main()
{
StringMap sentenceMap;
//...
std::string temp;
read_text >> temp;
temp.erase(std::remove_if(temp.begin(), temp.end(), isCharacterGarbage),temp.end());
sentenceMap[temp]++;
//...
}
That code alone does everything your original code did -- keep track of the strings, bumps up the word count, removes the junk characters from the word before being processed, etc. But best of all, no manual memory management. No calls to new[], delete[], nothing. The code just "works". That is effectively 5 lines of code that you would just need to write a "read" loop around.
I won't go through every detail, you can do that for yourself since the code is small, and there are vast amounts of resources available explaining std::map, remove_if(), etc.
Then printing out is merely going through the map and printing each entry (string and count). If you add the printing, that may be 4 lines of extra code. So in all, practically all of the assignment is done with effectively 10 or so lines of code.
Remove below code.
for(int i = 0; i < new_numwords; i++)
{
delete [] New_SentenceArry[i];
}
I am having a problem with my palindrome program. I am required to use arrays and show how a push and pop would work without .push or .pop. The trouble I am having is when I enter a 3 letter word it will say yes it is a palindrome but if I enter a word that is 4 or more characters it will say not a palindrome even if it is. ex. kayak. Dont see where I am going wrong.
#include <iostream>
#include <string>
using namespace std;
int main()
{
char original[13];
int stkptr=-1;
int x = strlen(original)-1;
cout <<"Enter a character"<<endl;
for( ++stkptr ; stkptr<13;stkptr++)
//store user input into the array
{
cin>>original[stkptr];
if(original[stkptr]=='0')
break;
cout<<original[stkptr]<<" Stack pointer is: "<<stkptr<<endl;
}
//POP
for (--stkptr; stkptr>=0;stkptr--)
cout<<original[stkptr]<<" Stack pointer is: "<<stkptr<<endl;
for(int i = 0; i <= x; i++)
{
if (original[i] == original[x-i])
{
continue;
}
else
{
cout<<"\nNot a palidrome\n"<<endl;
system("pause");
return 0;
}
}
cout << "\nIndeed Palidrome\n"<<endl;
system("pause");
return 0;
}
Though you overly complicated the logic, I will tell what is wrong the current code.
you are going wrong with x. You initialize it to string length when there is no "string" (Also, your char array should have a \0 at the end for strlen() to work). Assign stkptr-1 to x before pop and remove pop.
And in your loop you should iterate only till half of the array, since you are comparing char-by-char from begin and end
for(int i = 0; i <= x/2; i++)
bool checkIsPalindrome(string s){
int nLength = s.length();
string s1, s2;
if(nLength & 1) // is Odd
nLength--;
nLength = nLength/2;
//take the first half
s1 = s.substr(0,nLength);
//pop off the last half of characters into the string
for(int i = s.length()-1; i > nLength; i--)
s2+= s.at(i);
if(s1 == s2)
return true;
else
return false;
}