I need to find a way to create a vlookup that will populate a field if the lookup table contains the values in the table array.
For example, A1 contains account number 4563399P01/f/5. A2 contains account number 43823448P01S/f/5.
I need cell B1 to display $10.00, if the account contains P01, B2 to display 12.50 if the account contains P01S.
I was able to use vlookup using the whole account number, but as new account numbers are added, they need to be added to the table array. It would be much easier to search the account number if it contains P01, P01S, G01, S021, etc, since there are limited options.
I hope that makes sense since my brain is fried. It doesn't seem like it should be that hard, but clearly it is for me.
I think this may help. Use the SEARCH and ISNUMBER functions to find the string you want:
=IF(ISNUMBER(SEARCH("P01S",A1)), 10, IF(ISNUMBER(SEARCH("P01",A1)), 12.5, IF(ISNUMBER(SEARCH("G01",A1)), ...)))
The SEARCH checks for the position of the string within the account number, and the ISNUMBER returns true if the position is a number i.e. the string has been found. You could replace the values with a VLOOKUP on the relevant string too. This obviously needs extending for the remainder of the strings you wish to search for.
One thing to be careful of is when you have P01 and P01S. The search will find P01 in accounts that contain P01S too, so it is important to make sure you put these in the correct order - start with the P01S and if that is not found then look for P01.
Related
I need a formula that can multiply or divide all the numbers in a string without changing the text attached to the numbers.
I need the numbers in the next column to automatically change according to the given mathematical operation, but the text from the original line must remain unchanged.
I've tried using a combination of REGEXMATCH and REGEXEXTRACT and by doing this I just get the result of multiplying/dividing all the numbers in the string (no text whatsoever).
I also had no success using REGEXREPLACE. I'm not even sure we can actually use it in this case, and maybe I need a different formula instead. Maybe you first need to extract the numbers, multiply them and use something like TEXTJOIN or CONCATENATE to put them together in a string with the values already changed, and is this even possible in this specific example? It's totally fine to perform the operation in several steps if needed (for example, adding SPLIT function or something like that), but the format of the raw data we need to enter and recalculate, unfortunately, cannot be modified.
A sample table for better visualisation can be seen below. Any help would be greatly appreciated!
Raw data
Operation
Desired outcome
25STR/40DEX/70FRES
*0.25
6.25STR/10DEX/17.5FRES
80VIT/30INT/50CRES
*0.75
60STR/22.5INT/37.5CRES
60VIT/20STR/45LRES
*1.25
75VIT/25STR/56.25LRES
You may try:
=byrow(index(bycol(split(A2:A,"/"),lambda(z,ifna(ifs(left(B2:B,1)="*",regexextract(z,"\d+")*mid(B2:B,2,99),left(B2:B,1)="/",round(regexextract(z,"\d+")/mid(B2:B,2,99),2))®exextract(z,"\d+(.*)"))))),lambda(y,if(y="",,join("/",y))))
In desperate need of some assistance with this!
Wasn't sure how to title this question...
SAMPLE SHEET - CLICK ME! :)
In SupportingSheet!H1 I have the following formula:
=ArrayFormula(if(G1:G<>"", IF(DASHBOARD!N2<>"", G1:G/DASHBOARD!$P$2-filter(DASHBOARD!O1:O100,REGEXMATCH(DASHBOARD!N1:N100,E1:E100)),G1:G/(DASHBOARD!$M$3)),))
The part I struggle with is:
G1:G/DASHBOARD!$P$2-filter(DASHBOARD!O1:O100,REGEXMATCH(DASHBOARD!N1:N100,E1:E100))
It needs to divide two numbers and then subtract another number. I can't seem to get this formula to pull the correct number.
It needs to check if the text in E1:E100 exist in DASHBOARD!N1:N100, if yes, pull the number from DASHBOARD!O1:O100.
For example, text in SupportingSheet!E1 can be found in DASHBOARD!N2, hence it needs to pull the number from DASHBOARD!O2.
Column SupportingSheet!J has the actual end result that a formula needs to produce.
It doesn't look like Regexmatch works as an Arrayformula and I am not sure how to go about it.
Please note, that text in SupportingSheet!E1:E is not always identical. Often it will have a random number of "space" at the end (long story...). That is why Regexmatch was a perfect option until I realised it didn't work.
Please let me know if further clarification is needed.
Below is an image of the random spaces (non-printable characters) at the end.
use:
=ARRAYFORMULA(IF(G1:G="",,IF(DASHBOARD!N2<>"",
IFNA(G1:G/DASHBOARD!$P$2-VLOOKUP(E1:E1000, DASHBOARD!N1:O100, 2, 0),
G1:G/DASHBOARD!$M$3))))
The documentation for pattern matching for Google Sheets has not been helpful. I've been reading and searching for a while now and can't find this particular issue. Maybe I'm having a hard time finding the correct terms to search for but here is the problem:
I have several numbers (part numbers) that follow this format: ##-####
Categories can be defined by the part numbers, i.e. 50-03## would be one product category, and the remaining 2 digits are specific for a model.
I've been trying to run this:
=countif(E9:E13,"50-03[123][012]*")
(E9:E13 contains the part number formatted as text. If I format it any other way, the values show up screwed up because Google Sheets thinks I'm writing a date or trying to do arithmetic.)
This returns 0 every time, unless I were to change to:
=countif(E9:E13,"50-03*")
So it seems like wildcards work, but pattern matching does not?
As you identified and Wiktor mentioned COUNTIF only supports wildcards.
There are many ways to do what you want though, to name but 2
=ArrayFormula(SUM(--REGEXMATCH(E9:E13, "50-03[123][012]*")))
=COUNTA(FILTER(E9:E13, REGEXMATCH(E9:E13, "50-03[123][012]*")))
This is a really big hammer for a problem like yours, but you can use QUERY to do something like this:
=QUERY(E9:E13, "select count(E) where E matches '50-03[123][012]' label count(E) ''")
The label bit is to prevent QUERY from adding an automatic header to the count() column.
The nice thing about this approach is that you can pull in other columns, too. Say that over in column H, you have a number of orders for each part. Then, you can take two cells and show both the count of parts and the sum of orders:
=QUERY(E9:H13, "select count(E), sum(H) where E matches '50-03[123][012]' label count(E) '', sum(H) ''")
I routinely find this question on $searchEngine and fail to notice that I linked another question with a similar problem and other relevant answers.
I'm trying to apply a formula without having it add the formula data to each and every cell - in other words, I need the cells that are receiving the formula to be untouched until they get their data.
I was searching around and it looked like an ARRAYFORMULA would work but it doesn't seem to be doing anything when I apply it.
For example, I want to apply this formula to a cell range: =SPLIT(E2, ",")). Each cell in the E column needs to be split into two the two adjacent cells next to it based on it's comma. When I try to apply =ARRAYFORMULA(SPLIT(E2:E99, ",")) only the cell I add this to gets the formula.
In addition to the contribution of pnuts, also try:
=ArrayFormula(iferror(REGEXEXTRACT(","&E2:E,"^"&REPT(",+[^,]+",COLUMN(OFFSET(A1,,,1,6))-1)&",+([^,]+)")))
Note: the last parameter of OFFSET can be changed to match the maximum number of values you have in the cells of the range E2:E (separated by a comma). E.g: if you have a no more than 3 values per cell, set it to three. The output will then be three columns wide (one column for each value).
Hope that makes sense ?
Also credits due to AdamL who (I believe) orginally crafted this workaround.
I think what you want may be array_constrain but for your example I can only at present offer you two formulae (one for each side of the comma):
=Array_constrain(arrayformula(left(E2:E,find(",",E2:E)-1)),match("xxx",E:E)-1,1)
=Array_constrain(arrayformula(mid(E2:E,find(",",E2:E)+1,len(E2:E))),match("xxx",E:E)-1,1)
I'm trying to solve the "find all possible words for a set of letters" problems. There are some good answers out there, but I still can't figure it out.
In my first test, I put the whole dictionary in an array and then looped through each letter. This is super fast, but it takes forever to load the dictionary in the array, and requires huge amount of memory.
So I need to store the dictionary (750,000) letter is a sql database.
I guess there are two solutions to find all the possible words:
Make an advance query that returns all the possible words
Make a simple query that return a fraction of the database with words that might be possible, and then quickly loop through that array and valide the words.
The problem?:
It must be super fast. An iPhone 4 need to be able to get all possible words in under 5-6 seconds so it doesn't hinder the game.
Here's a similar questions:
IOS: Sqlite. Find record fast
Sulthans answer seems like a good idea. Create a hash table, and then:
Bitmask for ASCII letters (ignoring any non-ASCII alphabets). Bit at
position 0 means the word contains "a", at position 1 contains "b"
etc. If we create the same bitmask for our letters, we can select
words such as (wordMask & ~lettersMask) == 0
How do you make the bitmask, hash table, and how do you construct the sql query?
Thanks
sql is probably not the best option. The traditional data structure for storing a collection of words is called a Trie. I'm sure there implementations out there you can find. Someone else will have an answer to that.
The algorithm I envision is to permute the letters you are given, and check each permutation to see if it is in the Trie.