Error in Fortran: attempt to call a routine with argument number four as a real (kind=1) when a procedure was required - fortran

Question

I have never done programming in my life and this is my very first code for a uni assignment, I get no errors in the compiling stage but myh program does not run saying that I have the error in the title, guess the problem is when I call the subroutine. Can anyone help me? It is my first code and it is really frustrating. Thank you.
!NUMERICAL COMPUTATION OF INCOMPRESSIBLE COUETTE FLOW USING FINITE DIFFERENCE METHOD
!IMPLICIT APPROACH
!MODEL EQUATION
!PARTIAL(U)/PARTIAL(T)=1/RE*(PARTIAL(U) SQUARE/PARTIAL(Y) SQUARE)
!DEFINE VARIABLES
IMPLICIT NONE
!VELOCITY U AT TIME T, VELOCITY UNEW AT TIME T+1, TIME T
!MAXIMUM 1000 POINTS
REAL V(1000)
REAL VNEW(1000)
REAL T
!GRID SPACING DY, GRID POINTS N+1
REAL DY
INTEGER N
!TIME STEP
REAL DT
!FLOW REYNOLDS NUMBER IN THE MODEL EQUATION
REAL ALPHA
!TOTAL SIMULATION TIME - LOOP NUMBER
INTEGER REP, I, J
!COEFFICIENTS IN LINEAR EQUATION MATRIX, SOURCE TERM K, DIAGONAL B, NON-DIAGONAL A
REAL S(1000), B, A
!INITIALIZATION OF DATA
DATA ALPHA/5000.0/
DATA N/100/
DATA REP/3000/
!CALCULATION OF GRID SPACING
DY=1.0/N
!CALCULATION OF TIME STEP DELTA T, CAN BE LARGER THAN THAT IN AN EXPLICIT METHOD
DT=0.5*RE*DY*DY
DT=ALPHA*DY*DY
!INITIAL CONDITIONS OF VELOCITY PROFILE
!BOTTOM AND INNER POINTS
DO I=1,N
V(I)=0.0
ENDDO
!POINT AT MOVING PLATE
V(N+1)=1.0
!BOUNDARY CONDITIONS AT LOWER AND UPPER POINTS ON PLATE
V(1)=0.0
V(N+1)=1.0
!CALCULATION OF DIAGONAL B AND NON-DIAGONAL A IN LINEAR EQUATION MATRIX
B=1.0+DT/DY/DY/ALPHA
A=-(DT)/2.0/DY/DY/ALPHA
!INITIAL COMPUTATION TIME
T=0.0
!ENTER MAIN LOOP TO MARCH IN TIME DIRECTION
DO I=1,REP
!SIMULATION TIME INCREASE BY DELTA T EACH STEP
T=T+DT
!USE IMPLICIT METHOD TO UPDATE GRID POINT VALUES FOR ALL INTERNAL GRIDS ONLY
!TWO BOUNDARY GRID POINTS VALUES ARE CONSTANT WITHIN THE WHOLE SIMULATION
!CALCULATION OF SOURCE TERM IN LINEAR EQUATION
DO J=2,N
S(J)=(1.0-DT/DY/DY/ALPHA)*V(J)+DT/2.0/DY/DY/ALPHA*V(J+1)+V(J-1)
ENDDO
!INCLUDE BOUNDARY CONDITIONS FOR TWO POINTS NEAR BOUDNARY
S(2)=S(2)-A*V(1)
S(N)=S(N)-A*V(N+1)
!USE SOURCE TERM K, DIAGONAL B, NON-DIAGONAL A, ORDER OF MATRIX N, TO SOLVE LINEAR EQUATION TO GET UPDATED VELOCITY
!CHECK ON INTERNET HOW TO SOLVE THIS BECUASE THIS COMPILER
!DOES NOT SOLVE IT, SOLVE LINEAR EQUATIONS BY A LINEAR SOLVER, FIND AND DOWNLOAD THE MATH LIBRARY FOR THIS COMPILER
CALL SR1(A,B,N,S,VNEW)
!REPLACE OLD VELOCITY VALUES WITH NEW VALUES.
!SINCE UNEW IS FROM UNEW(1), UNEW(2)......., UNEW(N-1), WE SHOULD RE-ARRANGE NUMBERS AS FOLLOWS
DO J=1,N-1
V(J+1)=VNEW(J)
ENDDO
!RETURN TO MAIN LOOP HERE
ENDDO
PRINT*,'HERE'
!OUTPUT VELOCITY PROFILES AT THE END OF COMPUTATION
!CREATE OUPUT FILE NAME
OPEN(15,FILE='PLEASEWORK')
!WRITE GRID POINTS AND VELOCITY VALUES
DO I=1,N+1
WRITE(15,10) V(I),(I-1)*DY
10 FORMAT(2F12.3)
ENDDO
CLOSE(15)
!DISPLAY INFORMATION ON SCREEN
!WRITE(*,*) 'THE OUTPUT VELOCITY IS AFTER', ITER, ' TIME STEPS'
!TERMINATION OF COMPUTER PROGRAM
STOP
END
!!!!!!!!
!!!!!!!!!!!!
!!!!!!!!!
SUBROUTINE SR1(A,B,N,S,VNEW)
REAL DIAGM(N), DIAGU(N), DIAGL(N)
REAL SS(N)
DO J=1,N-1
SS(J)=S(J+1)
ENDDO
DO I=1,N
DIAGM(i)=B
!Sets main diagonal as B for every value of i
IF (I==0) then
DIAGU(I)=A
DIAGL(I)=0
! No lower diagonal coefficient when i = 0
ELSE IF (I==N) THEN
DIAGU(I)=0
! No upper diagonal coefficient when i = Num
DIAGL(I)=A
ELSE
DIAGU(I)=A
! For all other points there is an upper diagonal coefficient
DIAGL(I)=A
! For all other points there is a lower diagonal coefficient
ENDIF
ENDDO
!CALL STANDARD FORTRAN MATH LIBRARY TO SOLVE LINEAR EQUATION AND GET SOLUTION VECTOR X(N-1)
CALL SR2 (DIAGL,DIAGM,DIAGU,SS,VNEW,N-2)
!RETURN TO MAIN PROGRAM AND X(N-1) IS FEEDED INTO UNEW(N-1)
RETURN
END SUBROUTINE
!!!!!!!!!!!!!!!
!!!!!!!!!!!
!!!!!!!!!!!
SUBROUTINE SR2 (A,B,C,D,Z,N)
!a - sub-diagonal (means it is the diagonal below the main diagonal)
!b - the main diagonal
!c - sup-diagonal (means it is the diagonal above the main diagonal)
!K - right part
!UNEW - the answer
!E - number of equations
INTEGER N
REAL A(N), B(N), C(N), D(N)
REAL CP(N), DP(N), Z(N)
REAL M
INTEGER I
DATA M/1/
!initialize c-prime and d-prime
CP(1) = C(1)/B(1)
DP(1) = D(1)/B(1)
!solve for vectors c-prime and d-prime
DO I=2,N
M=b(i)-CP(I-1)*(A(I))
CP(I)=C(I)/M
DP(I)=(D(I)-DP(I-1)*A(I))/M
ENDDO
!initialize UNEW
Z(N)=DP(N)
!solve for x from the vectors c-prime and d-prime
DO I=N-1, 1, -1
Z(I)=DP(I)-CP(I)*Z(I+1)
ENDDO
END SUBROUTINE

Answer 1

As george says in a comment, the problem is with the subroutine SR1. So that this isn't just a CW-stealing-a-comment answer I'll also expand a bit.
The way things are structured SR1 is a different scope from the main program. The IMPLICIT NONE in the main program doesn't apply to the subroutine, so A, B, N, S and VNEW are all implicitly typed. Apart from N,which is an integer, they are (scalar) reals.
The reference to S(J+1), as george says, means that S is not only a scalar real, but also a function. Remember that SR1 is a different scope and no information is passed from the caller to the callee about types, shapes, etc.. Further, that the dummy argument in SR1 called A happens to be same name as the actual argument in the call doesn't mean that the callee "knows" things. Your call to SR2 with the VNEW is also a problem for the same reason.
The question is tagged as "fortran77" so there isn't too much you can do to ensure there is a lot of checking going on, but there may well be compiler options and as you can use IMPLICIT NONE (not Fortran 77) that would detect your problems.
But, the question is also tagged "fortran" and "fortran95" so I'll point out that there are far better ways to detect the issues, using more modern features. Look at interfaces, modules and internal procedures.