I am trying to append a new XML node under existing XML node but i wasn't able to achieve the desired result.
Please find my below XML,
<Root>
<Row>
<A1>0</A1>
<A2>1</A2>
<Preferred_First_Name>aaaa</Preferred_First_Name>
<Preferred_Last_Name>yyyy</Preferred_Last_Name>
<location>xxxx</location>
<ID>12345</ID>
</Row>
</Root>
I want to modify the above XML in such a way that Preferred_First_Name, Preferred_Last_Name and location node need to be under a new XML tag "Data".
The desired output should be like below,
<Root>
<Row>
<A1>0</A1>
<A2>1</A2>
<Data>
<Preferred_First_Name>aaaa</Preferred_First_Name>
<Preferred_Last_Name>yyyy</Preferred_Last_Name>
<location Descriptor="xxxx">
<ID type="ID">xxxx</ID>
<ID type="LocationID">xxxx</ID>
</location>
</Data>
<ID>12345</ID>
</Row>
</Root>
Can someone please help?
you can use below
<?xml version="1.0" encoding="utf-16"?>
<xsl:stylesheet xmlns:xalan="http://xml.apache.org/xalan" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" version="1.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template match="Root">
<xsl:element name="Root">
<xsl:call-template name="Row" />
</xsl:element>
</xsl:template>
<xsl:template name="Row">
<xsl:element name="Row">
<xsl:copy-of select="Row/A1"/>
<xsl:copy-of select="Row/A2"/>
<xsl:element name="Data">
<xsl:copy-of select="Row/Preferred_First_Name"/>
<xsl:copy-of select="Row/Preferred_Last_Name"/>
<xsl:element name="location">
<xsl:attribute name="Descriptor">
<xsl:value-of select="Row/location"/>
</xsl:attribute>
<xsl:element name="ID">
<xsl:attribute name="type">
<xsl:value-of select="'ID'"/>
</xsl:attribute>
<xsl:value-of select="Row/location"/>
</xsl:element>
<xsl:element name="ID">
<xsl:attribute name="type">
<xsl:value-of select="'LocationID'"/>
</xsl:attribute>
<xsl:value-of select="Row/location"/>
</xsl:element>
</xsl:element>
<xsl:copy-of select="Row/ID"/>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Please let me know this helps you
If it is okay to put <ID> after <Data> mentioned by Tim C, then the optimized solution can be:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Row">
<Row>
<xsl:apply-templates select="child::node()[not(self::Preferred_First_Name or self::Preferred_Last_Name
or self::location)]" />
<Data>
<xsl:apply-templates select="child::node()[self::Preferred_First_Name or self::Preferred_Last_Name
or self::location]"/>
</Data>
</Row>
</xsl:template>
</xsl:stylesheet>
This is my transformation:
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/root">
<output>
<xsl:apply-templates select="outer[#type='foo']/inner"/>
</output>
</xsl:template>
<xsl:template match="outer[#type='foo']/inner[#type='bar1' or #type='bar2' or #type='bar3' or #type='bar4']">
<item>
<xsl:value-of select="text()"/>
</item>
</xsl:template>
<xsl:template match="outer[#type='foo']/inner">
<xsl:message terminate="yes">
<xsl:value-of select="concat('Unexpected type: ', #type)"/>
</xsl:message>
</xsl:template>
</xsl:transform>
This is my input:
<root>
<outer type="foo">
<inner type="bar2">bar2</inner>
</outer>
</root>
When I execute the transformation on the input, Xalan quits with a fatal error, which is caused by the <xsl:message terminate="yes"> in the third <xsl:template>. Why? Shouldn't the second, more specialized <xsl:template> match instead?
Another solution would be to simply have the 2 templates trade positions:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/root">
<output>
<xsl:apply-templates select="outer[#type='foo']/inner"/>
</output>
</xsl:template>
<xsl:template match="outer[#type='foo']/inner">
<xsl:message terminate="yes">
<xsl:value-of select="concat('Unexpected type: ', #type)"/>
</xsl:message>
</xsl:template>
<xsl:template match="outer[#type='foo']/inner[#type='bar1' or #type='bar2' or #type='bar3' or #type='bar4']">
<item>
<xsl:value-of select="text()"/>
</item>
</xsl:template>
</xsl:transform>
Although this is probably not clean, so you should rather leave the order as it was and explicitly set a prio higher than .5 to the more specialized template instead:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/root">
<output>
<xsl:apply-templates select="outer[#type='foo']/inner"/>
</output>
</xsl:template>
<xsl:template match="outer[#type='foo']/inner[#type='bar1' or #type='bar2' or #type='bar3' or #type='bar4']" priority="1">
<item>
<xsl:value-of select="text()"/>
</item>
</xsl:template>
<xsl:template match="outer[#type='foo']/inner">
<xsl:message terminate="yes">
<xsl:value-of select="concat('Unexpected type: ', #type)"/>
</xsl:message>
</xsl:template>
</xsl:transform>
Both of your matching expressions have a priority of .5 according to http://lenzconsulting.com/how-xslt-works/#priority
So your templates are conflicting. How about handling everything in 1 single template?
<xsl:template match="outer[#type='foo']/inner">
<xsl:choose>
<xsl:when test="#type='bar1' or #type='bar2' or #type='bar3' or #type='bar4'">
<item>
<xsl:value-of select="text()"/>
</item>
</xsl:when>
<xsl:otherwise>
<xsl:message terminate="yes">
<xsl:value-of select="concat('Unexpected type: ', #type)"/>
</xsl:message>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Input:
<persons>
<person name="John" role="Writer"/>
<person name="John" role="Poet"/>
<person name="Jacob" role="Writer"/>
<person name="Jacob" role="Poet"/>
<person name="Joe" role="Poet"/>
</persons>
Expected Output:
<groups>
<group roles="Wriet, Poet" persons="John, Jacob"/>
<group roles="Poet" persons="Joe"/>
</groups>
As in the above example, I first need to group on person names and find everyone's roles. If more than one person is found to have the same set of roles (e.g. both John and Jacob are both Writer and Poet), then I need to group on each set of roles and list the person names.
I can do this for the first level of grouping using Muenchian method or EXSLT set:distinct etc.
<groups>
<group roles="Wriet, Poet" persons="John"/>
<group roles="Wriet, Poet" persons="Jacob"/>
<group roles="Poet" persons="Joe"/>
</groups>
The above was transformed using XSLT 1.0 and EXSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:sets="http://exslt.org/sets" extension-element-prefixes="sets">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:key name="persons-by-name" match="person" use="#name"/>
<xsl:template match="persons">
<groups>
<xsl:for-each select="sets:distinct(person/#name)">
<group>
<xsl:attribute name="persons"><xsl:value-of select="."/></xsl:attribute>
<xsl:attribute name="roles">
<xsl:for-each select="key('persons-by-name', .)">
<xsl:value-of select="#role"/>
<xsl:if test="position()!=last()"><xsl:text>, </xsl:text></xsl:if>
</xsl:for-each>
</xsl:attribute>
</group>
</xsl:for-each>
</groups>
</xsl:template>
</xsl:stylesheet>
However, I need help to understand how to group on the grouped roles.
If XSLT 1.0 solution is not available, please feel free to recommend XSLT 2.0 approach.
Try it this way?
XSLT 1.0
(using EXSLT node-set() and distinct() functions)
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
xmlns:set="http://exslt.org/sets"
extension-element-prefixes="exsl set">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:key name="person-by-name" match="person" use="#name" />
<xsl:key name="person-by-roles" match="person" use="#roles" />
<xsl:variable name="distinct-persons">
<xsl:for-each select="set:distinct(/persons/person/#name)">
<person name="{.}">
<xsl:attribute name="roles">
<xsl:for-each select="key('person-by-name', .)/#role">
<xsl:sort/>
<xsl:value-of select="." />
<xsl:if test="position()!=last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:attribute>
</person>
</xsl:for-each>
</xsl:variable>
<xsl:template match="/">
<groups>
<xsl:for-each select="set:distinct(exsl:node-set($distinct-persons)/person/#roles)">
<group roles="{.}">
<xsl:attribute name="names">
<xsl:for-each select="key('person-by-roles', .)/#name">
<xsl:value-of select="." />
<xsl:if test="position()!=last()">
<xsl:text>, </xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:attribute>
</group>
</xsl:for-each>
</groups>
</xsl:template>
</xsl:stylesheet>
Result:
<?xml version="1.0" encoding="UTF-8"?>
<groups>
<group roles="Poet, Writer" names="John, Jacob"/>
<group roles="Poet" names="Joe"/>
</groups>
I did exactly the same thing as you already did and then went a step further and grouped again. Now I get the following output with your input:
<?xml version="1.0" encoding="UTF-8"?>
<groups>
<group roles="Writer,Poet" persons="John,Jacob"/>
<group roles="Poet" persons="Joe"/>
</groups>
This is the XSLT 2.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns="" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:avintis="http://www.avintis.com/esb" exclude-result-prefixes="#all" version="2.0">
<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
<xsl:template match="/persons">
<groups>
<xsl:variable name="persons" select="."/>
<!-- create a temporary variable containing all roles of a person -->
<xsl:variable name="roles">
<xsl:for-each select="distinct-values(person/#name)">
<xsl:sort select="."/>
<xsl:variable name="name" select="."/>
<xsl:element name="group">
<xsl:attribute name="roles">
<!-- sort the roles of each person -->
<xsl:variable name="rolesSorted">
<xsl:for-each select="$persons/person[#name=$name]">
<xsl:sort select="#role"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="string-join($rolesSorted/person/#role,',')"/>
</xsl:attribute>
<xsl:attribute name="persons" select="."/>
</xsl:element>
</xsl:for-each>
</xsl:variable>
<!-- now loop again over all roles of the persons and group persons having the same roles -->
<xsl:for-each select="distinct-values($roles/group/#roles)">
<xsl:element name="group">
<xsl:variable name="name" select="."/>
<xsl:attribute name="roles" select="$name"/>
<xsl:attribute name="persons">
<xsl:value-of select="string-join($roles/group[#roles=$name]/#persons,',')"/>
</xsl:attribute>
</xsl:element>
</xsl:for-each>
</groups>
</xsl:template>
<xsl:template match="*|text()|#*">
<xsl:copy>
<xsl:apply-templates select="*|text()|#*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
The roles get also sorted - so independent from the input order of the roles and persons.
I have the following XML file:
<li id="s9781452281988.n39.i34"><i>See also</i>
<a class="term-ref" id="s9781452281988.n39.i6525" href="#s9781452281988.n39.i1899">Emotion</a>;
<a class="term-ref" id="s9781452281988.n39.i6526" href="#s9781452281988.n39.i3312">Interpersonal conflict</a></li>
And I want the output to be the following:
<item>See also
<list rend="runon">
<item><term>Emotion</term></item>
<item><term>Interpersonal conflict</term></item>
</list>
</item>
Basically if I have multiple a[#class='term-ref'], the first instance should start the list rend="runon" and subsequent a[#class='term-ref'] should be included as item/term within the list.
The below was my try, but it is not working as I had hoped, and is closing the list before the second item/term (elements which are also not being output):
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
version="2.0">
<xsl:template match="li">
<xsl:element name="item">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="a[#class='term-ref'][1]">
<xsl:element name="list">
<xsl:attribute name="rend" select="'runon'"/>
<xsl:element name="item">
<xsl:element name="term">
<xsl:apply-templates/>
</xsl:element>
</xsl:element>
<xsl:if test="a[#class='term-ref'][position() >1]">
<xsl:element name="item">
<xsl:element name="term">
<xsl:apply-templates/>
</xsl:element>
</xsl:element>
</xsl:if>
</xsl:element>
</xsl:template>
<xsl:template match="li//text()">
<xsl:value-of select="translate(., '.,;', '')"/>
</xsl:template>
</xsl:stylesheet>
On the source, XML, the above stylesheet produces this output:
<item>See also
<list rend="runon">
<item><term>Emotion</term></item>
</list>
Interpersonal conflict</item>
Which is incorrect.
What am i doing wrong?
This short transformation (almost completely "push style", with no conditional instructions, no xsl:element and no unnecessary function calls like translate() or replace()):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="li">
<item><xsl:apply-templates/></item>
</xsl:template>
<xsl:template match="a[#class='term-ref'][1]">
<list rend="runon">
<xsl:apply-templates mode="group"
select="../a[#class='term-ref']"/>
</list>
</xsl:template>
<xsl:template match="a[#class='term-ref']" mode="group">
<item><term><xsl:apply-templates/></term></item>
</xsl:template>
<xsl:template match="a[#class='term-ref']|li/text()" priority="-1"/>
</xsl:stylesheet>
when applied on the provided XML document -- which is well-formed:
<li id="s9781452281988.n39.i34"><i>See also</i>
<a class="term-ref" id="s9781452281988.n39.i6525"
href="#s9781452281988.n39.i1899">Emotion</a>;
<a class="term-ref" id="s9781452281988.n39.i6526"
href="#s9781452281988.n39.i3312">Interpersonal conflict.</a>.
</li>
produces the wanted, correct result:
<item>See also<list rend="runon">
<item>
<term>Emotion</term>
</item>
<item>
<term>Interpersonal conflict.</term>
</item>
</list>
</item>
This should work...
XML Input (well-formed)
<doc>
<li id="s9781452281988.n39.i34"><i>See also</i>
<a class="term-ref" id="s9781452281988.n39.i6525" href="#s9781452281988.n39.i1899">Emotion</a>;
<a class="term-ref" id="s9781452281988.n39.i6526" href="#s9781452281988.n39.i3312">Interpersonal conflict.</a>.
</li>
</doc>
XSLT 2.0
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="li">
<item>
<xsl:apply-templates select="i/text()"/>
<xsl:if test="a">
<list rend="runon">
<xsl:apply-templates select="a"/>
</list>
</xsl:if>
</item>
</xsl:template>
<xsl:template match="a">
<item><term><xsl:apply-templates select="node()"/></term></item>
</xsl:template>
<xsl:template match="li//text()">
<xsl:value-of select="replace(.,'[.,;]','')"/>
</xsl:template>
</xsl:stylesheet>
Output
<doc>
<item>See also<list rend="runon">
<item>
<term>Emotion</term>
</item>
<item>
<term>Interpersonal conflict</term>
</item>
</list>
</item>
</doc>
This should do what you are looking to do:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:template match="li">
<xsl:element name="item">
<xsl:apply-templates select="node()" />
<xsl:apply-templates select="." mode="items" />
</xsl:element>
</xsl:template>
<xsl:template match="li//text()">
<xsl:value-of select="normalize-space(translate(., '.,;', ''))"/>
</xsl:template>
<xsl:template match="a[#class = 'term-ref']" />
<xsl:template match="node()" mode="items" />
<xsl:template match="li" mode="items">
<xsl:apply-templates mode="items" />
</xsl:template>
<xsl:template match="li[count(a[#class = 'term-ref']) > 1]" mode="items">
<list rend="runon">
<xsl:apply-templates select="a[#class = 'term-ref']" mode="items" />
</list>
</xsl:template>
<xsl:template match="a[#class = 'term-ref']" mode="items">
<item>
<term>
<xsl:value-of select="."/>
</term>
</item>
</xsl:template>
</xsl:stylesheet>
When run on your sample input, this produces:
<item>
See also<list rend="runon">
<item>
<term>Emotion</term>
</item>
<item>
<term>Interpersonal conflict</term>
</item>
</list>
</item>
When run on an input file with just one a.term-ref, this produces:
<item>
See also<item>
<term>Interpersonal conflict</term>
</item>
</item>
I want do some sum of the values and return it as a row or column with the data.
taking the below xml as example:
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<root>
<default0>
<Group>
<groupEntry>
<Day>Mon</Day>
<ID>111</ID>
<Number>-3</Number>
</groupEntry>
</Group>
<Group>
<groupEntry>
<Day>Tue</Day>
<ID>222</ID>
<Number>4</Number>
</groupEntry>
</Group>
<Group>
<groupEntry>
<Day>Tue</Day>
<ID>444</ID>
<Number>5</Number>
</groupEntry>
<Breakdown>
<Details>
<Day>Tue</Day>
<ID>444</ID>
<Number>-3</Number>
</Details>
<Details>
<Day>Tue</Day>
<ID>444</ID>
<Number>8</Number>
</Details>
</Breakdown>
</Group>
<Group>
<groupEntry>
<Day>Fri</Day>
<ID>333</ID>
<Number>-3</Number>
</groupEntry>
</Group>
</default0>
</root>
My below xslt :
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:text>ID,Day,Number</xsl:text>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="groupEntry|Details">
<xsl:text>
</xsl:text>
<xsl:value-of select="ID"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Day"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Number"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
returns this result:
ID,Day,Number
111,Mon,-3
222,Tue,4
444,Tue,5
444,Tue,-3
444,Tue,8
333,Fri,-3
However I want to get the total number by Day and report it in the result as either of the below 2 options
create 1 summary row like:
ID,Day,Number
Mon,Mon,-3
111,Mon,-3
Tue,Tue,9
222,Tue,4
444,Tue,5
444,Tue,-3
444,Tue,8
Fri,Fri,-3
333,Fri,-3
create an extra column:
ID,Day,Number,TotalNumber
111,Mon,-3,-3
222,Tue,4,9
444,Tue,5,9
444,Tue,-3,9
444,Tue,8,9
333,Fri,-3,-3
Does anyone know if this is possible?
In either option, you would probably need to define a key to group the elements by Day
<xsl:key name="days" match="groupEntry|Details" use="Day"/>
Then you can just add your extra column like so
<xsl:value-of select="sum(key('days', Day)/Number)"/>
Here is the full XSLT for the first option
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="days" match="groupEntry|Details" use="Day"/>
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:text>ID,Day,Number,TotalNumber</xsl:text>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="groupEntry|Details">
<xsl:text>
</xsl:text>
<xsl:value-of select="ID"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Day"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Number"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="sum(key('days', Day)/Number)"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
This should output the following results
ID,Day,Number,TotalNumber
111,Mon,-3,-3
222,Tue,4,14
444,Tue,5,14
444,Tue,-3,14
444,Tue,8,14
333,Fri,-3,-3
In the second option, you would want to add a total line for the first occurrence of a particular Day. You can do this by checking if the current element is the first element in the key for that day
<xsl:if test="generate-id() = generate-id(key('days', Day)[1])">
Here is the XSLT for the second case
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="days" match="groupEntry|Details" use="Day"/>
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:text>ID,Day,Number</xsl:text>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="groupEntry|Details">
<xsl:if test="generate-id() = generate-id(key('days', Day)[1])">
<xsl:text>
</xsl:text>
<xsl:value-of select="Day"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Day"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="sum(key('days', Day)/Number)"/>
</xsl:if>
<xsl:text>
</xsl:text>
<xsl:value-of select="ID"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Day"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="Number"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
This should output the following results
ID,Day,Number
Mon,Mon,-3
111,Mon,-3
Tue,Tue,14
222,Tue,4
444,Tue,5
444,Tue,-3
444,Tue,8
Fri,Fri,-3
333,Fri,-3