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This is a code that takes a series of 3 numbers in a number pattern and figures out the difference between them. everything seems to be right but my compiler keeps telling me I need an initializer before int i? sorry, I'm new to C++ so I'm sure my code is horrible.
using namespace std;
void add(int a, int b, int c)
int i;
for (a+i!=b;b+i!=c)
{i=0; i<100; i++;}
else {cout i;}
};
int main()
{
int x, y, z;
cin>>x;
cin>>y;
cin>>z;
add(x, y, z);
}
Many things, first you're missing a curly braze after your add function.
Also, you have one extra ; in your for declaration.
Also, after your function add there shouldn't be a ;
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I am coding a cos(x) function in C++ but the result I am getting is infinity, except that it should be -1/3.
Here is my code:
#include <iostream>
#include <math.h>
using namespace std;
The factorial function:
int factorial(unsigned int n)
{
unsigned long factorial = 1;
for(int o=1;o<=n;o++)
{
factorial *= o;
}
}
int main()
{
double x;
double answre;
double input;
cin>>input;
for(int i=0;i<2;i++)
{
double y=2*(i)+2;
I declared y here instead of implementing it's value directly, since I thought it is dividing by factorial instantaneously and that is the reason for all the parentheses as well.
x=((pow(input,2*(i)+2))/(factorial(y)))*(pow(-1,(i)+1));
x=+x;
}
answere=1+x;
cout<<answere<<endl;
return 0;
}
You are not returning anything in factorial
x=((pow(input,2*(i)+2))/(factorial(y)))*(pow(-1,(i)+1));
x=+x; // ???
If you want to add to x, just write x += .... What you did was assign one (!) summand to x and then set x to itself. You are never adding anything.
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Okay so im trying to do some old quiz from my university and i have a question and this is the answer like this , when i try it on Dev-C++ its say wrong , but the teacher say its correct
#include <iostream>
using namespace std;
void add (int,int);
int substract(int,int);
int multiply(int,int);
void divide(int,int);
int main()
{
int a,b;
cout<<"Please Enter The Value of a: ";
cin>>a;
cout<<"Please Enter The Value of b: ";
cin>>b;
add(a,b);
cout<<"The substract a-b is: "<<substract(a,b)<<endl;
cout<<"The multiply a*b is : "<<multiply(a,b)<<endl;
divide(a,b);
return 0;
}
void add (int a,int b);
{
cout<<"There sum is: "<<a+b<<endl;
}
int substract(int a,int b);
{
return (a-b);
}
int multiply (int a,int b);
{
return (a*b);
}
void divide (int a,int b);
{
cout<<"There divide is: "<<a/b<<endl;
}
You are placing semi colons at the end of your functions params list For example:
int substract(int a,int b); ---> (Should not have a semi-colon here)
{
return (a-b);
}
Whenever C++ compiler throws an unexpected unqualified at you, it is usually in part because your semi-colons are incorrect. This is good to remember for debugging in the future!
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I thought the output would be 70? (20+20+20+10=70) Why is it so large?
#include <iostream>
using namespace std;
int main()
{
int a,b,c=20;
int d=10;
int sum = a+b+c+d;
cout << sum;
return 0;
}
The issue is that you are not initializing the variables a and b. That means when you attempt to run your program, the computer is looking in memory for a value to use for each, and that number could be very big or very small. Try this:
#include <iostream>
using namespace std;
int main()
{
int a = 20,b = 20,c=20; //here, a and b are defined
int d=10;
int sum = a+b+c+d;
cout << sum;
return 0;
}
C is the only one variable that you initialize to 20, the other 2 variables
(a and b) are holding garbage..
so your math calculation is undefined behaviour.
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help plz its showing invalid indirection
i used it to find the location or memory addresses of elements in the array b
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int *ptr;
int b[]={1,0,2,3,4,5,6,7,8,9};
ptr=b;
for(int i=0;i<10;i++)
cout<<ptr[i]<<" "<<*b[i];
}
In order to print the address of the ith element in an array b, use
std::cout << b + i;
This will work in all cases except when b is an array of char, in which case you need to cast to void*
std::cout << static_cast<const void*>(b + i);
in place of iostream.h it should be iostream.
void main() ; it should be int main().
cout<<ptr[i]<<" "<<(b+i)<<endl;
Formatting by using endl in above line of code will make the result clear.
Your function should return an integer value.
return 0;
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Is it possible to assign value of one structure variable to another structure variable
Is this code correct -
#include<iostream.h>
struct s1
{
int a;
float b;
char c;
} st1,st2,st3;
int main()
{
struct s2{
int x;
float y;
char z;
} ss1,ss2,ss3;
// Read & Initialize structures
ss2=ss1;
:
ss3.z=st1.c;
:
}
void func1()
{
ss2.x=st1.a;
ss3.y=st2.b;
ss1.z=st3.c;
:
ss1=ss3;
}
Kindly clear my doubt whether the above code is OK or not
ss2=ss1; this will depend on the compiler some compiler will allow to copy the structure variable and some not.
ss2.x=st1.a; ss2 structure will be local to the main function and it is not available in funct1(), so it must be throwing the compilation error.