CreateProcess won't start the proccess with arguments - c++

Question

So I used this code in order to start a console application with arguments:
#include <iostream>
#include <windows.h>
using namespace std;
void StartProgram(char argv[])
{
STARTUPINFO si;
PROCESS_INFORMATION pi;
ZeroMemory(&si, sizeof(si));
si.cb = sizeof(si);
ZeroMemory(&pi, sizeof(pi));
CreateProcess
(
TEXT("PlayerDebug.exe"),
(LPSTR)argv,
NULL,NULL,FALSE,
CREATE_NEW_PROCESS_GROUP | CREATE_NO_WINDOW,
NULL,NULL,
&si, &pi
);
};
int main()
{
StartProgram("sound.wav");
return 0;
}
"PlayerDebug.exe" display the arguments used to call it. But when I run it with CreateProcess the way I showed, it doesen't display anything. I checked and in Task Manager it seems to appear, but still does not display the arguments. I also tried to write cout << argv; in function void StartProgram(char argv[]) and it returned "sound.wav", which is correct. But it seems the argument is not passed to PlayerDebug.exe and I don't know why.
What I did wrong?
(I'm new at C++ programming)

Answer 1

The second parameter to CreateProcess is the full command line, not just the parameters to the EXE. Lets take two examples :
CreateProcess ("c:\\notepad.exe",
"c:\\notepad.exe c:\\wibble.txt",
...);
will work fine (if there is a copy of notepad.exe and a file called wibble.txt in the root of C:), whereas
CreateProcess ("c:\\notepad.exe",
"c:\\wibble.txt",
...);
will launch the EXE but fail to open the file. What this means is that when the help systems calls the second parameter the command line, it ain't lying - it wants the whole command line.
Note that you can use NULL as the first parameter if the whole command line is in the second param. That's how I normally use it in fact.