I`m trying to setup my calibre (calibre-ebook.com) to automatic get data from imported pdf files into library.
Usually i name my files this way:
Author. Title. Local. Publisher. Published. ISBN.pdf
Example:
C:\Test\RANCIÊRE, Jacques. O mestre ignorante. Belo Horizonte. Autêntica. 2010. 978-85-7526-045-6.pdf
I`m stuck trying get the first paramenter: Author, using the regex:
([^\\]+)\.
I`m getting this value:
RANCIÊRE, Jacques. O mestre ignorante. Belo Horizonte. Autêntica. 2010. 978-85-7526-045-6
Since regex read from left to right isn`t to stop on first dot (.) from .?
The desired value on this example is:
RANCIÊRE, Jacques
Any hint for the other fields? Example for Title the desired value is:
O mestre ignorante
Thanks in advice!!!
^.+?\. will get you the C:\Test\RANCIÊRE, Jacques.
it means get the all characters before the first dot.
if you want only RANCIÊRE, Jacques than use:
(?!(.*\\))(.+?\.)
will give you RANCIÊRE, Jacques.
Regex capturing is greedy, meaning it tries to get the largest match as possible. Try the non-greedy version:
([^\\]+?)\.
Note the only difference is the addition of a ?.
Afterwards, you should be able to retrieve the author's name ("RANCIÊRE, Jacques") with just \1.
Related
I have file names in a URL and want to strip out the preceding URL and filepath as well as the version that appears after the ?
Sample URL
Trying to use RegEx to pull, CaptialForecasting_Datasheet.pdf
The REGEXP_EXTRACT in Google Data Studio seems unique. Tried the suggestion but kept getting "could not parse" error. I was able to strip out the first part of the url with the following. Event Label is where I store URL of downloaded PDF.
The URL:
https://www.dudesolutions.com/Portals/0/Documents/HC_Brochure_Digital.pdf?ver=2018-03-18-110927-033
REGEXP_EXTRACT( Event Label , 'Documents/([^&]+)' )
The result:
HC_Brochure_Digital.pdf?ver=2018-03-18-110927-033
Now trying to determine how do I pull out everything after the? where the version data is, so as to extract just the Filename.pdf.
You could try:
[^\/]+(?=\?[^\/]*$)
This will match CaptialForecasting_Datasheet.pdf even if there is a question mark in the path. For example, the regex will succeed in both of these cases:
https://www.dudesolutions.com/somepath/CaptialForecasting_Datasheet.pdf?ver
https://www.dudesolutions.com/somepath?/CaptialForecasting_Datasheet.pdf?ver
Assuming that the name appears right after the last / and ends with the ?, the regular expression below will leave the name in group 1 where you can get it with \1 or whatever the tool that you are using supports.
.*\/(.*)\?
It basically says: get everything in between the last / and the first ? after, and put it in group 1.
Another regular expression that only matches the file name that you want but is more complex is:
(?<=\/)[^\/]*(?=\?)
It matches all non-/ characters, [^\/], immediately preceded by /, (?<=\/) and immediately followed by ?, (?=\?). The first parentheses is a positive lookbehind, and the second expression in parentheses is a positive lookahead.
This REGEXP_EXTRACT formula captures the characters a-zA-Z0-9_. between / and ?
REGEXP_EXTRACT(Event Label, "/([\\w\\.]+)\\?")
Google Data Studio Report to demonstrate.
Please try the following regex
[A-Za-z\_]*.pdf
I have tried it online at https://regexr.com/. Attaching the screenshot for reference
Please note that this only works for .pdf files
Following regex will extract file name with .pdf extension
(?:[^\/][\d\w\.]+)(?<=(?:.pdf))
You can add more extensions like this,
(?:[^\/][\d\w\.]+)(?<=(?:.pdf)|(?:.jpg))
Demo
I'm using an application called Firemon which uses regex to pull text out of various fields. I'm unsure what specific version of regex it uses, I can't find a reference to this in the documentation.
My raw text will always be in the following format:
CM: 12345
APP: App Name
BZU: Dept Name
REQ: First Last
JST: Text text text text.
CM will always be an integer, JST will be sentence that may span multiple lines, and the other fields will be strings that consist of 1-2 words - and there's always a return after each section.
The application, Firemon, has me create a regex entry for each field. Something simple that looks for each prefix and then a return should work, because I return after each value. I've tried several variations, such as "BZU:\s*(.*)", but can't seem to find something that works.
EDIT: To be clear I'm trying to get the value after each prefix. Firemon has a section for each field. "APP" for example is a field. I need a regex example to find "APP:" and return the text after it. So something as simple as regex that identifies "APP:", and grabs everything after the : and before the return would probably work.
You can use (?=\w+ )(.*)
Positive lookahead will remove prefix and space character from match groups and you will in each match get text after space.
I am a little late to the game, but maybe this is still an issue.
In the more recent versions of FireMon, sample regexes are provided. For instance:
jst:\s*([^;]?)\s;
will match on:
jst:anything in here;
and result in
anything in here
I am a new user of svlib package in systemverilog environment. Refer to Verilab svlib. I have following sample text , {'PARAMATER': 'lollg_1', 'SPEC_ID': '1G3HSB_1'} and I want to use regex to extract 1G3HSB from this text.
For this reason, I am using the following code snippet but I am getting the whole line instead of only the information.
wordsRe = regex_match(words[i], "\'SPEC_ID\': \'(.*?)\'");
$display("This is the output of Regex: %s", wordsRe.getStrContents())
Can anybody direct me what is going wrong?
The output I am getting : {'PARAMATER': 'lollg_1', 'SPEC_ID': '1G3HSB_1'}
And, I want to get: 1G3HSB_1
It seems you need to get the contents of the first capturing group with getMatchString(1). Also, you need to use a greedy quantifier (lazy ones are not POSIX compliant) and a negated bracket expression - [^']* instead of .*?:
wordsRe = regex_match(words[i], "\'SPEC_ID\': \'([^\']*)\'");
$display("This is the output of Regex: %s", wordsRe.getMatchString(1))
See the User Guide details:
getMatchString(m) is always exactly equivalent to calling the range method on the Str object containing the string that was searched:
range(getMatchStart(m), getMatchLength(m))
I have a set of strings that I'd like to parse in MATLAB 2012 that all have the following format:
string-int-int-int-int-string
I'd like to pluck out the third integer (the rest are 'don't cares'), but I haven't used MATLAB in ages and need to refresh on regular expressions. I tried using the regular expression '(.*)-(.*)-(.*)-\d-(.*)' but no dice. I did check out the MATLAB regexp page, but wasn't able to figure out how to apply that information to this case.
Anyone know how I might get the desired result? If so, could you explain what the expression you're using is doing to get that result so that others might be able to apply the answer to their unique situation?
Thanks in advance!
str = 'XyzStr-1-2-1000-56789-ILoveStackExchange.txt';
[tok] = regexp(str, '^.+?-.+?-.+?-(\d+?)-.+?-.+?', 'tokens');
tok{:}
ans =
'1000'
Update
Explanation, upon request.
^ - "Anchor", or match beginning of string.
.+? - Wildcard match, one or more, non-greedy.
- - Literal dash/hyphen.
(\d+?) - Digits match, one or more, non-greedy, captured into a token.
^.*?-.*?-.*?-(\d+)-.*?-.*?$
OR
^(?:[^-]*?-){3}(\d+)(?:.*?)$
Group1 now contains your required data
I'm trying to use a custom regex clean transformation (information found here ) to extract a post code from a mixed address column (Address3) and move it to a new column (Post Code)
Example of incoming data:
Address3: "London W12 9LZ"
Incoming data could be any combination of place names with a post code at the start, middle or end (or not at all).
Desired outcome:
Address3: "London"
Post Code: "W12 9LZ"
Essentially, in plain english, "move (not copy) any post code found from address3 into Post Code".
My regex skills aren't brilliant but I've managed to get as far as extracting the post code and getting it into its own column using the following regex, matching from Address3 and replacing into Post Code:
Match Expression:
(?<stringOUT>([A-PR-UWYZa-pr-uwyz]([0-9]{1,2}|([A-HK-Ya-hk-y][0-9]|[A-HK-Ya-hk-y][0-9] ([0-9]|[ABEHMNPRV-Yabehmnprv-y]))|[0-9][A-HJKS-UWa-hjks-uw])\ {0,1}[0-9][ABD-HJLNP-UW-Zabd-hjlnp-uw-z]{2}|([Gg][Ii][Rr]\ 0[Aa][Aa])|([Ss][Aa][Nn]\ {0,1}[Tt][Aa]1)|([Bb][Ff][Pp][Oo]\ {0,1}([Cc]\/[Oo]\ )?[0-9]{1,4})|(([Aa][Ss][Cc][Nn]|[Bb][Bb][Nn][Dd]|[BFSbfs][Ii][Qq][Qq]|[Pp][Cc][Rr][Nn]|[Ss][Tt][Hh][Ll]|[Tt][Dd][Cc][Uu]|[Tt][Kk][Cc][Aa])\ {0,1}1[Zz][Zz])))
Replace Expression:
${stringOUT}
So this leaves me with:
Address3: "London W12 9LZ"
Post Code: "W12 9LZ"
My next thought is to keep the above match/replace, then add another to match anything that doesn't match the above regex. I think it might be a negative lookahead but I can't seem to make it work.
I'm using SSIS 2008 R2 and I think the regex clean transformation uses .net regex implementation.
Thanks.
Just solved this. As usual, it was simpler logic than I thought it should be. Instead of trying to match the non-post code strings and replace them with themselves, I have added another line matching the postcode again and replacing it with "".
So in total, I have:
Match the post code using the above regex and move it to the Post Code column
Match the post code using the above regex and replace it with "" in the Address3 column