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I have a String like this
String s1="1 AND 1 OR 1";
I want split with AND OR and my result should be 1,1,1
I am using JAVA /eclipse
package com.test;
String s1="1 AND 1 OR 1";
String[] splits=s1.split("[AND\OR]");
for (int i = 0; i < splits.length; i++) {
System.out.println(splits[i]);
}
}
}
Can I get any help how to do this?
Any Help appreciated
I am unsure about the language, but for C# you can use the following:
string s1 = "1 AND 1 OR 1";
string s2 = s1.Replace("AND", ",").Replace("OR", ",");
Console.WriteLine(s2);
Which doesn't use regular expressions.
If you want an array, you can use the following:
string s1 = "1 AND 1 OR 1";
string[] s2 = Regex.Split(s1.Replace(" ", string.Empty), "AND|OR");
In Java you can replace using the same mechanism:
String s1 = "1 AND 1 OR 1";
String s2 = s1.replace("AND", ",").replace("OR", ",");
System.out.println(s2);
And to get an array:
String s1="1 AND 1 OR 1";
String[] s2 = s1.replace(" ", "").split("AND|OR");
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How can I get from string "C27_W112_V113_Table__6__1" string "6" or from string "C27_W120_V153_Table__22__1" string "22". thx
You can achieve it by two ways
Regex approach:
const re = /(\d+)__\d+$/;
let values = [
'C27_W112_V113_Table__6__1',
'C27_W120_V153_Table__22__1'
];
values.forEach(str => console.log(str.match(re)[1]));
string manipulation (I assume the value is always at the same place):
values.forEach(str => {
let reversed = str.split('').reverse().join('');
let index = reversed.indexOf('__');
console.log(reversed.slice(index+2, reversed.indexOf('__', index+1)));
});
Here a snippet
const re = /(\d+)__\d+$/;
let values = [
'C27_W112_V113_Table__6__1',
'C27_W120_V153_Table__22__1'
];
values.forEach(str => console.log(str.match(re)[1]));
console.log('--------');
values.forEach(str => {
let reversed = str.split('').reverse().join('');
let index = reversed.indexOf('__');
console.log(reversed.slice(index+2, reversed.indexOf('__', index+1)));
});
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I have the below format of a string:
str1 = "a, b, c, d, e";
str2 = "aa, ba, ca, da, essd";
str2 = "aass, bsda, cads, dsda, esssdsd";
I want to extract the end of the string after splitting --> e, essd, esssdsd.
Assuming these are std::strings, I'd use rfind to find the last occurrence of the delimiter, and then take a substring from there. E.g.:
size_t index = str.rfind(", ");
string last_element = str.substr(index + 2); // 2 is the size of the delimiter
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I want to reverse a substring in a string. For example
string x = "foobar";
So I want to reverse foo to be oof so x would be "oofbar";
Here's a sample of what I have tried:
string x = "foobar";
size_t pos = x.find("foo");
reverse(x.begin() + k, s.end()); // I got stuck here.
For a simple case as
string x = "foobar";
you can use
std::reverse(x.begin(), x.begin() + 3); // reverse the first three letters.
If "foo" is embedded in the string, i.e. it is not at the start of the string, you'll have to find its location first.
string x = "whoknowswhereitisfoobar";
auto loc = x.find("foo");
if ( loc != std::string::npos )
{
std::reverse(x.begin() + loc, x.begin() + loc + 3);
}
If you don't want to hard code the number 3, you can use std::string::size():
string hay = "whoknowswhereitisfoobar";
string needle = "foo";
auto loc = hay.find(needle);
if ( loc != std::string::npos )
{
std::reverse(hay.begin() + loc, hay.begin() + loc + needle.size());
}
See Live Here
Given auto x = "foobar"s and const auto value = "foo"s, I'd probably use iterators just cause of their convenience:
const auto it = search(cbegin(x), cend(x), cbegin(value), cend(value));
if(it != cend(x)) {
x.replace(it, next(it, size(value)), crbegin(value), crend(value));
}
Live Example
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I would like to use string class, to extract some information from the string.
Given the string: <12,Apple>,<20,Orange>,<49,iPhone>
I would like to let 12, 20, 49 to a int array.
that means a[0] = 12, a[1] = 20, a[2] = 49.
And let Apple, Orange, iPhone to a String array.
that means b[0] = "Apple", b[1] = "Orange" b[2] = "iPhone"
How should I do?
Assume the string follows the format <int,string>,.... Please find the pseudo-code below:
Loop through the string `str` and
{
smaller_sign_pos = str.find('<', prev_pos)
entry_comma_pos = str.find(',', smaller_sign_pos+1)
greater_sign_pos = str.find('>', entry_comma_pos+1)
if (all pos values are not `npos`)
{
int_value = atoi(str.substr(smaller_sign_pos+1, entry_comma_pos-smaller_sign_pos-1))
str_value = str.substr(entry_comma_pos+1, greater_sign_pos-entry_comma_pos-1)
prev_pos = greater_sign_pos+1
append int_value to int array
append str_value to string array
optional: you can check if the comma after '>' exists
}
else
{
break or set the end of loop flag
}
}
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I want to know how can I find empty or whitespaces within substring in C++. For example:
string str = "( )"; // or str = "()"
Here, I want to make sure there is always something in between parenthesis. Function isspace() takes only one character so I have to search in loop. Is there any better way to do this? Thanks for your help.
You can use std::string::find() to find the ( and ) characters, then use std::string::find_first_not_of() to check for any non-whitespace characters between those indexes.
string str = "( )"; // or str = "()"
string::size_type idx1 = str.find("(");
if (idx1 != string::npos) {
++idx1;
string::size_type idx2 = str.find(")", idx1);
if (idx2 != string::npos) {
string tmp = str.substr(idx, idx2-idx1);
string::size_type idx3 = tmp.find_first_not_of(" \t\r\n");
if (idx3 != string::npos) {
...
}
}
}