I have written the following function in google sheets in order to add "ID" to a column:
=if(and(E2>43%, E2<57%, C2=2016), "ID", " ")
I would like to add another logical operator, OR, to this. I would like to add "ID" if the following conditions are met, OR if the conditions above are met:
E2 >57%, C2=2016, J2=""
Column J has names written in it. What I'm trying to say with J2="" is that the space is not blank. I don't care about what the name is, just that there is text written. I wrote this but it doesn't work:
=if(or(and(E2>43%, E2<57%, C2=2016),AND(E2>57%, C2=2016, J2=""), "ID", " "))
Thanks for your help!
Try this one:
=IF(or(and(B1>43%, B1<57%, A1=2016),and(B1 >57%, A1=2016,istext(E1))), "ID",)
Related
How can I remove a large number of columns by name based on a pattern?
A data set exported from Jira has a ton of extra columns that I've no interest in. 400 Log entries, 50 Comments, dozens of links or attachments. Problem is that they get random numbers assigned which means that removing them with hardcoded column names will not work. That would look like this and break as the numbers change:
= Table.RemoveColumns(#"Previous Step",{"Watchers", "Watchers_10", "Watchers_11", "Watchers_12", "Watchers_13", "Watchers_14", "Watchers_15", "Watchers_16", "Watchers_17", "Watchers_18", "Watchers_19", "Watchers_20", "Watchers_21", "Watchers_22", "Watchers_23", "Watchers_24", "Watchers_25", "Watchers_26", "Watchers_27", "Watchers_28", "Log Work", "Log Work_29", "Log Work_30", "Log Work_31", "Log Work_32", ...
How can I remove a large number of columns by using a pattern in the name? i.e. remove all "Log Work" columns.
The best way I've found is to use List.FindText on Table.ColumnNames to get a list of column names dynamically based on target string:
= Table.RemoveColumns(#"Previous Step", List.FindText(Table.ColumnNames(#"Previous Step"), "Log Work")
This works by first grabbing the full list of Column Names and keeping only the ones that match the search string. That's then sent to RemoveColumns as normal.
Limitation appears to be that FindText doesn't offer complex pattern matching.
Of course, when you want to remove a lot of different patterns, having individual steps isn't very interesting. A way to combine this is to use List.Combine to join the resulting column names together.
That becomes:
= Table.RemoveColumns(L, List.Combine({ List.FindText(Table.ColumnNames(L), "Watchers_"), List.FindText(Table.ColumnNames(L), "Log Work"), List.FindText(Table.ColumnNames(L), "Comment"), List.FindText(Table.ColumnNames(L), "issue link"), List.FindText(Table.ColumnNames(L), "Attachment")} ))
SO what's actually written there is:
Table.RemoveColumns(PreviousStep, List.Combine({ foundList1, foundlist2, ... }))
Note the { } that signifies a list! You need to use this as List.Combine only accepts a single argument which is itself already a List of lists. And the Combine call is required here.
Also note the L here instead of #"Previous Step". That's used to make the entire thing more readable. Achieved by inserting a step named "L" that just has = #"Promoted Headers".
This allows relatively maintainable removal of multiple columns by name, but it's far from perfect.
IDENTIFIER
31-03-2022_13636075
01-04-2022_13650262
04-04-2022_13663174
05-04-2022_13672025
20220099001
11614491_R
10781198
00000000000
11283627_P
11614491_R
-1
how can i remove (only) the "XX-XX-XXXXX_" Part in certain values of a column in SSIS but WITHOUT affecting values that doesn't have this format? For example "21-05-2022_12345678" = "12345678" but the other values i don't want them affected. This are just examples of many rows from this column so i want only the ones that have this format to be affected.
SELECT REVERSE(substring(REVERSE('09-03-2022_13481330'),0,CHARINDEX('_',REVERSE('09-03-2022_13481330'),0)))
result
13481330
but this also affects others values.Also this is in ssms not ssis because i am not sure how to transform this expression in ssis code.
Update : Corrected code in SSIS goes as following:
(FINDSTRING(IDENTIFIER,"__-__-____[_]",1) == 1) ? SUBSTRING(IIDENTIFIER,12,LEN(IDENTIFIER) - 11) : IDENTIFIER
Do you have access to the SQL source? You can do this on the sql by using a LIKE and crafting a match pattern using the single char wildcard _ please see below example
DECLARE #Value VARCHAR(50) = '09-03-2022_13481330'
SELECT CASE WHEN #Value LIKE '__-__-____[_]%' THEN
SUBSTRING(#Value,12,LEN(#Value)-11) ELSE #Value END
Please see the Microsoft Documentation on LIKE and using single char wildcards
If you don't have access to the source SQL it gets a bit more tricky as you might need to use regex in a script task or maybe there is a expression you can apply
Goal: I have a bunch of keywords I'd like to categorise automatically based on topic parameters I set. Categories that match must be in the same column so the keyword data can be filtered.
e.g. If I have "Puppies" as a first topic, it shouldn't appear as a secondary or third topic otherwise the data cannot be filtered as needed.
Example Data: https://docs.google.com/spreadsheets/d/1TWYepApOtWDlwoTP8zkaflD7AoxD_LZ4PxssSpFlrWQ/edit?usp=sharing
Video: https://drive.google.com/file/d/11T5hhyestKRY4GpuwC7RF6tx-xQudNok/view?usp=sharing
Parameters Tab: I will add words in columns D-F that change based on the keyword data set and there will often be hundreds, if not thousands, of options for larger data sets.
Categories Tab: I'd like to have a formula or script that goes down the columns D-F in Parameters and fills in a corresponding value (in Categories! columns D-F respectively) based on partial match with column B or C (makes no difference to me if there's a delimiter like a space or not. Final data sheet should only have one of these columns though).
Things I've Tried:
I've tried a bunch of things. Nested IF formula with regexmatch works but seems clunky.
e.g. this formula in Categories! column D
=IF(REGEXMATCH($B2,LOWER(Parameters!$D$3)),Parameters!$D$3,IF(REGEXMATCH($B2,LOWER(Parameters!$D$4)),Parameters!$D$4,""))
I nested more statements changing out to the next cell in Parameters!D column (as in , manually adding $D$5, $D$6 etc) but this seems inefficient for a list thousands of words long. e.g. third topic will get very long once all dog breed types are added.
Any tips?
Functionality I haven't worked out:
if a string in Categories B or C contains more than one topic in the parameters I set out, is there a way I can have the first 2 to show instead of just the first one?
e.g. Cell A14 in Categories, how can I get a formula/automation to add both "Akita" & "German Shepherd" into the third topic? Concatenation with a CHAR(10) to add to new line is ideal format here. There will be other keywords that won't have both in there in which case these values will just show up individually.
Since this data set has a bunch of mixed breeds and all breeds are added as a third topic, it would be great to differentiate interest in mixes vs pure breeds without confusion.
Any ideas will be greatly appreciated! Also, I'm open to variations in layout and functionality of the spreadsheet in case you have a more creative solution. I just care about efficiently automating a tedious task!!
Try using custom function:
To create custom function:
1.Create or open a spreadsheet in Google Sheets.
2.Select the menu item Tools > Script editor.
3.Delete any code in the script editor and copy and paste the code below into the script editor.
4.At the top, click Save save.
To use custom function:
1.Click the cell where you want to use the function.
2.Type an equals sign (=) followed by the function name and any input value — for example, =DOUBLE(A1) — and press Enter.
3.The cell will momentarily display Loading..., then return the result.
Code:
function matchTopic(p, str) {
var params = p.flat(); //Convert 2d array into 1d
var buildRegex = params.map(i => '(' + i + ')').join('|'); //convert array into series of capturing groups. Example (Dog)|(Puppies)
var regex = new RegExp(buildRegex,"gi");
var results = str.match(regex);
if(results){
// The for loops below will convert the first character of each word to Uppercase
for(var i = 0 ; i < results.length ; i++){
var words = results[i].split(" ");
for (let j = 0; j < words.length; j++) {
words[j] = words[j][0].toUpperCase() + words[j].substr(1);
}
results[i] = words.join(" ");
}
return results.join(","); //return with comma separator
}else{
return ""; //return blank if result is null
}
}
Example Usage:
Parameters:
First Topic:
Second Topic:
Third Topic:
Reference:
Custom Functions
I've added a new sheet ("Erik Help") with separate formulas (highlighted in green currently) for each of your keyword columns. They are each essentially the same except for specific column references, so I'll include only the "First Topic" formula here:
=ArrayFormula({"First Topic";IF(A2:A="",,IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) & IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))))})
This formula first creates the header (which can be changed within the formula itself as you like).
The opening IF condition leaves any row in the results column blank if the corresponding cell in Column A of that row is also blank.
JOIN is used to form a concatenated string of all keywords separated by the pipe symbol, which REGEXEXTRACT interprets as OR.
IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) will attempt to extract any of the keywords from each concatenated string in Columns B and C. If none is found, IFERROR will return null.
Then a second-round attempt is made:
& IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>"")))))
Only this time, REGEXREPLACE is used to replace the results of the first round with null, thus eliminating them from being found in round two. This will cause any second listing from the JOIN clause to be found, if one exists. Otherwise, IFERROR again returns null for round two.
CHAR(10) is the new-line character.
I've written each of the three formulas to return up to two results for each keyword column. If that is not your intention for "First Topic" and "Second Topic" (i.e., if you only wanted a maximum of one result for each of those columns), just select and delete the entire round-two portion of the formula shown above from the formula in each of those columns.
I have a column in my table which looks like below.
ResourceIdentifier
------------------
arn:aws:ec2:us-east-1:7XXXXXX1:instance/i-09TYTYTY79716
arn:aws:glue:us-east-1:5XXXXXX85:devEndpoint/etl-endpoint
i-075656565f7fea3
i-02c3434343f22
qa-271111145-us-east-1-raw
prod-95756565631-us-east-1-raw
prod-957454551631-us-east-1-isin-repository
i-02XXXXXXf0
I want a new column called 'Trimmed Resource Identifier' which looks at ResourceIdentifier and if the value starts with "arn", then returns value after last "/", else returns the whole string.
For eg.
arn:aws:ec2:us-east-1:7XXXXXX1:instance/i-09TYTYTY79716 ---> i-09TYTYTY797168
i-02XXXXXXf0 --> i-02XXXXXXf0
How do I do this ? I tried creating a new column called "first 3 letters" by extracting first 3 letters of the ResourceIdentifier column but I am getting stuck at the step of adding conditional column. Please see the image below.
Is there a way I can do all of this in one step using DAX instead of creating a new intermediate column ?
Many Thanks
The GUI is too simple to do exactly what you want but go ahead and use it to create the next step, which we can then modify to work properly.
Filling out the GUI like this
will produce a line of code that looks like this (turn on the Formula Bar under the View tab in the query editor if you don't see this formula).
= Table.AddColumn(#"Name of Previous Step Here", "Custom",
each if Text.StartsWith([ResourceIdentifier], "arn") then "output" else [ResourceIdentifier])
The first three letters bit is already handled with the operator I chose, so all that remains is to change the "output" placeholder to what we actually want. There's a handy Text.AfterDelimiter function we can use for this.
Text.AfterDelimiter([ResourceIdentifier], "/", {0, RelativePosition.FromEnd})
This tells it to take the text after the first / (starting from the end). Replace "output" with this expression and you should be good to go.
For example we have a large database contains lots of oracle packages, and now we want to see where a specific table resists in the source code. The source code is stored in user_source table and our desired table is called 'company'.
Normally, I would like to use:
select * from user_source
where upper(text) like '%COMPANY%'
This will return all words containing 'company', like
121 company cmy
14 company_id, idx_name %% end of coding
453 ;companyname
1253 from db.company.company_id where
989 using company, idx, db_name,
So how to make this result more intelligent using regular expression to parse all the source lines matching a meaningful table name (means a table to the compiler)?
So normally we allow the matched word contains chars like . ; , '' "" but not _
Can anyone make this work?
To find company as a "whole word" with a regular expression:
SELECT * FROM user_source
WHERE REGEXP_LIKE(text, '(^|\s)company(\s|$)', 'i');
The third argument of i makes the REGEXP_LIKE search case-insensitive.
As far as ignoring the characters . ; , '' "", you can use REGEXP_REPLACE to suck them out of the string before doing the comparison:
SELECT * FROM user_source
WHERE REGEXP_LIKE(REGEXP_REPLACE(text, '[.;,''"]'), '(^|\s)company(\s|$)', 'i');
Addendum: The following query will also help locate table references. It won't give the source line, but it's a start:
SELECT *
FROM user_dependencies
WHERE referenced_name = 'COMPANY'
AND referenced_type = 'TABLE';
If you want to identify the objects that refer to your table, you can get that information from the data dictionary:
select *
from all_dependencies
where referenced_owner = 'DB'
and referenced_name = 'COMPANY'
and referenced_type = 'TABLE';
You can't get the individual line numbers from that, but you can then either look at user_source or use a regexp on the specific source code, which woudl at least reduce false positives.
SELECT * FROM user_source
WHERE REGEXP_LIKE(text,'([^_a-z0-9])company([^_a-z0-9])','i')
Thanks #Ed Gibbs, with a little trick this modified answer could be more intelligent.