using the week function to clean some data and eventually will order the weeks. I used week() on the date 8/26/2011 and I got 34, and when the function inserted the date 01/13/2012 it spit out 2. I thouhgt I was getting number of weeks since jan 1, 1960?
As per the WEEK Function documentation, the default U descriptor specifies the number of the week within the year, with Sunday being deemed the 1st day of the week. (You can use V if you want Monday to be considered the 1st day instead.)
The week function calculates the week of the current year. The answer to the implied question, "how do I calculated the number of days since 1/1/1960 [or some arbitrary date]," is the intck function.
data have;
input datevar date9.;
datalines;
01JAN1960
02JAN2013
13JAN2012
26AUG2011
;;;;
run;
data want;
set have;
wks = intck('week',0,datevar); *# of weeks from 0 to datevar [0=1/1/1960].
*Can replace 0 with any other date variable.;
run;
Related
Hi I need to calculate the value of month supposed in sas
01jan1960 is equal to 1
02jan1960 is equal to 2
So I need to calculate for 01aug2020
I used intck function but no output
I want in datastep only .
SAS stores dates as the number of days since 1960 with zero representing first day of 1960. To represent a date in a program just use a quoted string followed by the letter D. The string needs to be something the DATE informat can interpret.
Let's run a little test.
6 data _null_;
7 do dt=0 to 3,"01-JAN-1960"d,'01AUG2020'd;
8 put dt= +1 dt date9.;
9 end;
10 run;
dt=0 01JAN1960
dt=1 02JAN1960
dt=2 03JAN1960
dt=3 04JAN1960
dt=0 01JAN1960
dt=22128 01AUG2020
So the date value for '01AUG2020'd is 22,128.
Subtraction works
days_interval = '01Aug2020'd - '01Jan1960'd;
Or looking at the unformatted value as SAS stores dates from 01Jan1960
days_interval = '01Aug2020'd;
format days_interval 8.;
friday=intnx('week.5',today(),0)
Is this correct logic to get next Friday?
In SAS 1 is Sunday, so you need to check for 6 instead.
data test;
next_friday=intnx('week.6',today(),1);
following_friday=intnx('week.6',today(),2);
format next_friday date9. following_friday date9. ;
put _all_;
run;
Output:
today is 1-MAY-2018
next_friday=04MAY2018 following_friday=11MAY2018
Note:
According to SAS documentation 0 should show the current week but it shows the previous week because we used week.6 in our case here but when using 1 instead the correct Friday is picked.
Hi to all and good time of a day!
Here is my case I need to solve I will very gratefull if you can help me.
I have some data set it contains only one variable date format.
Example:
01JAN2016
06JAN2016
15FEB2016
The second data set is days - holidays for a period 5 years.
Example:
01JAN2016
02JAN2016
and etc, all these days are not working days.
The case is I need to count number of working days from date for every observation from first data set till now. It seems that I need to count number of days
"Now date" minus Date(from first data set) and minus number of days from second data set with holidays (count(date) where Date(from first data set)< date < "Now"
You can define your own type of interval to use with SAS funcions intck and intnx. Here's how to do it:
First create a table of weekdays for whichever years you have holidays for, up to present (or a future) year.
Here we'll start by including all weekdays from 2014 to 2016. This is assuming you don't want to count weekend days. If that's not the case, just modify the code so that the condition "weekday(date) in (2:6)" is not applied. You'll get the full 365 days of the year.
data mon_fri;
do date = "01JAN2014"d to "31DEC2016"d;
if weekday(date) in (2:6) then output;
end;
format date date9.;
run;
Then we'll create a table having all those dates we just created, minus the holidays we have in the table Holidays. We'll place the table in a library called myLib, and rename the date column to "Begin" for compliance with SAS custom intervals.
libname myLib "some/place/on/your/drive";
data mylib.workdays(RENAME=(date=Begin));
merge mon_fri (in=weekday)
Holidays (in=holiday);
by date;
if weekday and not holiday then output;
run;
Now we set up a custom interval which we'll simply call "workdays".
options intervalds=(workdays=mylib.workdays);
From there, all you have left to do is something like this:
data dateCalculations;
set mydata;
numOfDays = intck("workdays", theDate, today());
run;
SAS will take care of counting the number of dates (lines in the workdays dataset) separating the startdate (column called theDate) from the enddate (today's date).
Et voilà!
This is wonderful and very helpful. I use two different SAS systems (both on remote Unix servers). Setting the intervalds option only seems to work on one of them. I copy/paste the same code and on the other nothing happens - no warning, no error, it simply doesn't work.
Here is how I'm setting it (download the CSV from Yahoo! Finance for the S&P500, daily data, starting January 1950):
PROC IMPORT DATAFILE="sp500_1950_2016.csv"
OUT=sp500_1950_2016
DBMS=DLM
REPLACE;
delimiter=',';
getnames=yes;
RUN;
data trading_days;
set sp500_1950_2016 (keep = date rename=(date=begin));
where year(begin) < 2017;
run;
options intervalds=(TradingDay=trading_days) ;
Then I call it like so to count number of observations I should have from fund inception to Dec 31, 2016 or when the fund closed, whichever is sooner:
data ops2; set operations_master; where ~missing(inception);
if missing(enddate) then enddate = '31dec2016'd;
datadays = INTCK('TradingDay',inception,enddate);run;
proc univariate; var datadays;run;quit;
On system 1, this works just fine. On system 2, I get 0 for the variable datadays. I've already checked to see if there is a sys admin override on setting the intervalds option, and there is not. Is there another reason why this might not work on a given system?
Does anybody knows the SAS function, which could return the year days count by the given date?
For example:
input value - date,
output value - days in the year(date)
I took the example from the docs and edited it to match your request
data _null;
startdate='01jan14'd;
enddate=DATE();
actual=datdif(startdate, enddate, 'act/act');
put actual;
run;
This should output 160 because that is the amount of days between today and Jan 1 (not counting today)
The start date is Jan 1 '14
The end date is DATE() which is 'today'
This uses the datdif function that is explained in detail in the link.
Since SAS dates are just numbers...you can manipulate them by simply adding and subtracting them.
Data _null_;
Diff= today() - '01Jan2014'd;
Put Diff=;
Run;
Returns 160 in the log.
I'm new to SAS and have been trying to figure out how to get the week number for each month. I'm having an issue with the months where they don't start at the beginning of the week. For example, if I have a month where the data from the 1st of the month falls on a Thursday, it shows the 1st and 2nd of that month as week 0. Is there a way to display those weeks as week 1? I've tried different things and have been unsuccessful.
DATA getweek;
set test;
if year(rundt) ne year(today())then delete;
month = month(rundt);
week1=intck('week',intnx('month',rundt,0),rundt);
format rundt MMDDYY8.;
RUN;
This depends largely on how you want to define week number. If the first of the month falls on a wednesday, what week is that week? Is that week one, or week zero? It can be commonly referred to either way.
If you want one, so Thurs/Fri/Sat are week 1, then the 4th is week 1, then just add one to the result - it's consistently going to be off (down) by one, after all.
data test;
do rundt=19805 to 19904;
day_of_month=day(rundt);
output;
end;
format rundt date9.;
run;
DATA getweek;
set test;
if year(rundt) ne year(today())then delete;
month = month(rundt);
week1=intck('week',intnx('month',rundt,0),rundt)+1;
format rundt MMDDYY8.;
RUN;
Now, if you want the first 9 or 10 days to be week 1, you have a different solution (though I don't recommend this). Use min to set it to minimum of one. This means your first week could be as many as 13 days, which is counterintuitive, but if it's what you need, this is how you do it.
DATA getweek;
set test;
if year(rundt) ne year(today())then delete;
month = month(rundt);
week1=min(intck('week',intnx('month',rundt,0),rundt),1);
format rundt MMDDYY8.;
RUN;