Match node of called template - xslt

Question

lets say I have a random template in my xsl:
<xsl:template name="keywords">
<test>
<foo>bar</foo>
<bar>foo</bar>
</test>
<test>
<foo>foobar</foo>
<bar>barfoo</bar>
</test>
<xsl:template>
I want to output let's say only the first node set. Is there an elegant way to do this?
How can I match the node if it is not in the source xml, but the result of a called template?
Thanks!

Answer 1

If you save the result of calling the template in a variable then you can extract parts of it using XPath
<xsl:variable name="result">
<xsl:call-template name="keywords"/>
</xsl:variable>
<xsl:sequence select="$keywords/test[1]" />

Answer 2

You can access the nodes inside a named template using an Xpath expression like:
document('')/xsl:stylesheet/xsl:template[#name='keywords']/test[1]
Added:
For example, the following stylesheet:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<output>
<xsl:copy-of select="document('')/xsl:stylesheet/xsl:template[#name='keywords']/test[1]"/>
</output>
</xsl:template>
<xsl:template name="keywords">
<test>
<foo>bar</foo>
<bar>foo</bar>
</test>
<test>
<foo>foobar</foo>
<bar>barfoo</bar>
</test>
</xsl:template>
</xsl:stylesheet>
when applied to any well-formed XML input, will return:
<?xml version="1.0" encoding="UTF-8"?>
<output>
<test xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<foo>bar</foo>
<bar>foo</bar>
</test>
</output>
Note: you can get rid of the (harmless) redundant namespace declaration by applying templates instead of deep-copying.