I am trying to create a get function in my class to return that will take i, j argument and return the value of what is located at Object(i, j).
So far in my get function it is converting i, j to its equivalent in a 1d array by i * (number of columns) + j, which in my code would equal 5.
Next I want to show what value is at location 5 in my array. However it seems to return the first value of my array, not the location 5 value. Any ideas to where I am going wrong? am I using the pointer in the wrong way? My full program is below:
#include <iostream>
using namespace std;
class MyMatrix{
public:
//default constructor set member variables to null states
MyMatrix();
MyMatrix(int sizeR, int sizeC, double * input_data);
~MyMatrix(); //destructor
//member functions
int get(int i, int j);
private:
int m; //rows
int n; //columns
double * data;
};
int main(){
const int rows = 3;
const int columns = 2;
double * userInput;
cout << "The array is 3*2, or 6 elements." << endl;
userInput = new double[rows*columns];
double temp;
for (int i = 0; i < rows*columns; i++){ //let the user type in the array
cout << "Please enter value" << i << endl;
cin >> temp;
*(userInput + i) = temp;
}
MyMatrix ObjectA(rows, columns, userInput); //creating object with specifications
cout << "The value of ObjectA 2,1 is: " << ObjectA.get(2, 1) << endl;
return 0;
}
MyMatrix::MyMatrix(){
cout << "MyMatrix constructor lets go" << endl;
m = 0;
n = 0;
data = 0;
}
MyMatrix::MyMatrix(int sizeR, int sizeC, double * input_data){
cout << "MyMatrix::MyMatrix(int sizeR, int sizeC, double * input_data) is called." << endl; //Showing the constructor working :)
m = sizeR;
n = sizeC;
data = new double[m*n];
for (int i = 0; i < m*n; i++){
data[i] = *input_data;
}
cout << "The items you have entered are:" << endl; //printing out array showing the array is filled
for (int i = 0; i < m*n; i++){
cout << i << "item is: " << *(input_data + i) << endl;
}
}
int MyMatrix::get(int i, int j){
cout << "getFunction is happening" << endl;
//val should just be K [K = i * N + j]
int val = 0;
val = i * n + j; //n is COLUMNS, m is ROWS derp
cout << "val is equal to: " << val << endl; //so val would be 5
//how do i get it to display what is at location 5 in object A
return data[val]; // shouldnt this return the 5th element in data?
}
MyMatrix::~MyMatrix(){
cout << "MyMatrix::~MyMatrix() is invoked" << endl; //showing DESTRUCTA function is working
delete[] data; //the memory management
}
Use data[i] = input_data[i] instead data[i] = *input_data, and add delete [] userInput to free memory or you will memory leak.
Related
Having issues with my getPosNums3 function.....all the others work as I need them to. I'm having issues in general understanding pointers, but I am sure that will pass. The aforementioned function spits out the size and address as I need it to, but when I print the newly modified array, it prints out long identical negative integers akin to this: -5476891, -5476891. It'll put out the right amount of integers, which tells me it is a small adjustment that is hanging up my code.....all these functions modify an array down to only its positive values; they just do so via different methods. I appreciate the help
#include <iostream>
using namespace std;
typedef int* IntArrayPtr;
int* getPosNums1(int* arr, int arrSize, int& outPosArrSize);
int* getPosNums2(int* arr, int arrSize, int* outPosArrSizePtr);
void getPosNums3(int* arr, int arrSize, int*& outPosArr, int& outPosArrSize);
void getPosNums4(int* arr, int arrSize, int** outPosArrPtr, int* outPosArrSizePtr);
void printNewArray(int* arr, int arrSize);
void fillArray(int a[], int size);
int main() {
cout << "Fuction 1: " << endl;
int array_size;
cout << "What is the size of the array? ";
cin >> array_size;
IntArrayPtr a;
a = new int[array_size];
fillArray(a, array_size);
int posArraySize;
int* posNums1 = getPosNums1(a, array_size, posArraySize);
cout << "Original array is: ";
printNewArray(a, array_size);
cout << "The new address is " << posNums1 << " and the new size is " << posArraySize << " " << endl;
cout << "New array is: ";
printNewArray(posNums1, posArraySize);
delete[] a;
cout << endl;
cout << "Function 2: " << endl;
int array_size2;
cout << "What is the size of the array? ";
cin >> array_size2;
a = new int[array_size2];
fillArray(a, array_size2);
cout << "Original array is: ";
printNewArray(a, array_size2);
int* posArraySize2 = &array_size2;
int* posNums2 = getPosNums2(a, array_size2, posArraySize2);
cout << "The new address is " << posNums2 << " and the new size is " << *posArraySize2 << " " << endl;
cout << "New array is: ";
printNewArray(posNums2, *posArraySize2);
delete[] a;
cout << endl;
cout << "Function 3: " << endl;
int array_size3;
cout << "What is the size of the array? ";
cin >> array_size3;
a = new int[array_size3];
fillArray(a, array_size3);
cout << "Original array is: ";
printNewArray(a, array_size3);
int* posNums3 = new int[array_size3];
int posArraySize3 = array_size3;
getPosNums3(a, array_size3, posNums3, posArraySize3);
cout << "The new address is " << posNums3 << " and the new size is " << posArraySize3 << endl;
cout << "New array is: ";
printNewArray(posNums3, posArraySize3);
delete[] a;
cout << endl;
cout << "Function 4: " << endl;
int array_size4;
cout << "What is the size of the array? ";
cin >> array_size4;
a = new int[array_size4];
fillArray(a, array_size4);
cout << "Original array is: ";
printNewArray(a, array_size4);
int* posNums4ptr = &array_size4;
int* posNums4 = new int[array_size4];
int** posNums4ptrptr = &posNums4;
getPosNums4(a, array_size4, posNums4ptrptr, posNums4ptr);
cout << "The new address is " << posNums4ptrptr << " and the new size is " << *posNums4ptr << endl;
cout << "New array is: ";
printNewArray(posNums4, *posNums4ptr);
delete[] a;
return 0;
}
int* getPosNums1(int* arr, int arrSize, int& outPosArrSize) {
int* newArray = new int[arrSize];
int counter = 0;
for (int i = 0; i < arrSize; i++) {
if (arr[i] > 0) {
newArray[counter] = arr[i];
counter++;
}
}
outPosArrSize = counter;
return newArray;
}
int* getPosNums2(int* arr, int arrSize, int* outPosArrSizePtr) {
int size = 0, counter = 0;
int newArraySize = 0;
for (int i = 0; i < arrSize; i++) {
if (*(arr + i) > 0) {
newArraySize++;
}
}
int* newArray = new int[newArraySize];
for (int i = 0; i < arrSize; i++) {
if (*(arr + i) > 0) {
newArray[counter] = *(arr + i);
size++;
counter++;
}
}
*outPosArrSizePtr = size;
return newArray;
}
void getPosNums3(int* arr, int arrSize, int*& outPosArr, int& outPosArrSize){
int counter = 0, size = 0;
for (int i = 0; i < arrSize; i++) {
if (*(arr + i) > 0) {
size++;
}
}
int *newArray = new int[size];
for (int i = 0; i < arrSize; i++) {
if (*(arr + i) > 0) {
newArray[counter] = *(arr + i);
counter++;
}
}
delete[] outPosArr;
outPosArr = newArray;
outPosArrSize = size;
delete[] newArray;
newArray = nullptr;
}
void getPosNums4(int* arr, int arrSize, int** outPosArrPtr, int* outPosArrSizePtr){
int size = 0, counter = 0, newArraySize = 0;
for (int i = 0; i < arrSize; i++) {
if (*(arr + i) > 0) {
newArraySize ++;
}
}
int* temp = new int[newArraySize];
for (int i = 0; i < arrSize; i++) {
if (*(arr + i) > 0) {
temp[counter] = arr[i];
size++;
counter++;
}
}
*outPosArrSizePtr = size;
*outPosArrPtr = temp;
}
void printNewArray(int* arr, int arrSize) {
for (int i = 0; i < arrSize; i++)
cout << arr[i] << " ";
cout << endl;
}
void fillArray(int a[], int size) {
cout << "Enter " << size << " integers." << endl;
for (int i = 0; i < size; i++)
cin >> a[i];
}
The code in question is
void getPosNums3(int* arr, int arrSize, int*& outPosArr, int& outPosArrSize){
// [snip] count number of positive entries in arr and call it "size"
int *newArray = new int[size];
// [snip] copy positive entries in arr into newArray
delete[] outPosArr;
outPosArr = newArray;
outPosArrSize = size;
delete[] newArray;
newArray = nullptr;
}
First of all, it's not a good idea for this function to delete[] outPosArr because that presumes that outPosArr is either nullptr or something that was previously allocated with new[]. If it isn't one of those two things then this function has undefined behavior.
Somebody calling a function to copy numbers into an array is not typically going to also want the function to clean up some previous thing that may or may not have been in that array.
But your real problem is that you allocate memory for an array via int *newArray = new int[size], copy stuff in, and then immediately deallocate that memory by calling delete[] newArray. This leaves outPosArr to point to what used to be an array.
Also, assigning nullptr to newArray at the end of the function does nothing, because newArray is going out of scope anyway.
I am new, not that good with functions, and I am trying to solve this question:
Suppose A, B, C are arrays of integers of size [M], [N], and [M][N], respectively. The user will enter the values for the array A and B. Write a user defined function in C++ to calculate the third array C by adding the elements of A and B. If the elements have the same index number, they will be multiplied. C is calculated as the following: -
Use A, B and C as arguments in the function.
Below is my attempt at the problem.
#include<iostream>
using namespace std;
void Mix(int(&A)[], int(&B)[], int(&C)[][100], int N, int M);
//dont understand why you used Q
int main()
{
//variable declaration
int A[100], B[100], C[100][100], n, m, l = 0;
//input of size of elements for first ararys
cout << "Enter number of elements you want to insert in first array: ";
cin >> n;
cout << "-----------------" << endl;
cout << "-----------------" << endl;
cout << "Enter your elements in ascending order" << endl;
//input the elements of the array
for (int i = 0; i < n; i++)
{
cout << "Enter element " << i + 1 << ":";
cin >> A[i];
}
cout << endl << endl;
//input of size of elements for first ararys
cout << "Enter number of elements you want to insert in second array: ";
cin >> m;
cout << "-----------------" << endl;
cout << "-----------------" << endl;
cout << "Enter your elements in descending order" << endl;
//input the elements of the array
for (int i = 0; i < m; i++)
{
cout << "Enter element " << i + 1 << ":";
cin >> B[i];
}
Mix(A, B, C, n, m);
cout << "\nThe Merged Array in Ascending Order" << endl;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++)
{
cout << C[i][j] << " ";
}
cout << "\n"; //endline never use endl its 10 times slower
}
system("pause");
return 0;
}
void Mix(int(&A)[], int(&B)[], int(&C)[][100], int N, int M)
{
// rows is the index for the B array, cols is index for A array
int rows = 0;
int cols = 0;
while (rows < M) {
while (cols < N) {
if (rows == cols) { // remember ==
C[rows][cols] = B[rows] * A[cols];
}
else {
C[rows][cols] = B[rows] + A[cols];
}
cols++; // increment here
}
rows++; // increment here
}
return;
}
Here is an example of the output:
enter image description here
In order to make the C array two-dimensional, it needs to be expressed as C[100][100], instead of C[200]. That is the first step. Next, in your Mix() function, you need to cycle through each element of both A and B (ex. two for loops). Your rows change as B changes, and your columns change as A changes. Include a check for identical indices that will determine whether to add or multiply the two values together.
void Mix(int A[], int B[], int C[][], int N, int M) {
// rows is the index for the B array, cols is index for A array
for (int rows = 0; rows < M; rows++) {
for (int cols = 0; cols < N; cols++) {
if (rows == cols) { // remember ==
C[rows][cols] = B[rows] * A[cols];
} else {
C[rows][cols] = B[rows] + A[cols];
}
}
}
}
Make sure your arrays are properly defined and print out the C array by row and column to match the specifications.
UPDATE: If you want to use while loops, I would default to deconstructing the for loops and apply the same logic:
void Mix(int A[], int B[], int C[][], int N, int M) {
// rows is the index for the B array, cols is index for A array
int rows = 0;
int cols = 0;
while (rows < M) {
while (cols < N) {
if (rows == cols) { // remember ==
C[rows][cols] = B[rows] * A[cols];
} else {
C[rows][cols] = B[rows] + A[cols];
}
cols++; // increment here
}
rows++; // increment here
}
}
I would definitely recommend the for loop approach, as it is more compact, yet does the exact same operations.
There are a lot of things wrong with your code. First off an 2D array must be declared with 2 squared brackets so C[200][200]. In the Mix function the logical operator is == not = in if (A[I] = B[J])
Anyway here's the function that you need:
#include<iostream>
using namespace std;
void Mix(int A[], int B[], int C[], int N, int M) {
//dont understand why you used Q
int i, j;
for(i=0; i<N; i++) {
for(j=0; j<M; j++) {
if(i==j){
C[i][j] = A[i] * B[j];
}
else {
C[i][j] = A[i] + B[j];
}
}
}
return C[i][j];
}
int main()
{
//variable declaration
int A[100], B[100], C[200], j, i, n, m, l = 0;
string Comma;
//input of size of elements for first ararys
cout << "Enter number of elements you want to insert in first array: ";
cin >> n;
cout << "-----------------" << endl;
cout << "-----------------" << endl;
cout << "Enter your elements in ascending order" << endl;
//input the elements of the array
for (i = 0; i < n; i++)
{
cout << "Enter element " << i + 1 << ":";
cin >> A[i];
}
cout << endl << endl;
//input of size of elements for first ararys
cout << "Enter number of elements you want to insert in second array: ";
cin >> m;
cout << "-----------------" << endl;
cout << "-----------------" << endl;
cout << "Enter your elements in descending order" << endl;
//input the elements of the array
for (j = 0; j < m; j++)
{
cout << "Enter element " << j + 1 << ":";
cin >> B[j];
}
C = Mix(A, B, C, n, m);
cout << "\nThe Merged Array in Ascending Order" << endl;
for(i=0; i<n; i++) {
for(j=0; j<m; j++) {
cout<<C[i][j]<<" ";
}
cout<<"\n" //endline never use endl its 10 times slower
}
system("pause");
return 0;
}
Because M and N are defined at run time, you'll really want to use vectors to represent them. Additionally consider returning a 2D container so as to leverage return value optimization.
I'm going to write an example using a vector of vectors for simplicity (see What are the Issues with a vector-of-vectors? for more on why that's really just good for a toy example):
vector<vector<int>> Mix(const vector<int>& A, const vector<int>& B) {
vector<vector<int>> result(size(B), vector<int>(size(A)));
for(size_t i = 0U; i < size(B); ++i) {
for(size_t j = 0U; j < size(A); ++j) {
result[i][j] = A[j] * B[i];
}
}
return result;
}
Live Example
EDIT:
If you must use arrays you'll miss out on return value optimization. I'd only choose this as a good option in the situations:
That you weren't returning anything, in which case your function would probably look something like:
void Mix(const int* A, const int* B, const size_t size_A, const size_t size_B)
{
for(size_t i = 0U; i < size_B; ++i) {
for(size_t j = 0U; j < size_A; ++j) {
cout << '[' << i << "][" << j << "]: " << A[j] * B[i] << '\t';
}
cout << endl;
}
}
That you weren't calling a function and you'd already been given int A[M] and int B[N] as inputs and int C[N][M] as an output, in which case the code you'd inline would probably look something like this:
for(size_t i = 0U; i < size(B); ++i) {
for(size_t j = 0U; j < size(A); ++j) {
C[i][j] = A[j] * B[i];
}
}
I wrote a program to accept 15 integer values in an array, then pass this array to a function which will multiply each even index value by 4.
Currently the program displays the initial array, but seems like it's getting hung up before it displays the modified array.
Please help me understand why the program is getting stuck here!
int main(){
const int SIZE = 15;
int quad[SIZE] = {};
void quadruple(int[], const int);
cout << "Enter 15 integer values into an array." << endl;
for (int i = 0; i < SIZE; i++) // Accept 15 int values
{
cout << i << ": ";
cin >> quad[i];
}
cout << "Before quadruple function is called: " << endl;
for (int i = 0; i < SIZE; i++)
{
cout << quad[i] << " ";
}
cout << endl;
quadruple(quad, SIZE);
cout << "After even index value multiplication: " << endl;
for (int i = 0; i < SIZE; i++)
{
cout << quad[i] << " ";
}
cout << endl;
return 0;
}
void quadruple(int values[], const int SZ){
for (int i = 0; i < SZ; i + 2) // Multiply even values by 4
{
if ((i % 2) == 0)
{
values[i] = values[i] * 4;
}
else // Keep odd values the same
{
values[i] = values[i] * 1;
}
}
}
for (int i = 0; i < SZ; i + 2)
"i + 2" doesn't do anything.
You probably meant "i += 2;".
Your homework assignment is to find some documentation about your system's debugger. And find where your rubber duck is, as it's been suggested in the comments.
Why do I get a program crash for large values but not small values for my program? If I input 1-3 the program does what it is supposed to but when I enter a number greater than that the program crashes and/or does not complete? Is it something to do with a pointer error or the way I've referenced something? I'm unsure so any help is appreciated. Thanks!
Code:
#include <iostream>
using namespace std;
void getData (int size, int *Arr){
cout << "\n\nEnter integer data one line at a time\n" << endl ;
for (int i=0; i < size; i++){
cin >> Arr[i];
}
}
void findMinAndMax(int array[], int size, int *min, int *max) {
int smallest = array[0];
int largest = array[0];
*min = smallest;
*max = largest;
for (int i = 1; i < size; i++)
{
if (array[i] > *max){
*max = array[i];
cout << "Max Value (loop): " << *max << endl;
}
if (array[i] < *min){
*min = array[i];
cout << "Min Value (loop): " << *max << endl;
}
}
// testing code
cout << "Min Value: " << *min << endl;
cout << "Max Value: " << *max << endl;
}
int *makeFrequency (int data[], int dSize, int *minDataValue, int *maxDataValue) {
cout << "Min Value Pre: " << *minDataValue << endl;// testing code
cout << "Max Value Pre: " << *maxDataValue << endl;// testing code
findMinAndMax(data, dSize, minDataValue, maxDataValue);
cout << "Min Value Post: " << *minDataValue << endl; // testing code
cout << "Max Value Post: " << *maxDataValue << endl;// testing code
int fSize = *minDataValue + *maxDataValue;
cout << "fSize: " << fSize << endl; // testing code
int *frequency;
frequency = new int [fSize];
// if frequency is 0, end
if (frequency == 0)
{
return 0;
}
// set all elements to 0 in array frequency
for (int i = 0; i <= fSize; i++) {
frequency[i] = 0;
}
for (int i = 0; i <= dSize; i++) {
int j = data[i] - (*minDataValue) + 1;
frequency[j] = frequency[j] + 1;
}
return frequency;
}
void makeHistogram (int *freq, int min, int max ){
cout << "Frequency Value HISTOGRAM: " << *freq << endl;
cout << "\n\n\n ----------- Histogram ----------------\n" << endl;
int size = min + max;
cout << "Size Value HISTOGRAM: " << size << endl;
for (int i = 0; i < size; i++){
if (freq[i] > 0) {
cout << "\n" << min + i - 1 << ": ";
for (int j = 0; j < freq[i]; j++) {
cout << '*';
}
}
}
cout << endl << endl;
}
int main() {
int dSize;
int *ArrayOfInts;
cout << "How many data values? ";
cin >> dSize;
ArrayOfInts = new int [dSize];
getData(dSize, ArrayOfInts);
int *frequency, min, max;
frequency = makeFrequency(ArrayOfInts, dSize, &min, &max);
if (frequency == 0) return -1;
cout << "Min Value MAIN: " << min << endl; // testing code
cout << "Max Value MAIN: " << max << endl; // testing code
cout << "Frequency Value MAIN: " << *frequency << endl;
makeHistogram(frequency, min, max);
delete [] frequency;
return 0;
}
One place where you have undefined behaviour which can cause crashes:
here you allocate fSize elements:
frequency = new int [fSize];
later you iterate it until fSize:
for (int i = 0; i <= fSize; i++) {
you should change to i < fSize, because there is no fSize element in your array. And the same problem with i <= dSize later on. Should be i < dSize.
btw. I dont see why only large values should cause crashes in your code, maybe this is just UB.
You're setting fSize incorrectly. It should be the difference between the maximum and minimum values, not the sum of them. Otherwise, if you have negative numbers in your list, the frequency array will be too small. And if absolute value of any of the negative numbers is larger than the highest number, fSize will be negative, which is not valid for the size of an array.
Then you need to add 1 to include both endpoints. So it should be:
int fSize = *maxDataValue - *minDataValue + 1;
Then, as the other answer pointed out, you need to fix your for loops. When the size of an array is N, the array indexes from from 0 to N-1. So it should be:
for (int i = 0; i < fSize; i++) {
using < as the loop test, not <=. If you try to write outside an array, you invoke undefined behavior, so anything can happen -- if you're lucky you get a crash, but that's not guaranteed.
You have a similar problem when you assign to frequency:
for (int i = 0; i <= dSize; i++) {
int j = data[i] - (*minDataValue) + 1;
frequency[j] = frequency[j] + 1;
}
There's no need to add 1 when subtracting *minDataValue, and doing so will cause you to go outside the array when data[i] is the maximum.
I am Having Problem with Passing a 2D array to a c++ Function. The function is supposed to print the value of 2D array. But getting errors.
In function void showAttributeUsage(int)
Invalid types for int(int) for array subscript.
I know the problem is with the syntax in which I am passing the particular array to function but I don't know how to have this particular problem solved.
Code:
#include <iostream>
using namespace std;
void showAttributeUsage(int);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
int attVal[qN][aN];
cout << "\nEnter Attribute Usage Values" << endl;
for(int n = 0; n < qN; n++) { //for looping in queries
cout << "\n\n***************** COLUMN " << n + 1 << " *******************\n\n";
for(int i = 0; i < aN; i++) { //for looping in Attributes
LOOP1:
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if((attVal[n][i] > 1) || (attVal[n][i] < 0)) {
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
goto LOOP1; //if wrong input value
}
}
}
showAttributeUsage(attVal[qN][aN]);
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
getch();
return 0;
}
void showAttributeUsage(int att)
{
int n = 0, i = 0;
while(n != '\0') {
while(i != '\0') {
cout << att[n][i] << " ";
i++;
}
cout << endl;
n++;
}
}
I really suggest to use std::vector : live example
void showAttributeUsage(const std::vector<std::vector<int>>& att)
{
for (std::size_t n = 0; n != att.size(); ++n) {
for (std::size_t i = 0; i != att.size(); ++i) {
cout << att[n][i] << " ";
}
cout << endl;
}
}
And call it that way:
showAttributeUsage(attVal);
Looking at your code, I see no reason why you can't use std::vector.
First, your code uses a non-standard C++ extension, namely Variable Length Arrays (VLA). If your goal is to write standard C++ code, what you wrote is not valid standard C++.
Second, your initial attempt of passing an int is wrong, but if you were to use vector, your attempt at passing an int will look almost identical if you used vector.
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
typedef std::vector<int> IntArray;
typedef std::vector<IntArray> IntArray2D;
using namespace std;
void showAttributeUsage(const IntArray2D&);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
IntArray2D attVal(qN, IntArray(aN));
//... Input left out ...
showAttributeUsage(attVal);
return 0;
}
void showAttributeUsage(const IntArray2D& att)
{
for_each(att.begin(), att.end(),
[](const IntArray& ia) {std::copy(ia.begin(), ia.end(), ostream_iterator<int>(cout, " ")); cout << endl;});
}
I left out the input part of the code. The vector uses [] just like a regular array, so no code has to be rewritten once you declare the vector. You can use the code given to you in the other answer by molbdnilo for inputing the data (without using the goto).
Second, just to throw it into the mix, the showAttributeUsage function uses the copy algorithm to output the information. The for_each goes throw each row of the vector, calling std::copy for the row of elements. If you are using a C++11 compliant compiler, the above should compile.
You should declare the function like this.
void array_function(int m, int n, float a[m][n])
{
for (int i = 0; i < m; i++)
for (int j = 0; j < n; j++)
a[i][j] = 0.0;
}
where you pass in the dimensions of array.
This question has already been answered here. You need to use pointers or templates. Other solutions exists too.
In short do something like this:
template <size_t rows, size_t cols>
void showAttributeUsage(int (&array)[rows][cols])
{
for (size_t i = 0; i < rows; ++i)
{
std::cout << i << ": ";
for (size_t j = 0; j < cols; ++j)
std::cout << array[i][j] << '\t';
std::cout << std::endl;
}
}
You're using a compiler extension that lets you declare arrays with a size determined at runtime.
There is no way to pass a 2D array with such dimensions to a function, since all but one dimension for an array as a function parameter must be known at compile time.
You can use fixed dimensions and use the values read as limits that you pass to the function:
const int max_queries = 100;
const int max_attributes = 100;
void showAttributeUsage(int array[max_queries][max_attributes], int queries, int attributes);
int main()
{
int attVal[max_queries][max_attributes];
int qN = 0;
int aN = 0;
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
cout << "\nEnter Attribute Usage Values" << endl;
for (int n = 0; n < qN; n++)
{
cout << "\n\n***************** COLUMN " << n + 1 <<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad_input = true;
while (bad_input)
{
bad_input = false; // Assume that input will be correct this time.
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad_input = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal, qN, aN);
getch();
return 0;
}
void showAttributeUsage(int att[max_queries][max_attributes], int queries, int attributes)
{
for (int i = 0; i < queries; i++)
{
for (int j = 0; j < attributes; j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
For comparison, the same program using std::vector, which is almost identical but with no size limitations:
void showAttributeUsage(vector<vector<int> > att);
int main()
{
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
vector<vector<int> > attVal(qN, vector<int>(aN));
cout << "\nEnter Attribute Usage Values"<<endl;
for (int n = 0; n < qN; n++)
{
cout<<"\n\n***************** COLUMN "<<n+1<<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad = true;
while (bad)
{
bad = false;
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal);
getch();
return 0;
}
void showAttributeUsage(vector<vector<int> > att);
{
for (int i = 0; i < att.size(); i++)
{
for (int j = 0; j < att[i].size(); j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
The Particular Logic worked for me. At last found it. :-)
int** create2dArray(int rows, int cols) {
int** array = new int*[rows];
for (int row=0; row<rows; row++) {
array[row] = new int[cols];
}
return array;
}
void delete2dArray(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
delete [] ar[row];
}
delete [] ar;
}
void loadDefault(int **ar, int rows, int cols) {
int a = 0;
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
ar[row][col] = a++;
}
}
}
void print(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
cout << " | " << ar[row][col];
}
cout << " | " << endl;
}
}
int main () {
int rows = 0;
int cols = 0;
cout<<"ENTER NUMBER OF ROWS:\t";cin>>rows;
cout<<"\nENTER NUMBER OF COLUMNS:\t";cin>>cols;
cout<<"\n\n";
int** a = create2dArray(rows, cols);
loadDefault(a, rows, cols);
print(a, rows, cols);
delete2dArray(a, rows, cols);
getch();
return 0;
}
if its c++ then you can use a templete that would work with any number of dimensions
template<typename T>
void func(T& v)
{
// code here
}
int main()
{
int arr[][7] = {
{1,2,3,4,5,6,7},
{1,2,3,4,5,6,7}
};
func(arr);
char triplestring[][2][5] = {
{
"str1",
"str2"
},
{
"str3",
"str4"
}
};
func(triplestring);
return 0;
}