How to regex last part of URL only? - regex

I want to do a regex that target the end of a url:
www.company.com/orders/thanks
If you return from email or account page order ID is populated in the end:
www.company.com/orders/thanks/1sfasd523425
So I only want to target the URL that ends with /thanks
This thread bring is similiar: How do I get the last segment of URL using regular expressions
Had something similair .*\/thanks\/.+ but target incorrectly.
EDIT: Only target URLs ending with /thanks or /thanks/


Try with lookahead like this.
Regex: .+(?=\/thanks$).+
Explanation: This will match the URL only if thanks is at end of string by positive lookahead.
Regex101 Demo


Use URL object dont parse it yourself
URL url = new URL("http://stackoverflow.com/questions/36616915/how-to-regex-last-part-of-url-only");
URLDecoder.decode(url.getPath(), "utf-8");
url.getPath();
url.getContent();
url.getPort();
url.getContent();

Related

regex extract username from 2 types of url

I'm currently using this regex (?<=\/movie\/)[^\/]+, but it only matches the username from the second url, i know i could make a if (contains /movie/): use this regex, else: use another regex on my code, but i'm trying to do this directly on regex.
http://example.com:80/username/token/30000
http://example.com:80/movie/username/token/30000.mp4

To complete the Tensibai's answer, if you have not a port in url, you can use the last dot in url to start your regex :
\.[^\/\.]+\/(?:movie\/)?([^\/]+)
(demo)

You can use something like this to make the movie/ optional and have the username in a named capture group (Live exemple):
\d[/](?:movie\/)?(?<username>[^/]+)[/]
using \d/ to anchor the start of match at after the url.

Regex for Affiliate URL

For Matomo outgoing link tracking I need the regex pattern, which matched the following URLs:
https://www.example.com/product/?sku=12345&utm_source=123456789
and
https://www.example.com/product/?utm_source=123456789
"https://www.example.com/" and "utm_source=123456789" are always fixed in the URL, just "product/" or "category/product/" change and must replaced by regex pattern.
Thanks

Maybe this example can help you reach your goal:
(?<=https:\/\/www\.example\.com\/).+(?=utm_source=123456789)
It looks for any characters between these two groups:
https://www.example.com/
utm_source=123456789
Given the examples:
https://www.example.com/product/?sku=12345&utm_source=123456789
https://www.example.com/product/?utm_source=123456789
Your matches would be:
product/?sku=12345&
product/?

Conditional Regex to match url

I am trying to make a if/then condition to match the url, but I can't seem to get it to work. I am trying to match URLs and then capture the non-optional group. So - if a url comes in like this:
/en/testing.aspx
I want to capture /testing.aspx
if the url comes in like this:
/testing.aspx
I want to capture /testing.aspx
Is there an easy way to do this using regex?
EDIT:
The Url can be multi-part url, like /en/sub1/sub2/testing.aspx - I essentially want everything after "/en/".

use regex \/en(\/.+)$
Check this out
edited
https://regex101.com/r/lwowhi/6
If there is "/en/" in the URL and you still want to capture /testing.aspx then here is an edit (?:\/en)*(\/.+)$
https://regex101.com/r/lwowhi/8

You can use a greedy regex which will consume everything up until the final forward slash. Then, capture everything which comes after that point.
^.*?(?:\/en)?(\/.*)$
Demo

Guessing all pages are .aspx then use group.
regex: .(/..aspx)
this will match "/testing.aspx" in all bellow samples
/testing.aspx or
/en/testing.aspx or
www.abc.com/en-us/testing.aspx

RegExp matching url

I have the current url:
ristoranti/location/latvia/riga/other-tag
I need a regexp that do not get the url if has the location segment
Here what I tried:
ristoranti/(?!location$).*)?(.+?)/(.+?)
Example url I need to get:
ristoranti/latvia/riga/other-tag
I'm not so good with regexp but if I'm right the first segment shoulg get all but location, am I wrong?

Problem is presence of $ in your negative lookahead that will fail to stop ristoranti/location/latvia/riga/other-tag from matching because your URL is not really ending with location. You should replace it by
(?!location/)
which will fail the match when URL has location/ ahead.
Also use ^ at the start. So your final regex should be:
^ristoranti/(?!location/)([^/]*)/([^/]*)/(.*)
RegEx Demo

Extract last part of url without query string or jsessionid

I want a regex that will always return the last part of an url before the query string parameters and without the jessionid if present.
Here's some url examples:
http://www.somesite.com/some/path/test.action;jsessionid=000063vCmvJAn7VWyymA_dPsHZs:16u9pglit?sort=2&param1=1&param2=2
http://www.somesite.com/some/path/test;jsessionid=000063vCmvJAn7VWyymA_dPsHZs:16u9pglit?sort=2&param1=1&param2=2
http://www.somesite.com/some/path/test.action?sort=2&param1=1&param2=2
http://www.somesite.com/some/path/test?sort=2&param1=1&param2=2
Here's my regex so far:
.*http://.*/some/path.*/(.*);?.*\?.*
It is working for the url that does not contain jsessionid, but will return test;jessionid=... if it is present.
To test: http://regex101.com/r/fM0mE2

I would use this regex:
.*http:\/\/.*\/some\/path.*\/([^;\?]+);?.*\?.*
^^^^^^
Basically matches anything that isn't ; or ?. And I think it might be shortened to:
.*http:\/\/.*\/some\/path.*\/([^;\?]+)