I have two sheets named first and second in a Sheets and would like to populate Status column with three different value based on these four conditions:
First: if B:B=0 --> A
Second & Third: if A:A<second!A2 and (INDEX(A2:A,COUNT(A2:A)))<today())) --> C
Fourth: if A:A<today() --> B
(If all three fail, leave empty.)
These are the sample tables I am working on:
first
second
The following are the desired results on respective tables.
first
second
Here is what I have tried, but it says only less than three arguments are allowed.
=IF(B2>0, if(A2<today(), "B", ""), if(B2=0,"A", ""), IF((AND((A:A<second!A2),((INDEX(A2:A,COUNT(A2:A)))<today()))),"C",""))
Just made few small changes and it worked.
=if(B:B=0, "A", if(A:A<today(), IF((AND((A:A<second!A2),((INDEX(A2:A,COUNT(A2:A)))<today()))),"C","B"), ""))
Related
in my Google sheet table I have the first list with summary of invoices which are then separated to 4 lists according to parameters (manually). I need to know about all invoices from the first list, on which category/list they are.
So for example - lists: Alphabet, abc, def, mno, xyz. In Alphabet is column "list".
How to write function which found invoice on another list according to ID (column B) from Alphabet and write name of the correct list to column "list". I tried to write this function using IF, match, etc. But I still don't have solution. Can you help me please? Sorry for my English :-)
So here is an example which you could adapt. In columns E:H on the first sheet (and I could hide these columns later, starting in row2 and dragging down as needed, I put the following formulas:
=IF(LEN(iferror(query(abc!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"abc","")
=IF(LEN(iferror(query(def!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"def","")
=IF(LEN(iferror(query(mno!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"mno","")
=IF(LEN(iferror(query(xyz!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"xyz","")
Probably I could have simplified a little by putting the sheet names in E1:H1, but you get the idea.
Each of these looks for the ID. If the query succeeds, it returns the name of the sheet. If it fails, it returns the empty string.
Now in column B where I actually want the results, I put this formula in B2 and drag to copy as needed.
=if(E2&F2&G2&H2="","nowhere",E2&F2&G2&H2)
It says put those strings together, and if there is nothing there say nowhere, otherwise say the list. If it appears on more than one, and that can really happen, you could use JOIN instead.
Goal: I have a bunch of keywords I'd like to categorise automatically based on topic parameters I set. Categories that match must be in the same column so the keyword data can be filtered.
e.g. If I have "Puppies" as a first topic, it shouldn't appear as a secondary or third topic otherwise the data cannot be filtered as needed.
Example Data: https://docs.google.com/spreadsheets/d/1TWYepApOtWDlwoTP8zkaflD7AoxD_LZ4PxssSpFlrWQ/edit?usp=sharing
Video: https://drive.google.com/file/d/11T5hhyestKRY4GpuwC7RF6tx-xQudNok/view?usp=sharing
Parameters Tab: I will add words in columns D-F that change based on the keyword data set and there will often be hundreds, if not thousands, of options for larger data sets.
Categories Tab: I'd like to have a formula or script that goes down the columns D-F in Parameters and fills in a corresponding value (in Categories! columns D-F respectively) based on partial match with column B or C (makes no difference to me if there's a delimiter like a space or not. Final data sheet should only have one of these columns though).
Things I've Tried:
I've tried a bunch of things. Nested IF formula with regexmatch works but seems clunky.
e.g. this formula in Categories! column D
=IF(REGEXMATCH($B2,LOWER(Parameters!$D$3)),Parameters!$D$3,IF(REGEXMATCH($B2,LOWER(Parameters!$D$4)),Parameters!$D$4,""))
I nested more statements changing out to the next cell in Parameters!D column (as in , manually adding $D$5, $D$6 etc) but this seems inefficient for a list thousands of words long. e.g. third topic will get very long once all dog breed types are added.
Any tips?
Functionality I haven't worked out:
if a string in Categories B or C contains more than one topic in the parameters I set out, is there a way I can have the first 2 to show instead of just the first one?
e.g. Cell A14 in Categories, how can I get a formula/automation to add both "Akita" & "German Shepherd" into the third topic? Concatenation with a CHAR(10) to add to new line is ideal format here. There will be other keywords that won't have both in there in which case these values will just show up individually.
Since this data set has a bunch of mixed breeds and all breeds are added as a third topic, it would be great to differentiate interest in mixes vs pure breeds without confusion.
Any ideas will be greatly appreciated! Also, I'm open to variations in layout and functionality of the spreadsheet in case you have a more creative solution. I just care about efficiently automating a tedious task!!
Try using custom function:
To create custom function:
1.Create or open a spreadsheet in Google Sheets.
2.Select the menu item Tools > Script editor.
3.Delete any code in the script editor and copy and paste the code below into the script editor.
4.At the top, click Save save.
To use custom function:
1.Click the cell where you want to use the function.
2.Type an equals sign (=) followed by the function name and any input value — for example, =DOUBLE(A1) — and press Enter.
3.The cell will momentarily display Loading..., then return the result.
Code:
function matchTopic(p, str) {
var params = p.flat(); //Convert 2d array into 1d
var buildRegex = params.map(i => '(' + i + ')').join('|'); //convert array into series of capturing groups. Example (Dog)|(Puppies)
var regex = new RegExp(buildRegex,"gi");
var results = str.match(regex);
if(results){
// The for loops below will convert the first character of each word to Uppercase
for(var i = 0 ; i < results.length ; i++){
var words = results[i].split(" ");
for (let j = 0; j < words.length; j++) {
words[j] = words[j][0].toUpperCase() + words[j].substr(1);
}
results[i] = words.join(" ");
}
return results.join(","); //return with comma separator
}else{
return ""; //return blank if result is null
}
}
Example Usage:
Parameters:
First Topic:
Second Topic:
Third Topic:
Reference:
Custom Functions
I've added a new sheet ("Erik Help") with separate formulas (highlighted in green currently) for each of your keyword columns. They are each essentially the same except for specific column references, so I'll include only the "First Topic" formula here:
=ArrayFormula({"First Topic";IF(A2:A="",,IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) & IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))))})
This formula first creates the header (which can be changed within the formula itself as you like).
The opening IF condition leaves any row in the results column blank if the corresponding cell in Column A of that row is also blank.
JOIN is used to form a concatenated string of all keywords separated by the pipe symbol, which REGEXEXTRACT interprets as OR.
IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))) will attempt to extract any of the keywords from each concatenated string in Columns B and C. If none is found, IFERROR will return null.
Then a second-round attempt is made:
& IFERROR(CHAR(10)®EXEXTRACT(REGEXREPLACE(LOWER(B2:B&C2:C),IFERROR(REGEXEXTRACT(LOWER(B2:B&C2:C),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>""))))),""),JOIN("|",LOWER(FILTER(Parameters!D3:D,Parameters!D3:D<>"")))))
Only this time, REGEXREPLACE is used to replace the results of the first round with null, thus eliminating them from being found in round two. This will cause any second listing from the JOIN clause to be found, if one exists. Otherwise, IFERROR again returns null for round two.
CHAR(10) is the new-line character.
I've written each of the three formulas to return up to two results for each keyword column. If that is not your intention for "First Topic" and "Second Topic" (i.e., if you only wanted a maximum of one result for each of those columns), just select and delete the entire round-two portion of the formula shown above from the formula in each of those columns.
I am trying to combine two formulas
=TEXTJOIN("|", 1, AQ2, AR2)
If I drag this down each row independently gets joined
And
=ARRAYFORMULA({"AAA";IF(INDIRECT("Elements!D2:D")="Person","Yes", "No")})
I want to combine then
=ARRAYFORMULA({"AAA";IF(INDIRECT("Elements!D2:D")="Person",TEXTJOIN("|", 1, AQ2, AR2), "No")})
But this only expands the first join at A2 and copies it down
How do you combine the formulas, so each row independently gets joined like the manually dragged down version
I have tried adding INDIRECT(AQ2:AQ) and INDIRECT(AR2:AR) in the TextJoin formula but this does not work
Google sheet
https://docs.google.com/spreadsheets/d/1uOpOi41kjVWIRO__0y7jg0JKrJNy04Kv1O9jxQWmKjo/edit?usp=sharing
try:
=ARRAYFORMULA({"AAA"; IF(B2:B="Person", C2:C&IF(D2:D="",,"|"&D2:D), "No")})
to remove those No's for blank rows use:
=ARRAYFORMULA({"AAA"; IF(B2:B="",,IF(B2:B="Person", C2:C&IF(D2:D="",,"|"&D2:D), "No"))})
I have one sheet with data on my facebook ads. I have another sheet with data on the products in my store. I'm having trouble with some countifs where I'm counting how many times my product ID exists in a row where multiple numbers are. They are formatted like this: /2032/2034/2040/1/
It's easy on the rows where only one product ID exists but some rows have multiple ID's separated by a /. And I need to see if the ID exists as a exact match alone or somewhere between the /'s.
Rows with facebook ads data:
A1: /2032/2034/2040/1/
A2: /1548/84/2154/2001/
A3: /2032/1689/1840/2548/
Row with product data:
B1: 2034
C1: I need a countifs here that checks how many times B1 exists in column A. Lets say I have thousands of rows with different variations of A1 where B1 could standalone. How do I count this? I always need exact matches.
You can compare the number you want (56) with the REGEX #MonkeyZeus commented whith a little change -> "(?:^|/)"&B1&"(?:/|$)" so the end result is:
=IF(REGEXMATCH(A1, "(?:^|/)"&B1&"(?:/|$)"), true, false)
Example:
UPDATE
If you need to count the total of 56 in X rows you can change the "True / False" of the condition for "1 / 0" and then do a =SUM(C1:C5) on the last row:
=IF(REGEXMATCH(A1, "(?:^|/)"&B1&"(?:/|$)"), 1, 0)
UPDATE 2
Thanks for contributing. Unfortunately I'm not able to do it this way
since I have loads of data to do this on. Is there a way to do it with
a countif in a single cell without adding a extra step with "sum"?
In that case you can do:
=COUNTA(FILTER(A:A, REGEXMATCH(A:A, "(?:^|/)"&B2&"(?:/|$)")))
Example:
UPDATE 3
With the following condition you check every single possibility just by adding another COUNTIF:
=COUNTIF(A:A,B1) + COUNTIF(A:A, "*/"&B1) + COUNTIF(A:A, B1&"/*") + COUNTIF(A:A, "*/"&B1&"/*")
Hope this helps!
try:
=COUNTIF(SPLIT(A1, "/"), B1)
UPDATE:
=ARRAYFORMULA(IF(A2<>"", {
SUM(IF((REGEXMATCH(""&DATA!C:C, ""&A2))*(DATA!B:B="carousel"), 1, )),
SUM(IF((REGEXMATCH(""&DATA!C:C, ""&A2))*(DATA!B:B="imagepost"), 1, ))}, ))
I have two columns of data in "Meds" sheet...
MedContinuing AgeAtMedStop
Yes "Blank"
Yes 72.22
No "Blank"
No 72.57
"Blank" 73.85
I am writing a formula in a separate sheet to return 1 or 0 based on the following:
If MedContinuing is "Blank", do nothing
If MedContinuing is "No" and AgeAtMedStop is blank, do nothing
If MedContinuing is "Yes" and AgeAtMedStop is "Blank", return 1. If AgeAtMedStop is a number, return 0.
If MedContinuing is "No" and AgeAtMedStop is a number, return 1. Otherwise, return nothing.
I was able to write two separate functions (see below) for when MedContinuing is "Yes" or when it is "No", but I need to combine both into one formula.
When it's Yes...
=IF(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="","",
IF(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="No","",
IF(AND(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="Yes",INDEX(Meds!2:2,MATCH("AgeAtMedStop",Meds!$1:$1,0))=""),1,0)))
When it's No...
=IF(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="","",
IF(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="Yes","",
IF(AND(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="No",INDEX(Meds!2:2,MATCH("AgeAtMedStop",Meds!$1:$1,0))=""),"",
IF(AND(INDEX(Meds!2:2,MATCH("MedContinuing",Meds!$1:$1,0))="No",INDEX(Meds!2:2,MATCH("AgeAtMedStop",Meds!$1:$1,0))>0),1,0))))
EDIT: Solution
Using Peter K's logic...
=IF(INDEX(Meds!6:6,MATCH("MedContinuing",Meds!$1:$1,0))="","",
IF(AND(INDEX(Meds!6:6,MATCH("MedContinuing",Meds!$1:$1,0))="No",INDEX(Meds!6:6,MATCH("AgeAtMedStop",Meds!$1:$1,0))=""),"",
IF(AND(INDEX(Meds!6:6,MATCH("MedContinuing",Meds!$1:$1,0))="Yes",INDEX(Meds!6:6,MATCH("AgeAtMedStop",Meds!$1:$1,0))=""),1,
IF(AND(INDEX(Meds!6:6,MATCH("MedContinuing",Meds!$1:$1,0))="Yes",INDEX(Meds!6:6,MATCH("AgeAtMedStop",Meds!$1:$1,0))>0),0,
IF(AND(INDEX(Meds!6:6,MATCH("MedContinuing",Meds!$1:$1,0))="No",INDEX(Meds!6:6,MATCH("AgeAtMedStop",Meds!$1:$1,0))>0),1,"")))))
It is not entirely clear from your question why you would use INDEX and MATCH functions for such straightforward problem ?
I suggest to start with the basic nested if function :
=IF(A2="";"";IF(A2="No";IF(B2="";"";1);IF(B2="";1;0)))
You can put this function next to your two columns, and then copy to another worksheet, so the references are taken care of by Excel.
I also assume that your data is clean and correct i.e. only the 3 possible values for MedContinuing ("Yes", "No" or blank) and 2 for AgeAtMedStop (blank or a number) exist in your columns, so no IF test is needed to eliminate other possible values.
You can try this method below
I have created a helper table for the logic you require, it will help to update or extend the logic in future
Formula in cell C2 is
=INDEX($F$2:$G$4,MATCH(A2,$E$2:$E$4,0),IF(B2="Blank",1,IF(ISNUMBER(B2),2,0)))