Does anybody knows the SAS function, which could return the year days count by the given date?
For example:
input value - date,
output value - days in the year(date)
I took the example from the docs and edited it to match your request
data _null;
startdate='01jan14'd;
enddate=DATE();
actual=datdif(startdate, enddate, 'act/act');
put actual;
run;
This should output 160 because that is the amount of days between today and Jan 1 (not counting today)
The start date is Jan 1 '14
The end date is DATE() which is 'today'
This uses the datdif function that is explained in detail in the link.
Since SAS dates are just numbers...you can manipulate them by simply adding and subtracting them.
Data _null_;
Diff= today() - '01Jan2014'd;
Put Diff=;
Run;
Returns 160 in the log.
Related
I Have a file from excel that is in a short date format, but when SAS reads it in, it turns it into numbers in the 4000 range...when I try and convert this to an excel date with the below formula, it turns the year into 2077...is there a formula to ensure that this date remains in the original format on the read in, or avoid it turning into this 4000 range that is not at all close to the 2017 and 2018 year that my file is starting in. Does that make sense?
data change_date;
format Completed_Date mmddyy8. ;
set check;
completed_date = date_completed;
if 42005 => date_completed >=43466 and date_completed ^=. then
Completed_date = Date_Completed-21916; *commented out 12-21-17 Xalka
dates back to how they are expected;
run;
I am pretty sure this is a duplicate question, but I can't find it.
This is usually caused by mixing character and date values in the same column. This made SAS import the data as a character variable and it results in the actual dates being copied as character versions of the integers that Excel uses to store dates.
Frequently this is caused by entries that look like dates but are really character strings in the Excel file. The best way to fix it is to fix the Excel file so that the column only contains dates. Otherwise you just need to convert the strings to integers and adjust the values to account for the differences in index dates.
So if your values are in a SAS dataset named HAVE in the character variable DATESTRING then you could use this data step to create a new variable with an actual date value.
data want ;
set have ;
if indexc(datestring,'-/') then date=input(datestring,anydtdte32.);
else date = input(datestring,32.) + '01JAN1900'D -2;
format date yymmdd10. ;
run;
The minus 2 is because of difference in whether to start numbering with 1 or 0 and because Excel thinks 1900 was a leap year.
Excel and SAS have different default dates in back-end.
Day 0 in SAS is 1 January 1960 and Day 0 in Excel is 1 January 1900.
So, you will need to convert excel numeric date to sas date using the below formula.
SAS_date = Excel_date - 21916;
data dateExample;
informat dt mmddyy8.;
set dates;
SAS_date = dates - 21916;
dt=sas_Date;
format dt date9.;
run;
The date in the table is not one set,
Days in the days column and months in the month column and years in the year column
I have concatenated the columns and then put these concatenation in where clause and put the parameter I have made but I got no result
I assume you are querying a date dimension table, and you want to extract the record that matches a certain date.
Solution:
I created a dates table to match with,
data dates;
input key day month year ;
datalines;
1 19 2 2018
2 20 2 2018
3 21 2 2018
4 22 2 2018
;;;
run;
Output:
In the where clause I parse the date '20feb2018'd using day, month & year functions: in SAS you have to quote the dates in [''d]
proc sql;
select * from dates
/*if you want to match todays' date: replace '20feb2018'd with today()*/
where day('20feb2018'd)=day and month('20feb2018'd)=month and year('20feb2018'd)=year;
quit;
Output:
if you compare date from day month and year, then use mdy function in where clause as shown below. it is not totally clear what you are looking for.
proc sql;
select * from dates
where mdy(month,day, year) between '19feb2018'd and '21feb2018'd ;
Using 'intck' for calculating no of days between two dates.
data test;
x=intck('day','01dec2016'd,'31dec2016'd);
run;
Output is x=30.
It should be 31.How to solve it ?`
Here's one way!
data test;
x=intck('day','01dec2016'd,'31dec2016'd)+1;
run;
as #jonrsharpe comments.. There are indeed 30 days between those dates, so if you are looking for the number of days in a month, you can try starting from the last day of the previous month - or simply add one.
Hi to all and good time of a day!
Here is my case I need to solve I will very gratefull if you can help me.
I have some data set it contains only one variable date format.
Example:
01JAN2016
06JAN2016
15FEB2016
The second data set is days - holidays for a period 5 years.
Example:
01JAN2016
02JAN2016
and etc, all these days are not working days.
The case is I need to count number of working days from date for every observation from first data set till now. It seems that I need to count number of days
"Now date" minus Date(from first data set) and minus number of days from second data set with holidays (count(date) where Date(from first data set)< date < "Now"
You can define your own type of interval to use with SAS funcions intck and intnx. Here's how to do it:
First create a table of weekdays for whichever years you have holidays for, up to present (or a future) year.
Here we'll start by including all weekdays from 2014 to 2016. This is assuming you don't want to count weekend days. If that's not the case, just modify the code so that the condition "weekday(date) in (2:6)" is not applied. You'll get the full 365 days of the year.
data mon_fri;
do date = "01JAN2014"d to "31DEC2016"d;
if weekday(date) in (2:6) then output;
end;
format date date9.;
run;
Then we'll create a table having all those dates we just created, minus the holidays we have in the table Holidays. We'll place the table in a library called myLib, and rename the date column to "Begin" for compliance with SAS custom intervals.
libname myLib "some/place/on/your/drive";
data mylib.workdays(RENAME=(date=Begin));
merge mon_fri (in=weekday)
Holidays (in=holiday);
by date;
if weekday and not holiday then output;
run;
Now we set up a custom interval which we'll simply call "workdays".
options intervalds=(workdays=mylib.workdays);
From there, all you have left to do is something like this:
data dateCalculations;
set mydata;
numOfDays = intck("workdays", theDate, today());
run;
SAS will take care of counting the number of dates (lines in the workdays dataset) separating the startdate (column called theDate) from the enddate (today's date).
Et voilà!
This is wonderful and very helpful. I use two different SAS systems (both on remote Unix servers). Setting the intervalds option only seems to work on one of them. I copy/paste the same code and on the other nothing happens - no warning, no error, it simply doesn't work.
Here is how I'm setting it (download the CSV from Yahoo! Finance for the S&P500, daily data, starting January 1950):
PROC IMPORT DATAFILE="sp500_1950_2016.csv"
OUT=sp500_1950_2016
DBMS=DLM
REPLACE;
delimiter=',';
getnames=yes;
RUN;
data trading_days;
set sp500_1950_2016 (keep = date rename=(date=begin));
where year(begin) < 2017;
run;
options intervalds=(TradingDay=trading_days) ;
Then I call it like so to count number of observations I should have from fund inception to Dec 31, 2016 or when the fund closed, whichever is sooner:
data ops2; set operations_master; where ~missing(inception);
if missing(enddate) then enddate = '31dec2016'd;
datadays = INTCK('TradingDay',inception,enddate);run;
proc univariate; var datadays;run;quit;
On system 1, this works just fine. On system 2, I get 0 for the variable datadays. I've already checked to see if there is a sys admin override on setting the intervalds option, and there is not. Is there another reason why this might not work on a given system?
using the week function to clean some data and eventually will order the weeks. I used week() on the date 8/26/2011 and I got 34, and when the function inserted the date 01/13/2012 it spit out 2. I thouhgt I was getting number of weeks since jan 1, 1960?
As per the WEEK Function documentation, the default U descriptor specifies the number of the week within the year, with Sunday being deemed the 1st day of the week. (You can use V if you want Monday to be considered the 1st day instead.)
The week function calculates the week of the current year. The answer to the implied question, "how do I calculated the number of days since 1/1/1960 [or some arbitrary date]," is the intck function.
data have;
input datevar date9.;
datalines;
01JAN1960
02JAN2013
13JAN2012
26AUG2011
;;;;
run;
data want;
set have;
wks = intck('week',0,datevar); *# of weeks from 0 to datevar [0=1/1/1960].
*Can replace 0 with any other date variable.;
run;