how to remove a part of attribut to a node in xml file using xslt - xslt

Question

I have the following xml code:
<OML>
<bg-def xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="EX1"/>
</OML>
I want to remove the attribute xmlns:xsi and its value using XSLT, so that the result will look like this:
<OML>
<bg-def name="EX1"/>
</OML>
I tryied to do this with the following XSLT code:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:ex="http://exslt.org/dates-and-times" extension-element-prefixes="ex">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no" xml:space="preserve"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="bg-def|# xmlns:xsi"/>
</xsl:transform>
Before I finished to write my code, my editor warned me that:
"W Namespace prefix xmlns has not been declared".
When I remove the expression :xsi and just write xmlns, there is no warning more. But when I compile and execute my program, nothing happens and I don't get the expected output.
I try also to change the last line of my xslt file with this:
<xsl:template match="bg-def|# name"/>
then the result is looking like this:
<OML>
<bg-def xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
</OML>
That means, the attribute name has been removed very well. But I want to do this with the attribute xmlns:xsi.
Can someone help me to do this please?
Thanks for any help.
Franky

Answer 1

Use following template for bd-def node:
<xsl:template match="bg-def">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
Instead of
<xsl:template match="bg-def|# name"/>
This template will create node bg-def and copy all it context nodes and attributes, but not namespaces
Check similar question:
remove namespace for a perticular element
Update:
Source file:
<OML>
<bg-def xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="EX1"/>
</OML>
Stylesheet:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:ex="http://exslt.org/dates-and-times" extension-element-prefixes="ex">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no" xml:space="preserve"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="bg-def">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
</xsl:transform>
Transformation result (Saxon 6.5.5 - Xslt 1.0):
<?xml version="1.0" encoding="UTF-8"?><OML>
<bg-def name="EX1"/>
</OML>

Answer 2

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>