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Is it possible to assign value of one structure variable to another structure variable
Is this code correct -
#include<iostream.h>
struct s1
{
int a;
float b;
char c;
} st1,st2,st3;
int main()
{
struct s2{
int x;
float y;
char z;
} ss1,ss2,ss3;
// Read & Initialize structures
ss2=ss1;
:
ss3.z=st1.c;
:
}
void func1()
{
ss2.x=st1.a;
ss3.y=st2.b;
ss1.z=st3.c;
:
ss1=ss3;
}
Kindly clear my doubt whether the above code is OK or not
ss2=ss1; this will depend on the compiler some compiler will allow to copy the structure variable and some not.
ss2.x=st1.a; ss2 structure will be local to the main function and it is not available in funct1(), so it must be throwing the compilation error.
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While printing the address and value of 'X' in function foo1 and the address and value of Y in foo2, why it is showing the same values for both of the functions?
#include <stdio.h
void foo1(int xval)
{
int x;
x = xval;
/* print the address and value of x here */
}
void foo2(int dummy)
{
int y;
/* print the address and value of y here */
}
int main()
{
foo1(7);
foo2(11);
return 0;
}
Output of the program is
Address of X is: 65518
Value of X is: 7
Address of Y is: 65518
Value of Y is: 7
It's because they're created on the stack, which is unwound after each function call. So they are created at the same memory address.
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I have function declaration as int StartSale(CTXNSession & txnsession) where CTXNSession is a class.
I need to create pointer to this function.
I tried to achieve it like this:
int (*pFct)(CTXNSession&);
But I got compilation error.
But if the argument was of a predefined type , there was no error.
Please assist
Your declaration of function pointer is correct. Perhaps you forgot to declare the class? Or maybe some other error.
This code compiles without errors:
class CTXNSession; // your class
int StartSale(CTXNSession & txnsession) {} // your function
int main() {
int (*pFct)(CTXNSession&); // function pointer declaration
pFct = StartSale; // assignment for a bonus
return 0;
}
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This is a code that takes a series of 3 numbers in a number pattern and figures out the difference between them. everything seems to be right but my compiler keeps telling me I need an initializer before int i? sorry, I'm new to C++ so I'm sure my code is horrible.
using namespace std;
void add(int a, int b, int c)
int i;
for (a+i!=b;b+i!=c)
{i=0; i<100; i++;}
else {cout i;}
};
int main()
{
int x, y, z;
cin>>x;
cin>>y;
cin>>z;
add(x, y, z);
}
Many things, first you're missing a curly braze after your add function.
Also, you have one extra ; in your for declaration.
Also, after your function add there shouldn't be a ;
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struct info{
int num;
int weight;
};
vector<info> nbr;
the above declarations are global, and I have a loop in my function that looked like this
for(int i=0;i<nbr.size();i++){
info i = nbr.at(i);
vector<int> v;
v.push_back(i.weight);
tb[i.num] = v;
}
info i = nbr.at(i) gives me error: no matching function for call to 'std::vector<info, std::allocator<info> >::at(info&)'
why? what did I do wrong?
for(int i=0;i<nbr.size();i++){
info i = nbr.at(i);
This is why.
You're redefining what i refers to.
It's both your loop index int i and info i, and your compiler is wondering why you're passing an info& to vector::at.
Change the name and you should be good to go.
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I has a class A:
struct A
{
std::map<int,int> aa;
}
and a class B:
struct B
{
std::map<int,B> bb;
}
If those code in a infinite loop:
B b;
int inx=0;
while(true)
{
A a;
a.aa[0] = 0;
b.bb[inx] = a;
++inx;
}
Will that cause memory leak ?
I want all values of a copy to b[inx]. I just want to know that is the implementaion of std::map pointer ?
Will that cause memory leak ?
There are no memory leak in your program, but a compilation error, since there are no operator[] defined for struct B.
Assuming you add to map here:
while(true)
{
A a;
a[0] = 0;
b[inx] = a;
++inx;
}
there are no memory leaks. The memory will increase until you use all int numbers, but that's normal, since they have to be stored somewhere in memory.