I implemented a dialog-based Win32 Visual C++ application (Visual Studio Ultimate 2012) by following this article.
What is the way to call another dialog box (by clicking on a button) from the one I already created?
Add a button to the dialog in the dialog resource view. Just drag a button from the toolbar onto the dialog template. When the button is clicked you will get a WM_COMMAND message containing the button ID and the BN_CLICKED notification code.
http://msdn.microsoft.com/en-us/library/windows/desktop/bb761825(v=vs.85).aspx
Add a case in your DialogProc to detect the click. When you get it, create a new dialog by calling the DialogBox API.
http://msdn.microsoft.com/en-us/library/windows/desktop/ms645452(v=vs.85).aspx
This second dialog will need you to write a new DialogProc2, just like the first DialogProc, to handle messages from the second dialog.
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I am trying to build an MFC application Dialog based application. It runs ok. But I need to insert another Dialog. So how can I for example, pressing on a button from the first dialog to open the new added dialog?.
I am using Microsoft Visual Studio 2015.
I right clicked on the resources folder and insert a dialog.
It is inserted, but how to create it?.
Thank you.
The easiest way is: I consider you are creating a Dialog based application so you get a main Dialog box and an About Dialog box when Selecting menu->About.
To add Another Dialog to your application:
1- Right click on the solution explorer on the resources files and select Add->Resource->Dialog->New
You get a new Dialog right front of you. Right click on this Dialog and select Add Class. give it for example a name like "MyDlg2" and click ok.
You'll see two files added: MyDlg2.h and MyDlg2.cpp.
Now How to Popup this second dialog (MyDlg2)? Let's create a button on the main Dialog:
Drag a button onto Main Dialog.
Give it a caption "Gong to Dialog2..."
Double-click this button to add a handler for it.
In this handler enter:
MyDlg2 dlg;
dlg.DoModal();
Scroll to the top of this file and add:
#include "MyDlg2.h"
This is important so that main Dialog knows How to create dialog 2.
Build and run.
You need to derive a class from CDialog.
For more information check this MSDN example.
I have a dialog IDD_WINDOW_INFO that has to be opened when the user clicks a button or a menu item in my C++ Win32 application. The method that I use to open the dialog is in the following line:
DialogBox(hInstance, MAKEINTRESOURCE(IDD_WINDOW_INFO), hMainWindow, WindowInfoProc);
but my problem is that when that dialog box opens, the user cannot operate with the main window of my application. So what can I do to have both windows active?
You are calling DialogBox which shows the dialog modally. When a modal dialog is shown, the other owning windows are disabled and only the modal dialog can accept input. That is the very essence and intent of a modal dialog. The idea is that you can interact only with the dialog, and cannot interact with the other windows.
Another answer suggests passing NULL as the hWndParent parameter to DialogBox. That's not the solution. That will result in you having an unowned window. Yes, you will be able to interact with the main window, but when you do so your main window will appear on top of the dialog. That's because the ownership is set incorrectly. I recommend that you read about window ownership to better understand the issue.
The correct solution to your problem is to show a modeless dialog. A modeless dialog allows you to interact with the other windows in your application. And that's exactly what you ask for in the question.
You show modeless dialogs by calling CreateDialog followed by ShowWindow. This MSDN article shows an example: Using Dialog Boxes.
If I recall correctly, you can either pass NULL instead of the handle to the parent window or change the dialogbox type in the resource editor.
That is an easy way to do it, however the following is certainly better - since having an unowned dialog isn't your best choice.
The point is that DialogBox() will create a modal dialog window, while CreateDialog does not. Modal dialogs disable the parent window.
From MSDN: A modeless dialog box neither disables the owner window nor sends messages to it.
That should solve your problem.
CreateDialog(hInstance, MAKEINTRESOURCE(IDD_WINDOW_INFO), hMainWindow, WindowInfoProc);
ShowWindow(hWnd, SW_SHOW);
I have a custom dialog message box that pops-up when a edit control in my main dialog has wrong data.
CDlgError dlgError = new CDlgError(this);
dlgError.Create(CDlgError::IDD, this);
dlgError.m_staticMessage.SetWindowTextA("Error message!");
dlgError.ShowWindow(SW_SHOW);
//more code
I want the rest of the code to be executed only after i press an OK button in my CDlgError pop-up dialog. How can i do that?
Use DoModal instead of Create and ShowWindow to show your error dialog. e.g.
CDlgError dlgError = new CDlgError(this);
dlgError.m_strMessage = "Error message!";
dlgError.DoModal();
As you can see from the code you'll need to pass in the text and THEN set your message label inside CDlgError::OnInitDialog because the control won't be initialized before going modal.
You are creating a dialog using Create which shows a modalless dialog(you can click on other parts of application even dialog is open).
You requirement is for modal dialog where you can not click on any part of application until this dialog is closed.
To do this use DoModal function instead of create.
I tried a tutorial about C and ATL about a basic dialog. It has a window, and 2 buttons inside. In the beginning of the tutorial, there are 2 buttons and they all exit the application. But, these 2 buttons are created by default. So, I tried creating another button that can exit the application, and I failed.
My aim is to use radio buttons with this project. I want to create some radio buttons and when I press a button, I want to execute some commands.
Here are the links - In my opinion, the tutorial link is unrelated, but I guess it won't hurt: Tutorial, Working Project, Problematic Project.
Thanks in advance.
You add a button onto dialog resource template
You associate an identifier with the button in properties pane right there in resource editor, e.g. IDC_MYBUTT
You will find #define for the chosen constant IDC_MYBUTT in resource.h file on the project
You add handlers to button events on your dialog class. Those are COMMAND_ID_HANDLER macros on Sample ATL Dialog Window code, which connect the event (underlying WM_COMMAND message sent to the window) with specific method (both IDOK and IDCANCEL buttons execute OnCommand in the sample code).
There on the handler you decide how to handle, and in particular to end the dialog or not.
COMMAND_HANDLER, COMMAND_ID_HANDLER and friends are described on MSDN: Message Map Macros (ATL).
I have created a "check Box " window with a button, when the button is clicked, It should open a "Edit" window, How can I do?
thanks
It depends completely on the windowing system you are using, or the graphics library. ¿Are you using .NET? ¿MFC?
In any case, your button object will have a way to associate a function to its click event. Just write a function that does what you need (in this case, open the "Edit" window), associate this function to the click event of your button, and you are done.
Make your edit window hidden by default in the resource editor and show it with ShowWindow(hEditWnd,SW_SHOW) when the button is clicked.
You could instanciate a new window and show it on the click event