Subtracting minutes from Boost ptime - c++

I'm trying to clamp a posix_time::ptime instance into 5 minute intervals.
For example:
1. 10:31:00 -> 10:30:00
2. 11:59:00 -> 11:55:00
My understanding is that one can subtract time from a ptime based on a period. The code below however seems to increment the time not decrement it.
#include <iostream>
#include "boost/date_time.hpp"
using namespace boost::posix_time;
boost::posix_time::ptime make(int h, int m, int s)
{
return boost::posix_time::ptime
(boost::gregorian::date(1900,1,1),
boost::posix_time::time_duration(h,m,s,0));
}
int main()
{
boost::posix_time::ptime t = make(22,2,0);
int extra_mins = t.time_of_day().minutes() % 5;
t -= boost::posix_time::minutes(extra_mins);
if (t.time_of_day().minutes() != 0)
std::cout << "ERROR";
return 0;
}
I'm not able to immediately see the error, as it seems to be correctly decrement a duration from a time point.

I don't know what you mean with
I'm not able to immediately see the error, as it seems to be correctly decrement a duration from a time point.
I'm also not able to see the error, because the behaviour is what I expect. I don't, of course, know what you're expecting. Here goes:
#include <iostream>
#include "boost/date_time.hpp"
#include "boost/date_time/posix_time/posix_time_io.hpp"
using namespace boost::posix_time;
boost::posix_time::ptime make(int h, int m, int s)
{
return boost::posix_time::ptime
(boost::gregorian::date(1900,1,1),
boost::posix_time::time_duration(h,m,s,0));
}
int main()
{
boost::posix_time::ptime t = make(22,2,0);
std::cout << "made: " << t << "\n";
int extra_mins = t.time_of_day().minutes() % 5;
std::cout << "extra_mins: " << extra_mins << "\n";
t -= boost::posix_time::minutes(extra_mins);
std::cout << "t - extra_mins: " << t << "\n";
if (t.time_of_day().minutes() != 0)
std::cout << "ERROR";
}
Output:
made: 1900-Jan-01 22:02:00
extra_mins: 2
t - extra_mins: 1900-Jan-01 22:00:00
Which looks pretty okay to me. See ti Live On Coliru too.

Related

Advice on converting timestamp string in "HH:MM:SS.microseconds" format

I'm given a list of timestamps (suppose we have a ready-made std::vector<std::string>) in a string format of a kind std::vector<std::string> = {"12:27:37.740002", "19:37:17.314002", "20:00:07.140902",...}. No dates, no timezones. What would be a preferable way to parse these strings to some kind of C++ type (std::chrono::time_point ?) to be able to perform some comparisons and sorting later.
For example: compare value, which was parsed from "20:00:07.140902" and value, was parsed from "20:00:07.000000".
C++17 is ok, but I can't use any third-party library (Boost, Date etc).
Keeping microseconds precision essential.
You can build this functionality completly with C++ standard library functionality.
For parsing the string use std::regex.
For time related datatypes use std::chrono
Example :
#include <stdexcept>
#include <regex>
#include <chrono>
#include <iostream>
auto parse_to_timepoint(const std::string& input)
{
// setup a regular expression to parse the input string
// https://regex101.com/
// each part between () is a group and will end up in the match
// [0-2] will match any character from 0 to 2 etc..
// [0-9]{6} will match exactly 6 digits
static const std::regex rx{ "([0-2][0-9]):([0-5][0-9]):([0-5][0-9])\\.([0-9]{6})" };
std::smatch match;
if (!std::regex_search(input, match, rx))
{
throw std::invalid_argument("input string is not a valid time string");
}
// convert each matched group to the corresponding value
// note match[0] is the complete matched string by the regular expression
// we only need the groups which start at index 1
const auto& hours = std::stoul(match[1]);
const auto& minutes = std::stoul(match[2]);
const auto& seconds = std::stoul(match[3]);
const auto& microseconds = std::stoul(match[4]);
// build up a duration
std::chrono::high_resolution_clock::duration duration{};
duration += std::chrono::hours(hours);
duration += std::chrono::minutes(minutes);
duration += std::chrono::seconds(seconds);
duration += std::chrono::microseconds(microseconds);
// then return a time_point (note this will not help you with correctly handling day boundaries)
// since there is no date in the input string
return std::chrono::high_resolution_clock::time_point{ duration };
}
int main()
{
std::string input1{ "20:00:07.140902" };
std::string input2{ "20:00:07.000000" };
auto tp1 = parse_to_timepoint(input1);
auto tp2 = parse_to_timepoint(input2);
std::cout << "start time = " << ((tp1 < tp2) ? input1 : input2) << "\n";
std::cout << "end time = " << ((tp1 >= tp2) ? input1 : input2) << "\n";
return 0;
}
I don't see why this shouldn't work. Using std::chrono::from_stream to parse the string into a time point, then just compare the two time points.
However, I've been trying it now with Visual Studio 2022 17.0.2 (Community Edition) and it fails to parse the string into a tp.
There is this answer from Ted Lyngmo's talking about a bug (fixed in VS2022 17.0.3) when parsing seconds with subseconds. I have to say though that his solution didn't work for me either in my VS2022.
Anyway, you may want to give it a try.
#include <chrono>
#include <iomanip> // boolalpha
#include <iostream> // cout
#include <sstream> // istringstream
#include <string>
auto parse_string_to_tp(const std::string& str)
{
std::istringstream iss{ str };
std::chrono::sys_time<std::chrono::microseconds> tp{};
std::chrono::from_stream(iss, "%H:%M:%S", tp); // or simply "%T"
return tp;
}
int main()
{
const std::string str1{ "12:27:37.740002" };
const std::string str2{ "13:00:00.500000" };
auto tp1{ parse_string_to_tp(str1) };
auto tp2{ parse_string_to_tp(str2) };
std::cout << "tp1 < tp2: " << std::boolalpha << (tp1 < tp2) << "\n";
std::cout << "tp2 < tp1: " << std::boolalpha << (tp2 < tp1) << "\n";
}
EDIT: it works if you just use durations instead of time points:
#include <chrono>
#include <iomanip> // boolalpha
#include <iostream> // cout
#include <sstream> // istringstream
#include <string>
auto parse_string_to_duration(const std::string& str)
{
std::istringstream iss{ str };
std::chrono::microseconds d{};
std::chrono::from_stream(iss, "%T", d);
return d;
}
int main()
{
const std::string str1{ "12:27:37.740002" };
const std::string str2{ "23:39:48.500000" };
auto d1{ parse_string_to_duration(str1) };
auto d2{ parse_string_to_duration(str2) };
std::cout << "d1 < d2: " << std::boolalpha << (d1 < d2) << "\n";
std::cout << "d2 < d1: " << std::boolalpha << (d2 < d1) << "\n";
}

How to convert boost local_date_time to time_t

I have:
time_t dataFromTodayByAddingYearsMonthsDays(int years, int months, int days)
{
using namespace boost::local_time;
local_date_time local = local_sec_clock::local_time(time_zone_ptr());
local += boost::gregorian::years(years);
local += boost::gregorian::months(months);
local += boost::gregorian::days(days);
return ???;
}
How do I convert this boost local_date_time beast to time_t?
Here's the beef of the answer:
time_t to_time_t(boost::posix_time::ptime const& pt) //! assumes UTC
{
return (pt - boost::posix_time::from_time_t(0)).total_seconds();
}
I'd write the date calculation more succinctly, while you're at it:
int main()
{
using namespace boost::local_time;
auto now = local_sec_clock::local_time(time_zone_ptr()),
then = now + ymd_duration { 1, 3, -4 };
std::cout << now << ", " << to_time_t(now.utc_time()) << "\n";
std::cout << then << ", " << to_time_t(then.utc_time()) << "\n";
}
See it Live On Coliru, prints
2014-May-12 21:50:06 UTC, 1399931406
2015-Aug-08 21:50:06 UTC, 1439070606
Full Code:
#include <boost/date_time/posix_time/posix_time.hpp>
#include <boost/date_time/local_time/local_time.hpp>
#include <boost/date_time/local_time/local_time_io.hpp>
struct ymd_duration { int years, months, day; };
template <typename T>
T operator+(T const& pt, ymd_duration delta)
{
using namespace boost::gregorian;
return pt + years(delta.years) + months(delta.months) + days(delta.day);
}
time_t to_time_t(boost::posix_time::ptime const& pt) //! assumes UTC
{
return (pt - boost::posix_time::from_time_t(0)).total_seconds();
}
int main()
{
using namespace boost::local_time;
auto now = local_sec_clock::local_time(time_zone_ptr()),
then = now + ymd_duration { 1, 3, -4 };
std::cout << now << ", " << to_time_t(now.utc_time()) << "\n";
std::cout << then << ", " << to_time_t(then.utc_time()) << "\n";
}
time_t dataFromTodayByAddingYearsMonthsDays(int years, int months, int days)
{
using namespace boost::local_time;
using namespace boost::posix_time;
local_date_time local = local_sec_clock::local_time(time_zone_ptr());
local += boost::gregorian::years(years);
local += boost::gregorian::months(months);
local += boost::gregorian::days(days);
ptime utc = local.utc_time();
ptime epoch(boost::gregorian::date(1970, 1, 1));
time_duration::sec_type diff = (utc - epoch).total_seconds();
return time_t(diff);
}

Generating a random date

I wrote this code snippet to generate random dates:
std::time_t curr_time = time(0);
std::time_t ten_years = 365 * 12 * 30 * 24 * 60;
std::time_t rand_date = curr_time - std::rand() % ten_years;
tm *ltm = std::localtime(&rand_date);
std::cout << ltm->tm_year + 1900 << " " << ltm->tm_mon + 1 << " " << ltm->tm_mday << std::endl;
However it always gives me the current date. What am i doing wrong?
std::rand() may return rather small values, 0..32767 is the minimum range, and does so on some popular 32-bit platforms (MSVC among them). With time_t in seconds this only gives you about eight hours of random noise.
Try combining the results from a pair of std::rand calls instead. E.g.
(std::time_t) std::rand() * RAND_MAX + std::rand() or switch to a better random number generator.
I would suggest you don't modify a time_t directly, as the implementation is not specified by the standard. Better to convert it a la this question: How to add one day to a time obtained from time()
I would suggest to do it differently, based on the CPP Reference:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include <iostream>
using namespace std;
int main() {
time_t timer;
struct tm x_years;
struct tm* current;
int how_many_years = 10;
srand (time(NULL));
int randomYear = (rand()%how_many_years)+1;
int randomMonth = (rand()%12)+1;
int randomDays = (rand()%30)+1;
time(&timer); /* get current time; same as: timer = time(NULL) */
current = localtime(&timer);
x_years.tm_hour = 0;
x_years.tm_min = 0;
x_years.tm_sec = 0;
x_years.tm_year = current->tm_year - randomYear;
x_years.tm_mon = (current->tm_mon - randomMonth) <= 0 ? current->tm_mon + (12-randomMonth) : current->tm_mon - randomMonth;
x_years.tm_mday = (current->tm_mday - randomDays) <= 0 ? current->tm_mday + (30-randomDays) : current->tm_mday - randomDays;
//returns seconds ever since the random generated date until now
cout << "Years rolled back: " << randomYear << endl;
cout << "Months rolled back: " << randomMonth << endl;
cout << "Days rolled back: " << randomDays << endl;
cout << endl;
cout << "Current Year: " << current->tm_year+1900 << endl;
cout << "Current Month: " << current->tm_mon << endl;
cout << "Current Day: " << current->tm_mday << endl;
cout << endl;
cout << "Year: " << x_years.tm_year+1900 << endl;
cout << "Month: " << x_years.tm_mon << endl;
cout << "Day: " << x_years.tm_mday << endl;
}
EDIT
I have edited the code, and with it, you can even select how many years you want to go back. Basically, you go back X years in the time, and you can get the date rollbacked in the x_years struct.
Hope this helped!
The following solution uses C++11 with an internal uniform_int_distribution:
// uniform_time_dist.h
#include <chrono>
#include <random>
template <class TimePoint>
class uniform_time_distribution{
public:
uniform_time_distribution(TimePoint start, TimePoint end)
: m_start(start), m_end(end),
m_seconds(std::chrono::duration_cast<std::chrono::seconds>(end - start))
{}
template <class Generator>
TimePoint operator()(Generator && g){
std::uniform_int_distribution<std::chrono::seconds::rep> d(0, m_seconds.count());
return m_start + std::chrono::seconds(d(g));
}
private:
TimePoint m_start;
TimePoint m_end;
std::chrono::seconds m_seconds;
};
You can use it like any other distribution function with a generator:
// uniform_time_dist.h -- continuation
template <class TimePoint>
TimePoint randomTime(TimePoint start, TimePoint end){
static std::random_device rd;
static std::mt19937 gen(rd());
uniform_time_distribution<TimePoint> t(start, end);
return t(gen);
}
You can combine this method with your time_t functions by using clock::to_time_t:
#include <iostream>
#include "uniform_time_dist.h" // see above
using namespace std::chrono;
int main(){
auto k = system_clock::to_time_t(randomTime(
system_clock::now(),
system_clock::now() + hours(24 * 365 * 10)));
std::cout << std::ctime(&k);
}
Note that the class above is just a small sketch, you should be able to improve it vastly in order to match the other distribution functions.
I managed to create a solution based on Phil's answer:
time_t currTime = time(0);
tm *ltm = std::localtime(&currTime);
ltm->tm_mday = std::rand() % 3650 * -1;
time_t next = mktime(ltm);
ltm = std::localtime(&next);
std::cout << ltm->tm_year + 1900 << " " << ltm->tm_mon + 1 << " " << ltm->tm_mday << std::endl;
If you are using boost libs you can use this class that I wrote to get random dates:
#include <iostream>
#include <ctime>
#include <boost/random/mersenne_twister.hpp>
#include <boost/random/uniform_int_distribution.hpp>
#include <boost/random/variate_generator.hpp>
#include "boost/date_time/posix_time/posix_time.hpp"
#include "boost/date_time/gregorian/gregorian.hpp"
using namespace std;
using namespace boost;
using namespace boost::posix_time;
using namespace boost::gregorian;
class Randomizer {
private:
static const bool debug_mode = false;
random::mt19937 rng_;
// The private constructor so that the user can not directly instantiate
Randomizer() {
if(debug_mode==true){
this->rng_ = random::mt19937();
}else{
this->rng_ = random::mt19937(current_time_nanoseconds());
}
};
int current_time_nanoseconds(){
struct timespec tm;
clock_gettime(CLOCK_REALTIME, &tm);
return tm.tv_nsec;
}
// C++ 03
// ========
// Dont forget to declare these two. You want to make sure they
// are unacceptable otherwise you may accidentally get copies of
// your singleton appearing.
Randomizer(Randomizer const&); // Don't Implement
void operator=(Randomizer const&); // Don't implement
public:
static Randomizer& get_instance(){
// The only instance of the class is created at the first call get_instance ()
// and will be destroyed only when the program exits
static Randomizer instance;
return instance;
}
bool method() { return true; };
int rand(unsigned int floor, unsigned int ceil){
random::uniform_int_distribution<> rand_ = random::uniform_int_distribution<> (floor,ceil);
return (rand_(rng_));
}
// Is not considering the millisecons
time_duration rand_time_duration(){
boost::posix_time::time_duration floor(0, 0, 0, 0);
boost::posix_time::time_duration ceil(23, 59, 59, 0);
unsigned int rand_seconds = rand(floor.total_seconds(), ceil.total_seconds());
return seconds(rand_seconds);
}
date rand_date_from_epoch_to_now(){
date now = second_clock::local_time().date();
return rand_date_from_epoch_to_ceil(now);
}
date rand_date_from_epoch_to_ceil(date ceil_date){
date epoch = ptime(date(1970,1,1)).date();
return rand_date_in_interval(epoch, ceil_date);
}
date rand_date_in_interval(date floor_date, date ceil_date){
return rand_ptime_in_interval(ptime(floor_date), ptime(ceil_date)).date();
}
ptime rand_ptime_from_epoch_to_now(){
ptime now = second_clock::local_time();
return rand_ptime_from_epoch_to_ceil(now);
}
ptime rand_ptime_from_epoch_to_ceil(ptime ceil_date){
ptime epoch = ptime(date(1970,1,1));
return rand_ptime_in_interval(epoch, ceil_date);
}
ptime rand_ptime_in_interval(ptime floor_date, ptime ceil_date){
time_duration const diff = ceil_date - floor_date;
long long gap_seconds = diff.total_seconds();
long long step_seconds = Randomizer::get_instance().rand(0, gap_seconds);
return floor_date + seconds(step_seconds);
}
};

How to time a function in milliseconds without boost::timer

I am using boost 1.46 which does not include boost::timer, What other way can I time my functions.
I am currently doing this:
time_t now = time(0);
<some stuff>
time_t after = time(0);
cout << after - now << endl;
but it just gives the answer in seconds, so if the function takes < 1s it displays 0.
Thanks
In linux or Windows:
#include <ctime>
#include <iostream>
int
main(int, const char**)
{
std::clock_t start;
start = std::clock();
// your test
std::cout << "Time: " << (std::clock() - start) / (double)(CLOCKS_PER_SEC / 1000) << " ms" << std::endl;
return 0;
}
Good Luck ;)
Using std::chrono:
#include <chrono>
#include <thread>
#include <iostream>
// There are other clocks, but this is usually the one you want.
// It corresponds to CLOCK_MONOTONIC at the syscall level.
using Clock = std::chrono::steady_clock;
using std::chrono::time_point;
using std::chrono::duration_cast;
using std::chrono::milliseconds;
using namespace std::literals::chrono_literals;
using std::this_thread::sleep_for;
int main()
{
time_point<Clock> start = Clock::now();
sleep_for(500ms);
time_point<Clock> end = Clock::now();
milliseconds diff = duration_cast<milliseconds>(end - start);
std::cout << diff.count() << "ms" << std::endl;
}
std::chrono is C++11, std::literals is C++14 (otherwise you need milliseconds(500)).
Turns out there is a version of time in boost 1.46 (just in different location). Thanks to
#jogojapan for pointing it out.
It can be done like this:
#include <boost/timer.hpp>
timer t;
<some stuff>
std::cout << t.elapsed() << std::endl;
Or alternatively using std libs as #Quentin Perez has pointed out (and I will accept as is what was originally asked)
Building on Quentin Perez's solution, you can pass an arbitrary function to time using std::function and a lambda.
#include <ctime>
#include <iostream>
#include <functional>
void timeit(std::function<void()> func) {
std::clock_t start = std::clock();
func();
int ms = (std::clock() - start) / (double) (CLOCKS_PER_SEC / 1000);
std::cout << "Finished in " << ms << "ms" << std::endl;
}
int main() {
timeit([] {
for (int i = 0; i < 10; ++i) {
std::cout << "i = " << i << std::endl;
}
});
return 0;
}
You can use a long to hold the current time value as a start value, and then convert the current time to a double. here is some snippet code to use as an example.
#include <iostream>
#include <stdlib.h>
#include <time.h>
#include <sys/types.h>
#include <sys/timeb.h>
int main()
{
struct _timeb tStruct;
double thisTime;
bool done = false;
long startTime;
struct _timeb
{
int dstflag; // holds a non-zero value if daylight saving time is in effect
long millitm; // time in milliseconds since the last one-second hack
long time; // time in seconds since 00:00:00 1/1/1970
long timezone; // difference in minutes moving west from UTC
};
_ftime(&tStruct); // Get start time
thisTime = tStruct.time + (((double)(tStruct.millitm)) / 1000.0); // Convert to double
startTime = thisTime; // Set the starting time (when the function begins)
while(!done) // Start an eternal loop
{
system("cls"); // Clear the screen
_ftime(&tStruct); // Get the current time
thisTime = tStruct.time + (((double)(tStruct.millitm)) / 1000.0); // Convert to double
// Check for 5 second interval to print status to screen
cout << thisTime-startTime; // Print it.
}
}

How to get current time and date in C++?

Is there a cross-platform way to get the current date and time in C++?
Since C++ 11 you can use std::chrono::system_clock::now()
Example (copied from en.cppreference.com):
#include <iostream>
#include <chrono>
#include <ctime>
int main()
{
auto start = std::chrono::system_clock::now();
// Some computation here
auto end = std::chrono::system_clock::now();
std::chrono::duration<double> elapsed_seconds = end-start;
std::time_t end_time = std::chrono::system_clock::to_time_t(end);
std::cout << "finished computation at " << std::ctime(&end_time)
<< "elapsed time: " << elapsed_seconds.count() << "s"
<< std::endl;
}
This should print something like this:
finished computation at Mon Oct 2 00:59:08 2017
elapsed time: 1.88232s
C++ shares its date/time functions with C. The tm structure is probably the easiest for a C++ programmer to work with - the following prints today's date:
#include <ctime>
#include <iostream>
int main() {
std::time_t t = std::time(0); // get time now
std::tm* now = std::localtime(&t);
std::cout << (now->tm_year + 1900) << '-'
<< (now->tm_mon + 1) << '-'
<< now->tm_mday
<< "\n";
}
You can try the following cross-platform code to get current date/time:
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
// Get current date/time, format is YYYY-MM-DD.HH:mm:ss
const std::string currentDateTime() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
// Visit http://en.cppreference.com/w/cpp/chrono/c/strftime
// for more information about date/time format
strftime(buf, sizeof(buf), "%Y-%m-%d.%X", &tstruct);
return buf;
}
int main() {
std::cout << "currentDateTime()=" << currentDateTime() << std::endl;
getchar(); // wait for keyboard input
}
Output:
currentDateTime()=2012-05-06.21:47:59
Please visit here for more information about date/time format
std C libraries provide time().
This is seconds from the epoch and can be converted to date and H:M:S using standard C functions. Boost also has a time/date library that you can check.
time_t timev;
time(&timev);
New answer for an old question:
The question does not specify in what timezone. There are two reasonable possibilities:
In UTC.
In the computer's local timezone.
For 1, you can use this date library and the following program:
#include "date.h"
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
std::cout << system_clock::now() << '\n';
}
Which just output for me:
2015-08-18 22:08:18.944211
The date library essentially just adds a streaming operator for std::chrono::system_clock::time_point. It also adds a lot of other nice functionality, but that is not used in this simple program.
If you prefer 2 (the local time), there is a timezone library that builds on top of the date library. Both of these libraries are open source and cross platform, assuming the compiler supports C++11 or C++14.
#include "tz.h"
#include <iostream>
int
main()
{
using namespace date;
using namespace std::chrono;
auto local = make_zoned(current_zone(), system_clock::now());
std::cout << local << '\n';
}
Which for me just output:
2015-08-18 18:08:18.944211 EDT
The result type from make_zoned is a date::zoned_time which is a pairing of a date::time_zone and a std::chrono::system_clock::time_point. This pair represents a local time, but can also represent UTC, depending on how you query it.
With the above output, you can see that my computer is currently in a timezone with a UTC offset of -4h, and an abbreviation of EDT.
If some other timezone is desired, that can also be accomplished. For example to find the current time in Sydney , Australia just change the construction of the variable local to:
auto local = make_zoned("Australia/Sydney", system_clock::now());
And the output changes to:
2015-08-19 08:08:18.944211 AEST
Update for C++20
This library is now largely adopted for C++20. The namespace date is gone and everything is in namespace std::chrono now. And use zoned_time in place of make_time. Drop the headers "date.h" and "tz.h" and just use <chrono>.
#include <chrono>
#include <iostream>
int
main()
{
using namespace std::chrono;
auto local = zoned_time{current_zone(), system_clock::now()};
std::cout << local << '\n'; // 2021-05-03 15:02:44.130182 EDT
}
As I write this, partial implementations are just beginning to emerge on some platforms.
the C++ standard library does not provide a proper date type. C++ inherits the structs and functions for date and time manipulation from C, along with a couple of date/time input and output functions that take into account localization.
// Current date/time based on current system
time_t now = time(0);
// Convert now to tm struct for local timezone
tm* localtm = localtime(&now);
cout << "The local date and time is: " << asctime(localtm) << endl;
// Convert now to tm struct for UTC
tm* gmtm = gmtime(&now);
if (gmtm != NULL) {
cout << "The UTC date and time is: " << asctime(gmtm) << endl;
}
else {
cerr << "Failed to get the UTC date and time" << endl;
return EXIT_FAILURE;
}
auto time = std::time(nullptr);
std::cout << std::put_time(std::localtime(&time), "%F %T%z"); // ISO 8601 format.
Get the current time either using std::time() or std::chrono::system_clock::now() (or another clock type).
std::put_time() (C++11) and strftime() (C) offer a lot of formatters to output those times.
#include <iomanip>
#include <iostream>
int main() {
auto time = std::time(nullptr);
std::cout
// ISO 8601: %Y-%m-%d %H:%M:%S, e.g. 2017-07-31 00:42:00+0200.
<< std::put_time(std::gmtime(&time), "%F %T%z") << '\n'
// %m/%d/%y, e.g. 07/31/17
<< std::put_time(std::gmtime(&time), "%D");
}
The sequence of the formatters matters:
std::cout << std::put_time(std::gmtime(&time), "%c %A %Z") << std::endl;
// Mon Jul 31 00:00:42 2017 Monday GMT
std::cout << std::put_time(std::gmtime(&time), "%Z %c %A") << std::endl;
// GMT Mon Jul 31 00:00:42 2017 Monday
The formatters of strftime() are similar:
char output[100];
if (std::strftime(output, sizeof(output), "%F", std::gmtime(&time))) {
std::cout << output << '\n'; // %Y-%m-%d, e.g. 2017-07-31
}
Often, the capital formatter means "full version" and lowercase means abbreviation (e.g. Y: 2017, y: 17).
Locale settings alter the output:
#include <iomanip>
#include <iostream>
int main() {
auto time = std::time(nullptr);
std::cout << "undef: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("en_US.utf8"));
std::cout << "en_US: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("en_GB.utf8"));
std::cout << "en_GB: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("de_DE.utf8"));
std::cout << "de_DE: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("ja_JP.utf8"));
std::cout << "ja_JP: " << std::put_time(std::gmtime(&time), "%c") << '\n';
std::cout.imbue(std::locale("ru_RU.utf8"));
std::cout << "ru_RU: " << std::put_time(std::gmtime(&time), "%c");
}
Possible output (Coliru, Compiler Explorer):
undef: Tue Aug 1 08:29:30 2017
en_US: Tue 01 Aug 2017 08:29:30 AM GMT
en_GB: Tue 01 Aug 2017 08:29:30 GMT
de_DE: Di 01 Aug 2017 08:29:30 GMT
ja_JP: 2017年08月01日 08時29分30秒
ru_RU: Вт 01 авг 2017 08:29:30
I've used std::gmtime() for conversion to UTC. std::localtime() is provided to convert to local time.
Heed that asctime()/ctime() which were mentioned in other answers are marked as deprecated now and strftime() should be preferred.
(For fellow googlers)
There is also Boost::date_time :
#include <boost/date_time/posix_time/posix_time.hpp>
boost::posix_time::ptime date_time = boost::posix_time::microsec_clock::universal_time();
#include <stdio.h>
#include <time.h>
int main ()
{
time_t rawtime;
struct tm * timeinfo;
time ( &rawtime );
timeinfo = localtime ( &rawtime );
printf ( "Current local time and date: %s", asctime (timeinfo) );
return 0;
}
Yes and you can do so with formatting rules specified by the currently-imbued locale:
#include <iostream>
#include <iterator>
#include <string>
class timefmt
{
public:
timefmt(std::string fmt)
: format(fmt) { }
friend std::ostream& operator <<(std::ostream &, timefmt const &);
private:
std::string format;
};
std::ostream& operator <<(std::ostream& os, timefmt const& mt)
{
std::ostream::sentry s(os);
if (s)
{
std::time_t t = std::time(0);
std::tm const* tm = std::localtime(&t);
std::ostreambuf_iterator<char> out(os);
std::use_facet<std::time_put<char>>(os.getloc())
.put(out, os, os.fill(),
tm, &mt.format[0], &mt.format[0] + mt.format.size());
}
os.width(0);
return os;
}
int main()
{
std::cout << timefmt("%c");
}
Output: Fri Sep 6 20:33:31 2013
you could use C++ 11 time class:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
time_t now = chrono::system_clock::to_time_t(chrono::system_clock::now());
cout << put_time(localtime(&now), "%F %T") << endl;
return 0;
}
out put:
2017-08-25 12:30:08
There's always the __TIMESTAMP__ preprocessor macro.
#include <iostream>
using namespace std
void printBuildDateTime () {
cout << __TIMESTAMP__ << endl;
}
int main() {
printBuildDateTime();
}
example: Sun Apr 13 11:28:08 2014
std::ctime
Why was ctime only mentioned in the comments so far?
#include <ctime>
#include <iostream>
int main()
{
std::time_t result = std::time(nullptr);
std::cout << std::ctime(&result);
}
Output
Tue Dec 27 17:21:29 2011
You can use the following code to get the current system date and time in C++ :
#include <iostream>
#include <time.h> //It may be #include <ctime> or any other header file depending upon
// compiler or IDE you're using
using namespace std;
int main() {
// current date/time based on current system
time_t now = time(0);
// convert now to string form
string dt = ctime(&now);
cout << "The local date and time is: " << dt << endl;
return 0;
}
PS: Visit this site for more information.
You can also directly use ctime():
#include <stdio.h>
#include <time.h>
int main ()
{
time_t rawtime;
struct tm * timeinfo;
time ( &rawtime );
printf ( "Current local time and date: %s", ctime (&rawtime) );
return 0;
}
I found this link pretty useful for my implementation:
C++ Date and Time
Here's the code I use in my implementation, to get a clear "YYYYMMDD HHMMSS" output format. The param in is for switching between UTC and local time. You can easily modify my code to suite your need.
#include <iostream>
#include <ctime>
using namespace std;
/**
* This function gets the current date time
* #param useLocalTime true if want to use local time, default to false (UTC)
* #return current datetime in the format of "YYYYMMDD HHMMSS"
*/
string getCurrentDateTime(bool useLocalTime) {
stringstream currentDateTime;
// current date/time based on current system
time_t ttNow = time(0);
tm * ptmNow;
if (useLocalTime)
ptmNow = localtime(&ttNow);
else
ptmNow = gmtime(&ttNow);
currentDateTime << 1900 + ptmNow->tm_year;
//month
if (ptmNow->tm_mon < 9)
//Fill in the leading 0 if less than 10
currentDateTime << "0" << 1 + ptmNow->tm_mon;
else
currentDateTime << (1 + ptmNow->tm_mon);
//day
if (ptmNow->tm_mday < 10)
currentDateTime << "0" << ptmNow->tm_mday << " ";
else
currentDateTime << ptmNow->tm_mday << " ";
//hour
if (ptmNow->tm_hour < 10)
currentDateTime << "0" << ptmNow->tm_hour;
else
currentDateTime << ptmNow->tm_hour;
//min
if (ptmNow->tm_min < 10)
currentDateTime << "0" << ptmNow->tm_min;
else
currentDateTime << ptmNow->tm_min;
//sec
if (ptmNow->tm_sec < 10)
currentDateTime << "0" << ptmNow->tm_sec;
else
currentDateTime << ptmNow->tm_sec;
return currentDateTime.str();
}
Output (UTC, EST):
20161123 000454
20161122 190454
This works with G++ I'm not sure if this helps you.
Program output:
The current time is 11:43:41 am
The current date is 6-18-2015 June Wednesday
Day of month is 17 and the Month of year is 6,
also the day of year is 167 & our Weekday is 3.
The current year is 2015.
Code :
#include <ctime>
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
using namespace std;
const std::string currentTime() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%H:%M:%S %P", &tstruct);
return buf;
}
const std::string currentDate() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%B %A ", &tstruct);
return buf;
}
int main() {
cout << "\033[2J\033[1;1H";
std:cout << "The current time is " << currentTime() << std::endl;
time_t t = time(0); // get time now
struct tm * now = localtime( & t );
cout << "The current date is " << now->tm_mon + 1 << '-'
<< (now->tm_mday + 1) << '-'
<< (now->tm_year + 1900)
<< " " << currentDate() << endl;
cout << "Day of month is " << (now->tm_mday)
<< " and the Month of year is " << (now->tm_mon)+1 << "," << endl;
cout << "also the day of year is " << (now->tm_yday)
<< " & our Weekday is " << (now->tm_wday) << "." << endl;
cout << "The current year is " << (now->tm_year)+1900 << "."
<< endl;
return 0;
}
This compiled for me on Linux (RHEL) and Windows (x64) targeting g++ and OpenMP:
#include <ctime>
#include <iostream>
#include <string>
#include <locale>
////////////////////////////////////////////////////////////////////////////////
//
// Reports a time-stamped update to the console; format is:
// Name: Update: Year-Month-Day_of_Month Hour:Minute:Second
//
////////////////////////////////////////////////////////////////////////////////
//
// [string] strName : name of the update object
// [string] strUpdate: update descripton
//
////////////////////////////////////////////////////////////////////////////////
void ReportTimeStamp(string strName, string strUpdate)
{
try
{
#ifdef _WIN64
// Current time
const time_t tStart = time(0);
// Current time structure
struct tm tmStart;
localtime_s(&tmStart, &tStart);
// Report
cout << strName << ": " << strUpdate << ": " << (1900 + tmStart.tm_year) << "-" << tmStart.tm_mon << "-" << tmStart.tm_mday << " " << tmStart.tm_hour << ":" << tmStart.tm_min << ":" << tmStart.tm_sec << "\n\n";
#else
// Current time
const time_t tStart = time(0);
// Current time structure
struct tm* tmStart;
tmStart = localtime(&tStart);
// Report
cout << strName << ": " << strUpdate << ": " << (1900 + tmStart->tm_year) << "-" << tmStart->tm_mon << "-" << tmStart->tm_mday << " " << tmStart->tm_hour << ":" << tmStart->tm_min << ":" << tmStart->tm_sec << "\n\n";
#endif
}
catch (exception ex)
{
cout << "ERROR [ReportTimeStamp] Exception Code: " << ex.what() << "\n";
}
return;
}
The ffead-cpp provides multiple utility classes for various tasks, one such class is the Date class which provides a lot of features right from Date operations to date arithmetic, there's also a Timer class provided for timing operations. You can have a look at the same.
http://www.cplusplus.com/reference/ctime/strftime/
This built-in seems to offer a reasonable set of options.
localtime_s() version:
#include <stdio.h>
#include <time.h>
int main ()
{
time_t current_time;
struct tm local_time;
time ( &current_time );
localtime_s(&local_time, &current_time);
int Year = local_time.tm_year + 1900;
int Month = local_time.tm_mon + 1;
int Day = local_time.tm_mday;
int Hour = local_time.tm_hour;
int Min = local_time.tm_min;
int Sec = local_time.tm_sec;
return 0;
}
#include <iostream>
#include <chrono>
#include <string>
#pragma warning(disable: 4996)
// Ver: C++ 17
// IDE: Visual Studio
int main() {
using namespace std;
using namespace chrono;
time_point tp = system_clock::now();
time_t tt = system_clock::to_time_t(tp);
cout << "Current time: " << ctime(&tt) << endl;
return 0;
}
Here is the non-deprecated modern C++ solution for getting a timestamp as a std::string for use with e.g. filenames:
std::string get_file_timestamp()
{
const auto now = std::chrono::system_clock::now();
const auto in_time_t = std::chrono::system_clock::to_time_t(now);
std::stringstream output_stream;
struct tm time_info;
const auto errno_value = localtime_s(&time_info, &in_time_t);
if(errno_value != 0)
{
throw std::runtime_error("localtime_s() failed: " + std::to_string(errno_value));
}
output_stream << std::put_time(&time_info, "%Y-%m-%d.%H_%M_%S");
return output_stream.str();
}
You could use boost and chrono library:
#include <iostream>
#include <chrono>
#include <boost/date_time/posix_time/posix_time.hpp>
using boost::posix_time::to_iso_extended_string;
using boost::posix_time::from_time_t;
using std::chrono::system_clock;
int main()
{
auto now = system_clock::now();
std::cout << to_iso_extended_string(from_time_t(system_clock::to_time_t(now)));
}
#include <Windows.h>
void main()
{
//Following is a structure to store date / time
SYSTEMTIME SystemTime, LocalTime;
//To get the local time
int loctime = GetLocalTime(&LocalTime);
//To get the system time
int systime = GetSystemTime(&SystemTime)
}
I needed a way to insert current date-time at every update of a list.
This seems to work well, simply.
#include<bits/stdc++.h>
#include<unistd.h>
using namespace std;
int main()
{ //initialize variables
time_t now;
//blah..blah
/*each time I want the updated stamp*/
now=time(0);cout<<ctime(&now)<<"blah_blah";
}