Generated wrong namespace - xslt

Is it possible that the namespace you declare will change if you generate an output? Is it because it gets the last version of this schema?
Below are the namespaces in my schema:
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"xmlns:link="http://www.xbrl.org/2003/linkbase"xmlns="http://www.w3.org/2001/XMLSchema" xmlns:xbrli="http://www.xbrl.org/2003/instance" xmlns:gl-cor="http://www.xbrl.org/int/gl/cor/2006-10-25" targetNamespace="http://www.xbrl.org/int/gl/cor/2006-10-25" elementFormDefault="qualified" attributeFormDefault="unqualified">
and the output generated was like this:
<gl-cor:defter xmlns:gl-cor="http://www.xbrl.org/int/gl/cor/2010-04-12" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.xbrl.org/int/gl/cor/2010-04-12 gl-cor-content-2006-10-25.xsd">
if you notice that the namespace of xmlns:gl-cor in the output was changed to "http://www.xbrl.org/int/gl/cor/2010-04-12". I've checked all my files and there's no 2010-04-12 declared. Anyone knows the reason why it happened?
Here is my XSLT:
<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:gl-cor="http://www.xbrl.org/int/gl/cor/2010-04-12" xmlns:gl-bus="http://www.xbrl.org/int/gl/bus/2006-10-25" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:link="http://www.xbrl.org/2003/linkbase" xmlns:xbrli="http://www.xbrl.org/2003/instance">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="/gl-cor:defter">
<edefter:defter xmlns:edefter="http://www.edefter.gov.tr"
xmlns:xades="http://uri.etsi.org/01903/v1.3.2#"
xmlns:ds="http://www.w3.org/2000/09/xmldsig#"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:apply-templates select="#*|node()"/>
</edefter:defter>
</xsl:template>
<xsl:template match="/gl-cor:defter/gl-cor:xbrl">
<xbrli:xbrl
xmlns:iso639="http://www.xbrl.org/2005/iso639"
xmlns:link="http://www.xbrl.org/2003/linkbase"
xmlns:xlink="http://www.w3.org/1999/xlink"
xmlns:gl-plt="http://www.xbrl.org/int/gl/plt/2006-10-25"
xmlns:iso4217="http://www.xbrl.org/2003/iso4217">
<xsl:apply-templates select="#*|node()"/>
</xbrli:xbrl>
</xsl:template>
<xsl:template match="*[ancestor::gl-cor:entityInformation]">
<xsl:element name="gl-bus:{local-name()}">
<xsl:copy-of select="#*" />
<xsl:apply-templates />
</xsl:element>
</xsl:template>
<xsl:template match="*[self::gl-cor:creator]">
<xsl:element name="gl-bus:{local-name()}">
<xsl:copy-of select="#*" />
<xsl:apply-templates />
</xsl:element>
</xsl:template></xsl:stylesheet>
and my xml input file:
<gl-cor:defter xmlns:gl-cor="http://www.xbrl.org/int/gl/cor/2010-04-12" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.xbrl.org/int/gl/cor/2010-04-12 gl-cor-content-2006-10-25.xsd"><gl-cor:xbrl><gl-cor:accountingEntries><gl-cor:documentInfo><gl-cor:creator contextRef="ledger_context"></gl-cor:creator><gl-cor:entityInformation><gl-cor:entityPhoneNumber><gl-cor:phoneNumberDescription contextRef="ledger_context"></gl-cor:phoneNumberDescription>

Your XSLT just copies the input to the output (the first template is an identity transformation).
Since the namespace mappings for the prefix gl-cor are different in the XSLT and the XML input file, none of the other templates will match.

Related

XSLT change from elements to attribute format

What would be the XSLT to change this XML
<?xml version="1.0" encoding="utf-8"?>
<cas:ADDRESS_DETAILS PRIMARY_ADDRESS_INDICATOR="1" ADDRESS_ID="-289495914026885120" ADDRESS_TYPE="45001" ADDRESS_ACTIVE_FROM_DATE="2006-12-23" PERSON_ID="14512823342202880">
<cas:ADDRESS_ELEMENT VALUE="McMurchy Avenue" TYPE="ADD2" />
<cas:ADDRESS_ELEMENT VALUE="ON" TYPE="PROV" />
<cas:ADDRESS_ELEMENT VALUE="CA" TYPE="COUNTRY" />
<cas:ADDRESS_ELEMENT VALUE="Brampton" TYPE="CITY" />
<cas:ADDRESS_ELEMENT VALUE="440" TYPE="ADD1" />
</cas:ADDRESS_DETAILS>
In to this format
<?xml version="1.0" encoding="utf-8"?>
<cas:ADDRESS_DETAILS PRIMARY_ADDRESS_INDICATOR="1" ADDRESS_ID="-289495914026885120" ADDRESS_TYPE="45001" ADDRESS_ACTIVE_FROM_DATE="2006-12-23" PERSON_ID="14512823342202880" ADD2 ="McMurchy" PROV="ON" COUNTRY="CA" CITY="Brampton" ADD1="440">
</cas:ADDRESS_DETAILS>
Assuming you want to merge all ADDRESS_ELEMENTs inside their parent you can use
<xsl:template match="ADDRESS_ELEMENT[1]">
<xsl:copy>
<xsl:apply-templates select="../ADDRESS_ELEMENT" mode="to-attribute"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ADDRESS_ELEMENT[position() > 1]"/>
<xsl:template match="ADDRESS_ELEMENT" mode="to-attribute">
<xsl:attribute name="{#TYPE}" select="#VALUE"/>
</xsl:template>
plus the identity transformation to handle the rest (i.e. <xsl:mode on-no-match="shallow-copy"/> in XSLT 3 (https://xsltfiddle.liberty-development.net/6qM2e2q) or the corresponding template in earlier versions)
If you want to transform the child elements into attributes of the parent, as your edit seems to indicate, you can simplify the code. Using a namespace requires some adaption however:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xpath-default-namespace="http://example.com/cas"
version="3.0">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="ADDRESS_DETAILS">
<xsl:copy>
<xsl:apply-templates select="#*, ADDRESS_ELEMENT"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ADDRESS_ELEMENT">
<xsl:attribute name="{#TYPE}" select="#VALUE"/>
</xsl:template>
</xsl:stylesheet>
https://xsltfiddle.liberty-development.net/6qM2e2q/2

Replace strings XSLT

i'm stucked. Please help me with a little problem.
I have to change just two specific lines in XML file like this:
<?xml version="1.0" encoding="UTF-8"?>
<max:PublishTP_WORKORDER xmlns:max="http://www.ibm.com/maximo" creationDateTime="2014-04-11T10:43:51+04:00" transLanguage="RU" baseLanguage="EN" messageID="1397198631936413520" maximoVersion="7 5 20130829-1209 V7510--1" event="1">
<TP_WORKORDERSet xmlns="http://www.ibm.com/maximo" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<WORKORDER action="Replace">
<ACTCOST xsi:nil="true"/>
<ACTFINISH xsi:nil="true"/>
<ACTINTLABCOST>0.0</ACTINTLABCOST>
<ACTINTLABHRS>0.0</ACTINTLABHRS>
<ACTLABCOST>0.0</ACTLABCOST>
<ACTLABHRS>0.0</ACTLABHRS>
<ACTMATCOST>0.0</ACTMATCOST>
<ACTOUTLABCOST>0.0</ACTOUTLABCOST>
<ACTOUTLABHRS>0.0</ACTOUTLABHRS>
<ACTSERVCOST>0.0</ACTSERVCOST>
<ACTSTART>2013-11-08T12:03:26+04:00</ACTSTART>
<ACTTOOLCOST>0.0</ACTTOOLCOST>
<ADDRESS/>
<AMCREW/>
<AMS>0</AMS>
<AOS>0</AOS>
...........................
<WORKORDERID>10</WORKORDERID>
<WORKPACKMTLSTATUS/>
<WORKTYPE/>
<WOSEQUENCE xsi:nil="true"/>
</WORKORDER>
</TP_WORKORDERSet>
</max:PublishTP_WORKORDER>
I need to replace "PublishTP_WORKORDER" with "Create_WORKORDER", both open and close tags.
It works fine with:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:max="http://www.ibm.com/maximo" version="1.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/max:PublishTP_WORKORDER">
<xsl:element name="max:CreateTP_WORKORDER">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
But in XML file it could be "PublishTP_WORKORDER2" or "PublishTP_WORKORDER3" and so on.
It should be changed to "CreateTP_WORKORDER2", "CreateTP_WORKORDER3" etc
And this XSLT scheme stops working. It's just doesn't recognize strings with added numeric symbols. How could i turn it out? Thanks in advance.
It's always root element
Then how about:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:max="http://www.ibm.com/maximo">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<xsl:variable name="suffix" select="substring-after(local-name(), 'PublishTP_WORKORDER')" />
<xsl:element name="max:CreateTP_WORKORDER{$suffix}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

How to remove the rootnodes using XSLT?

Input file:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:root xmlns:ns0="http://xyz.com/separate">
<ns0:root1>
<ns3:Detail xmlns:ns3="http://POProject/Details">
<DetailLines>
<ItemID>
<ItemDescription/>
</DetailLines>
</ns3:Detail>
</ns0:root1>
</ns0:root>
Output file:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Detail xmlns:ns0="http://POProject/Details">
<DetailLines>
<ItemID>
<ItemDescription/>
</DetailLines>
</ns0:Detail>
Question: I have to remove the root1 and root nodes and need to do small
changes in Detail node. How to write a xslt code to achieve this?
This...
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xyz.com/separate"
xmlns:ns3="http://POProject/Details">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:apply-templates select="*/*/ns3:Detail" />
</xsl:template>
<xsl:template match="ns3:Detail">
<xsl:apply-templates select="." mode="copy-sans-namespace" />
</xsl:template>
<xsl:template match="*" mode="copy-sans-namespace">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-sans-namespace" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
...will yield this...
<?xml version="1.0" encoding="utf-8"?>
<ns3:Detail xmlns:ns3="http://POProject/Details">
<DetailLines>
<ItemID />
<ItemDescription />
</DetailLines>
</ns3:Detail>
I'm not sure it is possible to control the prefix. The XDM data model does not consider it to be significant information.
UDPATE
To get the prefix rename, I thought you would have to go to an XML 1.1 supporting XSLT processor (allowing prefix undefine), but I found a way to do it with XML 1.0 . Try this ...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xyz.com/separate">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/" xmlns:ns3="http://POProject/Details">
<xsl:apply-templates select="*/*/ns3:Detail" />
</xsl:template>
<xsl:template match="ns0:Detail" xmlns:ns0="http://POProject/Details">
<ns0:Detail xmlns:ns0="http://POProject/Details">
<xsl:apply-templates select="*" mode="copy-sans-namespace" />
</ns0:Detail>
</xsl:template>
<xsl:template match="*" mode="copy-sans-namespace">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-sans-namespace" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>

how to remove a part of attribut to a node in xml file using xslt

I have the following xml code:
<OML>
<bg-def xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="EX1"/>
</OML>
I want to remove the attribute xmlns:xsi and its value using XSLT, so that the result will look like this:
<OML>
<bg-def name="EX1"/>
</OML>
I tryied to do this with the following XSLT code:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:ex="http://exslt.org/dates-and-times" extension-element-prefixes="ex">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no" xml:space="preserve"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="bg-def|# xmlns:xsi"/>
</xsl:transform>
Before I finished to write my code, my editor warned me that:
"W Namespace prefix xmlns has not been declared".
When I remove the expression :xsi and just write xmlns, there is no warning more. But when I compile and execute my program, nothing happens and I don't get the expected output.
I try also to change the last line of my xslt file with this:
<xsl:template match="bg-def|# name"/>
then the result is looking like this:
<OML>
<bg-def xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
</OML>
That means, the attribute name has been removed very well. But I want to do this with the attribute xmlns:xsi.
Can someone help me to do this please?
Thanks for any help.
Franky
Use following template for bd-def node:
<xsl:template match="bg-def">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
Instead of
<xsl:template match="bg-def|# name"/>
This template will create node bg-def and copy all it context nodes and attributes, but not namespaces
Check similar question:
remove namespace for a perticular element
Update:
Source file:
<OML>
<bg-def xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="EX1"/>
</OML>
Stylesheet:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:ex="http://exslt.org/dates-and-times" extension-element-prefixes="ex">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no" xml:space="preserve"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="bg-def">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
</xsl:transform>
Transformation result (Saxon 6.5.5 - Xslt 1.0):
<?xml version="1.0" encoding="UTF-8"?><OML>
<bg-def name="EX1"/>
</OML>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>

XSLT: How to change an attribute value during <xsl:copy>?

I have an XML document, and I want to change the values for one of the attributes.
First I copied everything from input to output using:
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
And now I want to change the value of the attribute "type" in any element named "property".
This problem has a classical solution: Using and overriding the identity template is one of the most fundamental and powerful XSLT design patterns:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:param name="pNewType" select="'myNewType'"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="property/#type">
<xsl:attribute name="type">
<xsl:value-of select="$pNewType"/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
When applied on this XML document:
<t>
<property>value1</property>
<property type="old">value2</property>
</t>
the wanted result is produced:
<t>
<property>value1</property>
<property type="myNewType">value2</property>
</t>
Tested on a simple example, works fine:
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#type[parent::property]">
<xsl:attribute name="type">
<xsl:value-of select="'your value here'"/>
</xsl:attribute>
</xsl:template>
Edited to include Tomalak's suggestion.
The top two answers will not work if there is a xmlns definition in the root element:
<?xml version="1.0"?>
<html xmlns="http://www.w3.org/1999/xhtml">
<property type="old"/>
</html>
All of the solutions will not work for the above xml.
The possible solution is like:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()[local-name()='property']/#*[local-name()='type']">
<xsl:attribute name="{name()}" namespace="{namespace-uri()}">
some new value here
</xsl:attribute>
</xsl:template>
<xsl:template match="#*|node()|comment()|processing-instruction()|text()">
<xsl:copy>
<xsl:apply-templates select="#*|node()|comment()|processing-instruction()|text()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
You need a template that will match your target attribute, and nothing else.
<xsl:template match='XPath/#myAttr'>
<xsl:attribute name='myAttr'>This is the value</xsl:attribute>
</xsl:template>
This is in addition to the "copy all" you already have (and is actually always present by default in XSLT). Having a more specific match it will be used in preference.
I had a similar case where I wanted to delete one attribute from a simple node, and couldn't figure out what axis would let me read the attribute name. In the end, all I had to do was use
#*[name(.)!='AttributeNameToDelete']
I also came across same issue and i solved it as follows:
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<!-- copy property element while only changing its type attribute -->
<xsl:template match="property">
<xsl:copy>
<xsl:attribute name="type">
<xsl:value-of select="'your value here'"/>
</xsl:attribute>
<xsl:apply-templates select="#*[not(local-name()='type')]|node()"/>
</xsl:copy>
</xsl:template>
For the following XML:
<?xml version="1.0" encoding="utf-8"?>
<root>
<property type="foo"/>
<node id="1"/>
<property type="bar">
<sub-property/>
</property>
</root>
I was able to get it to work with the following XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//property">
<xsl:copy>
<xsl:attribute name="type">
<xsl:value-of select="#type"/>
<xsl:text>-added</xsl:text>
</xsl:attribute>
<xsl:copy-of select="child::*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If your source XML document has its own namespace, you need to declare the namespace in your stylesheet, assign it a prefix, and use that prefix when referring to the elements of the source XML - for example:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xhtml="http://www.w3.org/1999/xhtml">
<xsl:output method="xml" encoding="utf-8" indent="yes" omit-xml-declaration="yes" />
<!-- identity transform -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- exception-->
<xsl:template match="xhtml:property/#type">
<xsl:attribute name="type">
<xsl:text>some new value</xsl:text>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
Or, if you prefer:
...
<!-- exception-->
<xsl:template match="#type[parent::xhtml:property]">
<xsl:attribute name="type">
<xsl:text>some new value</xsl:text>
</xsl:attribute>
</xsl:template>
...
ADDENDUM:
In the highly unlikely case where the XML namespace is not known beforehand, you could do:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="utf-8" indent="yes" omit-xml-declaration="yes" />
<!-- identity transform -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- exception -->
<xsl:template match="*[local-name()='property']/#type">
<xsl:attribute name="type">
<xsl:text>some new value</xsl:text>
</xsl:attribute>
</xsl:template>
Of course, it's very difficult to imagine a scenario where you would know in advance that the source XML document contains an element named "property", with an attribute named "type" that needs replacing - but still not know the namespace of the document. I have added this mainly to show how your own solution could be streamlined.