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apologies for what is probably a really simple question but I am a complete noob when it come to using regular expressions.
I am trying to create an expression that matches some set criteria together, and although I can find the code to validate these things separately I'm struggling to understand how you put it all together.
What I am looking for is an expression that validates an entered code:
It will always a start with either OR or TR and then you will have 6 digits after that e.g. TR002563
Any help would be greatly appreciated.
Try this regex:
/^(?:O|T)R[0-9]{6}$/
You can use this regex:
/^[OT]R[0-9]{6}$/
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I want to do the following match and capture the group
(inside),(inside),...,(inside)
or
(inside)
That is, either the same inside appears multiple times inside parentheses and separated by a comma, or it only appear once inside parentheses.
The capture group is the stuff inside. Could anybody help me?
Thanks.
change
Sorry that I did not make it clear. The stuff inside may contain parentheses, but not comma. That is the way it is distinguished.
Use a back-reference to test that the same string is repeated.
/^\(([^,]*)\)(?:,\(\1\))*$/
DEMO
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what is the regular expression to validate a string. the string should contain
all lower case
_ is allowed in the string.
Thanks in advance.
You need to use regex pattern
^[a-z_]*$
You can use a POSIX class as an alternative to a simple character class to achieve this:
[[:lower:]_]*
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How to match anything between {esbmsg:header: and }
like xxxxxx could be any string {esbmsg:header:xxxxxx}
Try with:
{esbmsg:header:([^}]*)}
Where [^}]* matches everything that is not } character.
Try this regex
{esbmsg:header:(.*)}
It will also allow you to have any character in value.
Well, if you want to capture only the content of your expression (the "xxxxx" part) the best approach is to use positive look ahead:
(?<={esbmsg:header:)[^}]+
Depending on how your content looks you might have to tweak the [^}] part. For further information on regex (or a detailed explanation of the expression above) I recommend the following:
Regex reference
Regex tutorial
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I currently have this Regex:
.*[a-z]$|.*[A-Z]$|.*[0-9]$
I need to add the following to the existing - /:.#[]()
Does anyone know how to do it?
You don't need multiple OR conditions. Have only one and include special characters also:
[0-9A-Za-z\/#:.()\[\]]
Per your comments, this should do it for you:
^[a-zA-Z0-9/:.#\[\]()]+$
This will match a string containing only the characters you've specified.
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How would I go about writing a regex to match the first example, but not the second?
Thank you --
Try
\[Test\]
You need to escape the [ and ] as they indicate range start/end.
[] are special characters for a regex, used for defining a character class, therefore escape them with backslashes.
\[Test\]
If you use [Test], it will match a single character which is either T, e, s or t.