How to predict a single new sample after dict-vectorization in python scikit-learn? - python-2.7

Question

I am using logistic regression classifier to predict ethnicity class label 0, 1. My data is split into testing and training sample and got dict-vectorized into sparse matrix.
The following is the working codes, where I predict and validate X_train and X_test which are part of the features that got vectorized:
for i in mass[k]:
df = df_temp # reset df before each loop
#$$
if 1==1:
count+=1
ethnicity_tar = str(i)
############################################
############################################
def ethnicity_target(row):
try:
if row[ethnicity_var] == ethnicity_tar:
return 1
else:
return 0
except: return None
df['ethnicity_scan'] = df.apply(ethnicity_target, axis=1)
print '1=', ethnicity_tar
print '0=', 'non-'+ethnicity_tar
# Random sampling a smaller dataframe for debugging
rows = df.sample(n=subsample_size, random_state=seed) # Seed gives fixed randomness
df = DataFrame(rows)
print 'Class count:'
print df['ethnicity_scan'].value_counts()
# Assign X and y variables
X = df.raw_name.values
X2 = df.name.values
X3 = df.gender.values
X4 = df.location.values
y = df.ethnicity_scan.values
# Feature extraction functions
def feature_full_name(nameString):
try:
full_name = nameString
if len(full_name) > 1: # not accept name with only 1 character
return full_name
else: return '?'
except: return '?'
def feature_full_last_name(nameString):
try:
last_name = nameString.rsplit(None, 1)[-1]
if len(last_name) > 1: # not accept name with only 1 character
return last_name
else: return '?'
except: return '?'
def feature_full_first_name(nameString):
try:
first_name = nameString.rsplit(' ', 1)[0]
if len(first_name) > 1: # not accept name with only 1 character
return first_name
else: return '?'
except: return '?'
# Transform format of X variables, and spit out a numpy array for all features
my_dict = [{'last-name': feature_full_last_name(i)} for i in X]
my_dict5 = [{'first-name': feature_full_first_name(i)} for i in X]
all_dict = []
for i in range(0, len(my_dict)):
temp_dict = dict(
my_dict[i].items() + my_dict5[i].items()
)
all_dict.append(temp_dict)
newX = dv.fit_transform(all_dict)
# Separate the training and testing data sets
X_train, X_test, y_train, y_test = cross_validation.train_test_split(newX, y, test_size=testTrainSplit)
# Fitting X and y into model, using training data
classifierUsed2.fit(X_train, y_train)
# Making predictions using trained data
y_train_predictions = classifierUsed2.predict(X_train)
y_test_predictions = classifierUsed2.predict(X_test)
However, I would like to predict just a single name for example "John Carter" and predict the ethnicity label. I replaced the y_train_predictions = classifierUsed2.predict(X_train) and y_train_predictions = classifierUsed2.predict(X_train) with the following line but resulting in error:
print classifierUsed2.predict(["John Carter"])
#error
Error: X has 1 features per sample; expecting 103916

Answer 1

You need to transform your data in the exact same way as a training one, thus something like (if your input data was just list of strings)
classifierUsed2.predict(dv.transform(["John Carter"]))