I am using Django REST framework 3.3 and am trying to serialize a list that could be empty with the provided serializers.ListField class that is included in the framework. My current instantiation of the field looks like this
countrypreferences = serializers.ListField(child=serializers.IntegerField(),
source='country_preference_ids',
allow_null=True)
When testing the API I always seem to get a 400 response if I let the field be an empty list. It would seem like this kind of functionality would be pretty common but I can't find a way to allow the empty list. Thanks!
You should set:
child=serializers.IntegerField(required=False)
In addition to that you can also provide a default value to the ListField in the serializers
field = serializers.ListField(default = [])
This will set the field as an empty list if u send None or no value.
I would rather use
field = serializers.ListField(child=serializers.CharField(), allow_empty=True)
Related
I'm implementing a search feature where I'm matching keys from the description. and also matching media if description and media type of ['mp4','mkv','mov','avi'] match so the condition is satisfied.
So I have tried many methods but didn't find an efficient way. to make it possible without for loop.
I want to use those together.
description and media type ['mp4','mkv','mov','avi']
postinlang_queryset = PostInLanguages.objects.filter(description__contains=search_name)
media_type_query_set = LanguageMedia.objects.filter(content_type__contains ['mp4','mkv','mov','avi'])
yes, it's possible without for loop.Just follow the following script:
postinlang_queryset = PostInLanguages.objects.filter(description__contains=search_name)
media_type_query_set = LanguageMedia.objects.filter(content_type__in=['mp4','mkv','mov','avi'])
N.B: content_type__in=['mp4','mkv','mov','avi'] If we pass an empty list then it will never throw exceptions but return empty queryset
I understand that Django want to generate forms automatically so you don't have to do so in your template, and I do understand that many people find it cool.
But I have specific requirements and I have to write my forms on my own. I just need something to parse the data, be it a form submitted using a user interface, or an API request, or whatever.
I tried to use ModelForm, but it doesn't seem to work as I want it to work.
I'd like to have something with the following behavior:
possibility to specify the model of the object I am going to create/update
possibility to specify an object in case of an update
possibility to provide new data in a dictionary
if I am creating a new object, missing fields in my data should be replaced by their default values as specified in my model definition
if I am updating an existing object, missing fields in my data should be replaced by the current values of the object I am updating. Another way of saying is, do not update values that are missing in my data dictionary.
data validation should be performed before calling save(), and it should throw a ValidationError with the list of erroneous fields and errors.
Currently, I prefer to do everything manually :
o = myapp.models.MyModel() # or o = myapp.Models.MyModel.objects.get(pk = data['pk'])
o.field1 = data['field1']
o.field2 = data['field2']
…
o.full_clean()
o.save()
It would be nice to have a shortcut :
o = SuperCoolForm(myapp.models.MyModel, data)
o.save()
Do you know if Django does provide a solution for this or am I asking too much?
Thank you!
My Post model have list of authors id
class Post(Document):
authors_id = ListField(IntField(required=True), required=True)
But sometime I need to use default Django User class. How most rapidly I can do it?
(I'm using sqlite for users and sessions and MongoDB (mongoengine ODM) for other. Don't ask why:))
I was tried to write it:
def get_authors(self):
authors = list()
for i in self.authors_id:
authors.append(get_user(IntField.to_python(self.authors_id[i])))
return authors
...and it raises 'list index out of range' exception. (authors id not empty, really). What I'm doing wrong?
Not sure about the to_python method but since you are looping through the authors_id, there is no need to do
authors.append(get_user(IntField.to_python(self.authors_id[i])))
You should be good with
authors.append(get_user(IntField.to_python(i)))
Instead of
IntField.to_python(self.authors_id[i]))
I think you just need to do:
IntField.to_python(i)
In Python the 'for i in some_list' construction gives you elements of the list, not integer indexes.
You said that you were getting this error:
and unbound method to_python() must be called with IntField instance as first argument (got int instance instead)
I got a similar error from MongoEngine. In my case the problem was that I defined the field like this:
foo_id = IntField
The correct way to define it is:
foo_id = IntField()
When I added the parenthesis, the problem went away.
I've been using the built-in Django comments system which has been working great. On a particular page I need to list the latest X comments which I've just been fetching with:
latest_comments =
Comment.objects.filter(is_public=True, is_removed=False)
.order_by('submit_date').reverse()[:5]
However I've now introduced a Boolean field 'published' into the parent object of the comments, and I want to include that in the query above. I've tried using the content_type and object_pk fields but I'm not really getting anywhere. Normally you'd do something like:
Comment.objects.filter(blogPost__published=True)
But as it is not stored like that I am not sure how to proceed.
posts_ids = BlogPost.objects.filter(is_published=True).values_list('id', flat=True) #return [3,4,5,...]
ctype = ContentType.objects.get_for_model(BlogPost)
latest_comments = Comment.objects.filter(is_public=True, is_removed=False, content_type=ctype, content_object__in=posts_ids).order_by('-submit_date')[:5]
Comments use GenericForeignKey to store the relation to parent object. Because of the way generic relations work related lookups using __<field> syntax are not supported.
You can accomplish the desired behaviour using the 'in' lookup, however it'll require lot of comparisons when there'll be a lot of BlogPosts.
ids = BlogPost.objects.filter(published=True).values_list('id', flat=True) # Get list of ids, you would probably want to limit number of items returned here
content_type = ContentType.objects.get_for_model(BlogPost) # Becasue we filter only comments for BlogPost
latest_comments = Comment.objects.filter(content_type=content_type, object_pk__in=ids, is_public=True, is_removed=False, ).order_by('submit_date').reverse()[:5]
See the Comment model doc for the description of all fields.
You just cannot do that in one query. Comments use GenericForeignKey. Documentation says:
Due to the way GenericForeignKey is implemented, you cannot use such
fields directly with filters (filter() and exclude(), for example) via
the database API.
I'd like to have access to one my model field verbose_name.
I can get it by the field indice like this
model._meta._fields()[2].verbose_name
but I need to get it dynamically. Ideally it would be something like this
model._meta._fields()['location_x'].verbose_name
I've looked at a few things but I just can't find it.
For Django < 1.10:
model._meta.get_field_by_name('location_x')[0].verbose_name
model._meta.get_field('location_x').verbose_name
For Django 1.11 and 2.0:
MyModel._meta.get_field('my_field_name').verbose_name
More info in the Django doc
The selected answer gives a proxy object which might look as below.
<django.utils.functional.__proxy__ object at 0x{SomeMemoryLocation}>
If anyone is seeing the same, you can find the string for the verbose name in the title() member function of the proxy object.
model._meta.get_field_by_name(header)[0].verbose_name.title()
A better way to write this would be:
model._meta.get_field(header).verbose_name.title()
where header will be the name of the field you are interested in. i.e., 'location-x' in OPs context.
NOTE: Developers of Django also feel that using get_field is better and thus have depreciated get_field_by_name in Django 1.10. Thus I would suggest using get_field no matter what version of Django you use.
model._meta.get_field_by_name('location_x')[0].verbose_name
You can also use:
Model.location_x.field.verbose_name
Model being the class name. I tested this on my Animal model:
Animal.sale_price.field.verbose_name
Animal.sale_price returns a DeferredAttribute, which has several meta data, like the verbose_name
Note: I'm using Django 3.1.5
If you want to iterate on all the fields you need to get the field:
for f in BotUser._meta.get_fields():
if hasattr(f, 'verbose_name'):
print(f.verbose_name)
# select fields for bulk_update : exclude primary key and relational
fieldsfields_to_update = []
for field_to_update in Model._meta.get_fields():
if not field_to_update.many_to_many and not field_to_update.many_to_one and not field_to_update.one_to_many and not field_to_update.one_to_one and not field_to_update.primary_key and not field_to_update.is_relation :
fields_to_update = fields_to_update + [field_to_update.name]
Model.objects.bulk_update(models_to_update , fields_to_update)