I am trying to merge below four pattern into single pattern using pipe(|), but not getting the required result.
Scenario:
max 7 entry(alphabet and digits)
should contain 4 and only 4 consecutive digits(mandatory)
Patterns:
([\d]{4}[a-zA-Z]{0,3})
[a-zA-Z]{0,1}[\d]{4}[a-zA-Z]{0,2}
[a-zA-Z]{0,2}[\d]{4}[a-zA-Z]{0,1}
[a-zA-Z]{0,3}[\d]{4})
You can use
^(?=[a-zA-Z\d]{4,7}$)[a-zA-Z]*\d{4}[a-zA-Z]*$
See the regex demo
If you are using the regex pattern in a method that anchors the pattern by default, the ^ and/or $ might be redundant, but will still work.
The regex breakdown:
^ - start of string
(?=[a-zA-Z\d]{4,7}$) - the positive lookahead requiring the string to only consist of 4 to 7 letters or digits
[a-zA-Z]*\d{4}[a-zA-Z]* - the string should contain 4 digits (\d{4}`) that can be preceded or followed with zero or more letters
$ - end of string.
Related
I need to build a regex that have the following:
Rules to be applied:
exactly 14 characters
only letters (latin characters) and numbers
at least 3 letters
Regex still confuses me so I am struggling to get the correct output. I want to use it with swift and swiftui in an app I am making
(?=(.*[a-zA-Z]){3,}([0-9]){0,}){14,14}$
I tried this. But I know it is not the way
I would use a positive lookahead for the length requirement:
^(?=.{14}$)(?:[A-Za-z0-9]*[A-Za-z]){3}[A-Za-z0-9]*$
This pattern says to match:
^ from the start of the input
(?=.{14}$) assert exact length of 14
(?:
[A-Za-z0-9]*[A-Za-z] zero or more alphanumeric followed by one alpha
)
[A-Za-z0-9]* any alphanumeric zero or more times
$ end of the input
You need to use
^(?=(?:[0-9]*[a-zA-Z]){3})[a-zA-Z0-9]{14}$
Details
^ - start of string
(?=(?:[0-9]*[a-zA-Z]){3}) - at least three repeations of a letter after any zero or more digits sequence required
[a-zA-Z0-9]{14} - fourteen letters/digits
$ - end of string.
See the regex demo.
I would like to have an expression to validate the plates of monaco.
They are written as follows:
A123
123A
1234
I started by doing:
^[a-zA-Z0-9]{1}?[0-9]{2}?[a-zA-Z0-9]{1}$
But the case A12A which is false is possible with that.
You can use
^(?!(?:\d*[a-zA-Z]){2})[a-zA-Z\d]{4}$
See the regex demo. Details:
^ - start of string
(?!(?:\d*[a-zA-Z]){2}) - a negative lookahead that fails the match if there are two occurrences of any zero or more digits followed with two ASCII letters immediately to the right of the current location
[a-zA-Z\d]{4} - four alphanumeric chars
$ - end of string.
You can write the pattern using 3 alternatives specifying all the allowed variations for the example data:
^(?:[a-zA-Z][0-9]{3}|[0-9]{3}[a-zA-Z]|[0-9]{4})$
See a regex demo.
Note that you can omit {1} and
To not match 2 chars A-Z you can write the alternation as:
^(?:[a-zA-Z]\d{3}|\d{3}[a-zA-Z\d]|\d[a-zA-Z\d][a-zA-Z\d]\d)$
See another regex demo.
So it needs 3 connected digits and 1 letter or digit.
Then you can use this pattern :
^(?=.?[0-9]{3})[A-Za-z0-9]{4}$
The lookahead (?=.?[0-9]{3}) asserts the 3 connected digits.
Test on Regex101 here
I created a Regex to check a string for the following situation:
first 4 chars are numbers
following by a point
following by 3 numbers
following by a point
following by 4 to 8 numbers or letters
ie: 1234.123.125B
My Regex: ^[0-9]{4}[.][0-9]{3}[.][0-9a-zA-Z]{4,8}$
But now I need a wildcard search: The Regex should also match if there is a '*' after the first 8 characters. For example:
1234.123.12* MATCH
1234.123* MATCH
1234.123.45B9* MATCH
1234.12* NO MATCH
1234.12345* NO MATCH
How can I add the wildcard search to my Regex?
Thank you
You may use this regex with alternation:
^\d{4}\.\d{3}(?:\*|\.[\da-zA-Z]{0,7}\*|\.[\da-zA-Z]{4,8})$
RegEx Demo
RegEx Details:
^: Start
\d{4}\.\d{3}: Match 4 digits + 1 dot + 3 digits
(?:\*|\.[\da-zA-Z]{0,7}\*|\.[\da-zA-Z]{4,8}): matches a single * OR a * after after a dot and 0 to 7 digits/letters OR match 4 to 8 digits/letters
$: End
My assumptions are that:
You don't allow wildcards to be mid-string
Nor do you want to allow wildcards after the full pattern (e.g.: 1234.123.12345678*).
So, alternatively you may possibily use something like:
^\d{4}\.\d{3}(?!.*\*.)(?![^*]{0,4}$)[.*][*\da-zA-Z]{0,8}$
See the online demo.
^ - Start string ancor.
\d{4}\.\d{3} - Four digits, a dot and another three digits.
(?!.*\*.) - Negative lookahead for zero or more characters followed by asterisk and another character other than newline.
(?![^*]{0,4}$) - Negative lookahead for zero to four characters other than asterisk before end string ancor.
[.*] - A literal dot or asterisk.
[*\da-zA-Z]{0,8} - Zero to eight characters from the character class.
$ - End string ancor.
I have a dozen input ID's and I need to match only two particular patterns while ignoring the rest. I have a column that would flag those valid/invalid if the regex match is true.
Test string:
1.) B-123456
2.) 985463728
My regex should strictly match the above two patterns and ignore the rest. The first test string would have an alphabet B followed by a hyphen and then few digits while the second test string is purely numbers. Below is what I tried:
[Bb\d][-\d][0-9]{1,9}
Please help me out with this as I have tried weird combinations and I am missing out on something tiny. My regex includes other combinations as well which should not happen.
You could match either bB a - and 6 digits, or match 9 digits surrounded by word boundaries:
\b(?:[Bb]-[0-9]{6}|[0-9]{9})\b
Regex demo
If the number of digits can vary, you could make the bB and the hyphen optional and either match 1+ digits using [0-9]+ or use a quantifier [0-9]{1,9}
\b(?:[bB]-)?[0-9]+\b
Or use anchors to assert the start ^ and the end $ of the string
^(?:[bB]-)?[0-9]+$
I'm having issues with the validation of the chilean RUT/RUN with a regex expression in PCRE. I have the next regular expression but sadly can't make it work:
\b[0-9|.]{1,10}\-[K|k|0-9]
I need help to see what is wrong with the code. The application I need to use only uses PCRE.
Thank you.
You may use
^(\d{1,3}(?:\.\d{1,3}){2}-[\dkK])$
to match and capture (that is not usually necessary, but your app requires a capturing group to extract its contents) a whole string that matches the pattern. See the regex demo.
To match shorter strings that match this pattern inside a larger string, you may remove ^ and $ (see demo) or use \b word boundaries instead (see this demo).
Details:
^ - start of string
\d{1,3} - 1 to 3 digits
(?:\.\d{1,3}){2} - 2 sequences of a literal . and 1 to 3 digits
- - a hyphen
[\dkK] - a digit, k or K.
$ - end of string.
As they sometimes omit the dots, I used this one:
^(\d{1,2}(?:[\.]?\d{3}){2}-[\dkK])$
Details:
^ - start of string
\d{1,2} - 1 or 2 digits
(?:[.]?\d{3}){2} - 2 sequences of an optional '.' and 3 digits
- a hyphen
[\dkK] - a digit, k or K
$ - end of string
1234567-k OK
12345678-k OK
1.234.567-k OK
12.345.678-k OK
known issue:
12.345678-k and 12345.678-k still OK and I do not like this :(
You need to change to ^(\d{1,3}(?:\.\d{3}){2}-[\dkK])$ to capture only 2 sequence of 3 digits after the first sequence of 1-3 digits.
please consider being more specific in the REGEX build, since it matched wrong numbers, such as 17.87.335-2. Also the included one did't match formats without the dots or the hyphens.
Please consider using the following format: \b(\d{1,3}(?:(.?)\d{3}){2}(-?)[\dkK])\b
Modified prior version to try the other formats: https://regex101.com/r/2Us0j6/9