I have this code to create a file, when I run it with CLion it prints out to the console but does not create file, how can I fix this? thanks
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ofstream log_file;
log_file.open("sample23.txt");
if (log_file.is_open())
std::cout << "Open";
log_file << "stuff" << endl;
log_file.close();
return 0;
}
The file may be created into another directory (the working directory).
You can find that location (and change it if needed) as indicated here:
How do I change the working directory for my program
make sure to flush before closing because file is empty
try this out
ofstream f;
f.open( "sample.txt", ios::out );
f << flush;
f.close();
3 things here:
1.) In order to output to another file, you must make another variable like this:
ifstream someoutputfile;
someoutputfile.open("filename");
2.) you actually must make another variable to be "placeholder" of sorts that will automatically assign the first thing your file finds and assigns that to. This may depend on what datatype (int, double, string etc) your input file consists of. Instead of:
log_file << "stuff" << endl;
you can do something like this...
// if my input file is integers for instance..
int data = 0;
log_file >> data;
This can also work for if your file contains multiple data types.
ex:
// if I have two different data types...
string somebody;
int data = 0;
log_file >> data >> somebody;
3.) to output your file data to the screen, just follow a similar way as the example in #1.
someoutputfile << data << somebody << endl;
in addition, dont forget to close the data of BOTH your input and output files:
someoutputfile.close()
Hope that helps in some way :)
Related
I would like to make a read and write file in c++. I would also like the information i write be a string. so then i can read that string from the file and see the value. Im gonna use this sort of like a settings file where the program can read your settings that you've used and apply them without having to reconfigure the program everytime. In small here's what i got:
int main()
{
std::string tortilla = "tacos";
std::string godast = "pizza";
std::ofstream MyFile;
MyFile.open("1.txt");
MyFile << tortilla;
MyFile.close();
std::ifstream ReadFile("1.txt");
while (std::getline(ReadFile, tortilla))
As you see the code is not done yet by far but i just want to learn this element for now. Thank you in before.
EDIT: Here i want the output of reading "tortilla" to be tacos. So the string is intact troughout
To output the content of tortilla add:
{
std::cout << "tortilla is " << tortilla << std::endl;
}
And iostream must be included for std::cout. HTH.
I am writing an MFC program that has a dialog with an "Export" button that will take all of the data that has been entered into the file and export it to a .txt (at some point I want to change this to a .msg file...but that's a question for another day).
However, when I click the button, it creates the file but doesn't write anything inside the file. For testing, I removed everything except just a simple literal string and even that isn't printing. Here is the current code for that event: The myfile.flush() statement is leftover from when I had a loop that I was trying to print to the file.
void CEHDAHTTimerDlg::OnBnClickedExport()
{
// in this function, we want to export the items to a text file
std::ofstream myfile("TodayTime.txt");
myfile.open("TodayTime.txt");
if (myfile.is_open())
{
myfile << "The average call time is ";
myfile.flush();
myfile.close();
}
else
{
SetDlgItemText(IDC_EXPORT, L"Export Unsuccessful! -- No File");
}
}
Is there anything you all can think of that could be causing this? I've been at it for a few hours trying different things, like utilizing a myfile.write() function instead. I've searched a lot around here, reddit, and google in general trying to find out why this isn't writing.
I appreciate your help.
EDIT:
Okay, calling the myfile constructor the way that I did, by including the file name, went ahead and did what open file would have done
Thanks for your help!
commenting out the redundant "open" solves it.
#include <iostream>
#include <fstream>
int main()
{
// in this function, we want to export the items to a text file
std::ofstream myfile("TodayTime.txt");
// myfile.open("TodayTime.txt");
if (myfile.is_open())
{
myfile << "The average call time is ";
myfile.flush();
myfile.close();
}
else
{
std::cerr << "didn't write" << std::endl;
}
}
I strongly suspect that you're invoking undefined behaviour by opening and already-open stream.
Here is the explanation:
The call to myfile.open("TodayTime.txt"); will fail because the stream is already associated with the file, setting the failbit.
The call to is_open() will succeed, as the file is open.
Then the call to streaming operator << will fail (because of the failbit).
this is because myfile << "The average call time is "; not working
to fix that
std::ofstream myfile;
myfile.open("TodayTime.txt",std::ios:app) //app for appending you can use trunc for
//truncating file
//for flushing content's of existing file use myfile.flush();
if (!data_pack.is_open())
{
std::cerr << "unable to open the file for writing";
}
myfile << "some stuff tho write you can replace the string with variable"
<<std::endl; //for next line
//at last close file
myfile.close();
This question already has answers here:
How to append text to a text file in C++?
(5 answers)
Closed 7 years ago.
I have created a code writing stuff in a .txt file and read from it. But if I close the program and start to write again, it deletes the old text and overwrites it with the new one.
Is there a way to not overwrite existed data?
#include "stdafx.h"
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
void check() {
string text;
ifstream file;
file.open("test.txt");
getline(file, text);
if (text == "") {
cout << "There's no data in file" << endl;
} else {
cout << "File contains:" << endl;
cout << text << endl;
}
}
int main() {
check();
string text;
ofstream file;
file.open("test.txt");
cout << "Type some text" << endl;
getline(cin, text);
file << text;
return 0;
}
You need to open the file in 'append' mode like in the following example
#include <fstream>
int main() {
std::ofstream outfile;
outfile.open("yourfile.txt", std::ios_base::app);//std::ios_base::app
outfile << "your data";
return 0;
}
You can read here about fstream flagshttp://www.cplusplus.com/reference/fstream/fstream/open/
Keep in mind that in c++ there are several ways to open, save, and read text data to and from a file. It sounds like you opened with with a function (and its options) to always create a new file. One thing you could do is run your program and then close the program and use a text editor to open the file to verify whether the text you wrote to the file is actually there. Also take a look at the code that was provided by Evyatar. That example uses ofstream which allows options for read, write, and append. The "app" parameter tells the program to keep what is already in the file and append any new data that you add in the next run. When testing files where you are appending, be careful you don't end up with a huge file you did not intend to have so large.
In the code that you posted in your revised question, be sure to close the file in your check function and at the end of the program. It is possible to get things hung up if you don't. As a precaution, I usually close a file prior to opening it, just to be sure it is closed with no problems. This practice comes form my days programming in BASIC where it was an essential. If the program crashed, you couldn't open it again until you got it closed. Also, of course, close the file after you're done with it and before the end of the program. Then, when you open it in main, open with the append option.
Please, insert code for next time. If you open file in write mode, than is normal that every time you write to file, the content of file is changed. You need to use append mode.
Can anyone tell me what is wrong with this code? I always get not open.
#include <iostream>
#include <fstream>
using namespace std;
int main(){
fstream fs;
fs.open("fsfile2",ios::in|ios::out|ios::binary);
if(fs.is_open()){
fs.write("wow",sizeof("wow"));
char str[20];
fs.read((char*)str,sizeof(str));
cout<<str<<endl;}
else
cout<<"Not open\n";
return 0;
}
Try this code
fs.open("fsfile2", ios::app|ios::in|ios::out|ios::binary);
By using the open() like you are that file will not be created if that is your goal.
If you want to create a new file please look at: fstream won't create a file
If the file exists, you are not looking for it in the right path. Or change the file name to the full path or put the executable in the folder where the file is.
Hope this helps.
Probably, you do not have permissions to create files in the directory, where your executable is.
Solution:
Please add a file extension to the filename.
If it's a text file, it will be
"fsfile2.txt"
Then, I tried removing
ios::in
since the first process only writes to file, and by removing that, the file is created and "wow" is also written at it.
In order for these lines
fs.read((char*)str,sizeof(str));
cout<<str<<endl;
to work,
You need to close the stream after writing to it, then open the stream in read mode, then read the contents. Take note that closing the stream will save the edited file.
Additional:
You can also change
fs.write("wow",sizeof("wow"));
to
fs << "wow";
You can do the same when reading from file,
fs >> str;
You can also use the string class of C++, instead of char array so that the number of characters inside the file won't be your problem anymore.
#include <string>
string str;
Checking for EOF (end-of-file) is recommended since files are read line by line. Once you add a new line and add a character to the line, the code that doesn't loop until EOF will only read the first line of the file.
In order to solve this, it is recommended to loop until EOF is reached.
while(!fs.eof()) {
fs >> str;
cout << str << endl;
}
So here is the improved snippet:
#include <string>
fs.open("fsfile2.txt", ios::out); // ios::out for write only
if(fs.is_open()) {
// writes "wow" to file
fs << "wow";
// closes the file
fs.close();
// ios::in for read only
fs.open("fsfile2.txt", ios::in);
// better to define variable just before using it
string str;
// loops until end-of-file
while(!fs.eof()) {
// reads a line from file, stores it to str
fs >> str;
// shows str to screen
cout << str << endl;
}
}
*Note: I removed
ios::binary
Since your code is not dealing with binary files yet.
I tried these and it worked fine! Have a nice day!
fstream fs; does not create a new file for you.
You need to make sure that the file exists in your project directory.
On the other hand, if you were to use ofstream fs("file.txt"); it would create the file for you. Or use only ios::out when you open fstream fs, this will create the file for you.
I need to create a program that writes a text file in the current folder, the text file always contains the same information, for example:
Hello,
This is an example of how the text file may look
some information over here
and here
and so on
So I was thinking in doing something like this:
#include <iostream>
#include <fstream>
using namespace std;
int main(){
ofstream myfile("myfile.txt");
myfile << "Hello," << endl;
myfile << "This is an example of how the text file may look" << endl;
myfile << "some information over here" << endl;
myfile << "and here" << endl;
myfile << "and so on";
myfile.close();
return 0;
}
Which works if the number of lines in my text file is small, the problem is that my text file has over 2000 lines, and I'm not willing to give the myfile << TEXT << endl; format to every line.
Is there a more effective way to create this text file?
Thanks.
If you have the problem of writing in same file, you need to use an append mode.
i.e., your file must be opened like this
ofstream myfile("ABC.txt",ios::app)
You may use Raw string in C++11:
const char* my_text =
R"(Hello,
This is an example of how the text file may look
some information over here
and here
and so on)";
int main()
{
std::ofstream myfile("myfile.txt");
myfile << my_text;
myfile.close();
return 0;
}
Live example
Alternatively, you may use some tools to create the array for you as xxd -i
If you don't care about the subtile differences between '\n' and std::endl, then you can create a static string with your text outside of your function, and then it's just :
myfile << str // Maybe << std::endl; too
If your text is really big, you can write a small script to format it, like changing every newlines with "\n", etc.
It sounds like you should really be using resource files. I won't copy and paste all of the information here, but there's a very good Q&A already on this website, over here: Embed Text File in a Resource in a native Windows Application
Alternatively, you could even stick the string in a header file then include that header file where it's needed:
(assuming no C++11 since if you do you could simply use Raw to make things a little easier but an answer for that has already been posted - no need to repeat).
#pragma once
#include <iostream>
std::string fileData =
"data line 1\r\n"
"data line 2\r\n"
"etc.\r\n"
;
Use std::wstring and prepend the strings with L if you need more complex characters.
All you need to do is to write a little script (or even just use Notepad++ if it's a one off) to replace backslashes with double backslash, replace double quotation marks with backslash double quotation marks, and replace line breaks with \r\n"{line break}{tab}". Tidy up the beginning and end, and you're done. Then just write the string to a file.