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Would some one please tell me the following Regex?
At least eight or more characters.
At least one lower-case letter.
At least one upper-case letter.
At least one number.
Thanks in advance.
Variation on Complex Password Regular Expression
You can use this lookahead based regex:
^(?=.*?[a-z])(?=.*?[A-Z])(?=.*?[0-9]).{8,}$
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I have string that could come in several forms
“PSM000216556880035450088|TRF”
“VNM000216556880035450088|TRF FROM MACK”
“NXG000216556880035450088”
“Transfer from josh SL000216556880035450088 to jack”
“X00000216556880035450088 0098123 TRANSFER 789121”
I need a Regex pattern that could get the string that starts with PSM, VNM, NXG, SL00 or X00.
i.e. in 1, I need “PSM000216556880035450088”. This string is the reference and it is what I need. It can be found in any position in a sentence and sometimes the reference might not be separated from the other words by a space. Sometimes a special character can be used as a separator. i…e. in 2 “VNM000216556880035450088|TRF FROM MACK”.
I will be using the Regex in my VB.NET code.
What about this with multiline flag?
((?:PSM|VNM|NXG|(SL|X)00)\d+)
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I am looking for a regex matches any string in the following format:
string#substring -> where substring = substring of the string and string is only letters from a to d
e.g.
abcddd#cd accepted
abcddd#cccc not accepted
This regex should meet your requirements:
[a-d]*?([a-d]+)[a-d]*#\1
It matches abcddd#cd but doesn't match abcddd#cccc.
Depending on your choice of tool and how you use it, you may or may not have to anchor it with a ^ and $ at the beginning and end respectively (turning it into ^[a-d]*?([a-d]+)[a-d]*#\1$).
Experiment here.
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i am new to this regex thing, how can we build regex expression for following thig
input==>[User:1490474408:michaelayliffe]
output should be ==>1490474408
input will be anything like below:
1.[User:1490474408:michaelayliffe]
2.[User:12345:dfhdfhdf]
3.[User:56789:utyutyutyu]
Output should be middle value.
Please reply.
(?<=\[User:)[^:]+
Using lookbehind should work for you.
/\d+/g
It is find digits those are middle of your string
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I'm looking for the regular expression to find failures in a log file.
The format is "Failures: " following the number of error, a digit not zero
Thanks!
You can use this:
"Failures:\s+[1-9]\d*"
this would be what you are looking for:
Failures:\s*[1-9]\d*
btw, you may want to know that in character class, the not notation is ^, not !.
E.g. [^a-zA-Z] means not letters.
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In Perl, I would like to determine if a given string is valid, the rule is to check if values exist between commas.
e.g. abc,abc is a valid case, but abc, or abc,,abc are not.
m/^\s*,|,\s*,|,\s*$/
matches all invalid combinations, assuming whitespace does not count as "values".