XSLT sort case sensitive - xslt

Please look at example:
xslt:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates>
<xsl:sort select="name()" case-order="upper-first"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
source xml:
<?xml version="1.0" encoding="UTF-8"?>
<Test>
<Z>Z</Z>
<a>a</a>
<A>A</A>
<B>B</B>
<k>k</k>
</Test>
Result is. This is case insensitive order. How to force upper-case letters be first?
<?xml version="1.0" encoding="UTF-8"?>
<Test>
<A>A</A>
<a>a</a>
<B>B</B>
<k>k</k>
<Z>Z</Z>
</Test>
But, i need something like this:
<?xml version="1.0" encoding="UTF-8"?>
<Test>
<A>A</A>
<B>B</B>
<Z>Z</Z>
<a>a</a>
<k>k</k>
</Test>
What I'm doing wrong?

You may need to sort by the case in a separate sort instruction:
<xsl:apply-templates>
<xsl:sort select="translate(name(), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', '00000000000000000000000000')" />
<xsl:sort select="name()"/>
</xsl:apply-templates>
This solution might need some testing though.

Related

Splitting Multiline XML tag into multiple Nodes

I have a XML below, where new lines are added after each line at Note__c tag. I need to produce the XML by splitting them into multiple Note__c tags.
Input XML-
<?xml version="1.0" encoding="UTF-8"?>
<snotification>
<data>
<schema>yify-xjmoeLTbNXA560rHQ</schema>
<payload>
<Note__c>01/15/2020
123456
DFGRTE766
6tgBFR</Note__c>
<Line_Length__c>72.0</Line_Length__c>
<CreatedById>00554000003OENsAAO</CreatedById>
<Contact_Name__c/>
<Sent_By_Name__c>SBM</Sent_By_Name__c>
<CreatedDate>2020-01-15T16:10:40.551Z</CreatedDate>
<Order_Number__c>14831</Order_Number__c>
<Does_not_require_reformatting__c>false</Does_not_require_reformatting__c>
</payload>
<event>
<replayId>139219</replayId>
</event>
</data>
<channel>/event/Order_Note__e</channel>
</snotification>
Where Note__c contains multiple strings with new line added after each(except the last one)
Expected Output -
<?xml version="1.0" encoding="UTF-8"?>
<snotification>
<data>
<schema>yify-xjmoeLTbNXA560rHQ</schema>
<payload>
<Notes>
<Note__c>01/15/2020</Note__c>
<Note__c>123456</Note__c>
<Note__c>DFGRTE766</Note__c>
<Note__c>6tgBFR</Note__c>
</Notes>
<Line_Length__c>72.0</Line_Length__c>
<CreatedById>00554000003OENsAAO</CreatedById>
<Contact_Name__c/>
<Sent_By_Name__c>SBM</Sent_By_Name__c>
<CreatedDate>2020-01-15T16:10:40.551Z</CreatedDate>
<Order_Number__c>14831</Order_Number__c>
<Does_not_require_reformatting__c>false</Does_not_require_reformatting__c>
</payload>
<event>
<replayId>139219</replayId>
</event>
</data>
<channel>/event/Order_Note__e</channel>
</snotification>
I have written this XSLT but it is missing few tags under the payload element -
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="snotification/data/payload">
<Notes>
<xsl:for-each select="tokenize(Note__c,'\n')">
<Note__c>
<xsl:value-of select="."/>
</Note__c>
</xsl:for-each>
</Notes>
</xsl:template>
</xsl:stylesheet>
Output of this-
<?xml version="1.0" encoding="UTF-8"?>
<snotification>
<data>
<schema>yify-xjmoeLTbNXA560rHQ</schema>
<Notes>
<Note__c>01/15/2020</Note__c>
<Note__c> 123456</Note__c>
<Note__c> DFGRTE766</Note__c>
<Note__c> 6tgBFR</Note__c>
</Notes>
<event>
<replayId>139219</replayId>
</event>
</data>
<channel>/event/Order_Note__e</channel>
</snotification>
not sure what is missing.
Thanks
Sugata
Change your XSLT to
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="snotification/data/payload/Note__c">
<Notes>
<xsl:for-each select="tokenize(.,'\n')">
<Note__c>
<xsl:value-of select="normalize-space(.)"/>
</Note__c>
</xsl:for-each>
</Notes>
</xsl:template>
</xsl:stylesheet>
The output should be as desired.

Difference between 'where' and 'if' in an XSLT script

I am new to XML/XSLT, and I'm a bit confused about the difference between the <xsl:if test="x"> and adding a where="x" at the end of a statement.
Below is some example data and two XSLT versions of code. I tried running it both ways here: https://www.w3schools.com/xml/tryxslt.asp?xmlfile=cdcatalog&xsltfile=cdcatalog_ex1 but nothing appears, so I may be doing something wrong. Is anyone able to clarify this for me?
<?xml version="1.0"?>
<Tests xmlns="http://www.adatum.com">
<Test TestId="0001" TestType="CMD">
<Name>Convert number to string</Name>
<CommandLine>Examp1.EXE</CommandLine>
<Input>1</Input>
<Output>One</Output>
</Test>
<Test TestId="0002" TestType="CMD">
<Name>Find succeeding characters</Name>
<CommandLine>Examp2.EXE</CommandLine>
<Input>abc</Input>
<Output>def</Output>
</Test>
<Test TestId="0003" TestType="GUI">
<Name>Convert multiple numbers to strings</Name>
<CommandLine>Examp2.EXE /Verbose</CommandLine>
<Input>123</Input>
<Output>One Two Three</Output>
</Test>
<Test TestId="0004" TestType="GUI">
<Name>Find correlated key</Name>
<CommandLine>Examp3.EXE</CommandLine>
<Input>a1</Input>
<Output>b1</Output>
</Test>
<Test TestId="0005" TestType="GUI">
<Name>Count characters</Name>
<CommandLine>FinalExamp.EXE</CommandLine>
<Input>This is a test</Input>
<Output>14</Output>
</Test>
</Tests>
Using where my XSLT is:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:output method="text" version="1.0" encoding="UTF-8" indent="no"/>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="Tests/Test" where="#TestType='CMD'">
<xsl:value-of select="current()">
</xsl:for-each>
</xsl:template>
</xsl:stylesheet
Code using the if statemtent
<?xml version="1.0" encoding="UTF-8"?>
<xsl:output method="text" version="1.0" encoding="UTF-8" indent="no"/>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="Tests/Test">
<xsl:if test="#TestType='CMD'">
<xsl:value-of select="current()">
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet
The is no where attribute for xsl:for-each.
What you mean is called a predicate which is enclosed by Double brackets.
So change your xsl:for-each from
<xsl:for-each select="Tests/Test" where="#TestType='CMD'">
<xsl:value-of select="current()">
</xsl:for-each>
to
<xsl:for-each select="Tests/Test[#TestType='CMD']">
<xsl:value-of select="current()">
</xsl:for-each>
That should do the trick.

Split based on just tags

I am looking for a simple split of an xml file just based on tags; say 3 tags always repeat and need split as depicted below:
Input
<?xml version="1.0" encoding="UTF-8"?>
<Test>
<tag1>A</tag1>
<tag2>B</tag2>
<tag3>C</tag3>
<tag1>1</tag1>
<tag2>2</tag2>
<tag3>3</tag3>
<tag1>apple</tag1>
<tag2>orange</tag2>
<tag3>mango</tag3>
</Test>
Expected Output
<Root>
<Test>
<tag1>A</tag1>
<tag2>B</tag2>
<tag3>C</tag3>
</Test>
<Test>
<tag1>1</tag1>
<tag2>2</tag2>
<tag3>3</tag3>
</Test>
<Test>
<tag1>apple</tag1>
<tag2>orange</tag2>
<tag3>mango</tag3>
</Test>
</Root>
Any help is appreciated
Thanks
If the structure is regular, you could do simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/Test">
<Root>
<xsl:for-each select="tag1">
<Test>
<xsl:copy-of select=". | following-sibling::tag2[1] | following-sibling::tag3[1] "/>
</Test>
</xsl:for-each>
</Root>
</xsl:template>
</xsl:stylesheet>

Match node of called template

lets say I have a random template in my xsl:
<xsl:template name="keywords">
<test>
<foo>bar</foo>
<bar>foo</bar>
</test>
<test>
<foo>foobar</foo>
<bar>barfoo</bar>
</test>
<xsl:template>
I want to output let's say only the first node set. Is there an elegant way to do this?
How can I match the node if it is not in the source xml, but the result of a called template?
Thanks!
If you save the result of calling the template in a variable then you can extract parts of it using XPath
<xsl:variable name="result">
<xsl:call-template name="keywords"/>
</xsl:variable>
<xsl:sequence select="$keywords/test[1]" />
You can access the nodes inside a named template using an Xpath expression like:
document('')/xsl:stylesheet/xsl:template[#name='keywords']/test[1]
Added:
For example, the following stylesheet:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<output>
<xsl:copy-of select="document('')/xsl:stylesheet/xsl:template[#name='keywords']/test[1]"/>
</output>
</xsl:template>
<xsl:template name="keywords">
<test>
<foo>bar</foo>
<bar>foo</bar>
</test>
<test>
<foo>foobar</foo>
<bar>barfoo</bar>
</test>
</xsl:template>
</xsl:stylesheet>
when applied to any well-formed XML input, will return:
<?xml version="1.0" encoding="UTF-8"?>
<output>
<test xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<foo>bar</foo>
<bar>foo</bar>
</test>
</output>
Note: you can get rid of the (harmless) redundant namespace declaration by applying templates instead of deep-copying.

XSLT remove unwanted elements

I have XML
<getInquiryAboutListReturn xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<inquiryAbouts>
<inquiryAbout>
<code>Code</code>
<nameKk>Something</nameKk>
<nameRu>Something</nameRu>
<documents xsi:nil="true"/>
</inquiryAbout>
</inquiryAbouts>
</getInquiryAboutListReturn>
And I want to process it with XSLT to copy all XML
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes" />
<xsl:template match="/">
<xsl:copy-of select="//getInquiryAboutListReturn/inquiryAbouts"/>
</xsl:template>
</xsl:stylesheet>
How could I copy all XML without <documents xsi:nil="true"/> or without xsi:nil="true"?
Desired output XML
<getInquiryAboutListReturn xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<inquiryAbouts>
<inquiryAbout>
<code>Code</code>
<nameKk>Something</nameKk>
<nameRu>Something</nameRu>
</inquiryAbout>
</inquiryAbouts>
</getInquiryAboutListReturn>
This simple XSLT:
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
version="1.0">
<xsl:output omit-xml-declaration="no" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- TEMPLATE #1 -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- TEMPLATE #2 -->
<xsl:template match="*[#xsi:nil = 'true']" />
</xsl:stylesheet>
...when applied to the OP's source XML:
<?xml version="1.0"?>
<getInquiryAboutListReturn xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<inquiryAbouts>
<inquiryAbout>
<code>Code</code>
<nameKk>Something</nameKk>
<nameRu>Something</nameRu>
<documents xsi:nil="true"/>
</inquiryAbout>
</inquiryAbouts>
</getInquiryAboutListReturn>
...produces the expected result XML:
<?xml version="1.0"?>
<getInquiryAboutListReturn xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<inquiryAbouts>
<inquiryAbout>
<code>Code</code>
<nameKk>Something</nameKk>
<nameRu>Something</nameRu>
</inquiryAbout>
</inquiryAbouts>
</getInquiryAboutListReturn>
EXPLANATION:
The first template -- the Identity Template -- copies all nodes and attributes from the source XML document as-is.
The second template, which matches all elements with the specified, namespaced attribute equalling "true", effectively removes those elements.