XSLT for converting empty body to a SUCCESS message - xslt

Question

I am trying to replace an empty response body, which is getting generated by a successful DELETE operation with a "Success" message via XSLT.
Can anyone help me with the XSLT which can simply print a SUCCESS message, if the response body is empty.
Response Body will be:
<response status="204"> </response>
Expected output:
<response status="204">SUCCESS</response>
Update from comment: If the response is not empty then it should print the same what comes back as a response.
Currently using the below XSLT:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(*) and not(normalize-space())]">
<xsl:element name="{name()}" namespace="{namespace-uri()}"/>
</xsl:template>
</xsl:stylesheet>
But it gives:
<response/>
as output.

Answer 1

Can anyone help me with the XSLT which can simply print a SUCCESS
message, if the response body is empty.
If the response is not empty then it should print the same what comes
back as a response.
Then try:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/response[not(node())]">
<xsl:copy>
<xsl:apply-templates select="#*"/>
<xsl:text>SUCCESS</xsl:text>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>