I am creating a dynamic array of LPCWSTR, and want to assign values at run time.
I have following code :
cin>>count
LPCWSTR * lpwcstrArray = new LPCWSTR[count]();
for (int i = 0; i < count; i++)
{
// some logic to create different wstring on each iteration
wstring tempWString = L"somerandomstuff";
lpwcstrArray[i] = reinterpret_cast<LPSWSTR>tempWString.c_str();
}
Now if i access lpwcstrArray - all the indexs point at data of last string that was assigned.
I know this is not correct way to assign values, but i do not know the correct way.
wstring tempWString is created and destroyed with each iteration of the loop.
You have dangling pointers in your lpwcstrArray and are experiencing undefined behaviour when you access one of them.
You need to allocate the space yourself or use a std::wstring as the array type instead of a LPCWSTR.
You are storing pointers that point at the internals of temporary std::wstring objects. When those objects are destroyed on each loop iteration, your array is left with danging pointers. You need to dynamically allocate the individual strings instead, eg:
std::cin >> count
LPWSTR *lpwstrArray = new LPWSTR[count];
for (int i = 0; i < count; i++)
{
// some logic to create different wstring on each iteration
std::wstring tempWString = L"somerandomstuff";
LPWSTR str = new WCHAR[tempWString.length()+1];
const wchar_t *p = tempWString.c_str();
std::copy(p, p+tempWString.length(), str);
lpwstrArray[i] = str;
}
// use lpwstrArray as needed...
// don't forget to free the memory when you are done using it...
for (int i = 0; i < count; i++)
delete[] lpwstrArray[i];
delete[] lpwstrArray;
Depending on what you are really trying to accomplish, something more like the following would be safer, at least if you just need read-only access to the strings (which you likely do, as the C in LPCWSTR stands for const, so the user of the array is not going to be modifying them):
std::cin >> count
std::vector<std::wstring> wstrArray(count);
for (int i = 0; i < count; i++)
{
// some logic to create different wstring on each iteration
wstrArray[i] = L"somerandomstuff";
}
std::vector<LPWSTR> lpwstrArray(count);
for (int i = 0; i < count; i++)
lpwstrArray[i] = const_cast<wchar_t*>(wstrArray[i].c_str());
// use lpwstrArray as needed. if you need to pass it where an
// LPWSTR* is expected, you can use &lpwstrArray[0] for that...
// lpwstrArray and wstrArray will be freed automatically
// when they go out of scope...
Try the approach
std::wstring ws(_T("Hello"));
LPCTSTR lps= (LPCTSTR)(ws.c_str());
TRACE(lps);
Notes:
You should not use the W types directly (ex: LPCWSTR). Use the T types instead (ex: LPCTSTR). Why? Because they will automatically translate to the version they should be (LPCSTR for non-Unicode / ASCII; LPCWSTR for Unicode), depending on your project.
For the same reason you should surround your strings with _T() or precede them with an L.
Try to dive deep using "Go To Definition" successively beginning on LPCTSTR
See also the _tcscpy_s function documentation
Related
My program uses an external ocx library and receives data through it. The code below shows how it works.
VARIANT varArrItem, varArrData;
ocx_instance.GetItemArr(real, &varArrItem); // the library provides GetItemArr
// 1) receives data
long lLBound, lUBound;
VARIANT varItem, varData;
long index[2];
index[0] = 0;
index[1] = 0;
COleSafeArray* pSafeItemArr = (COleSafeArray*)&varArrItem; // 2) casts varArrItem to COleSafeArray
CString strItem;
CStringArray arrItem;
pSafeItemArr->GetLBound(1, &lLBound);
pSafeItemArr->GetUBound(1, &lUBound);
int nItemCnt = (lUBound - lLBound + 1);
for (int i = 0; i < nItemCnt; i++)
{
index[0] = i;
VariantInit(&varItem);
pSafeItemArr->GetElement(index, (void *)&varItem); // 3) gets its values using GetElement
strItem = varItem.bstrVal;
arrItem.Add(strItem);
VariantClear(&varItem);
}
A big problem of the program is that this code is run whenever new data arrives, which is quite often, and it consumes a lot of resources. So, I'd like to simplify the code and get just contents of varArrItem, as strings or an array of structs of strings, for example.
varArrItem.vt gives me 8204 and it's said that it consists of 8192(VT_ARRAY) and 12(VT_VARIANT). I'm stuck here and don't know what to do after this. How can I simply get what's in them? Is it possible to access to them without using COleSafeArray?
You don't NEED to use COleSafeArray, it is just a wrapper for convenience. You could just extract the SAFEARRAY* pointer directly from varArrItem and then use the SafeArray APIs directly: SafeArrayGet(L|U)Bound(), SafeArrayGetElement(), etc, though if performance is important then consider using SafeArrayAccessData() to access the VARIANT[] array directly, and thus its BSTR pointers. The less copying of data you do, the faster the code will run. The only copy of data this code actually needs to make is the assignment of the initial VARIANT and each CString you add to the CStringArray:
VARIANT varArray;
ocx_instance.GetItemArr(real, &varArray);
LPSAFEARRAY psa = varArrar.parray;
LONG lLBound, lUBound;
SafeArrayGetLBound(psa, 1, &lLBound);
SafeArrayGetUBound(psa, 1, &lUBound);
CStringArray arrItem;
VARIANT *varArrayData;
if (SUCCEEDED(SafeArrayAccessData(psa, (void**) &varArrayData)))
{
int nItemCnt = (lUBound - lLBound + 1);
for (int i = 0; i < nItemCnt; i++)
{
CString strItem = varArrayData[i].bstrVal;
arrItem.Add(strItem);
}
SafeArrayUnaccessData(psa);
}
I'm trying to allocate the exact size of the array here. However I need to initialize it before I calculate the size of the array. does anyone know what I should do now?
Thanks in advance!
b.t.w I'm making a hangman game, just for fun.
char letters[30];
strcpy(letters, word.c_str());
int wordLen = 0;
for (int i = 0; i < letters[i]; i++){
wordLen++;
}
It is not clear, what you are trying to do with that loop, and it looks very suspicious (you need to provide more information on what you are trying to do here for advise on how to fix it if necessary), but assuming it is correct your code can be fixed by eliminating that buffer and strcpy() call at all:
int wordLen = 0;
for (int i = 0; i < word[i]; i++){
wordLen++;
}
if you need a copy of variable word to modify, not changing original, then just create another std::string instance as a copy. There is no reason to create raw char array in your case.
Environment: Windows 7 pro x64, Microsoft Visual Studio 2015 Enterprise, Version 14.0.25424.00 Update 3
int testFunction()
{
std::string _orig = "[188 80% (1/2)O:152]";
std::string _orig2 = "[999 99% (1/1)O:999]";
char *orig = NULL;
char *orig2 = NULL;
orig = new char[_orig.length() + 1];
strcpy(orig, _orig.c_str());
orig2 = new char[_orig2.length() + 1];
strcpy(orig2, _orig2.c_str());
*orig++;
*orig2++;
int a = atoi(orig);
int b = atoi(orig2);
delete[] orig;
delete[] orig2;
return 0;
}
Running the above code crashes with the "_CrtIsValidHeapPointer(block)" error.
If I don't iterate (*orig++ and *orig2++), then no issues.
So my question is, how can I iterate through the pointers and then when I'm done doing what I need to do with them, delete[] them correctly?
You did not delete the pointers you allocated!
delete must be called on the original memory address returned by new. Since you did orig++, you cant delete the address being pointed at!
Iterating can be done with an index, and using array subscription to dereference:
orig[i] = 'a';
Which is the same as doing this:
*(orig+i) = 'a';
Or you can get another pointer onto the same data, and modify this one.
char* pOrig = orig;
++pOrig;
Why did you write
*orig++; // why dereferencing?
Just ++ by itself would do the iteration.
Avoid to use raw pointers. Your code can be simpler:
std::string orig = "[188 80% (1/2)O:152]";
std::string orig2 = "[999 99% (1/1)O:999]";
int a = atoi(orig.c_str() + 1);
int b = atoi(orig2.c_str() + 1);
Your mistake is that you try to delete the shifted pointers instead of the original pointers. As the result heap manager gets wrong allocated block information usually put before the allocated pointer and you got heap corruption.
how can I iterate through the pointers and then when I'm done doing what I need to do with them, delete[] them correctly?
Create a copy of the pointer:
char* orig = new char[size];
char* i = orig;
*i++ = 'a';
delete orig;
A perhaps more common idiom is to dereference a temporary:
for(int i = 0; i < size - 1; i++)
orig[i] = 'a';
I would love to [use std::string], but I need to use atoi(), which won't work on std::string
You are mistaken. atoi works with std::string just fine. Simply use std::string::c_str() just like you did with strcpy. There is absolutely no reason to allocate a block of memory with new.
int testFunction()
{
std::string _orig = "[188 80% (1/2)O:152]";
int a = 0;
for (std::string::iterator it = _orig.begin(); it != _orig.end(); ++it)
{
if (isdigit((char)*it))
a = (atoi(it._Ptr));
}
return 0;
}
I got it. Thanks for everyone who helped me come to this conclusion. Staying with std::string was in fact the best approach.
I created a function that returns an error code (ErrCode enum) and pass two output parameters. But when I print the result of the function, I don't get the correct values in the array.
// .. some codes here ..
ErrCode err;
short lstCnt;
short lstArr[] = {};
err = getTrimmedList(lstArr, &lstCnt);
// list returned array (for comparison)
for (int i=0; i<lstCnt; ++i)
printf("lstArr[%3d] = %d", i, lstArr[i]);
// .. some codes here ..
The getTrimmedList function is like this:
ErrCode getTrimmedList(short* vList, short* vCnt)
{
short cnt;
ErrCode err = foo.getListCount(FOO_TYPE_1, &cnt);
if (NoError!=err) return err;
short* list = new short [cnt];
short total = 0;
for (short i=0; i<cnt; ++i)
{
FooBar bar = foo.getEntryByIndex(FOO_TYPE_1, i);
if (bar.isDeleted) continue;
list[total] = i;
++total;
}
*vCnt = total;
//vList = (short*)realloc(index, sizeof(short)*total);
vList = (short*)malloc(sizeof(short)*total);
memcpy(vList, list, sizeof(short)*total)
// list returned array (for comparison)
for (int i=0; i<lstCnt; ++i)
printf("lstArr[%3d] = %d", i, lstArr[i]);
return NoError;
}
where:
foo is an object that holds arrays of FooBar objects
foo.getListCount() returns the number of objects with type FOO_TYPE_1
FOO_TYPE_1 is the type of object we want to take/list
foo.getEntryByIndex() returns the ith FooBar object with type FOO_TYPE_1
bar.isDeleted is a flag that tells if bar is considered as 'deleted' or not
What's my error?
Edit:
Sorry, I copied a wrong line. I commented it above and put the correct line.
Edit 2
I don't have control over the returns of foo and bar. All their function returns are ErrCode and the outputs are passed through parameter.
Couple of questions before I can answer your post...
Where is "index" defined in:
vList = (short*)realloc(index, sizeof(short)*total);
Are you leaking the memory associated with:
short* list = new short [cnt];
Is it possible you have accidentally confused your pointers in memory allocation? In any case, here is an example to go from. You have a whole host of problems, but you should be able to use this as a guide to answer this question as it was originally asked.
WORKING EXAMPLE:
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
int getTrimmedList(short** vList, short* vCnt);
int main ()
{
// .. some codes here ..
int err;
short lstCnt;
short *lstArr = NULL;
err = getTrimmedList(&lstArr, &lstCnt);
// list returned array (for comparison)
for (int i=0; i<lstCnt; ++i)
printf("lstArr[%3d] = %d\n", i, lstArr[i]);
// .. some codes here ..
return 0;
}
int getTrimmedList(short** vList, short* vCnt)
{
short cnt = 5;
short* list = new short [cnt];
short* newList = NULL;
short total = 0;
list[0] = 0;
list[1] = 3;
list[2] = 4;
list[3] = 6;
total = 4;
*vCnt = total;
newList = (short*)realloc(*vList, sizeof(short)*total);
if ( newList ) {
memcpy(newList, list, sizeof(short)*total);
*vList = newList;
} else {
memcpy(*vList, list, sizeof(short)*total);
}
delete list;
return 0;
}
You have serious problems.
For starters, your function has only one output param as you use it: vCnt.
vList you use as just a local variable.
realloc is called with some index that we kow nothing about, not likely good. It must be something got from malloc() or realloc().
The allocated memory in vList is leaked as soon as you exit getTrimmedList.
Where you call the function you pass the local lstArr array as first argument that is not used for anything. Then print the original, unchanged array, to bounds in cnt, while it has 0 size still -- behavior is undefined.
Even if you managed to pass that array by ref, you could not reassign it to a different value -- C-style arrays can't do that.
You better use std::vector that you can actually pass by reference and fill in the called function. eliminating the redundant size and importantly the mess with memory handling.
You should use std::vector instead of raw c-style arrays, and pass-by-reference using "&" instead of "*" here. Right now, you are not properly setting your out parameter (a pointer to an array would look like "short **arr_ptr" not "short *arr_ptr", if you want to be return a new array to your caller -- this API is highly error-prone, however, as you're finding out.)
Your getTrimmedList function, therefore, should have this signature:
ErrCode getTrimmedList(std::vector<short> &lst);
Now you no longer require your "count" parameters, as well -- C++'s standard containers all have ways of querying the size of their contents.
C++11 also lets you be more specific about space requirements for ints, so if you're looking for a 16-bit "short", you probably want int16_t.
ErrCode getTrimmedList(std::vector<int16_t> &lst);
It may also be reasonable to avoid requiring your caller to create the "out" array, since we're using smarter containers here:
std::vector<int16_t> getTrimmedList(); // not a reference in the return here
In this style, we would likely manage errors using exceptions rather than return-codes, however, so other things about your interface would evolve, as well, most likely.
I'm relatively new to C++ memory management, and I'm getting this weird error of heap corruption (plus an automatic breakpoint in Visual Studio before it). Here is the offending code:
z_world::z_world(char* name)
{
unsigned int i, skip;
char tmp;
//Load data from file
std::string* data = loadString(name);
//Base case if there is no world data
tiles = NULL;
w = 0;
h = 0;
if(data->length() > 0) {
//Set up the 'tiles' array
for(i = 0; i < data->length(); i++) {
if(data->at(i) == '\n')
h++;
if(h == 0)
w++;
}
tiles = new int[data->length()-h];
//Load Data
skip = 0;
for(i = 0; i < data->length(); i++) {
if(data->at(i) == '\n') {
skip++;
printf("\n");
continue;
}
tmp = data->at(i);
tiles[i+skip] = atoi(&tmp);
printf("%i ",tiles[i+skip]);
}
}
delete data;
}
Here's where I load in the string:
std::string* loadString(char* name)
{
ifstream in(name);
std::string* input = new string();
while(in) {
std::string line;
getline(in,line);
input->append(line);
input->append("\n");
}
in.close();
return input;
}
I get the breakpoint and error inside of "delete data;", which makes me think that "data" gets deleted somewhere before that, but I can't find where it would. For reference, this method is to create an object that contains world data for a game in the form of a virtual 2D integer array (for the ID's of the tiles).
Youre problem is probably here:
tiles[i+skip] = atoi(&tmp);
Problem 1:
It should be -skip
tiles[i - skip] =
Problem 2:
The atoi() command is being used incorrectly (tmp does not contain a string). But also I don't think atoi() is the appropriate method. I think what you are looking for is simple assignment. The conversion from char to int is automatic:
tiles[i - skip] = tmp;
Problem 3:
You are not using objects correctly. In this situation there is no need to generate dynamic objects and create a mess with dynamic memory management. It would be simpler to just to create automatic objects and pass those back normally:
std::string* loadString(char* name)
// ^ Don't do this.
std::string loadString(std::string const& name)
// ^^^^^^^ return a string by value.
// The compiler will handle memory management very well.
In general you should not be passing pointers around. In the few situations where you do need pointers they should be held within a smart pointer object or containers (for multiple objects) so that their lifespan is correctly controlled.
atoi(&tmp);
atoi expects a pointer to a null terminated string - not a pointer to a char
There's no need to dynamically allocate the string in the code you've shown. Change the loadString function to
std::string loadString(char* name)
{
ifstream in(name);
std::string input;
// ...
return input;
}
In the caller
std::string data = loadString( name );
Now there's no need to delete the string after you're done.
Instead of
int *tiles = NULL;
tiles = new int[data->length()-h];
use
std::vector<int> tiles;
tiles.resize(data.length() - h);
Also, if you do need to dynamically allocate objects you should be using smart pointers (std::unique_ptr and std::shared_ptr) instead of raw pointers.
There is a bug in
tiles[i+skip] = atoi(&tmp);
For example, for a string
Hello\n
World\n
and for the loop iteration at the point of i == 10, skip is already 1 (since we have encountered the first \n before) and you are writing to tiles[10 + 1], but tiles only has been allocated as an array with 10 elements.
May be the variable input is local to this function. So after returning from this the memory is freed. So, calling later delete on this string tries to free already freed memory.