I have a code where the values are coming as:
a,b,c from database..
now i want to remove c from the string based upon condition, c can be at any place, 1st, last or middle.
i am using replace to do it like this:
<cfset answer = Replace('a,b,c','c','','all')>
This works but it leaves a trailing comma at the end or at the start or 2 commas in middle breaking the whole string, what can be my approach here
<cfscript>
input = 'a,b,c';
foundAt = listFind(input, 'c');
answer = foundAt ? listDeleteAt(input, foundAt) : input;
writeOutput(answer);
</cfscript>
Run this code LIVE on TryCF.com
See: List functions
OR use REReplace(). The solution was just one google search away: Regex for removing an item from a comma-separated string?
function listRemoveAll(list, item) {
return REReplace(list, "\b#item#\b,|,\b#item#\b$", "", "all");
}
Related
what I wanna do is
change
1.apple2.cat3.green(1)table(2)computer①what②can i③do?●help●me●plz
this to
1.apple
2.cat
3.green
(1)table
(2)computer
①what
②can i
③do?
●help
●me
●plz
this
there're many kind of delimiter
"1.", "2." .. "(1)".."(2)"..■ ○
and so on
number is only a single digit
I want to list many delimiter can split or add linebreak, but keep delimiter
number or bullet should not be deleted.
You can use regex like below:
let s = '1.apple2.cat3.green(1)table(2)computer①what②can i③do?●help●me●plz';
let regex = /(\d\.|\(\d\)|[①-⑳]|●|■|○)[a-z]+/ig;
let result = null;
while (result = regex.exec(s)) {
console.log(result[0]); // or you can push into an array, etc.
}
I am trying to remove a string from another string using VBA replace function.
The string from which I am trying to remove looks like below which contains cell address concatenated by ;
"$B$1;$B$21;$B$2;$C$3;$B$20;$B$201"
and the string which I would like to remove is $B$2 by say xxx.
The replace function matches all occurrences of $B$2 in the string and gives me the output as below
$B$1;xxx1;xxx;$C$3;xxx0;xxx01
However I would like to search for $B$2 exactly in the string and expect an output like
$B$1;$B$21;xxx;$C$3;$B$20;$B$201
I one way I could think of doing this is by splitting up the string on ;(separator and looping and looking at each value) but I am looking at more direct solution here. Like using pattern matching techniques or something else.
You can include the following ; in the replace operation, to make sure you only match "complete" references. You just need to take a precaution for also matching the last entry, by adding a dummy semicolon at the end:
s = "$B$1;$B$21;$B$2;$C$3;$B$20;$B$201"
find = "$B$2"
repl = "xxxx"
result = Replace(s & ";", find & ";", repl & ";")
result = Left(result, Len(result)-1) ' Remove the final semicolon
Although this works for your case, in a more general exercise, you would also want to test for the preceding delimiter, and then the last two lines would look like this:
result = Replace(";" & s & ";", ";" & find & ";", ";" & repl & ";")
result = Mid(result, 2, Len(result)-2)
you cold use:
Function myReplace(strng As String, findStr As String, replacementStrng As String)
myReplace = Replace(strng & ";", findStr & ";", replacementStrng & ";")
myReplace = Left(myReplace, Len(myReplace) - 1)
End Function
to be exploited in your "main" sub like follows:
strng = "$B$1;$B$21;$B$2;$C$3;$B$20;$B$201"
MsgBox myReplace(strng, "$B$2", "xxx")
I am trying to use multiple characters as the delimeter in ColdFusion list like ,( comma and blank) but it ignores the blank.
I then tried to use:
<cfset title = listappend( title, a[ idx ].title, "#Chr(44)##Chr(32)#" ) />
But it also ignores the blank and without blanks the list items to diffucult to read.
Any ideas?
With ListAppend you can only use one delimiter. As the docs say for the delimiters parameter:
If this parameter contains more than one character, ColdFusion uses only the first character.
I'm not sure what a[ idx ].title contains or exactly what the expected result is (would be better if you gave a complete example), but I think something like this will do what you want or at least get you started:
<cfscript>
a = [
{"title"="One"},
{"title"="Two"},
{"title"="Three"}
];
result = "";
for (el in a) {
result &= el.title & ", ";
}
writeDump(result);
</cfscript>
I think there's a fundamental flaw in your approach here. The list delimiter is part of the structure of the data, whereas you are also trying to use it for "decoration" when you come to output the data from the list. Whilst often conveniently this'll work, it's kinda conflating two ideas.
What you should do is eschew the use of lists as a data structure completely, as they're a bit crap. Use an array for storing the data, and then deal with rendering it as a separate issue: write a render function which puts whatever separator you want in your display between each element.
function displayArrayAsList(array, separator){
var list = "";
for (var element in array){
list &= (len(list) ? separator : "");
list &= element;
}
return list;
}
writeOutput(displayAsList(["tahi", "rua", "toru", "wha"], ", "));
tahi, rua, toru, wha
Use a two step process. Step 1 - create your comma delimited list. Step 2
yourList = replace(yourList, ",", ", ", "all");
I have the following strings in a long string:
a=b=c=d;
a=b;
a=b=c=d=e=f;
I want to first search for above mentioned pattern (X=Y=...=Z) and then output like the following for each of the above mentioned strings:
a=d;
b=d;
c=d;
a=b;
a=f;
b=f;
c=f;
d=f;
e=f;
In general, I want all the variables to have an equal sign with the last variable on the extreme right of the string. Is there a way I can do it using regexprep in MATLAB. I am able to do it for a fixed length string, but for variable length, I have no idea how to achieve this. Any help is appreciated.
My attempt for the case of two equal signs is as follows:
funstr = regexprep(funstr, '([^;])+\s*=\s*+(\w+)+\s*=\s*([^;])+;', '$1 = $3; \n $2 = $3;\n');
Not a regexp but if you stick to Matlab you can make use of the cellfun function to avoid loop:
str = 'a=b=c=d=e=f;' ; %// input string
list = strsplit(str,'=') ;
strout = cellfun( #(a) [a,'=',list{end}] , list(1:end-1), 'uni', 0).' %'// Horchler simplification of the previous solution below
%// this does the same than above but more convoluted
%// strout = cellfun( #(a,b) cat(2,a,'=',b) , list(1:end-1) , repmat(list(end),1,length(list)-1) , 'uni',0 ).'
Will give you:
strout =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
Note: As Horchler rightly pointed out in comment, although the cellfun instruction allows to compact your code, it is just a disguised loop. Moreover, since it runs on cell, it is notoriously slow. You won't see the difference on such simple inputs, but keep this use when super performances are not a major concern.
Now if you like regex you must like black magic code. If all your strings are in a cell array from the start, there is a way to (over)abuse of the cellfun capabilities to obscure your code do it all in one line.
Consider:
strlist = {
'a=b=c=d;'
'a=b;'
'a=b=c=d=e=f;'
};
Then you can have all your substring with:
strout = cellfun( #(s)cellfun(#(a,b)cat(2,a,'=',b),s(1:end-1),repmat(s(end),1,length(s)-1),'uni',0).' , cellfun(#(s) strsplit(s,'=') , strlist , 'uni',0 ) ,'uni',0)
>> strout{:}
ans =
'a=d;'
'b=d;'
'c=d;'
ans =
'a=b;'
ans =
'a=f;'
'b=f;'
'c=f;'
'd=f;'
'e=f;'
This gives you a 3x1 cell array. One cell for each group of substring. If you want to concatenate them all then simply: strall = cat(2,strout{:});
I haven't had much experience w/ Matlab; but your problem can be solved by a simple string split function.
[parts, m] = strsplit( funstr, {' ', '='}, 'CollapseDelimiters', true )
Now, store the last part of parts; and iterate over parts until that:
len = length( parts )
for i = 1:len-1
print( strcat(parts(i), ' = ', parts(len)) )
end
I do not know what exactly is the print function in matlab. You can update that accordingly.
There isn't a single Regex that you can write that will cover all the cases. As posted on this answer:
https://stackoverflow.com/a/5019658/3393095
However, you have a few alternatives to achieve your final result:
You can get all the values in the line with regexp, pick the last value, then use a for loop iterating throughout the other values to generate the output. The regex to get the values would be this:
matchStr = regexp(str,'([^=;\s]*)','match')
If you want to use regexprep at any means, you should write a pattern generator and a replace expression generator, based on number of '=' in the input string, and pass these as parameters of your regexprep func.
You can forget about Regex and Split the input to generate the output looping throughout the values (similarly to alternative #1) .
FOR EXAMPLE: Given a string... "1,2,3,4"
I need to be able to remove a given number and the comma after/before depending on if the match is at the end of the string or not.
remove(2) = "1,3,4"
remove(4) = "1,2,3"
Also, I'm using javascript.
As jtdubs shows, an easy way is is to use a split function to obtain an array of elements without the commas, remove the required element from the array, and then rebuild the string with a join function.
For javascript something like this might work:
function remove(array,to_remove)
{
var elements=array.split(",");
var remove_index=elements.indexOf(to_remove);
elements.splice(remove_index,1);
var result=elements.join(",");
return result;
}
var string="1,2,3,4,5";
var newstring = remove(string,"4"); // newstring will contain "1,2,3,5"
document.write(newstring+"<br>");
newstring = remove(string,"5");
document.write(newstring+"<br>"); // will contain "1,2,3,4"
You also need to consider the behavior you want if you have repeats, say the string is "1,2,2,4" and I say "remove(2)" should it remove both instances or just the first? this function will remove only the first instance.
Just use multiple substitutions.
s/^$removed,//;
s/,$removed$//;
s/,$removed,/,/;
This will be easier than trying to invent a single replacement that handles all those cases.
string input = "1,2,3,4";
List<string> parts = new List<string>(input.Split(new char[] { ',' }));
parts.RemoveAt(2);
string output = String.Join(",", parts);
Instead of using regex, I would do something like:
- split on comma
- delete the right element
- join with comma
Here is a perl script that does the job:
#!/usr/bin/perl
use 5.10.1;
use strict;
use warnings;
my $toremove = 5;
my $string = "1,2,3,4,5";
my #tmp = split/,/, $string;
#tmp = grep{ $_ != $toremove }#tmp;
$string =join',', #tmp;
say $string;
Output:
1,2,3,4
Javascript has improved since this question was posted.
I use the following regex to remove items from a csv string
let searchStr = "359";
let regex = new RegExp("^" + searchStr + ",?|," + searchStr);
csvStr = csvStr.replace(regex, "");
If the child_id is the start, middle or end, or only item it is replaced.
If the searchStr is at the start of the csvStr it and any trailing comma is replaced. Else if the searchStr is anywhere else in the csvStr it must be preceded with a comma so the searchStr and its preceding comma are replaced by an empty string.