Conditional return to beginning of function - c++

Question

I'm trying to return or repeat the function if the results of it do not meet the criteria. I've tried various things, such as do while statements, settings a BOOL flag, etc. and have been unsuccessful. What's the best way to restart the function until the criteria is met?
CODE:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
int main() {
std:int nine;
std::srand(std::time(NULL));
std::cout << nine << (rand() % 10);
std::cout << '\n';
if (nine == 9) {
std::cout << 'nine';
} else {
main();
}
}

Answer 1

You may not recursively call main in C++. Also your code contains some other errors. The program could look the following way.
#include <iostream>
#include <cstdlib>
#include <ctime>
int main()
{
std::srand( ( unsigned )std::time( NULL) );
int nine;
do
{
nine = std::rand() % 10;
} while ( nine != 9 );
std::cout << "nine" << std::endl;
}
You could also add an output statement
#include <iostream>
#include <cstdlib>
#include <ctime>
int main()
{
std::srand( ( unsigned )std::time( NULL) );
int nine;
do
{
nine = std::rand() % 10;
std::cout << nine << std::endl;
} while ( nine != 9 );
std::cout << "nine" << std::endl;
}

Answer 2

A while loop should work just fine:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
int main() {
int nine = 0;
srand(std::time(NULL));
while (nine != 9)
{
nine = (rand() % 10);
std::cout << nine << std::endl;
if (nine == 9) {
std::cout << 'nine';
}
}
}

Answer 3

i think your problem is in nine , you don't assign it
nine = rand()%10;
and with the basic loop it should be fine
while ( nine != 9){
nine = rand()%10;
}

Answer 4

You can do as follows:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
int main() {
std::srand(std::time(NULL));
do {
std:int nine;
std::cout << nine << (rand() % 10);
std::cout << '\n';
if(nine == 9) {
std::cout << 'nine';
break;
}
} while(true);
}
Note that you don't ever change nine in your code, the loop will go forever.

Answer 5

This particular code wouldn't even compile due to the std:int (missing colon typo). But assuming the typo was fixed, it also wouldn't do anything because you never assign a value to nine.
Anyway, if you want to repeat an action in your code, your best bet is a loop:
int nine = 0;
do {
nine = rand() % 10;
} while (nine != 9);