Declare a empty variable - xslt

I wrote :-
<xsl:variable name="cAddress" select=""></xsl:variable>
I don't want to assign any value here, I want to assign later. Is this possible?

No it is not possible. In XSLT, variables are immutable. You cannot assign - or reassign - a value to an existing variable. Technically, you can declare an empty variable as:
<xsl:variable name="myVar"/>
but you won't be able to do anything with it later.
If you want to pass a parameter to a stylesheet or to a template at runtime, use:
<xsl:param name="cAddress"/>
or:
<xsl:param name="cAddress" select="'default value'"/>

Related

assigning the value to a variable through xsl

I am stuck up in an odd situation I have an variable named PaymentabcflowsVar as shown below
<xsl:with-param name="PaymentabcflowsVar" select="$RBC_CDSERStream_Obj/CTM_PaymentPeriod"/>
and I am fetching the value at some logic as shown below..
<xsl:value-of select="$TTeturnVar/onal/onalAmount/amount" />
now I want to assign this value to the above variable named PaymentabcflowsVar such as
PaymentabcflowsVar = <xsl:value-of select="$TTeturnVar/onal/onalAmount/amount" />
please advise how to achieve this..!!
well now what I have done is that i have assign the value a variable temporarily
<xsl:variable name="holodingtnalamount"><xsl:value-of select="$TTeturnVar/onal/onalAmount/amount" />
now please advise can I assign the variable holodingtnalamount value to PaymentabcflowsVar
A few matters of apparent confusion require clarification:
(1) Here's how to assign the value to a variable:
<xsl:variable name="PaymentabcflowsVar"
select="$TTeturnVar/onal/onalAmount/amount"/>
(2) A variable can only be assigned a value once. Explanation here.
(3) xsl:with-param is for use in passing parameters to named templates.

xpath for selecting elements which are not included in a specific list

I have an xslt variable declared as below:
<xsl:variable name="list">
<item>Elem1</item>
<item>Elem2</item>
<item>Elem3</item>
</xsl:variable>
I need an xpath to match all elements whose local name does not belong in $list. I could have opted for *[not(self::Elem1|self::Elem2|self::Elem3)] and so on. But I want to declare the variable so that it is easier to maintain later on. Please advice.
try..........
*[not(name()=$list/item)]

In XSLT, why do I need to do comparisons with variables instead of with attribute values (in a test expression)

I am parsing a document, with different behavior depending on whether the id attribute is an element of a collection of values ($item-ids in the code below). My question is, why do I need to assign a variable and then compare with that value, like this:
<xsl:template match="word/item">
<xsl:variable name="id" select="#abg:id"/>
<xsl:if test="$item-ids[.=$id]">
<xsl:message>It matches!</xsl:message>
</xsl:if>
</xsl:template>
It seems to be that I should be able to do it like this, though it doesn't work:
<xsl:template match="word/item">
<xsl:if test="$item-ids[.=#abg:id]">
<xsl:message>It matches!</xsl:message>
</xsl:if>
</xsl:template>
This is something I keep forgetting and having to relearn. Can anybody explain why it works this way? Thanks.
To understand XPath, you need to understand the concept of the context node. An expression like #id is selecting an attribute of the context node. And the context node changes inside square brackets.
You don't have to use a variable in this case. Here you can use:
<xsl:template match="word/item">
<xsl:if test="$item-ids[. = current()/#abg:id]">
<xsl:message>It matches!</xsl:message>
</xsl:if>
</xsl:template>
The reason you can't just use $item-ids[. = #abg:id] is that inside the [], you are in the context of whatever is right before the [] (in this case $item-ids), so #abg:id would be treated as $item-ids/#abg:id, which isn't what you want.
current() refers to the current context outside of the <xsl:if> so current()/#abg:id should reflect you the value you want.
I think it's because the line
<xsl:if test="$item-ids[.=#abg:id]">
compares the value of $item-ids to the string '#abg:id' - you need to compare it to the value of #abg:id which is why you need to select that value into the $id variable for the test to work.
Does that help at all?
Edit: I've misunderstood the issue - the other answers are better than mine.

How to use an XSL variable as a condition to evaluate XPath?

I have faced an issue when using a variable as a condition for XPath evaluation. I have the following template which works fine:
<xsl:template name="typeReasonDic">
<xsl:variable name="dic" select="$schema//xs:simpleType[#name = 'type_reason_et']"/>
<!-- do something with the variable -->
</xsl:template>
However, when I change it to look like this:
<xsl:template name="typeReasonDic">
<xsl:param name="choose_dic" select="#name = 'type_reason_et'"/>
<xsl:variable name="dic" select="$schema//xs:simpleType[$choose_dic]"/>
<!-- do something with the variable -->
</xsl:template>
it fails to find the desired node.
What I wish to get is a template with a default value for $choose_dic which can be overriden where necessary.
What am I missing here?
UPD: there is this link I found with the description of what I'm trying to do, but it doesn't seem to work for me.
You can't do this directly in XSLT 1.0 or 2.0 without an extension function. The problem is that with
<xsl:template name="typeReasonDic">
<xsl:param name="choose_dic" select="#name = 'type_reason_et'"/>
<xsl:variable name="dic" select="$schema//xs:simpleType[$choose_dic]"/>
<!-- do something with the variable -->
</xsl:template>
the <xsl:param> will evaluate its select expression a single time in the current context and store the true/false result of this evaluation in the $choose_dic variable. The <xsl:variable> will therefore select either all xs:simpleType elements under the $schema (if $choose_dic is true) or none of them (if $choose_dic) is false. This is very different from
<xsl:variable name="dic" select="$schema//xs:simpleType[#name = 'type_reason_et']"/>
which will evaluate #name = 'type_reason_et' repeatedly, in the context of each xsl:simpleType, and select those elements for which the expression evaluated to true.
If you store the XPath expression as a string you can use an extension function such as dyn:evaluate or the XSLT 3.0 xsl:evaluate element if you're using Saxon.
By doing
<xsl:param name="choose_dic" select="#name = 'type_reason_et'"/>
the XSL engine will try to evaluate "#name = 'type_reason_et'" as an XPath expression, and will assign the RESULT to your variable.
You should use the following variable declaration instead:
<xsl:param name="choose_dic">#name = 'type_reason_et'</xsl:param>
This is the default value, but you can override it when you call your template by using xsl:with-param.
XSLT is not a macro language where you might be able to concatenate your code at run-time from strings and then evaluate them dynamically. So in general for your purpose you would need an extension function to evaluate an XPath expression stored in a string or you need to look into a new XSLT 3.0 features like http://www.saxonica.com/documentation/xsl-elements/evaluate.xml.
What is possible in the scope of XSLT 1.0 or 2.0 is doing e.g.
<xsl:param name="p1" select="'foo'"/>
<xsl:variable name="v1" select="//bar[#att = $p1]"/>
where the param holds a value you compare to other value, for instance those in a node like an attribute or element node.

How to know variable has value or not in XSLT

I am creating XSLT file.
I have one variable which take value from XML file.But it may happen that there is no reference in xml for the value and at that time XSL variable will return False/None(don't know).I want keep condition like,If there is no value for the variable use the default one.
How to do that ?
With the few details given in the question, the simplest test you can do is:
<xsl:if test="$var">
...
</xsl:if>
Or you might use xsl:choose if you want to provide output for the else-case:
<xsl:choose>
<xsl:when test="not($var)"> <!-- parameter has not been supplied -->
</xsl:when>
<xsl:otherwise> <!--parameter has been supplied --> </xsl:otherwise>
</xsl:choose>
The second example will also handle the case correctly that the variable or parameter has not been supplied with an actual value, i.e. it equals the empty string. This works because not('') returns true.
You haven't explained what you mean by "has no value". Here is a generic solution:
not($v) and not(string($v))
This expression evaluates to true() iff $v "has no value".
Both conditions need to be met, because a string $v defined as '0' has a value, but not($v) is true().
In XSLT 1.0 using a default can be achieved in different ways if the "value" is a node-set or if the value is a scalar (such as a string, a number or a boolean).
#Alejandro provided one way to get a default value if a variable that is supposed to contain a node-set is empty.
If the variable is supposed to contain a scalar, then the following expression returns its value (if it has a value) or (otherwise) the desired default:
concat($v, substring($default, 1 div (not($v) and not(string($v)))))
You can use string-length to check, if a variable called $reference for example contains anything.
<xsl:choose>
<xsl:when test="string-length($reference) > 0">
<xsl:value-of select="$reference" />
</xsl:when>
<xsl:otherwise>
<xsl:text>some default value</xsl:text>
</xsl:otherwise>
</xsl:choose>
If necessary use normalize-space, too.
First, all variables has values, because XSLT belongs to declarative paradigm: there is no asignation instruction, but when you declare the variable you are also declaring the expression for its value relationship.
If this value it's a node set data type (that looks from your question), then you should test for an empty node set in case nothing was selected. The efective boolean value for an empty node set is false. So, as #0xA3 has answered: test="$node-set".
You wrote:
If there is no value for the variable
use the default one. How to do that ?
Well, that depends on what kind of data type you are looking for.
Suppose the node set data type: if you want $node-set-1 value or $node-set-2 if $node-set-1 is empty, then use:
$node-set-1|$node-set-2[not($node-set-1)]
I tried a lot of solution from SO, my last solution was taken from #dimitre-novatchev, but that one also not working every time. Recently I found one more solution from random google search, thought to share with the community.
In order to check empty variable value, we can declare an empty variable and compare its value against test condition. Here is code snippet:
<xsl:variable name="empty_string"/>
<xsl:if test="testVariableValue != $empty_string">
...
</xsl:if>
Here testVariableValue hold the value of new variable to be tested for empty
scenario.
Hope it would help to test empty variable state.