I am having a hard time with replacing this text with something else .
This XML uses also next lines .
<Need>
<Need type="money" amount="100"/>
</Need>
I have tried it with this :
<Need>([\n]*[a-Z]*)</Need>
<Need>(?:[^\n]*(\n+))+</Need>
<Need>([^\n]*[0->]*[a-Z]*)</Need>
<Need>([^\n]*[a-Z]*)</Need>
Non of them worked and 2 deleted the whole text :( .
Find:
<Need>(.*?)</Need>
Replace by:
$1
Be sure that:
regular expression is checked.
. (dot) matches newline is checked.
Use this for extensive search and replace considering white space and new line.
[\s]*<Need>[\r\s]*<Need[^/]*/>[\r\s]*</Need>
Related
I have something like this in txt
[[asdfg]] [[abcd|qwerty]]
in a row, but I want it to look like that
[[asdfg]] [[qwerty]]
using wildcards ( [[.*\| ) when trying to search, results in it finding the whole line up to the "|" Not allowing it to have a space in between should work, but I don't know how to do that.
Edit 1
It's from a wikipedia dump, so the first part is the word in it's basic form and the second is how it fits into the sentence. Something like [[I]] [[be|was]] [[at]] [[the]] [[doctor]] And I want to change it into normal sentences
[[I]] [[was]] [[at]] [[the]] [[doctor]]
Edit 2
I found somewhat of a solution. I just put every word in a new line, did the first regex and then deleted newlines. That did kinda mess up my spacing though...
Try this regex:
\[\[\w+\|(\w+)\]\]
Replace with:
[[$1]]
Make sure you choose Regular expression at the bottom before you click Replace All in Notepad++.
You can do it all in one run like so
\[{2}(?:(?!\]{2}).)+?\|([^\]]+)
This needs to be replaced by
[[$1
See a demo on regex101.com.
Broken down this says:
\[{2} # match [[
(?:(?!\]{2}).)+? # do not overrun ]]
\| # |
([^\]]+) # capture anything not ] into group 1
Afterwards, you'll only need to replace the open brackets and the content of group $1
I don't know anything about Notepad++ Regex.
This is the data I have in my CSV:
6454345|User1-2ds3|62562012032|324|148|9c1fe63ccd3ab234892beaf71f022be2e06b6cd1
3305611|User2-42g563dgsdbf|22023001345|0|0|c36dedfa12634e33ca8bc0ef4703c92b73d9c433
8749412|User3-9|xgs|f|98906504456|1534|51564|411b0fdf54fe29745897288c6ad699f7be30f389
How can I use a Regex to remove the 5th and 6th column? The numbers in the 5th and 6th column are variable in length.
Another problem is the User row can also contain a |, to make it even worse.
I can use a macro to fix this, but the file is a few millions lines long.
This is the final result I want to achieve:
6454345|User1-2ds3|62562012032|9c1fe63ccd3ab234892beaf71f022be2e06b6cd1
3305611|User2-42g563dgsdbf|22023001345|c36dedfa12634e33ca8bc0ef4703c92b73d9c433
8749412|User3-9|xgs|f|98906504456|411b0fdf54fe29745897288c6ad699f7be30f389
I am open for suggestions on how to do this with another program, command line utility, either Linux or Windows.
Match \|[^|]+\|[^|]+(\|[^|]+$)
Repalce $1
Basically, Anchor to the end of the line, and remove columns [-1] and [-2] (I assume columns can't be empty. Replace + with * if they can)
If you need finer detail then that, I'd recommend writing a Java or Python script to manual parse and rewrite the file for you.
I've captured three groups and given them names. If you use a replace utility like sed or vimregex, you can replace remove with nothing. Or you can use a programming language to concatenate keep_before and keep_after for the desired result.
^(?<keep_before>(?:[^|]+\|){3})(?<remove>(?:[^|]+\|){2})(?<keep_after>.*)$
You may have to remove the group namings and use \1 etc. instead, depending on what environment you use.
Demo
From Notepad++ hit ctrl + h then enter the following in the dialog:
Find what: \|\d+\|\d+(\|[0-9a-z]+)$
Replace with: $1
Search mode: Regular Expression
Click replace and done.
Regex Explain:
\|\d+ : match 1st string that starts with | followed by number
\|\d+ : match 2nd string that starts with | followed by number
(\|[0-9a-z]+): match and capture the string after the 2nd number.
$ : This is will force regex search to match the end of the string.
Replacement:
$1 : replace the found string with whatever we have between the captured group which is whatever we have between the parentheses (\|[0-9a-z]+)
Hi masters i need your help on Notepad++ RregExpp
i have text like this :
01:example#mail.com:test
need to convert like this :
example#mail.com:test
Thank you in advance if you help me.
Use expression ^... and replace it with empty string or better with \n like following (and remove the first two characters):
Here is a way to go:
Ctrl+H
Find what: ^[^:]+:(.+)
Replace with: $1
Replace all
Make sure to have checked Regular expresion but NOT . matches newline
I want to remove everything comes after " . " with nothing using simple regex on notepad++ It seems to be really simple one. I tried with regex "..*$" but no luck.
Eg: 129.435456
I would like to replace everything after . and get just 129
Since dot is a regex character (match one character) you need to escape the first dot
:
"\..*$"
Try without quotes in Notepad++ making sure you select "Regular expression" radio button in the bottom. Works great!
I have a file which has hundreds of links like this:
<h3>aspnet</h3>
Ex 1
Ex 2
Ex 3
So I want to remove all the elements
icon="data:image/png;base64,ivborw0kggoaaaansuheugaaabaaaaaqcayaaaaf8..."
from all the lines. I went through the official Notepad++ regex wiki and have come up with this after several trials:
icon=\"[^\.]+\"
The problem with this is, it is selecting past the second double quote and stopping at the next occurring double quote. To illustrate, this will select the following content:
icon="data:image/png;base64,...jbvebich4sec9zgth1sfue1cdt...">EX 1</a> <a href="
If I modify the above regex to,
icon=\"[^\.]+\">
Then it is almost perfect, but it is also selecting the >:
icon="data:image/png;base64,...jbvebich4sec9zgth1sfue1cdt...">
The regex I am looking for would select like this:
icon="data:image/png;base64,...jbvebich4sec9zgth1sfue1cdt..."
I also tried the following, but it doesn't match anything at all
icon=\"[^\.]+\"$
Just match anything but a quote, followed by a quote:
icon="[^"]+"
Just tested with notepad++ 6.2.2 and confirmed that this matches correctly as written.
Broken down:
icon="
This is fairly obvious, match the literal text icon=".
[^"]+
This means to match any character that is not a ". Adding the + after it means "one or more times."
Finally we match another literal ".
I am not a notepad++ user. so don't know how notepad++ plays with regex, but can you try to replace
icon=\"[^>]* to (empty string) ?
Try this solution:
This is I just check was working as you wanted it.
The way achieving your goal:
Find what: (icon.*")|.*?
Replace with: $1