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i am new to this regex thing, how can we build regex expression for following thig
input==>[User:1490474408:michaelayliffe]
output should be ==>1490474408
input will be anything like below:
1.[User:1490474408:michaelayliffe]
2.[User:12345:dfhdfhdf]
3.[User:56789:utyutyutyu]
Output should be middle value.
Please reply.
(?<=\[User:)[^:]+
Using lookbehind should work for you.
/\d+/g
It is find digits those are middle of your string
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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]
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I have read How to "inverse match" with regex? and i would like to know if i can apply it to a non-content regex. In particular i'm talking about: ^[A-z0-9+\/]{44}$
I tried https://regex101.com/r/NmOs7Z/1 but it does not work
I didn't get exactly what you really, but from my understanding you want to match the two lines in your demo
So what i did :
^(?![a-zA-Z0-9+\/]{44}).*$
Demo
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How to determine that string doesn't contain both symbols &# together using regular expression ?
You can use a negative lookahead:
/^(?!.*&#)(.*)/m
Demo
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Today I attemped several time to build regular expression to validate a set of double number with semi-colon delimeted following example data below:
Should match:
123.1234567890
123.1234567890;123.1234567890;123.1234567890
Should not match:
123.1234567890;
123.1234567890;123.1234567890;123.1234567890;
If you have any idea, Could you please help me ?
Thank you very much
You can try this:
(\d+\.\d+;)*\d+\.\d+(?![\d;])
to match the whole 123.1234567890;123.1234567890;123.1234567890
\d+\.\d+(?![\d;])
to match just the last.
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I have the following sentence:
distributed over a considerable extent; "far-flung trading
operations"; "the West's far-flung mountain ranges"; "widespread
nuclear fallout"
What I want is to pickup the sentence between "**********";
My regular expression is \"(.+)", but the result is not what I want(only 1 match)
Any suggestion? Thanks
May this will work.
/\"(.+?)\"/g
I'm not sure that you need to escape quotes so this maybe just fine too.
/"(.+?)"/g