I have a list of text lines. Each line contains a title and a URL as follows:
product-title-7134 http://domain.com/page-1
another-product-title-822 http://domain.com/page-218
etc.
Using only .NET regex, please help me extract the url from each line.
I understand it can be done by looking at the string from the end until the http is met and output that part but I don't know the exact regex formula for that. Any help is much appreciated.
I would do that with this regex:
http://(\S+)
And find first group in every match.
This regex will math all https:// and http:// links:
(http|https)(://\S+)
You can test this in the .NET regex tester: http://regexstorm.net/tester
Related
I am trying to create a regex in pcre, that is going to salinize URL with multiple slashes like the following:
https://www.domin.com/test1/////test2/somemoretests_67142 https://www.domin.com/test1/test2/somemoretests_67142///// https://www.domin.com/test1/test2///somemoretests_67142
So that I can replace it with the following: https://\2\4 and the link at the end of it looks: https://www.domin.com/test1/test2/somemoretests_67142
I have been struggling with it for the past couple of days, so any regex guru help is more than welcome :)
I have tried the following and more:
(http|https):\/\/(.*)(\/\/+)(.*)
(http|https):\/\/(.*)(\/\/){2,}(.*)
(http|https):\/\/(.*)(\/\/{2})(.*)
I am going to utilize these for Akamai to sanitize our URLs though cloudlet.
You can try:
(?<!https:\/)(?<!http:\/)(\/+$|(?<=\/)\/+)
And substitute the first group with empty string.
Regex demo.
This will produce this output:
https://www.domin.com/test1/test2/somemoretests_67142
https://www.domin.com/test1/test2/somemoretests_67142
https://www.domin.com/test1/test2/somemoretests_67142
For Matomo outgoing link tracking I need the regex pattern, which matched the following URLs:
https://www.example.com/product/?sku=12345&utm_source=123456789
and
https://www.example.com/product/?utm_source=123456789
"https://www.example.com/" and "utm_source=123456789" are always fixed in the URL, just "product/" or "category/product/" change and must replaced by regex pattern.
Thanks
Maybe this example can help you reach your goal:
(?<=https:\/\/www\.example\.com\/).+(?=utm_source=123456789)
It looks for any characters between these two groups:
https://www.example.com/
utm_source=123456789
Given the examples:
https://www.example.com/product/?sku=12345&utm_source=123456789
https://www.example.com/product/?utm_source=123456789
Your matches would be:
product/?sku=12345&
product/?
I want to match shop name from a url .Please see the example below. Its for url redirection in a word press application.
See the examples given below
http://example.com/outlets/19-awok?page=2
http://example.com/outlets/19-awok
http://example.com/outlets/159-awok?page=3
In all cases i need to get only awok from the url .It will be the text coming after '-' and before query string .
I tried below and its not working
/outlets/(\d+)-(.*)? => /shop/$2
Any help will be greatly appreciated.
You can use this regex:
/outlets/\d+-([^?]+)?
Trailing ? is used to strip previous query string.
I have a challenge with a regex match to a url I hope I can bug some of you clever heads with :-)
Please take a look at this testcase https://www.regex101.com/r/bH4hE1/2
I use the regex: (\w+)(.\w+)+(?!.*(\w+)(.\w+)+)
Problem is, it only finds reports.html but I also need to find reports in the first url
https://my.website.com/reports?ref_=kdp_BS
https://my.website.com/reports.html
To capture "reports" or "reports.html" in any path, begin your match after the last /, and capture word characters and .:
/.*\/([.\w+]+)/
See: https://www.regex101.com/r/iZ7dF3/8
Try:
/([^\/?]+)(?:\?.+)?$/gim
It will work end selects:
reports
reports.html
I've searched around quite a bit now, but I can't get any suggestions to work in my situation. I've seen success with negative lookahead or lookaround, but I really don't understand it.
I wish to use RegExp to find URLs in blocks of text but ignore them when quoted. While not perfect yet I have the following to find URLs:
(https?\://)?(\w+\.)+\w{2,}(:[0-9])?\/?((/?\w+)+)?(\.\w+)?
I want it to match the following:
www.test.com:50/stuff
http://player.vimeo.com/video/63317960
odd.name.amazone.com/pizza
But not match:
"www.test.com:50/stuff
http://plAyerz.vimeo.com/video/63317960"
"odd.name.amazone.com/pizza"
Edit:
To clarify, I could be passing a full paragraph of text through the expression. Sample paragraph of what I'd like below:
I would like the following link to be found www.example.com. However this link should be ignored "www.example.com". It would be nice, but not required, to have "www.example.com and www.example.com" ignored as well.
A sample of a different one I have working below. language is php:
$articleEntry = "Hey guys! Check out this cool video on Vimeo: player.vimeo.com/video/63317960";
$pattern = array('/\n+/', '/(https?\:\/\/)?(player\.vimeo\.com\/video\/[0-9]+)/');
$replace = array('<br/><br/>',
'<iframe src="http://$2?color=40cc20" width="500" height="281" frameborder="0" webkitAllowFullScreen mozallowfullscreen allowFullScreen></iframe>');
$articleEntry = preg_replace($pattern,$replace,$articleEntry);
The result of the above will replace any new lines "\n" with a double break "" and will embed the Vimeo video by replacing the Vimeo address with an iframe and link.
I've found a solution!
(?=(([^"]+"){2})*[^"]*$)((https?:\/\/)?(\w+\.)+\w{2,}(:[0-9]+)?((\/\w+)+(\.\w+)?)?\/?)
The first part from (? to *$) what makes it work for me. I found this as an answer in java Regex - split but ignore text inside quotes? by https://stackoverflow.com/users/548225/anubhava
While I had read that question before, I had overlooked his answer because it wasn't the one that "solved" the question. I just changed the single quote to double quote and it works out for me.
add ^ and $ to your regex
^(https?\://)?(\w+\.)+\w{2,}(:[0-9])?\/?((/?\w+)+)?(\.\w+)?$
please notice you might need to escape the slashes after http (meaning https?\:\/\/)
update
if you want it to be case sensitive, you shouldn't use \w but [a-z]. the \w contains all letters and numbers, so you should be careful while using it.