I've run into a strange behavior with Coldfusion 10- I have a variable named myString, "12600A07xxx".
I want the substrings before and after "A07", so I use "A07" as a list delimiter, and type listFirst(myString, "A07") and listLast(myString, "A07").
For the first, it's stripping out the zeros, and returning "126" when it should be returning "12600". It does the same with ListGetAt(). Why is this happening?
I see - CF is treating "A07" as three different delimiters, "A", "0", and "7", instead of a single delimiter, "A07". And there a couple of ways to deal with this, the simplest being to temporarily substitute "A07" with a single character such as a pipe and use that as the temporary delimiter.
As you already noticed, ColdFusion has many functions with single character delimiters. However, there are also functions that support multi-character delimiters, e.g.
listToArray( list [, delimiters[, includeEmptyFields[, multiCharacterDelimiter]]] ).
Example:
parts = listToArray("12600A07xxx", "A07", false, true);
writeOutput( parts[1] ); // >> 12600
writeOutput( parts[2] ); // >> xxx
On a side note: Are you sure you want to split the input using a specific delimiter? You might be better off using regular expression patterns with this kind of data. Just a guess though.
Another approach could be to use reReplaceNoCase(). Like this:
theString = "12600A07xxx";
prefix = reReplaceNoCase(theString , "A07.*", "");
suffix = reReplaceNoCase(theString , ".*A07", "");
Related
I've been struggling to get all items of below string into an array.
abc,"de,f",hi,"hello","te,st&" items into an array in Typescript.
If any string has comma (,) or ampersand (&) in it,It will be placed in double quotes.
Tried split function but it fails as my strings can have comma as well.
Any help in this regard is highly appreciated.
Thank you.
If you are looking to use a regular expression matching, can you try a different regEx that would match strings inside quotes first, then strings outside quotes, something like (\".+?\")|(^[^\"]+,)|(,[^\"]+,)
I don't know how relevant it would be in case of TypeScript, but I am guessing you'd be able to work something out that takes this Pattern and gives you the matches one by one
First of all, I think that you are making the things more complicated than what they are by implementing the following logic:
has comma (,) or ampersand (&) in it,It will be placed in double quotes.
Instead of doing this that way, you should systematically put your elements inside double quote:
abc,"de,f",hi,"hello","te,st&"
→
"abc","de,f","hi","hello","te,st&"
you will have then the following string to parse.
A regex like this one will do the job:
(?<=,")([^"]*)(?=",)|(?<=")([^"]*)(?=",)|(?<=")([^"]*)(?="$)
using back references $1$2$3, you can extract your elements.
RegEx /(?:^|,)(\"(?:[^\"])\"|[^,])/ has helped me get the required values.
var test = '"abc,123",test,123,456,"def:get"';
test.split(/(\"(?:[^\"])\"|[^,])/);
Its returning the below array.
["", ""abc,123"", ",", "test", ",", "123", ",", "456", ",", ""def:get"", ""]
And when a particular values in side double quotes,I just trimmed them to get the actual values and have ignore empty items of array..
use the split a string .....
let fullName = "First,Last"
let fullNameArr = fullName.characters.split{$0 == ","}.map(String.init)
fullNameArr[0] // First
fullNameArr[1] // Last
I have a string, and I want to extract, using regular expressions, groups of characters that are between the character : and the other character /.
typically, here is a string example I'm getting:
'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh'
and so, I want to retrieved, 45.72643,4.91203 and also hereanotherdata
As they are both between characters : and /.
I tried with this syntax in a easier string where there is only 1 time the pattern,
[tt]=regexp(str,':(\w.*)/','match')
tt = ':45.72643,4.91203/'
but it works only if the pattern happens once. If I use it in string containing multiples times the pattern, I get all the string between the first : and the last /.
How can I mention that the pattern will occur multiple time, and how can I retrieve it?
Use lookaround and a lazy quantifier:
regexp(str, '(?<=:).+?(?=/)', 'match')
Example (Matlab R2016b):
>> str = 'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh';
>> result = regexp(str, '(?<=:).+?(?=/)', 'match')
result =
1×2 cell array
'45.72643,4.91203' 'hereanotherdata'
In most languages this is hard to do with a single regexp. Ultimately you'll only ever get back the one string, and you want to get back multiple strings.
I've never used Matlab, so it may be possible in that language, but based on other languages, this is how I'd approach it...
I can't give you the exact code, but a search indicates that in Matlab there is a function called strsplit, example...
C = strsplit(data,':')
That should will break your original string up into an array of strings, using the ":" as the break point. You can then ignore the first array index (as it contains text before a ":"), loop the rest of the array and regexp to extract everything that comes before a "/".
So for instance...
'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh'
Breaks down into an array with parts...
1 - 'abcd'
2 - '45.72643,4.91203/Rou'
3 - 'hereanotherdata/defgh'
Then Ignore 1, and extract everything before the "/" in 2 and 3.
As John Mawer and Adriaan mentioned, strsplit is a good place to start with. You can use it for both ':' and '/', but then you will not be able to determine where each of them started. If you do it with strsplit twice, you can know where the ':' starts :
A='abcd:45.72643,4.91203/Rou:hereanotherdata/defgh';
B=cellfun(#(x) strsplit(x,'/'),strsplit(A,':'),'uniformoutput',0);
Now B has cells that start with ':', and has two cells in each cell that contain '/' also. You can extract it with checking where B has more than one cell, and take the first of each of them:
C=cellfun(#(x) x{1},B(cellfun('length',B)>1),'uniformoutput',0)
C =
1×2 cell array
'45.72643,4.91203' 'hereanotherdata'
Starting in 16b you can use extractBetween:
>> str = 'abcd:45.72643,4.91203/Rou:hereanotherdata/defgh';
>> result = extractBetween(str,':','/')
result =
2×1 cell array
{'45.72643,4.91203'}
{'hereanotherdata' }
If all your text elements have the same number of delimiters this can be vectorized too.
I need to convert this (date) String "12112014" to "12.11.2014"
What i would like to to is:
Split first 2 Strings "12", add ".",
then split the string from 3-4 to get "11", add "."
at the end split the last 4 strings (or 5-8) to get "2012"
I already found out how to get the first 2 characters ( "^\d{2}" ), but I failed to get characters based on a position.
Whatever be the programming language, You should try to extract the digits from string and then join them with a ".".
In perl, it can be done as :
$_ = '12112014';
s/(\d{2})(\d{2})(\d{4})/$1.$2.$3/;
print "$_";
Without you specifying the language you're after, I've picked javascript:
var s = '12012011';
var s2 = s.replace(/(\d{2})(\d{2})(\d{4})/,'$1.$2.$3'));
console.log(s2); // prints "12.01.2011"
The gist of it is that you use () to specify groups inside your regular expression and then can use the groups in your replace expression.
Same in Java:
String s = "12012011";
String s2 = s.replaceAll("(\\d{2})(\\d{2})(\\d{4})", "$1.$2.$3");
System.out.println(s2);
I dont think that you could do that only with split.
You could expand your expression to:
"(^(\d{2})(\d{2})(\d{4}))"
Then access the groups with the Regex language of your choice and build the string you want.
Note that - besides all regex learning - alternatively you could always parse the original string into strongly typed Date or DateTime variables and output the value using the appropriate locales.
I have s string that looks like
txt = '"EMB","iShares J,P. Morg",110.81,N/A'
I'm using strsplit(txt,','); to break this into separate strings based on the comma delimiter. However I want to ignore the comma between the 'J' and the 'P', since it's not a delimiter; it's just part of the name.
Is there a way I can say "if a comma is between two quotes but there are other characters between the quotes, delete the comma"?
Here's an equivalent regexp one-liner:
C = regexp(txt, '("[^"]*")|([^,"]+)', 'match')
The result is a cell array with already split strings. Unfortunately, I don't have MATLAB R2013, so I cannot benchmark this versus strsplit.
A silly (but functional) answer:
inquotes=false;
keep=true(1,length(txt));
for v=1:length(txt)
if (txt(v)=='"')
inquotes=~inquotes;
elseif (txt(v)==',' && inquotes)
keep(v)=false;
end
end
txt=txt(keep);
tt=strsplit(txt,',');
This will, if you are in quotes, remove the commas so that you can use strsplit. That is what I understood you want to do, correct?
I'm trying to retrieve a filename without the extension in ColdFusion. I am using the following function:
REMatchNoCase( "(.+?)(\.[^.]*$|$)" , "Doe, John 8.15.2012.docx" );
I would like this to return an array like: ["Doe, John 8.15.2012","docx"]
but instead I always get an array with one element - the entire filename:["Doe, John 8.15.2012.docx"]
I tried the regex string above on rexv.org and it works as expected, but not on ColdFusion. I got the string from this SO question: Regex: Get Filename Without Extension in One Shot?
Does ColdFusion use a different syntax? Or am I doing something wrong?
Thanks.
Why you're not getting expected results...
The reason you are getting a one-item array with the whole filename is because your pattern matches the entire filename, and matches once.
It is capturing the two groups, but rematch returns arrays of matches, not arrays of the captured groups, so you don't see those groups.
How to solve the problem...
If you are dealing with simple files (i.e. no .htaccess or similar), then the simplest solution is to just use...
ListLast( filename , '.' )
....to get only the file extension and to get the name without extension you can do...
rematch( '.+(?=\.[^.]+$)' , filename )
This uses a lookahead to ensure there is a . followed by at least one non-. at the end of the string, but (since it's a lookahead) it is excluded from the match (so you only get the pre-extension part in your match).
To deal with non-extensioned files (e.g. .htaccess or README) you can modify the above regex to .+(?=(?:\.[^.]+)?$) which basically does the same thing except making the extension optional. However, there isn't a trivial way to get update the ListLast method for these (guess you'd need to check len(extension) LT len(filename)-1 or similar).
(optional) Accessing captured groups...
If you want to get at the actual captured groups, the closest native way to do this in CF is using the refind function, with the fourth argument set to true - however, this only gives you positions and lengths - requiring that you use mid to extract them yourself.
For this reason (amongst many others), I've created an improved regex implementation for CF, called cfRegex, which lets you return the group text directly (i.e. no messing around with mid).
If you wanted to use cfRegex, you can do so with your original pattern like so:
RegexMatch( '(.+?)(\.[^.]*$|$)' , filename , 1 , 0 , 'groups' )
Or with named arguments:
RegexMatch( pattern='(.+?)(\.[^.]*$|$)' , text=filename , returntype='groups' )
And you get returned an array of matches, within each element being an array of the captured groups for that match.
If you're doing lots of regex work dealing with captured groups, cfRegex is definitely better than doing it with CF's re methods.
If all you care about is getting the extension and/or the filename with extension excluded then the previous examples above are sufficient.
#Peter's response is great, however the approach is perhaps a bit longer-winded than necessary. One can do this with reMatch() with a slight tweak to the regex.
<cfscript>
param name="URL.filename";
sRegex = "^.+?(?=(?:\.[^.]+?)?$)";
aMatch = reMatch(sRegex, URL.filename);
writeDump(aMatch);
</cfscript>
This works on the following filename patterns:
foo.bar
foo
.htaccess
John 8.15.2012.docx
Explanation of the regex:
^ From the beginning of the string
.+? One or more (+) characters (.), but the fewest (?) that will work with the rest of the regex. This is the file name.
(?=) Look ahead. Make sure the stuff in here appears in the string, but don't actually match it. This is the key bit to NOT return any file extension that might be present.
(?: Group this stuff together, but don't remember it for a back reference.
. A dot. This is the separator between file name and file extension.
[^.]+? One or more (+) single ([]) non-dot characters (^.), again matching the fewest possible (?) that will allow the regex as a whole to work.
? (This is the one after the (?:) group). Zero or one of those groups: ie: zero or one file extensions.
$ To the end of the string
I've only tested with those four file name patterns, but it seems to work OK. Other people might be able to finetune it.
A few more ways of achieving the same result. They all execute in roughly the same amount of time.
<cfscript>
str = 'Doe, John 8.15.2012.docx';
// sans regex
arr1 = [
reverse( listRest( reverse( str ), '.' ) ),
listLast( str, '.' )
];
// using Java String lastIndexOf()
arr2 = [
str.substring( 0, str.lastIndexOf( '.' ) ),
str.substring( str.lastIndexOf( '.' ) + 1 )
];
// using listToArray with non-filename safe character replace
arr3 = listToArray( str.replaceAll( '\.([^\.]+)$', '|$1' ), '|' );
</cfscript>