I'm creating 9 threads using something like this (all threads will process infinity loop)
void printStr();
thread func_thread(printStr);
void printStr() {
while (true) {
cout << "1\n";
this_thread::sleep_for(chrono::seconds(1));
}
}
I also create 10th thread to control them. How would I stop or kill any of this 9 threads from my 10th? Or suggest another mechanism please.
You can use, for example, atomic boolean:
#include <thread>
#include <iostream>
#include <vector>
#include <atomic>
using namespace std;
std::atomic<bool> run(true);
void foo()
{
while(run.load(memory_order_relaxed))
{
cout << "foo" << endl;
this_thread::sleep_for(chrono::seconds(1));
}
}
int main()
{
vector<thread> v;
for(int i = 0; i < 9; ++i)
v.push_back(std::thread(foo));
run.store(false, memory_order_relaxed);
for(auto& th : v)
th.join();
return 0;
}
EDIT (in response of your comment): you can also use a mutual variable, protected by a mutex.
#include <thread>
#include <iostream>
#include <vector>
#include <mutex>
using namespace std;
void foo(mutex& m, bool& b)
{
while(1)
{
cout << "foo" << endl;
this_thread::sleep_for(chrono::seconds(1));
lock_guard<mutex> l(m);
if(!b)
break;
}
}
void bar(mutex& m, bool& b)
{
lock_guard<mutex> l(m);
b = false;
}
int main()
{
vector<thread> v;
bool b = true;
mutex m;
for(int i = 0; i < 9; ++i)
v.push_back(thread(foo, ref(m), ref(b)));
v.push_back(thread(bar, ref(m), ref(b)));
for(auto& th : v)
th.join();
return 0;
}
It is never appropriate to kill a thread directly, you should instead send a signal to the thread to tell it to stop by itself. This will allow it to clean up and finish properly.
The mechanism you use is up to you and depends on the situation. It can be an event or a state checked periodically from within the thread.
std::thread objects are non - interruptible. You will have to use another thread library like boost or pthreads to accomplish your task. Please do note that killing threads is dangerous operation.
To illustrate how to approach this problem in pthread using cond_wait and cond_signal,In the main section you could create another thread called monitor thread that will keep waiting on a signal from one of the 9 thread.
pthread_mutex_t monMutex;////mutex
pthread_cond_t condMon;////condition variable
Creating threads:
pthread_t *threads = (pthread_t*) malloc (9* sizeof(pthread_t));
for (int t=0; t < 9;t++)
{
argPtr[t].threadId=t;
KillAll=false;
rc = pthread_create(&threads[t], NULL, &(launchInThread), (void *)&argPtr[t]);
if (rc){
printf("ERROR; return code from pthread_create() is %d\n", rc);
exit(-1);
}
}
creating monitor thread:
monitorThreadarg.threadArray=threads;//pass reference of thread array to monitor thread
monitorThreadarg.count=9;
pthread_t monitor_thread;
rc= pthread_create(&monitor_thread,NULL,&monitorHadle,(void * )(&monitorThreadArg));
if (rc){
printf("ERROR; return code from pthread_create() is %d\n", rc);
exit(-1);
}
then wait on 9 threads and monitor thread:
for (s=0; s < 9;s++)
{
pthread_join(threads[s], &status);
}
pthread_cond_signal(&condMon);// if all threads finished successfully then signal monitor thread too
pthread_join(monitor_thread, &status);
cout << "joined with monitor thread"<<endl;
The monitor function would be something like this:
void* monitorHadle(void* threadArray)
{
pthread_t* temp =static_cast<monitorThreadArg*> (threadArray)->threadArray;
int number =static_cast<monitorThreadArg*> (threadArray)->count;
pthread_mutex_lock(&monMutex);
mFlag=1;//check so that monitor threads has initialised
pthread_cond_wait(&condMon,&monMutex);// wait for signal
pthread_mutex_unlock(&monMutex);
void * status;
if (KillAll==true)
{
printf("kill all \n");
for (int i=0;i<number;i++)
{
pthread_cancel(temp[i]);
}
}
}
the function what will be launched over 9 threads should be something like this:
void launchInThread( void *data)
{
pthread_setcanceltype(PTHREAD_CANCEL_ASYNCHRONOUS, NULL);
while(1)
{
try
{
throw("exception whenever your criteria is met");
}
catch (string x)
{
cout << "exception form !! "<< pthread_self() <<endl;
KillAll=true;
while(!mFlag);//wait till monitor thread has initialised
pthread_mutex_lock(&monMutex);
pthread_cond_signal(&condMon);//signail monitor thread
pthread_mutex_unlock(&monMutex);
pthread_exit((void*) 0);
}
}
}
Please note that if you dont't put :
thread_setcanceltype(PTHREAD_CANCEL_ASYNCHRONOUS, NULL);
after launching your thread then your threads wouldn't terminate on thread_cancel call.
It is necessary that you clean up up all the data before you cancel a thread.
Related
I'm wanting to have several threads all waiting on a conditional variable (CV) and when the main thread updates a variable they all execute. However, I need the main thread to wait until all these have completed before moving on. The other threads don't end and simply go back around and wait again, so I can't use thread.join() for example.
I've got the first half working, I can trigger the threads, but the main just hangs and doesn't continue. Below is my current code
#include <iostream> // std::cout
#include <thread> // std::thread
#include <mutex> // std::mutex, std::unique_lock
#include <condition_variable> // std::condition_variable
#include <Windows.h>
#define N 3
std::mutex mtx;
std::condition_variable cv;
bool ready = false;
bool finished[N];
void print_id(int id) {
while (1) {
std::unique_lock<std::mutex> lck(mtx); //Try and Lock the Mutex
while (finished[id]) cv.wait(lck); //Wait until finished is false
// ...
std::cout << "thread " << id << '\n';
finished[id] = true; //Set finished to be true. When true, program should continue
}
}
int main()
{
std::thread threads[N];
// spawn 10 threads:
for (int i = 0; i < N; ++i) {
threads[i] = std::thread(print_id, i); //Create n threads
finished[i] = true; //Set default finished to be true
}
std::cout << "N threads ready to race...\n";
for (int i = 0; i < 5; i++) {
std::unique_lock<std::mutex> lck(mtx); //Lock mutex
for (int i = 0; i < N; i++) {
finished[i] = false; //Set finished to false, this will break the CV in each thread
}
cv.notify_all(); //Notify all threads
cv.wait(lck, [] {return finished[0] == true; }); //Wait until all threads have finished (but not ended)
std::cout << "finished, Sleeping for 2s\n";
Sleep(2000);
}
return 0;
}
Thank you.
Edit: I am aware I am only currently checking the status of the finished[0] and not each one. This is done just for simplicity atm and would eventually need to be all of them. I will write a function to manage this later.
You have cv.wait(lck, [] {return finished[0] == true; }); in main thread, but it is not being notified.
You'd need to notify it, and you'd better use another condition_variable for it, not the same as for worker thead notifiecation.
My program has three threads, and I am trying to learn about synchronization and thread safety. Below I outline what the different threads do, but I would like to learn how to use events instead to trigger each process in the different threads instead of infinitely reading (which is giving me concurrency issues).
Googling throws up many options but I'm not sure what is best to implement in this case - could you point the direction to a standard method/event that I could learn to best implement this?
I am doing this on VS 2012, and ideally I would not use external libraries e.g. boost.
Thread 1: receives a message and pushes it into a global queue, queue<my_class> msg_in.
Thread 2: on infinite loop (i.e. while(1) ); waits till if (!msg_in.empty()), does some processing, and pushes it into a global map<map<queue<my_class>>> msg_out.
while (1)
{
if (!msg_in.empty())
{
//processes
msg_map[i][j].push(); //i and j are int (irrelevant here)
}
}
Thread 3:
while (1)
{
if (msg_map.find(i) != msg_map.end())
{
if (!msg_map[i].find(j)->second.empty())
{
//processes
}
}
}
Your problems is a producer consumer problem. You can use condition variables for your events. There is one example of it here: http://en.cppreference.com/w/cpp/thread/condition_variable
I have adapted it to your example if your need it.
#include "MainThread.h"
#include <iostream>
#include <string>
#include <thread>
#include <mutex>
#include <atomic>
#include <condition_variable>
std::mutex m;
std::condition_variable cv;
bool ready = false;
bool processed = false;
void worker_thread(unsigned int threadNum)
{
// Wait until main() sends data
{
std::unique_lock<std::mutex> lk(m);
cv.wait(lk, []{return ready;});
}
std::cout << "Worker thread "<<threadNum <<" is processing data"<<std::endl;
// Send data back to main()
{
std::lock_guard<std::mutex> lk(m);
processed = true;
std::cout << "Worker thread "<< threadNum <<" signals data processing completed\n";
}
cv.notify_one();
}
int initializeData()
{
// send data to the worker thread
{
std::lock_guard<std::mutex> lk(m);
ready = true;
std::cout << "Data initialized"<<std::endl;
}
cv.notify_one();
return 0;
}
int consumerThread(unsigned int nbThreads)
{
std::atomic<unsigned int> nbConsumedthreads=0;
while (nbConsumedthreads<nbThreads)
{
std::unique_lock<std::mutex> lk(m);
cv.wait(lk, []{return processed;});
std::cout<<"Data processed counter="<<nbConsumedthreads << " "<< std::endl;
++nbConsumedthreads;
cv.notify_one();
}
return 0;
}
int main()
{
const unsigned int nbThreads=3;
std::thread worker1(worker_thread,1);
std::thread worker2(worker_thread,2);
std::thread worker3(worker_thread,3);
std::thread init(initializeData);
std::thread consume(consumerThread, nbThreads);
worker1.join();
worker2.join();
worker3.join();
init.join();
consume.join();
return 0;
}
Hope that helps, tell me if you need more info.
Example:
void start(void)
{
pthread_create(&threadID, Null, run_thread_function,arguments);
//is there a way to ensure if the run_thread_function(basically new thread) started
//execution before returning from this(start) function
}
Check the return code.
if ((retcode = pthread_create(&threadID, Null, run_thread_function,arguments)) != 0)
{
//something went wrong
}
Pass a synchro object, (condvar, event or semaphore), as part of the arguments. Wait on it after calling pthread_create(). In the thread, signal it in the first line, (or after the thread has performed its init stuff, if that's what you are trying to achieve).
Check the return code of the pthread_create function for error.
Update some shared variable and test it from another thread. Remember to use synchronization primitives, like mutex when updating the shared variable.
Or to make simple test, print some message with the thread id, or some other kind of identifier.
With C++11, creating a thread through an object of type std::thread won't return until the new thread has started.
Use pthread_barrier_wait if you want to know for certain that your new thread has begun.
Though, I really question code that cares deeply about this. Seems like you're asking for race conditions.
Note that I should be checking for return values all over the place and I'm not for the sake of succinctness clarity. sigh
#include <iostream>
#include <pthread.h>
#include <unistd.h>
void *newthread(void *vbarrier)
{
pthread_barrier_t *barrier = static_cast<pthread_barrier_t *>(vbarrier);
sleep(2);
int err = pthread_barrier_wait(barrier);
if ((err != 0) && (err != PTHREAD_BARRIER_SERIAL_THREAD)) {
::std::cerr << "Aiee! pthread_barrier_wait returned some sort of error!\n";
} else {
::std::cerr << "I am the new thread!\n";
}
return 0;
}
int main()
{
pthread_barrier_t barrier;
pthread_barrier_init(&barrier, NULL, 2);
pthread_t other;
pthread_create(&other, NULL, newthread, &barrier);
pthread_barrier_wait(&barrier);
::std::cerr << "Both I and the new thread reached the barrier.\n";
pthread_join(other, NULL);
return 0;
}
C++11 doesn't have barriers. But barriers can easily be simulated, to an extent, using condition variables:
#include <thread>
#include <condition_variable>
#include <iostream>
#include <unistd.h>
void runthread(::std::mutex &m, ::std::condition_variable &v, bool &started)
{
sleep(2);
{
::std::unique_lock< ::std::mutex> lock(m);
started = true;
v.notify_one();
}
::std::cerr << "I am the new thread!\n";
}
int main()
{
::std::mutex m;
::std::condition_variable v;
bool started = false;
::std::thread newthread(runthread, ::std::ref(m), ::std::ref(v), ::std::ref(started));
{
::std::unique_lock< ::std::mutex> lock(m);
while (!started) {
v.wait(lock);
}
}
::std::cerr << "Both I and the new thread are running.\n";
newthread.join();
return 0;
}
I am using boost::thread, and I meet some problems.
The thing is, are there any ways I can join a thread before the last join finish?
for example,
int id=1;
void temp()
{
int theardID = id++;
for(int i=0;i<3;i++)
{
cout<<theardID << " : "<<i<<endl;
boost::this_thread::sleep(boost::posix_time::millisec(100));
}
}
int main(void)
{
boost::thread thrd1(temp);
thrd1.join();
boost::thread thrd2(temp);
boost::thread thrd3(temp);
thrd2.join();
thrd3.join();
return 0;
}
In this simple example, the order of output may be:
1:0
1:1
1:2
2:0
3:0
3:1
2:1
2:2
3:2
As the above example, we can see find out that thrd2 and thrd3 start to run after thrd1 finish.
Are there any ways to let thrd2 and thrd3 run before thrd1 finish?
You can use Boost.Thread's condition variables to synchronize on a condition more complex than what join can provide. Here's a example based on yours:
#include <iostream>
#include <boost/thread.hpp>
#include <boost/thread/locks.hpp>
#include <boost/thread/mutex.hpp>
#include <boost/thread/condition_variable.hpp>
boost::mutex mutex;
boost::condition_variable cond;
// These three variables protected by mutex
bool finishedFlag = false;
int finishedID = 0;
int finishedCount = 0;
int id=1;
void temp()
{
int threadID = id++;
for(int i=0;i<3;i++)
{
std::cout << threadID << " : " << i << std::endl;
boost::this_thread::sleep(boost::posix_time::millisec(100));
}
{
boost::lock_guard<boost::mutex> lock(mutex);
finishedFlag = true;
finishedID = threadID;
++finishedCount;
}
cond.notify_one();
}
int main(void)
{
boost::thread thrd1(temp);
boost::this_thread::sleep(boost::posix_time::millisec(300));
boost::thread thrd2(temp);
boost::thread thrd3(temp);
boost::unique_lock<boost::mutex> lock(mutex);
while (finishedCount < 3)
{
while (finishedFlag != true)
{
// mutex is released while we wait for cond to be signalled.
cond.wait(lock);
// mutex is reacquired as soon as we finish waiting.
}
finishedFlag = false;
if (finishedID == 1)
{
// Do something special about thrd1 finishing
std::cout << "thrd1 finished" << std::endl;
}
};
// All 3 threads finished at this point.
return 0;
}
The join function means "stop this thread until that thread finishes." It's a simple tool for a simple purpose: ensuring that, past this point in the code, thread X is finished.
What you want to do isn't a join operation at all. What you want is some kind of synchronization primitive to communicate and synchronize behavior between threads. Boost.Thread has a number of alternatives for synchronization, from conditions to mutexes.
The main() function creates a thread that is supposed to live until the user wishes to exit the program. The thread needs to return values to the main functions at periodic intervals. I tried doing something like this, but hasn't worked well -
std::queue<std::string> q;
void start_thread(int num)
{
std::string str;
//Do some processing
q.push(str);
}
int main()
{
//Thread initialization
int i;
//Start thread
pthread_create(&m_thread,NULL,start_thread,static_cast<void *>i);
while(true)
{
if(q.front())
{
std::cout<<q.front();
return 0;
}
}
//Destroy thread.....
return 0;
}
Any suggestions?
It is not safe to read and write from STL containers concurrently. You need a lock to synchronize access (see pthread_mutex_t).
Your thread pushes a single value into the queue. You seem to be expecting periodic values, so you'll want to modify start_thread to include a loop that calls queue.push.
The return 0; in the consumer loop will exit main() when it finds a value in the queue. You'll always read a single value and exit your program. You should remove that return.
Using if (q.front()) is not the way to test if your queue has values (front assumes at least one element exists). Try if (!q.empty()).
Your while(true) loop is gonna spin your processor somethin' nasty. You should look at condition variables to wait for values in the queue in a nice manner.
try locking a mutex before calling push() / front() on the queue.
Here is a working example of what it looks like you were trying to accomplish:
#include <iostream>
#include <queue>
#include <vector>
#include <semaphore.h>
#include <pthread.h>
struct ThreadData
{
sem_t sem;
pthread_mutex_t mut;
std::queue<std::string> q;
};
void *start_thread(void *num)
{
ThreadData *td = reinterpret_cast<ThreadData *>(num);
std::vector<std::string> v;
std::vector<std::string>::iterator i;
// create some data
v.push_back("one");
v.push_back("two");
v.push_back("three");
v.push_back("four");
i = v.begin();
// pump strings out until no more data
while (i != v.end())
{
// lock the resource and put string in the queue
pthread_mutex_lock(&td->mut);
td->q.push(*i);
pthread_mutex_unlock(&td->mut);
// signal activity
sem_post(&td->sem);
sleep(1);
++i;
}
// signal activity
sem_post(&td->sem);
}
int main()
{
bool exitFlag = false;
pthread_t m_thread;
ThreadData td;
// initialize semaphore to empty
sem_init(&td.sem, 0, 0);
// initialize mutex
pthread_mutex_init(&td.mut, NULL);
//Start thread
if (pthread_create(&m_thread, NULL, start_thread, static_cast<void *>(&td)) != 0)
{
exitFlag = true;
}
while (!exitFlag)
{
if (sem_wait(&td.sem) == 0)
{
pthread_mutex_lock(&td.mut);
if (td.q.empty())
{
exitFlag = true;
}
else
{
std::cout << td.q.front() << std::endl;
td.q.pop();
}
pthread_mutex_unlock(&td.mut);
}
else
{
// something bad happened
exitFlag = true;
}
}
return 0;
}