xsl merge same elements - xslt

Question

Following big problem:
<root>
<div>
<programm></programm>
<systemes><p></p></systemes>
<systemes><table>.1.</table></systemes>
<systemes><table>.2.</table></systemes>
<systemes><p></p></systemes>
<requirements></requirements>
</div>
<div>
<programm></programm>
<systemes><table>.1.</table></systemes>
<systemes><p></p></systemes>
<requirements></requirements>
</div>
<div>
<programm></programm>
<systemes><table>.1.</table></systemes>
<systemes><table>.2.</table></systemes>
<systemes><p></p></systemes>
<requirements></requirements>
</div>
</root>
I need the output to be this:
<root>
<div>
<programm></programm>
<systemes><p></p><table>.1.</table><table>.2.</table><p></p></systemes>
<requirements></requirements>
</div>
<div>
<programm></programm>
<systemes><table>.1.</table><p></p></systemes>
<requirements></requirements>
</div>
<div>
<programm></programm>
<systemes><table>.1.</table><table>.2.</table><p></p></systemes>
<requirements></requirements>
</div>
</root>
I hope someone can help me with this problem. I know the Muenchian Method but dont get it to work properly. Thank you very much!
This is what I tried so far:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes" />
<xsl:strip-space elements="*"/>
<xsl:key name="systemsKey" match="//systemes" use="name()"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="systemes[generate-id()=generate-id(key('systemesKey', name())[1])]">
<xsl:copy>
<xsl:apply-templates select="#*|key('systemesKey', name())/node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="systemes[not(generate-id()=generate-id(key('systemesKey', name())[1]))]"/>
</xsl:stylesheet>

Answer 1

This produces exactly the output you described (except for the order of childs inside systemes elements).
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="root">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="requirements|programm|p">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="div">
<xsl:copy>
<xsl:element name="systemes">
<xsl:for-each select="systemes">
<xsl:apply-templates/>
</xsl:for-each>
</xsl:element>
<xsl:apply-templates select="requirements|programm"/>
</xsl:copy>
</xsl:template>
<xsl:template match="table">
<xsl:copy>
<xsl:value-of select="."/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
You do not need to use grouping at all, Muenchian or not. I would not advise you use something as complex as keys if it is not necessary for the goal you want to achieve.
EDIT: I have used XSLT 2.0 but there is nothing in it which cannot be done in 1.0.