Change link text in template based on referrer - django

I'm making a navbar for my blog. If a reader arrives at a post from the post listing, I want the navigation link to say "Back to the post listing" or something like that. If the visitor comes from another source, I'd like the link to say "Read other posts like this one."
I know I can test the referrer with request.META.HTTP_REFERER, but I'm wondering what to compare this with. I could always hard-code a comparison to the post listing URL, but I'd prefer something more durable.

A combination of reverse() and build_absolute_uri() should do the trick:
if request.META['HTTP_REFERER'] == request.build_absolute_uri(reverse('posts')):
...
(This assumes that you have only a single URL mapping to the post list.)
Since you're using Jinja2 you could do this in the template as well.

Related

Add custom url action parameter to django-cms

The common url action parameters in django-cms are for example: ?edit to enter Edit-mode, ?toolbar_off to disable/hide the toolbar.
Now I'd like to add a new action parameter e.g. ?logout which just logs out the user no matter on which url he/she currently is. I'd tried to include this in the urls.py with the following pattern:
url(r'^.*\?logout$', RedirectView.as_view(url='/admin/logout/')),
I read in another SO answer that you shouldn't catch URL Params with an url pattern...
Should I do this in a kind of middleware? Or where else?
Using django==1.11, django-cms==3.5.3
This should definily go into a middleware. It would probably work as well as an url pattern, but is kind of not "how you do it" - at least I never saw anything like it in a tutorial or documentation.

API RESTful Resource Naming

I always have the doubt that you can see below when i need to create theresource URLs for a REST API. I wonder if some one can help me.
Let's suppose that i have two models.
User
Post
User can submit his own posts and can comment his own and another posts.
Main resources URLs for User would be:
GET /users # Retrieve all users.
POST /users # Create a new user.
GET/DELETE/PUT /users/{user_id} # Get, remove and update an user.
Main resource URLs for Post would be:
GET /posts # Retrieve all posts.
POST /posts # Create a new post.
GET/DELETE/PUT /posts/{post_id} # Get, remove and update a post.
My problem come when for example i want:
Top 10 submitters (filter for a parameter(external link, discussion, all)). The URL should be:
GET /users/top?type=ext
GET /users/top?type=disc
GET /users/top # for all
Or maybe it should be:
GET /users?top=ext
GET /users?top=disc
GET /users?top=all
The same but with posts:
Top 10 commented post (filter for a parameter(external link, discussion, all)). The URL should be:
GET /posts/comments?type=ext
GET /posts/comments?type=disc
GET /posts/comments # for all
Or maybe it should be:
GET /posts?top=ext
GET /posts?top=disc
GET /posts?top=all
Any of above options are good for you or it should be another way?
Regards
I like to think of the REST URI as a model representation in itself.
So /users/top doesn't make a lot of sense but /posts/comments seems to be fine (as comments could also be a different model). But for your case, I recommend other set of query parameters as they're widely used for filtering & sorting requests. So in your case, I'd recommend something like:
GET /users?sort=ext&order=desc&limit=10
which would help me understand that I'm requesting 10 user resources which have been sorted for ext in the descending order. (you can even change it to type=ext if you want)
As usual; REST doesn't care what spellings you use.
One place you might look for inspiration is... stack overflow itself. Do these URI look familiar?
/questions?sort=newest
/questions?sort=featured
/questions?sort=votes
The API has pretty decent documentation, which will also offer hints at decent spellings to deal with paging and search ranges.
That said, IMDB takes a different approach - The Shawshank Redemption uses a straight forward "I am an element of a collection" spelling
http://www.imdb.com/title/tt0111161/
But the top rated titles of all time? they appear as a chart
http://www.imdb.com/chart/top
But i want to know if there is a standard according to #Hawkes answer or there is no standard at all.
No standard at all; just local spelling conventions. Which is, to some degree, part of the point of REST: the server can use whatever spellings for URI make sense, and the client just "follows its nose" based on its understanding of the processing rules for the media type and the data provided by the server.

Django documentation, part3 understanding problems

I read the documentation of Django but now I am at a point where I need some explanation. It is on this site and I understand the views but I really don't get how the urls work. It looks pretty cryptic and confusing to me. Can anybody explain to me how the urls work and what their purpose is?
Your urls.py file is virtual. They do it this way so you don't need to worry about a static url to http://yoursite.com/polls/34. By using this number as a regular expression /(d+) you can keep it dynamic so one url with this regular expression can be millions of different polls.
when the url is requested that regular expression number (whether it's 1 or 13352) is sent to the view which then says, I need to query the database for a Poll that has a PrimaryKey (PK) of whatever this number is. If it's found the Poll object is sent to the template by the view. The template then displays all the data in the poll object.
The bottom line is using something like this you can have one line for a url which is essentially millions of different urls. I use this same format for a movies website I'm creating www.noobmovies.com. I follow the same structure for Stars, Movies and blogs. Essentially three lines of code has created urls for 10,000 pages or so.
There is a dedicated Django documentation page for that: https://docs.djangoproject.com/en/1.6/topics/http/urls/
Maybe it will help you?

Regular expression for URL filter that makes it hard to read the filterd URL

I want to insert a URL filter and I would like the URL to be hard to dechiffre.
For example .*porn\.* in a way maybe that it uses the ASCII code for the letters in hex form .
Of course, the example is obvious and I definately will leave that one as it is ;)
But for the others I would like them to be hard to read!
Thx!
You can use the $_GET function in PHP to pull an ID out of the URL and display it that way, similar to Youtube with their "watch?v=". I recently did one using "?id=49" (I only have a few pages ATM, I will have about 70 soon). What I did is use a database with a song_id to index the information. I use the same basic layout, but you can use the ID to access information wrapped in PHP so that it doesnt get sent to the browser but will still display the page you want.
Or if you really want it to look crazy, you could use a database using the SHA() or MD5() function to encrypt it.
and your display will look like /page.php?id=21a57f2fe765e1ae4a8bf15d73fc1bf2a533f547f2343d12a499d9c0592044d4.

Django url pattern to retrieve query string parameters

I was about ready to start giving a jqgrid in a django app greater functionality (pagination, searching, etc). In order to do this it looks as though jqgrid sends its parameters in the GET to the server. I plan to write an urlpattern to pull out the necessary stuff (page number, records per page, search term, etc) so I can pass it along to my view to return the correct rows to the grid. Has anyone out there already created this urlpattern I am in search of?
Thanks much.
The answer to this was simpler than I realized. As stated in Chapter 7 of the djangobook in the section titled "Query string parameters" one can simply do something as follows, where "someParam" is the parameter in the query string you want to retrieve. However, Django is designed to be clean in that address bar at the top of the page so you should only use this option if you must.
The query string might look something like this.
http://somedomainname.com/?someString=1
The view might look like this.
def someView(request):
if 'someParam' in request.GET and request.GET['someParam']:
someParam = request.GET['someParam']
Hopefully this is of some help to someone else down the road.