The Below is my input XML:
<?xml version="1.0" encoding="utf-8" ?>
<LogiusInhouse>
<qty9 field="QTY_9,11#">
<type>90</type>
<value>12</value>
</qty9>
<qty9 field="QTY_9,11#">
<type>90</type>
<value>12</value>
</qty9>
<dtm9 field="DTM_9,11#">
<type>145</type>
<date>20130308</date>
<format>102</format>
</dtm9>
</LogiusInhouse>
XSL:
<xsl:template match="/LogiusInhouse">
<xsl:value-of select="abs(sum(qty9[type='90']/value))div 1000 "/>
</xsl:template>
my problem is i need to get the absolute sum afterthat it has to be divided by 1000 but iam not getting the result.Please help me on this.
Or, you can use just this:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" indent="yes"/>
<xsl:template match="/LogiusInhouse">
<xsl:value-of select="sum(qty9/value)" />
</xsl:template>
</xsl:stylesheet>
do not use for-each. use the template below
<xsl:template match="/LogiusInhouse">
<xsl:value-of select="sum(//value)"/>
</xsl:template>
using for-each will output 1212 because for-each node (in your code), the result is 12
Related
I want to convert the following source xml structure to the target xml structure using xslt transformation. I am mot able to convert the following source xml to target xml using xslt. Please help us in coneverting this.
Source XML
<XxhrPiEmpcompOutIntCollection>
<XxhrPiEmpcompOutInt>
<employeeNumber>
200000562
</employeeNumber>
<competencyName>
Comp1
</competencyName>
<proficiencyLevel>
Prof1
</proficiencyLevel>
<compDateTo>
16-NOV-12
</compDateTo>
</XxhrPiEmpcompOutInt>
<XxhrPiEmpcompOutInt>
<employeeNumber>
200000562
</employeeNumber>
<competencyName>
Comp2
</competencyName>
<proficiencyLevel>
Prof2
</proficiencyLevel>
<compDateTo>
16-NOV-12
</compDateTo>
</XxhrPiEmpcompOutInt>
</XxhrPiEmpcompOutIntCollection>
Target xml
<EmployeeCompetencyRequest>
<EmployeeNumber>200000562</EmployeeNumber>
<Competencies>
<Competency>
<Name>Comp1</Name>
<ProficiencyLevel>Prof1</ProficiencyLevel>
<EndDate>16-NOV-12</EndDate>
</Competency>
<Competency>
<Name>Comp2</Name>
<ProficiencyLevel>Prof2</ProficiencyLevel>
<EndDate>16-NOV-12</EndDate>
</Competency>
</Competencies>
</<EmployeeCompetencyRequest>
Some hint :
<EmployeeCompetencyRequest>
template match /XxhrPiEmpcompOutIntCollection
for-each-group XxhrPiEmpcompOutInt group by employeeNumber
<EmployeeNumber> value-of current-group-key </EmployeeNumber>
<Competencies>
for-each current-group
<Competency>
value-of name
value-of proficiencyLevel
</competency>
/for-each
</Competencies>
/for-each-group
<EmployeeCompetencyRequest>
Hope you can finish it.
You can group users with for-each-group:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<EmployeeCompetencyRequest>
<xsl:for-each-group select="//XxhrPiEmpcompOutInt" group-by="employeeNumber">
<Name><xsl:value-of select="current-grouping-key()"/></Name>
<Competencies>
<xsl:for-each select="current-group()">
<Competency>
<Name><xsl:value-of select="competencyName"/></Name>
<ProfiencyLevel><xsl:value-of select="profiencyLevel"/></ProfiencyLevel>
<EndDate><xsl:value-of select="compDateTo"/></EndDate>
</Competency>
</xsl:for-each>
</Competencies>
</xsl:for-each-group>
</EmployeeCompetencyRequest>
</xsl:template>
Salut,
For XSLT 1.0 you must group widht xsl:key:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="groups" match="/XxhrPiEmpcompOutIntCollection/XxhrPiEmpcompOutInt" use="employeeNumber" />
<xsl:template match="/">
<EmployeeCompetencyRequest>
<xsl:apply-templates select="//XxhrPiEmpcompOutInt[generate-id() = generate-id(key('groups', employeeNumber)[1])]"/>
</EmployeeCompetencyRequest>
</xsl:template>
<xsl:template match="XxhrPiEmpcompOutInt">
<Name><xsl:value-of select="employeeNumber"/></Name>
<Competencies>
<xsl:for-each select="key('groups', employeeNumber)">
<Competency>
<Name><xsl:value-of select="competencyName"/></Name>
<ProfiencyLevel><xsl:value-of select="proficiencyLevel"/></ProfiencyLevel>
<EndDate><xsl:value-of select="compDateTo"/></EndDate>
</Competency>
</xsl:for-each>
</Competencies>
</xsl:template>
</xsl:stylesheet>
I can't test it with Oracle ...
I need to copy a subnode from a XML to a certain node of a new XML in a Biztalk Map using XSLT.
Consider the following input XML:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:root xmlns:ns0="http://not/useful/data/">
<ns0:notuseful>
<ns0:foo></ns0:foo>
<ns0:foo2></ns0:foo2>
<ns0:blabla></ns0:blabla>
</ns0:notuseful>
<ns0:data>
<ns1:usefulDataList xmlns:ns1="http://useful/data/">
<ns1:usefulData>
<ns1:usefulChild1></ns1:usefulChild1>
<ns1:usefulChild2></ns1:usefulChild2>
<ns1:usefulChild3></ns1:usefulChild3>
<ns1:usefulChild4></ns1:usefulChild4>
<ns1:usefulChild5></ns1:usefulChild5>
</ns1:usefulData>
</ns1:usefulDataList>
</ns0:data>
<ns0:root>
What I need is to extract the node called "usefulDataList", so I need to copy it in a new XML like this one:
<?xml version="1.0" encoding="UTF-8"?>
<ns2:root2 xmln:ns2="http://new/xml">
<ns2:blabla>
<ns2:stuff />
</ns2:blabla>
<ns2:data>
<ns2:usefulDataList>
<ns2:usefulData>
<ns2:usefulChild1></ns2:usefulChild1>
<ns2:usefulChild2></ns2:usefulChild2>
<ns2:usefulChild3></ns2:usefulChild3>
<ns2:usefulChild4></ns2:usefulChild4>
<ns2:usefulChild5></ns2:usefulChild5>
</ns2:usefulData>
</ns2:usefulDataList>
</ns2:data>
</ns2:root2>
This should be done inside a Biztalk Functoid, as you see namespaces from source and target are diferent.
I'm an absolute beginner with XSLT, and I've been doing some tests, but I've something wrong with my XSLT expressions:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns2="http://new/xml">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template name="testTemplate" match="//*[local-name() = 'usefulDataList ']">
<xsl:element name="ns0:usefulDataList " namespace="">
<xsl:apply-templates mode="copy-no-ns" select="usefulDataList"/>
</xsl:element>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-no-ns"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I'd appreciate any tip, with XSLT or Biztalk mapper. I don't like linking a huge amount of fields one by one if I can solve it with a XSLT expression.
Greetings.
Beware you had a space in *[local-name() = 'usefulDataList ']" so that would never match. this works:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns2="http://new/xml">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<ns2:root>
<ns2:blabla>
<ns2:stuff />
</ns2:blabla>
<ns2:data>
<xsl:apply-templates mode="copy-no-ns" select="//*[local-name() = 'usefulDataList']"/>
</ns2:data>
</ns2:root>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="ns2:{local-name(.)}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-no-ns"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I am new to XSLT I am trying to transform a name value pair to its corresponding XML. This feature is primarily used in case of special extensions to a standard.
The file I want to transform is the following. There are no spaces expected in any of the extNames.
<?xml version="1.0" encoding="UTF-8"?>
<extensionItems xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="ExtensionItems.xsd">
<extensionsItem>
<extName> callCode</extName>
<extValue>1</extValue>
<extType>integer</extType>
</extensionsItem>
<extensionsItem>
<extName>callbackType</extName>
<extValue>All</extValue>
<extType>string</extType>
</extensionsItem>
<extensionsItem>
<extName>callbackEmail</extName>
<extValue>me#mine.org</extValue>
<extType>string</extType>
</extensionsItem>
</extensionItems>
to the following:
<ODEventNotificationExtraField>
<callCode> 1</callCode>
<callbackType> All </callbackType>
<callbackEmail> me#mine.org </callbackEmail>
</ODEventNotificationExtraField>
The following stylesheet produces the desired result:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="extensionItems">
<ODEventNotificationExtraField>
<xsl:apply-templates/>
</ODEventNotificationExtraField>
</xsl:template>
<xsl:template match="extensionsItem">
<xsl:element name="{extName}">
<xsl:value-of select="extValue"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I wanted to use a dynamic variable name in the select statement in xslt.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:variable name="input" select="input/message" />
<xsl:variable name="Name" select="'MyName'" />
<xsl:variable name="Address" select="MyAddress" />
<xsl:variable name="output" select="concat('$','$input')" /> <!-- This is not working -->
<output>
<xsl:value-of select="$output" />
</output>
</xsl:template>
The possible values for the variable "input" is 'Name' or 'Address'.
The select statement of the output variable should have a dynamic variable name based on the value of input variable. I don't want to use xsl:choose. I wanted to select the value dynamically.
Please provide me a solution.
Thanks,
dhinu
XSLT 1.0 and XSLT 2.0 don't have dynamic evaluation.
Solution for your problem:
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:my="my:my">
<xsl:output method="text"/>
<my:values>
<name>MyName</name>
<address>MyAdress</address>
</my:values>
<xsl:template match="/">
<xsl:variable name="vSelector"
select="input/message"/>
<xsl:value-of select=
"document('')/*/my:values/*[name()=$vSelector]"/>
</xsl:template>
</xsl:stylesheet>
when applied on the following XML document:
<input>
<message>address</message>
</input>
produces the wanted, correct result:
MyAdress
when the same transformation is applied on this XML document:
<input>
<message>name</message>
</input>
again the wanted, correct result is produced:
MyName
Finally: If you do not wish to use the document() function, but would go for using the xxx:node-set() extension function, then this solution (looking very similar) is what you want, where you may consult your XSLTprocessor documentation for the exact namespace of the extension:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ext="http://exslt.org/common" >
<xsl:output method="text"/>
<xsl:variable name="vValues">
<name>MyName</name>
<address>MyAdress</address>
</xsl:variable>
<xsl:template match="/">
<xsl:variable name="vSelector"
select="input/message"/>
<xsl:value-of select=
"ext:node-set($vValues)/*[name()=$vSelector]"/>
</xsl:template>
</xsl:stylesheet>
Beside #Dimitre's good answer, for this particular case (output string value) you could also use:
<xsl:variable name="output"
select="concat(substring($Name, 1 div ($input = 'Name')),
substring($Address, 1 div ($input = 'Address')))"/>
I have this simplified xml:
<?xml version="1.0" encoding="UTF-8"?>
<a>
<b>
<c>
<d>1</d>
<e>2</e>
</c>
</b>
<f>
<g>3</g>
</f>
</a>
This is the xslt i try to apply:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="a">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="b">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="c">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="d">
</xsl:template>
</xsl:stylesheet>
When I apply this sheet, I get output 2 3, which are the remaining textnodes. I've read about the built-in templates which get applied if it can't find a matching template, but in this case, it should find a template?
What is going on?
Edit:
In this case, i would expect to see nothing, because the templates are empty. But i get 2 3 in stead.
When you do <xsl:template match="d">, you tell the processor to ignore all nodes under <d>.
All other nodes are processed with default rules, including the text() one, which is to print the text.
That's why you see 23, and not 1.
Start from the root:
<xsl:template match="/a">
And specify either a mode (so that the default template does not get called, because it does not find a template for e, f and g) or define your own * template which does nothing at the end of the stylesheet:
<xsl:template match="*"/>