I've to add numbers incrementally in the beginning of every line using Notepad++.
It is the not the very beginning. But, like
when ID = '1' then data
when ID = '2' then data
when ID = '3' then data
.
.
.
.
when ID = '700' then
Is there any way i can increment these numbers by replacing with any expression or is there any inbuilt-notepad functions to do so.
Thanks
If you want to do this with notepad++ you can do it in the following way.
First you can write all the 700 lines with template text (you can use a Macro or use the Edit -> Column Editor). Once you have written it, put the cursor on the place you want the number, click Shift+Alt and select all the lines:
It's not possible to accomplish this with a regular expression, as you will need to have a counter and make arithmetic operations (such as incrementing by one).
You can try the cc.p command of ConyEdit. It is a cross-editor plugin for the text editors, of course including Notepad++.
With ConyEdit running, copy the text and the command line below, then paste:
when ID = '#1' then data
cc.p 700
Gif example
Related
I have a text in cell (A1) like this:
✌😋👅👅☝️😉🍌🍪💧💧
I want to extract the unique emojis from this cell into separate cells:
✌😋👅☝️😉🍌🍪💧
Is this possible?
You want to put each character of ✌😋👅👅☝️😉🍌🍪💧💧 to each cell by splitting using the built-in function of Google Spreadsheet.
Sample formula:
=SPLIT(REGEXREPLACE(A1,"(.)","$1#"),"#")
✌😋👅👅☝️😉🍌🍪💧💧 is put in a cell "A1".
Using REGEXREPLACE, # is put to between each character like ✌#😋#👅#👅#☝#️#😉#🍌#🍪#💧#💧#.
Using SPLIT, the value is splitted with #.
Result:
Note:
In your question, the value of ️ which cannot be displayed is included. It's \ufe0f. So "G1" can be seen like no value. But the value is existing. So please be careful this. If you want to remove the value, you can use ✌😋👅👅☝😉🍌🍪💧💧.
References:
REGEXREPLACE
SPLIT
Added:
From marikamitsos's comment, I could notice that my understanding was not correct. So the final result is as follows. This is from marikamitsos.
=TRANSPOSE(UNIQUE(TRANSPOSE(SPLIT(REGEXREPLACE(A1,"(.)","$1#"),"#"))))
or try:
=TRANSPOSE(UNIQUE(TRANSPOSE(REGEXEXTRACT(A1, REPT("(.)", LEN(A1))))))
Formula
Appears, one of the best formula solutions would be:
=SPLIT(REGEXREPLACE(A1,"(.)","$1#"),"#")
You may also add some additional checks like skin tones & intermediate chars:
=TRANSPOSE(SPLIT(REGEXREPLACE(A2,"(.[🏻🏼🏽🏾🏿"&CHAR(8205)&CHAR(65039)&"]*)","#$1"),"#"))
It will help to join some emojis as a single emoji.
Script
More precise way is to use the script:
https://github.com/orling/grapheme-splitter/blob/master/index.js
↑
Add the code to Script editor
Add code for sample usage:
function splitEmojis(string) {
var splitter = new GraphemeSplitter();
// split the string to an array of grapheme clusters (one string each)
var graphemes = splitter.splitGraphemes(string);
return graphemes;
}
Tests
Not 100% precise
1
Please note: some emojis are not correctly shown in sheets
🏴🏴🏴🏴
↑ emojis:
flag: England
flag: Scotland
flag: Wales
black flag
are the same for Google Sheets.
2
Vlookup function in #GoogleSheets and in #Excel thinks chars
#️⃣ and
*️⃣
are the same!
How can I extract the text up to the 4th instance of a character in a column?
I'm selecting text out of a column called filter_type up to the fourth > character.
To accomplish this, I've been trying to find the position of the fourth > character, but it's not working:
select substring(filter_type from 1 for position('>' in filter_type))
You can use the pattern matching function in Postgres.
First figure out a pattern to capture everything up to the fourth > character.
To start your pattern you should create a sub-group that captures non > characters, and one > character:
([^>]*>)
Then capture that four times to get to the fourth instance of >
([^>]*>){4}
Then, you will need to wrap that in a group so that the match brings back all four instances:
(([^>]*>){4})
and put a start of string symbol for good measure to make sure it only matches from the beginning of the String (not in the middle):
^(([^>]*>){4})
Here's a working regex101 example of that!
Once you have the pattern that will return what you want in the first group element (which you can tell at the online regex on the right side panel), you need to select it back in the SQL.
In Postgres, the substring function has an option to use a regex pattern to extract text out of the input using a 'from' statement in the substring.
To finish, put it all together!
select substring(filter_type from '^(([^>]*>){4})')
from filter_table
See a working sqlfiddle here
If you want to match the entire string whenever there are less than four instances of >, use this regular expression:
^(([^>]*>){4}|.*)
You can also use a simple, non-regex solution:
SELECT array_to_string((string_to_array(filter_type, '>'))[1:4], '>')
The above query:
splits your string into an array, using '>' as delimeter
selects only the first 4 elements
transforms the array back to a string
substring(filter_type from '^(([^>]*>){4})')
This form of substring lets you extract the portion of a string that matches a regex pattern.
You can also split the string, then choose the N'th element inside the result list. For example:
SELECT SPLIT_PART('aa,bb,cc', ',', 2)
will return: bb.
This function is defined as:
SPLIT_PART(string, delimiter, position)
In order to look at this problem, I did the following (all of the code below is available on the fiddle here):
CREATE TABLE s
(
a TEXT
);
I then created a PL/pgSQL function to generate random strings as follows.
CREATE FUNCTION f() RETURNS TEXT LANGUAGE SQL AS
$$
SELECT STRING_AGG(SUBSTR('abcdef>', CEIL(RANDOM() * 7)::INTEGER, 1), '')
FROM GENERATE_SERIES(1, 40)
$$;
I got the code from here and modified it so that it would produce strings with lots of > characters for testing purposes.
I then manually inserted a few strings at the beginning so that a quick look would tell me if the code was working as anticipated.
INSERT INTO s VALUES
('afsad>adfsaf>asfasf>afasdX>asdffs>asfdf>'),
('23433>433453>4>4559>455>3433>'),
('adfd>adafs>afadsf>'), -- only 3 '>'s!
('babedacfab>feaefbf>fedabbcbbcdcfefefcfcd'),
('e>>>>>'), -- edge case - multiple terminal '>'s
('aaaaaaa'); -- edge case - no '>'s whatsoever
The reason I put in the records with fewer than 4 >s is because the accepted answer (see discussion at the end of this answer) puts forward a solution which should return the entire string if this is the case!
On the fiddle, I then added 50,000 records as follows:
INSERT INTO s
SELECT f() FROM GENERATE_SERIES(1, 50000);
I also created a table s on a home laptop (16GB RAM, 500MB NVMe SSD) and populated it with 40,000,000 (50M) records - times also shown.
Now, my reading of the question is that we need to extract the string up to but not including the 4th > character.
The first solution (from treecon) was this one (I also show them running on the fiddle, but to save space here, I've only included the partial output of EXPLAIN (ANALYZE, BUFFERS, VERBOSE)) - the times shown are typical over a few runs:
EXPLAIN (ANALYZE, BUFFERS, VERBOSE)
SELECT
ARRAY_TO_STRING((STRING_TO_ARRAY(a, '>'))[1:4], '>'),
a
FROM s;
Result (only key parts included):
Seq Scan on public.s
Execution Time: 81.807 ms
40M Time: 46 seconds
A regex solution which works (significantly faster):
EXPLAIN (ANALYZE, BUFFERS, VERBOSE)
SELECT
SUBSTRING(a FROM '^(?:[^>]*>){0,3}[^>]*'),
a
FROM s;
Result:
Seq Scan on public.s
Execution Time: 74.757 ms
40M Time: 32 seconds
The accepted answer fails on many levels (see the fiddle). It leaves a > at the end and fails on various strings even when modified. Also, the solution proposed to include strings with fewer than 4 >s (i.e. ^(([^>]*>){4}|.*)) merely returns the original string (see end of fiddle).
I have a text file that looks like the following:
Chanelle
Jettie
Winnie
Jen
Shella
Krysta
Tish
Monika
Lynwood
Danae
2649
2466
2890
2224
2829
2427
2816
2648
2833
2453
I need to make it look like this
Chanelle 2649
Jettie 2466
... ...
I tried a lot on sublime editor but couldn't figure out the regex to do that. Can somebody demonstrate if it can be done.
I tested the following in Notepad++ but it should work universally.
Use this as the search string:
(?:(\s+[A-Za-z]+)(\r?\n))((?:\s*[A-Za-z]*\r?\n)+)\s+(\d+)
and this as the replacement:
$1 $4$2$3
Running a replace with it once will do one line at a time, if you run it multiple times it'll continue to replace lines until there are no matching lines left.
Alternatively, you can use this as the replacement if you want to have the values aligned by tabs, but it's not going to match in all cases:
$1\t\t$4$2$3
While the regex answer by SeinopSys will work, you don't need a regex to do this - instead, you can take advantage of Sublime's multiple cursors.
Place your cursor at the beginning of line 1, then hold down Shift↓ to select all the names.
Hit CtrlShiftL (Selection -> Split into Lines) to split the selection into lines.
CtrlC to copy.
Place your cursor on line 11 (the first number line) and press CtrlShift↓ (Windows/OS X) or AltShift↓ (Linux) to place a cursor at the beginning of each number line.
Hit CtrlV to paste the names before the numbers.
You can now delete the names at the top and you're all set. Alternatively, you could use CtrlX to cut the names in step 3.
How can I use regular expression in excel ?
In above image I have column A and B. I have some values in column A. Here I need to move data after = in column B. For e.g. here in 1st row I have SELECT=Hello World. Here I want to remove = sign and move Hello world in column B. How can I do such thing?
Stackoverflow has many posts about adding regular expressions to Excel using VBA. For your particular example, you would need VBA to actually move a substring from one cell to another.
If you simply want to copy the substring, you can do so easily using the MID function:
=IFERROR(MID(A1,FIND("=",A1)+1,999),A1)
I used 999 to ensure that enough characters were grabbed.
IFERROR returns the cell as-is if an equals sign is not found.
To return the portion of string before the equals sign, do this:
=LEFT(A1,FIND("=",A1&"=")-1)
In this case, I appended the equals sign to A1, so FIND won't return an error if not found.
You can use the Text to Column functionality of MS-Excel giving '=' as delimiter.
Refer to this link:
Chop text in column to 60 charactersblocks
You can simply use Text to Column feature of excel for this:
Follow the below steps :
1) Select Column A.
2) Goto Data Tab in Menu Bar.
3) Click Text to Column icon.
4) Choose Delimited option and do Next and then check the Other options in delimiter and enter '=' in the entry box.
5) Just click finish.
Here are URL for Text to Column : http://www.excel-easy.com/examples/text-to-columns.html
I've to add numbers incrementally in the beginning of every line using Notepad++.
It is the not the very beginning. But, like
when ID = '1' then data
when ID = '2' then data
when ID = '3' then data
.
.
.
.
when ID = '700' then
Is there any way i can increment these numbers by replacing with any expression or is there any inbuilt-notepad functions to do so.
Thanks
If you want to do this with notepad++ you can do it in the following way.
First you can write all the 700 lines with template text (you can use a Macro or use the Edit -> Column Editor). Once you have written it, put the cursor on the place you want the number, click Shift+Alt and select all the lines:
It's not possible to accomplish this with a regular expression, as you will need to have a counter and make arithmetic operations (such as incrementing by one).
You can try the cc.p command of ConyEdit. It is a cross-editor plugin for the text editors, of course including Notepad++.
With ConyEdit running, copy the text and the command line below, then paste:
when ID = '#1' then data
cc.p 700
Gif example