I have this kind of text:
0
4.496
4.496
Plain text.
7.186
Plain text
10.949
Plain text
12.988
Plain text
16.11
Plain text
17.569
Plain text
ESP:
Plain text
I am trying to make a sed substitution because I need all aligned after the numbers, something like:
0
4.496
4.496 Plain text.
7.186 Plain text
10.949 Plain text
12.988 Plain text
16.11 Plain text
17.569 Plain text ESP:Plain text
But I'm trying with different combinations of commands with sed but I can't keep a part of the matching pattern
sed -r 's/\([0-9]+\.[0-9]*\)\s*/\1/g'
I am trying to remove all \n after the numbers and align the text, but it does not work. I need to align text with text too.
I tried this as well:
sed -r 's/\n*//g'
But without results.
Thank you
This is a bit tricky. Your approach does not work because sed operates in a line-based manner (it reads a line, runs the code, reads another line, runs the code, and so forth), so it doesn't see the newlines unless you do special things. We'll have to completely override sed's normal control flow.
With GNU sed:
sed ':a $!{ N; /\n[0-9]/ { P; s/.*\n//; }; s/\n/ /; ba }' filename
This works as follows:
:a # Jump label for looping (we'll build our own loop, with
# black jack and...nevermind)
$! { # Unless the end of the input was reached:
N # fetch another line, append it to what we already have
/\n[0-9]/ { # if the new line begins with a number (if the pattern space
# contains a newline followed by a number)
P # print everything up to the newline
s/.*\n// # remove everything before the newline
}
s/\n/ / # remove the newline if it is still there
ba # go to a (loop)
}
# After the end of the input we drop off here and implicitly
# print the last line.
The code can be adapted to work with BSD sed (as found on *BSD and Mac OS X), but BSD sed is a bit picky about labels and jump instructions. I believe
sed -e ':a' -e '$!{ N; /\n[0-9]/ { P; s/.*\n//; }; s/\n/ /; ba' -e '}' filename
should work.
This gnu-awk command can also handle this:
awk -v RS= 'BEGIN{ FPAT="(^|\n)[0-9]+(\\.[0-9]+)?(\n[^0-9][^\n]*)*" }
{for (i=1; i<=NF; i++) {f=$i; sub(/^\n/, "", f); gsub(/\n/, " ", f); print f}}' file
0
4.496
4.496 Plain text.
7.186 Plain text
10.949 Plain text
12.988 Plain text
16.11 Plain text
17.569 Plain text ESP: Plain text
sed -n '1h;1!H;$!b
x;s/\n\([^0-9]\)/ \1/gp' YourFile
-n: print only at demand
'1h;1!H;$!b;xload the whole file in buffer until the end (at the end the whole file is in work buffer)
s/\n\([^0-9]\)/ \1/gp: replace all new line followed by a non digit character by a space character and print the result.
This might work for you (GNU sed):
sed ':a;N;s/\n\([[:alpha:]]\)/ \1/;ta;P;D' file
Process two lines at a time. If the second line begins with an alphabetic character, remove the preceeding newline and append another line and repeat. If the second line does not begin with an alphabetic character, print and then delete the first line and its newline. The second line now becomes the first line and the process repeats.
Related
Can't seem to find the right way to do this, despite checking my regex in a reg checker.
Given a text file containing, amongst others, this entry:
zone "example.net" {
type master;
file "/etc/bind/zones/db.example.net";
allow-transfer { x.x.x.x;y.y.y.y; };
also-notify { x.x.x.x;y.y.y.y; };
};
I want to add lines after the also-notify line, for that domain specifically.
So using this sed command string:
sed '/"example\.net".*?also-notify.*?};/a\nxxxxxxx/s' named.conf.local
I thought should work to add 'xxxxxxx' after the line. But nope. What am I doing wrong?
With POSIX sed, you can use the a for append command with an escaped literal new line:
$ sed '/^[[:blank:]]*also-notify/ a\
NEW LINE' file
With GNU sed, a is slightly more natural since the new line is assumed:
$ gsed '/^[[:blank:]]*also-notify/ a NEW LINE' file
The issue with the sed in your example is two fold.
The first is any sed regex cannot be for a multi-line match as in example\.net".*?also-notify.*?. That is more of a perl type match. You would need to use a range operator for the start as in:
$ sed '/"example\.net/,/also-notify/{
/^[[:blank:]]*also-notify/ a\
NEW LINE
}' file
The second issue is the \n in the appended text. With POSIX sed, the \n is not supported in any context. With GNU sed, the new line is assumed and the \n is out of context (if immediately after the a) and interpreted as an escaped literal n. You can use \n with GNU sed after 1 character but not immediately after. In POSIX sed, leading spaces of the appended line will always be stripped.
Following awk may help on this.
awk -v new_lines="new_line here" '/also-notify/{flag=1;print new_lines} /^};/{flag=""} !flag' Input_file
In case you want to edit Input_file itself then append > temp_file && mv temp_file Input_file to above code too. Also print new_lines here new_lines is a variable you could print the new liens directly too in there.
You're pretty close already. Just use a range (/pattern/,/pattern/{ #commands }) to select the text you want to operate on and then use /pattern/a/\ ... to add the line you want.
/"example\.net"/,/also-notify/{
/also-notify/a\
\ this is the text I want to add.
}
sed trims leading space on text to be appended. Adding a backslash \ at the start of the line prevents this.
In Bash, this would look like something like:
sed -e '/"example\.net"/,/also-notify/{
/also-notify/a\
\ this is the text I want to add.
}' named.conf.local
Also note that sed uses an older dialect of regular expressions that doesn't support non-greedy quantifies like *?.
Is it possible to merge multiple blocks/lines into a "single" line?
So basically if the next line starts with the same "#Msg" tag then append it to the previous line. (Hard to explain, but my example speaks for itself) (The blocks are separated by a new/blank line)
My input file looks like this:
#Msg,00000
#Msg,00001
#Msg,00002
#Msg,00003
#Msg,00004
#Msg,00005
#Msg,00006
#Msg,00007
#Msg,00008
#Msg,00009
#Msg,00010
#Msg,00011
Output should be like this:
#Msg,00000
#Msg,00001 #Msg,00002
#Msg,00003 #Msg,00004
#Msg,00005
#Msg,00006 #Msg,00007 #Msg,00008
#Msg,00009
#Msg,00010 #Msg,00011
Any advice is very welcome.
This would be pretty easy to do in Perl:
perl -00 -ple 'tr/\n/ /'
-e CODE specifies the program.
-p wraps a read/write line loop around it (by default it reads from STDIN, but you can also specify one or more filenames on the command line).
-00 specifies that the input "lines" are actually paragraphs.
-l has two effects: Incoming line terminators are automatically stripped from lines, and outgoing lines get line terminators added to them (and because we used -00 (paragraph mode), our line terminator is actually \n\n).
To recap:
We read the input one paragraph at a time. For each paragraph, we remove any trailing newlines. We then translate every newline to a space. Finally we output the transformed paragraph, followed by \n\n.
No point in trying to produce a shorter code than is possible with Perl!
Collect lines from the input file in list group until a blank line appears. Then output the contents of group, empty it and start again. When end-of-file is encountered output whatever is in group, if it is non-empty.
group = []
with open('vollschauer.txt') as vollschauer:
for line in vollschauer:
line = line.rstrip()
if line:
group.append(line)
else:
if group:
print (' '.join(group))
print()
group = []
if group:
print (' '.join(group))
group = []
$ awk -v RS= -v ORS='\n\n' '{$1=$1}1' file
#Msg,00000
#Msg,00001 #Msg,00002
#Msg,00003 #Msg,00004
#Msg,00005
#Msg,00006 #Msg,00007 #Msg,00008
#Msg,00009
#Msg,00010 #Msg,00011
If you insist on using sed, this should do the trick:
sed -r ':a; N; /^(#[^,]+,).*\n\1/! { P; D }; s/\n/ /; ba' file
It takes different tags into account. Such tags won't be grouped together (that's what I understood is the desired behavior):
$ cat file
#Msg,00000
#Msg,00001
#Hello,00002
#Hello,00003
#What,00004
#What,00005
$ sed -r ':a; N; /^(#[^,]+,).*\n\1/! { P; D }; s/\n/ /; ba' file
#Msg,00000 #Msg,00001
#Hello,00002
#Hello,00003
#What,00004 #What,00005
Note that this solution uses GNU sed.
This might work for you (GNU sed):
sed ':a;N;/^$/M!s/\n/ /;ta' file
Gather up lines, replacing each newline by a space until an empty line.
N.B. The use of the M flag on the repexp /^$/ which matches an empty line on a pattern space containing multiple lines.
I have several lines with certain values and i want to merge every second line or every line beginning with <name> to the end of the line ending with
<id>rd://data1/8b</id>
<name>DM_test1</name>
<id>rd://data2/76f</id>
<name>DM_test_P</name>
so end up with something like
<id>rd://data1/8b</id><name>DM_test1</name>
The reason why it came out like this is because i used two piped xpath queries
Regex
Simply remove the newline at the end of a line ending in </id>. On a windows, replace (<\/id>)\r\n with \1 or $1 (which is perl syntax). On a linux search for (<\/id>)\n and replace it with the same thing.
awk
The ideal solution uses awk. The idea is simply, when the line number is odd, we print the line without a newline, if not we print it with a newline.
awk '{ if(NR % 2) { printf $0 } else { print $0 } }' file
sed
Using sed we place a line in the hold space when it contains <id>ยด and append the line to it when it's a` line. Then we remove the newline and print the hold buffer by exchanging it with the pattern space.
sed -n '/<id>.*<\/id>/{h}; /<name>.*<\/name>/{H;x;s/\n//;p}' file
pr
Using pr we can achieve a similar goal:
pr -s --columns 2 file
I'd like to know if I can remove a \n (newline) only if the current line has one ore more keywords from a list; for instance, I want to remove the \n if it contains the words hello or world.
Example:
this is an original
file with lines
containing words like hello
and world
this is the end of the file
And the result would be:
this is an original
file with lines
containing words like hello and world this is the end of the file
I'd like to use sed, or awk and, if needed, grep, wc or whatever commands work for this purpose. I want to be able to do this on a lot of files.
Using awk you can do:
awk '/hello|world/{printf "%s ", $0; next} 1' file
this is an original
file with lines
containing words like hello and world this is the end of the file
here is simple one using sed
sed -r ':a;$!{N;ba};s/((hello|world)[^\n]*)\n/\1 /g' file
Explanation
:a;$!{N;ba} read whole file into pattern, like this: this is an original\nfile with lines\ncontaining words like hell\
o\nand world\nthis is the end of the file$
s/((hello|world)[^\n]*)\n/\1 /g search the key words hello or world and remove the next \n,
g command in sed substitute stands to apply the replacement to all matches to the regexp, not just the first.
A non-regex approach:
awk '
BEGIN {
# define the word list
w["hello"]
w["world"]
}
{
printf "%s", $0
for (i=1; i<=NF; i++)
if ($i in w) {
printf " "
next
}
print ""
}
'
or a perl one-liner
perl -pe 'BEGIN {#w = qw(hello world)} s/\n/ / if grep {$_ ~~ #w} split'
To edit the file in-place, do:
awk '...' filename > tmpfile && mv tmpfile filename
perl -i -pe '...' filename
This might work for you (GNU sed):
sed -r ':a;/^.*(hello|world).*\'\''/M{$bb;N;ba};:b;s/\n/ /g' file
This checks if the last line, of a possible multi-line, contains the required string(s) and if so reads another line until end-of-file or such that the last line does not contain the/those string(s). Newlines are removed and the line printed.
$ awk '{ORS=(/hello|world/?FS:RS)}1' file
this is an original
file with lines
containing words like hello and world this is the end of the file
sed -n '
:beg
/hello/ b keep
/world/ b keep
H;s/.*//;x;s/\n/ /g;p;b
: keep
H;s/.*//
$ b beg
' YourFile
a bit harder due to check on current line that may include a previous hello or world already
principle:
on every pattern match, keep the string in hold buffer
other wise, load hold buffer and remove \n (use of swap and empty the current line due to limited buffer operation available) and print the content
Add a special case of pattern in last line (normaly hold so not printed otherwise)
OCR texts often have words that flow from one line to another with a hyphen at the end of the first line. (ie: the word has '-\n' inserted in it).
I would like rejoin all such split words in a text file (in a linux environment).
I believe this should be possible with sed or awk, but the syntax for these is dark magic to me! I knew a text editor in windows that did regex search/replace with newlines in the search expression, but am unaware of such in linux.
Make sure to back up ocr_file before running as this command will modify the contents of ocr_file:
perl -i~ -e 'BEGIN{$/=undef} ($f=<>) =~ s#-\s*\n\s*(\S+)#$1\n#mg; print $f' ocr_file
This answer is relevant, because I want the words joined together... not just a removal of the dash character.
cat file| perl -CS -pe's/-\n//'|fmt -w52
is the short answer, but uses fmt to reform paragraphs after the paragraphs were mangled by perl.
without fmt, you can do
#!/usr/bin/perl
use open qw(:std :utf8);
undef $/; $_=<>;
s/-\n(\w+\W+)\s*/$1\n/sg;
print;
also, if you're doing OCR, you can use this perl one-liner to convert unicode utf-8 dashes to ascii dash characters. note the -CS option to tell perl about utf-8.
# 0x2009 - 0x2015 em-dashes to ascii dash
perl -CS -pe 'tr/\x{2009}\x{2010}\x{2011}\x{2012\x{2013}\x{2014}\x{2015}/-/'
cat file | perl -p -e 's/-\n//'
If the file has windows line endings, you'll need to catch the cr-lf with something like:
cat file | perl -p -e 's/-\s\n//'
Hey this is my first answer post, here goes:
'-\n' I suspect are the line-feed characters. You can use sed to remove these. You could try the following as a test:
1) create a test file:
echo "hello this is a test -\n" > testfile
2) check the file has the expected contents:
cat testfile
3) test the sed command, this sends the edited text stream to standard out (ie your active console window) without overwriting anything:
sed 's/-\\n//g' testfile
(you should just see 'hello this is a test file' printed to the console without the '-\n')
If I build up the command:
a) First off you have the sed command itself:
sed
b) Secondly the expression and sed specific controls need to be in quotations:
sed 'sedcontrols+regex' (the text in quotations isn't what you'll actually enter, we'll fill this in as we go along)
c) Specify the file you are reading from:
sed 'sedcontrols+regex' testfile
d) To delete the string in question, sed needs to be told to substitute the unwanted characters with nothing (null,zero), so you use 's' to substitute, forward-slash, then the unwanted string (more on that in a sec), then forward-slash again, then nothing (what it's being substituted with), then forward-slash, and then the scale (as in do you want to apply the edit to a single line or more). In this case I will select 'g' which represents global, as in the whole text file. So now we have:
sed 's/regex//g' testfile
e) We need to add in the unwanted string but it gets confusing because if there is a slash in your string, it needs to be escaped out using a back-slash. So, the unwanted string
-\n ends up looking like -\\n
We can output the edited text stream to stdout as follows:
sed 's/-\\n//g' testfile
To save the results without overwriting anything (assuming testfile2 doesn't exist) we can redirect the output to a file:
sed 's/-\\n//g' testfile >testfile2
sed -z 's/-\n//' file_with_hyphens