I want a find/replace that matches the HTML encoded tab character and replace it with a space.
When I load the following query via Dreamweaver's dreamweaver.setUpComplexFindReplace API function, the is converted to a literal tab character, so no matches are made.
How do I stop the HTML encoded string from being converted?
dreamweaver.setUpComplexFindReplace('<dwquery> <queryparams matchcase="false" ignorewhitespace="false" useregexp="false" wholeword="true" /> <find searchmode="document"> <qtext qname=" " qraw="true"></qtext> </find> <replace action="replaceText" param1="" param2=""/></dwquery>');
dreamweaver.replaceAll();
In your qtext node, change the qname value from to 	.
Related
I want to use regex select the first quote after each instance of img_ in the below code. In this example, it would be the " after the jpg.
I tried using the following regex:
\(?<=img_.*)"+?\g
but all the quotes after img_ in each line were selected, including the quotes around "533". How do I match the quotes after .jpg without matching any other quotes?
<img class="confluence-embedded-image confluence-content-image-border" height="399" src="img_78.jpg" width="533" />
<img class="confluence-embedded-image confluence-content-image-border" height="399" src="img_78.jpg" width="533" />
<img class="confluence-embedded-image confluence-content-image-border" height="399" src="img_78.jpg" width="533" />
I want to avoid using .jpg because that .jpg could be many other thing (.png, .jpeg, etc). I want to get the first quote after img_ regardless of what come between img_ and the quote.
I basically want to search in a file using that regex expression and only return the first quote after each instance of img_. I'm using the replace-in-file module in nodejs which takes in this regular expression and replaces it with a given expression. I tried the above regular expression but it replaces the entire match.
How do I match the quotes after .jpg without matching any other quotes?
\.jpg(")
Link
I want to avoid using .jpg because that .jpg could be many other thing (.png, .jpeg, etc). I want to get the first quote after img_ regardless of what come between img_ and the quote.
img_.*?(")
Link
I've got several files that have double <body> tags in them (either on purpose or by accident). I'm looking to find the first occurrence only of the <body> tag and append it with additional HTML code. But the second occurrence shouldn't be affected. I'm using TextWrangler. The regex I'm using now replaces both occurrences rather than just the first.
Text:
<body someattribute=...>
existing content
<body onUnload=...>
RegEx I'm using:
Find: (\<body.*\>)
Replace with:
\n\1
appended HTML code
Current result:
<body someattribute=...>
appended HTML code
existing content
<body onUnload=...>
appended HTML code
So it's adding my appended code twice. I just want it to happen to the first <body...> only.
Regex:
(?s)(<body.*?>)(.*)
Replace:
\1\nappended content\n\2
Explanation:
(?s) makes the . character match new lines. Without this, the . character will match all characters until it hits a new line character.
(<body.*?>) Finds the first "body" and captures as group 1 (\1).
(.*) Finds everything after the first "body", and captures as group 2 (\2).Replaces everything that was found with group 1 + new line + appended content + new line + group 2
Tested in Notepad++
I am trying to pull a value from my HTML Source code and use it as a Grep Extract.
Using Burp Suite's 'Grep - Extract', how do I extract the following text value (in this case the text is hello, but it changes every time and I want to be able to extract the value of text=)?
<div id="CaptchaImage">
<img src="Captcha.ashx?text=hello">
</div>
Define at start and end?
Or Extract from regex group?
I can't seem to get this to work.
Define at start and end, start after expression src="Captcha.ashx?text=, end at delimiter ".
Alternatively, define from regex group src="Captcha.ashx\?text=([^"]+)". And here's hoping I didn't forget any backslashes in there.
I have the following content
<li>Title: [...]</li>
and I'm looking for regex that will match and replace this so that I can parse it as XML. I'm just looking to use a regex find and replace inside Sublime Text 2, so I want to match everything in the above example except for the [...] which is the content.
Why not extract the content and use it to build the xml rather than trying to mold the wrapper of the content into xml? (or am i mis understanding you?)
<li>Title: ([^<]*)<\/li>
is the regular expression to extract the content.
Its pretty self explanatory other than the [^<]* which means match any number of characters that is not a "<"
I don't know Sublime, but something like this should suffice to get you the contents of the li. It allows for there being optional extra attributes on the tag. Make sure and turn off case-sensitivity, incase of LI or Li etc. (lifted straight from http://www.regular-expressions.info/examples.html ):
<li\b[^>]*>(.*?)</li>
<li>\S*(.*)?</li>
That should match your string, with the content being capturing group 1.
Assuming i got really really large list of random numbers in a text file each entry separated by newline how do i construct a xml structure.
Source
6253266057
3970002069
6837266077
...
Result wanted
<Random value="6253266057" />
..
I did string replace on Source but then it complained of unclosed string since last quote would have to be in last line making other entries look abandoned.
In some programming languages or even text editors you can replace:
^(\d+)$
with
<Random value="\1" />
Where \1 is matching number