get node and value if it's not null using Xslt - xslt

Question

I have a requierement as below:
if i give input as :
<?xml version="1.0"?>
<new:NewAddressData xmlns:new="http://www.example.org/NewAddress">
<new:NewStreet></new:NewStreet>
<new:NewArea>Area_1</new:NewArea>
<new:NewState></new:NewState>
</new:NewAddressData>
Output should be:
<new:NewArea>Area_1</new:NewArea>
Actually Iam new bee to XSLT but I read some basics and tried below code :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:choose>
<xsl:when test="#*|node() != ''">
<xsl:value-of select="." disable-output-escaping="yes" />
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="#*|node()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:copy>
</xsl:template>
for this I am getting output as :
<new:NewAddressData xmlns:new="http://www.example.org/NewAddress">Area_1</new:NewAddressData>
where expected value should be like :
<new:NewArea>Area_1</new:NewArea>
So how can I achieve this using XSLT 1.0
Thanks in advance

Answer 1

You could do something like this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*[text()]">
<xsl:copy-of select="."/>
</xsl:template>
</xsl:stylesheet>
Depending on input, like if there was more than one element that contained text, this might result in output that is not well formed.

Answer 2

It looks like you have read about the XSLT Identity Template, which is good!
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
On its own, this will copy across all nodes unchanged (such as your NewArea element), so you need to then write templates for the things you do want to change. In this case, it looks like you want to remove elements that don't have non-empty text nodes as children.
<xsl:template match="*[not(text()[normalize-space()])]">
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(text()[normalize-space()])]">
<xsl:apply-templates />
</xsl:template>
</xsl:stylesheet>
This would output the following
<new:NewArea xmlns:new="http://www.example.org/NewAddress">Area_1</new:NewArea>
The namespace is necessary here. You can not output an element with a prefix without also declaring the namespace associated with it.