When I use a dereference in a function as an argument, the preprocessor spits out an error.
I believe the * right before the parentheses causes ambiguity with the compiler.
Is there any way to get around this?
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
int main ()
{
char *in = NULL;
char *out = NULL;
getline(cin,in*);//error
out=system(in*);//error
printf(out);
return 0;
}
The errors are on marked lines.
Thank you!
Dereferencing in is written *in, not in*. (Also, even with that fixed, your program still won't work, as you're trying to dereference NULL, and the second argument to getline will have the wrong type. char* strings do not work the way you think they work.)
getline only works with C++ strings (not C-style strings). C++ strings can allocate memory as they go, in response to how much data is read.
There are other functions for reading into C strings, but you must pre-allocate the amount of memory you want, and also specify to the function how much memory you have allocated. In general there is no reason to do this, as the C++ string version is much simpler and less prone to error.
Also, avoid including C-style standard headers (i.e. ending in .h) and avoid using pointers. And system returns an int, not a string.
Example:
#include <iostream> // cin, cout
#include <string> // string
#include <cstdlib> // system
int main()
{
std::string s;
std::getline( std::cin, s );
int system_result = std::system( s.c_str() );
std::cout << system_result << "\n";
}
Related
#include <iostream>
#include <numeric>
#include <ranges>
#include <vector>
#include <string>
#include <string_view>
int main() {
auto str = (
std::views::iota(1)
| std::ranges::views::take(5)
| std::ranges::views::transform([](int x) -> std::string_view {
return std::to_string(x) + "|";
})
| std::ranges::views::join
);
for (const char ch : str) {
std::cout << ch;
}
return 0;
}
I'm new to functional programming in cpp. I want to generate first five natural numbers and translate them to string, then join them and print it.
If I use std::string for return type of lambda for transform, it throws many error on compile time. I thought that I should change it into std::string_view. I changed so, and it compiled without compile error. However, if I use std::string_view there, the lambda function returns only reference for string, and translated string that on stack memory is removed on memory when lambda ends. So, the program doesn't print anything.
How can I fix it?
If I use std::string for return type of lambda for transform, it
throws many error on compile time.
What you have observed is a C++20 defect that has been resolved by P2328. If you use a newer compiler version that has already implemented P2328 (such as gcc-11.2), your code will be well-formed.
Before P2328, I think there is no simple solution in the standard.
I keep getting this error (it's a really long one but I think the most important part is this):
main.cpp:9:30: note: mismatched types 'std::__cxx11::basic_string<_CharT, _Traits, _Alloc>' and 'const char [2]'
While compiling this bit of code:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string x = getline(cin, " ");
return 0;
}
The lines in the error won't match with the ones in the code I brought up here because I don't know how to make a new line whilst writing code in the Stack Overflow editor; I'm new here ;) Anyways, the error points to the line with the declaration of string x.
Basically what I want this code to do is to get a line from the user until he/she hits space. Maybe I'm doing something wrong from the beginning, so I'm open for suggestions of fixing this problem. (I'm not very experienced in C++, it's just that my teacher required to complete a task using this language.) Thanks,
Anthony
The second parameter of std::getline() is a reference to a std::string variable that accepts the read data. The string is not outputted in the function's return value.
Also, std::getline() does not accept a string for the delimiter. It takes only a single character.
Try this instead:
#include <iostream>
#include <string>
using namespace std;
int main() {
string x;
getline(cin, x, ' ');
return 0;
}
If I set a string as a filename, it doesn't work and I have no idea why. (I'm using codeblocks and it seems to work on other IDEs)
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
string FileName="Test.txt";
ofstream File;
File.open(FileName);
}
This does not work,while this next one does:
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
ofstream File;
File.open("Test.txt");
}
Error message:
no matching function for call to std::basic_ofstream::open(std::string&)
Can someone help a bit with this problem, I cannot understand why this error occurs.
Due to what should be considered a historical accident in the early era of C++ standardisation, C++ file streams originally didn't support std::string for filename parameters, only char pointers.
That's why something like File.open(FileName), with FileName being a std::string, didn't work and had to written as File.open(FileName.c_str()).
File.open("Test.txt") always worked because of the usual array conversion rules which allow the "Test.txt" array to be treated like a pointer to its first element.
C++11 fixed the File.open(FileName) problem by adding std::string overloads.
If your compiler doesn't support C++11, then perhaps you should get a newer one. Or perhaps it does support C++11 and you just have to turn on the support with a flag like -std=c++11.
I am working with C++ in eclipse CDT and I am trying to convert string to uint64_t by using strtoull but everytime I get below error message -
..\src\HelloTest.cpp:39:42: error: strtoull was not declared in this scope
Below is my C++ example
#include <iostream>
#include <cstring>
#include <string>
using namespace std;
int main() {
string str = "1234567";
uint64_t hashing = strtoull(str, 0, 0);
cout << hashing << endl;
}
return 0;
}
Is there anything wrong I am doing?
Why your solution doesn't work has already been pointed out by others. But there hasn't been a good alternative suggested yet.
Try this for C++03 strtoull usage instead:
#include <string>
#include <cstdlib>
int main()
{
std::string str = "1234";
// Using NULL for second parameter makes the call easier,
// but reduces your chances to recover from error. Check
// the docs for details.
unsigned long long ul = std::strtoull( str.c_str(), NULL, 0 );
}
Or, since C++11, do it directly from std::string via stoull (which is just a wrapper for the above, but saves on one include and one function call in your code):
#include <string>
int main()
{
std::string str = "1234";
// See comment above.
unsigned long long ul = std::stoull( str, nullptr, 0 );
}
Never use char[] or pointers if you have a working alternative. The dark side of C++, they are. Quicker, easier, more seductive. If once you start down the dark path, forever will it dominate your destiny, consume you it will. ;-)
the structure for strtoull is: strtoull(const char *, char * *, int)
You have given it a std::string as pointed out by #juanchopanza
This is the solution I came up with is
#include <iostream>
#include <cstring>
#include <string>
#include <cstdlib>
using namespace std;
int main() {
char str[] = "1234567";
unsigned long long ul;
char* new_pos;
charDoublePointer = 0;
ul = strtoull(str, &new_pos, 0);
cout << ul << endl;
return 0;
}
The output I got was: 1234567
Straight from the eclipse console.
Also at the end of your program you have return 0 out of scope with an extra curly brace.
I'm experimenting with C++ file I/O, specifically fstream. I wrote the following bit of code and as of right now it is telling me that there is no getline member function. I have been told (and insisted still) that there is a member function getline. Anybody know how to use the getline member function for fstream? Or perhaps another way of getting one line at a time from a file? I'm taking in two file arguments on the command line with unique file extensions.
./fileIO foo.code foo.encode
#include <fstream>
#include <iostream>
#include <queue>
#include <iomanip>
#include <map>
#include <string>
#include <cassert>
using namespace std;
int main( int argc, char *argv[] )
{
// convert the C-style command line parameter to a C++-style string,
// so that we can do concatenation on it
assert( argc == 2 );
const string foo = argv[1];
string line;string codeFileName = foo + ".code";
ifstream codeFile( codeFileName.c_str(), ios::in );
if( codeFile.is_open())
{
getline(codeFileName, line);
cout << line << endl;
}
else cout << "Unable to open file" << endl;
return 0;
}
getline(codeFileName, line);
Should be
getline(codeFile, line);
You're passing in the file name, not the stream.
By the way, the getline you're using is a free function, not a member function. In fact, one should avoid the member function getline. It's much harder to use, and harkens back to a day when there was no string in the standard library.
Typo
getline(codeFileName, line);
should be
getline(codeFile, line);
I guess the lesson is you have to learn how to interpret compiler error messages. We all make certain kinds of mistakes and learn the compiler errors they tend to generate.